5

(M{IO =Iim fu=Iim /() =Jmthe eraph above dcscribe the discontinulty a the followlng Ylutt.224 +8e80 Mnled uu tn intta Using continulty falls: Xrj5 Type: Because 10....

Question

(M{IO =Iim fu=Iim /() =Jmthe eraph above dcscribe the discontinulty a the followlng Ylutt.224 +8e80 Mnled uu tn intta Using continulty falls: Xrj5 Type: Because 10.BecauseL* Type:BecauseX3 Type:12

(M{ IO = Iim fu= Iim /() = Jm the eraph above dcscribe the discontinulty a the followlng Ylutt.224 +8e80 Mnled uu tn intta Using continulty falls: Xrj5 Type: Because 10. Because L* Type: Because X3 Type: 12



Answers

For $\mathrm{H}_{2} \mathrm{SO}_{3}(\mathrm{aq}), K_{\mathrm{a}_{1}}=1.3 \times 10^{-2}$ and $K_{\mathrm{a}_{2}}=6.3 \times$ $10^{-8} \cdot \operatorname{In} 0.10 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{3}(\mathrm{aq}),(\mathrm{a})\left[\mathrm{HSO}_{3}^{-}\right]=0.013 \mathrm{M}$ (b) $\left[\mathrm{SO}_{3}^{2-}\right]=6.3 \times 10^{-8} \mathrm{M} ;$ (c) $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=0.10 \mathrm{M}$ (d) $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=0.013 \mathrm{M} ;$ (e) $\left[\mathrm{SO}_{3}^{2-}\right]=0.036 \mathrm{M}$ $.

In this problem. We asked our ass to find the center of mass of this two dimensional system with the masses. 2 8 to 1 and four in the positions. Negative three negative. 100 And negative one, too. In order to find the center of mass, we first need to calculate the center mass in the ex direction, which we will do by calculating the moment in the UAE direction divided by the total mass. Once you've done that, we will calculate the, um, center of mass in the wind direction. Just calculate the moment in the ex direction of over the center of mess. Okay, So calculating Expert, um, the moment of wise calculating by multiplying the masses by the X coordinates. So we have eight times negative. Three plus one time, zero plus four times negative. One all over. The total mass, which is given by eight plus one is nine plus four gives us 13 doing some arithmetic. We can find out that eight times negative three is negative. 24 0 minus forgives us negative. 28 over 13. Now, to find the center of mass in the UAE direction, we're going to take the moment of X, which is the masses times there. Why Coordinates? So we're going to have eight times negative. One plus one time, zero plus four times two all over the total mass, which is still 13 here. Only two are particularly. Get negative 80 plus h, which gives us zero over 13 for our center of mass. Explore why BAR is given by the coordinate point. Negative 28 over 13 from a zero.

Eso we want to know about, um a sulfuric acid solution 0.1 muller sulfuric acid solution on And we want to know the hydro Nia, my on concentration and ah, sulfuric acid, of course, is a strong acid. The first proton will disassociate 100% and give us 0.1 model airport once era Moeller I droning on my on, But then the hydrogen sulfate ion has got a pretty large K a for a weak acid points. It's 1 to 1.1 times 10 to the minus two, which is 20.11 So we are going to get a little bit mawr age plus from the 2nd 1 And so it's gonna be a little more than, uh, 10.1 Moeller because we get that from the first proton, plus a little from the second. But we're not going to get both of the protons to dissociate completely. So those are all out. And in fact, what we have seen is that the second Proton, once we've had 100% association or whatever dissociation of the 1st 1 then the 2nd 1 tends to give hydro Nia my on equal to the K a value. So the second Proton will give us this much high droning my on the 1st 100% So this much so when you add them to get 0.111 and so that would be the hydro me in my own concentration.

Wherever you sell the cell. It was. Probably would have to do first. So I need to write out the equation. The happy closed for half years. So I know you have coffer foreigners close because we worked on those copper. You the new triple yourself. Okay, but I also don't have the concentration for copper. Plus, so I can calculate that. So if I have K S p that equals a concentration of, um here, see you toes. So mercury is P is for one. No, I you You're okay. So now one of those things Q. Same thing here. This is his copper. The and alluded. Sorry. Use. It was the same day Because you have a copper of the air. Knows a copper with the capital. You do you work?

So the relationship between the standard sound potential and equilibrium constant is as follows. We have E. Of the cell equal to eat not of the South negative, not point not 592 volts divided by N. Multiplied by log K. So here N is the number of electrons transferred in the balanced reaction. And so what we can do is plug in our values. So what we have is negative, not point not 592, invited by one, multiplied by log Of 1.1 times 10 to the -12. Where according to the next equation for a given concentration, South South is equal to zero. That is why we get rid of that caution of the equation. And what we end up with is not .71 faults.


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