5

[2/4 Points]DETAILSPREVIOUS ANSWERSSERPOPS 26.P.053_MY NOTESASK YOUR TEACHERPRACTICE ANOTHERThe object In the figure below is midway between the lens and the mirror...

Question

[2/4 Points]DETAILSPREVIOUS ANSWERSSERPOPS 26.P.053_MY NOTESASK YOUR TEACHERPRACTICE ANOTHERThe object In the figure below is midway between the lens and the mirror; which are separated by distance d = 24.5 cm_ The magnitude of the mirror's radius of curvature is 20.5 cm _ and the lens has focal length of -16.8 cm.Lens Object Mimor(a) Considering only the light that leaves the object and travels first toward the mirror locate the final image formed by this systemEnter a number: to the right

[2/4 Points] DETAILS PREVIOUS ANSWERS SERPOPS 26.P.053_ MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The object In the figure below is midway between the lens and the mirror; which are separated by distance d = 24.5 cm_ The magnitude of the mirror's radius of curvature is 20.5 cm _ and the lens has focal length of -16.8 cm. Lens Object Mimor (a) Considering only the light that leaves the object and travels first toward the mirror locate the final image formed by this system Enter a number: to the right of the mirror (b) Is this image real or virtual? real virtual Is it upright or inverted? upright inverted What is the overall magnification? Need Help? Fad @ Submit Answer



Answers

The object in Figure $\mathrm{P} 26.53$ is midway between the lens and the mirror, which are separated by a distance $d=$ $25.0 \mathrm{cm} .$ The magnitude of the mirror's radius of curvature is $20.0 \mathrm{cm}$ and the lens has a focal length of $-16.7 \mathrm{cm} .$ (a) Considering only the light that leaves the object and travels first toward the mirror, locate the final image formed by this system. (b) Is this image real or virtual? (c) Is it upright or inverted? (d) What is the overall magnification?

Put this question. We're told to look at figure p 23.5 to to see that the object is midway between a lens with a focal focal length. F of negative 16.7 centimeters in a mirror with the radius of curvature are 20 centimeters and they're separated by a distance D equal to 25 centimeters. And for part, A wants us to consider only the light that leaves the object and travels first towards the mirror and locate the final image formed by this system. Okay, so to do this, we're gonna use the lens equation which says that one over F which is equal to two over the radius of curvature since the mirror is the first thing it interacts with here, this is going to be equal to one over p one. The distance to the object from the mere plus one over kyu won the distance to the image formed by this. Well, P one is 12.5 centimeters, So we can rearrange this to solve for Kyu won. We see that q one is equal to ah p one times are divided by two times p one minus R so Q one comes out to equal that d centimeters. It's positive. Therefore, it's to the left of the mirror so we can use Kyu won the image produced by this as the object for the second part here. So for part B to find P to the object for the lens, P two is equal to the distance between the two minus Q one. So this comes out to equal negative 25 centimeters. Now, if you go back to this page, we can use this equation here, which I'm gonna underline. One over f is equal to one over p one plus one over kyu won. We can rearrange that then to solve for Q except for this time instead of one. Were using some script too. Right? So que tu is equal to p two times the focal length of the lens divided by P two minus the focal length of the lens playing those values and we find that que tu is equally negative. 50 0.3 centimeters. Weekend box said in his air solution for part A Oh, this wasn't part. Be sorry about that. This was all part of a here. So to race this okay, part be asked if this image that is produced is riel or virtual well, To do that, we just have to look at the sign of Q two. And since que Tu is negative, it's virtual. So if you two would have been positive, it would have been real making box in it. And this is their solution for part B. Parsi asked. If, uh, if the image that is produced is upright or if it's inverted To do that, we need to know the sign of the magnification. So magnification of thing Entire system is equal to the magnification produced by the mirror, which is Kyu won over P one, multiplied by the magnification produced by the lips so minus Q two over Key, too. And we know all those values, so we complex them in. We find that this is equal to positive 8.5 So since the magnification is positive, that means it's upright, so we can say, uh, in is positive. So it's up right? Making box. It is their solution for C in the part D asked for the value of this magnification. We already found that in part, see, so the value of the magnification M is equal to 8.5 making box set in as our solution for D in the final part of our question.

The mirror is a concave mirror, and lens is also often give type. Imagine the light rays passing through the mirror, forming a real inverted image in the absence of silence. Once the light risk converge to the image point, they continue through the image point and interact with the lens. The race is living. The image point behave in the same way as the race, living the object. Therefore, the image of the mirror serves as the object for and then, um so If B is the object distance Q. Is the image distance and a festive focal length of the lens or mirror, then the relation between them is one upon p. Less one upon. Q is equal to one upon If let's stay. This is Equation one. Now first, Ah, we have to find the position of the image formed by the mirror in absence of the lens. So the substitute values we have PS 1.25 There's one upon Q. And when a born, uh, every 10. So when upon Q is equal to one minus when a point then my nurse one upon two five, So Cuba will be 50 centimetre now This image will act. Is it as the object for the Let's next? Uh, we will use the lenses makers formula. That is, um when upon P plus when upon q is equal to F one upon f So we have, um, when? Upon PS minus 50 a point to less one upon Q and we have Q is minus 16 point seven. So we will get you as minus 50.3 centimetre does the why No image is 50.3 centimeters to the right of the lands. That is, um, 25.3 centimeter today, left of the later now for the second one for, uh, given objects position, object position. The final image position is negative, which confirms good form that the image is I was sure no, um, the third one magnification m is given us minus Q upon B. Since the arrangement consists of the lenses and mirrors, the overall magnification were the product of magnification, of lands and minutes. So the total magnification will be the magnification of lands multiplied by magnification of teeth. Minutes. So we have you're still lands upon the lens might be played by my neck. Rescue of the Mira one BLT meter. So, um, the mm uh huh. The image distance and they object. Distance. I hear the image distance of the middle is positive and female responsive. Also, Q of the lens is negative and he is also negative. Therefore, and total will be positive. The positive sign of the overall magnification in the case of the images up right, images upright. So now the overall Yeah. Magnification. Yeah. This and total shown in part C is of lands and magnification of the middle. We have minor skew or the lens upon P of Dylan's Yeah, the media. Yeah, the tomato. Thanks. So we have, um 50 upon 12.5 multiplied by minus minus 50.3 upon minus 25 point three. That is 8.5 for the overall magnification. Found is to be 8.5

In this problem, we have conversion and with its focal length in a complex mirror with these radius. And also we have a non recently, its location. They're in serum, uterus, impromptu of the land in the less in the mirror are gloves, centimeters a park. In the first part of the problem, we want who a compute where image produced by the linen ease. So, in order to companies, when when I use the let's equation for the situation for the lance is this and we replaced the values for the folks earlier, we have that teaches three. The optical insistence is right here for the land sleaze. Well, over living last movie you want and from here we can compute the value off you. Well, who want is five point 25 centimeters, though is more or less at this point. This is the location off the ridge produced by that first length in in second for the program. We want to know this image that is producing this point here is ah, a really or ah view jewel image. But the US would have completely body off if you are in the s party. Did you mean that is a really image. And in earth, see is a ah in government or upright image where one of compute the magnification, the magnification because of delayed this mind you won over, Do you want? This is my five point when you find three mirrors holder, the one that is living mirrors. So it is just my oath 0.75 Because this is my note. It means that this a much getting Bert. We could also say that this image is Imbert because our conversion and produce an image that when these images in the open style GOP yes, it burns. But wait, I also see that from the tine off the magnification. In the next part of the problem, we want to know where the image produced by the Comebacks mirror is. So for the Olympics mirror, the all is located at this point so hard that we can compute the optic distance. Your business will be a 12 miners 5.25 in this is it sinks point being before mirrors. So this is the object, this us And in order to compute the image this us, we're gonna use the mirror equation. So this is for the mural. So for the mirror, a focal land is it's off. Oh, uh, radius. So this is just one of voting here, it miles. Wow. Very true. Are So this is just minus two. And this is mine. Not because is a convex mirror still replacing the value of B That is 1/6. Identify, plus own. While ordering you drew, we can completely value of cultural. So good to is this mind ALS? Well, im going 64 um, years. And because this is mine ALS in minutes that the image is located past the mirror. Still, at this point, maybe 11 before. So at this point, okay, one of body that did the point. Uh huh. And in the next part of the problem, you want to know this? It's a really or image or a beautiful image, because this is his name. It is a teardrop. You know, the magnetic issue because of the mirror is just mind if you drool over being so and we already have all these values. So we just need to replace, uh, the results. And this is born to die. They're finally the order magnification. We know that Arista brother off the magnification due to the Linz in the magnification produced by the mirror. And this is just mindless born 75 that is going through tonight. Indeed it is. Just mind off or wanted one. And because this is mine was invested, a final image is inverted. Okay, in respect to the original. Okay, so we can say that is imaginatively computing the part e off. The problem is embarrassed. We respect. So the original off.

After the converging lens. The main position will be one of our F one minus one over B one, and worse. It was one of our 10 minus one of what bless buying five in verse. It was 50 centimeter. Now this is to the so Basically, here is the conference. Here's the look in the mirror. Here is the major and then the images formed 50 centimeter every and the lenses that 25 centimeter every so this distance will act as be do now. So we do is the virtual object, so that distance will be negative. 25 centimeters. Distance is 25 because it is a heart without cases negative 25 centimeters. So over here we can find Q do. It was one of our F to minus one of what we do in verse. Focus is negative. 16.7 centimeters in verse, minus my guess. 25 inverse in the worst. So we find Q do. It was negative 50.3. So that means this is ah, large, well, image again, and that is formed in this direction at 50.3 centimeters away. And this is 25 so that image. He's form 50.3, minus 25. It was 25.3 centimeter to the night off the meter. This is the main on here.


Similar Solved Questions

5 answers
M (kg) 0.2 0.4 0.6 0.8 [email protected] (rad/s) 28 40 48 56 63time (s) 0.72 0.51 0.40 0.36 0.32a (rad/s?)
m (kg) 0.2 0.4 0.6 0.8 1.0 @ (rad/s) 28 40 48 56 63 time (s) 0.72 0.51 0.40 0.36 0.32 a (rad/s?)...
5 answers
2 For h (x) = find h' (c) sin(2 )2 sin(c) 2x cos(z) 0 A) h' (x) = sin? (r2 cos(z) 2x cos(z) sin? (2)0 B) h' (c)2 sin(€) 22 cos(r) cos? (2)c) h' (.)D) h' (1)2 sin(€) 22 sin(2) Sin '(2)
2 For h (x) = find h' (c) sin(2 ) 2 sin(c) 2x cos(z) 0 A) h' (x) = sin? (r 2 cos(z) 2x cos(z) sin? (2) 0 B) h' (c) 2 sin(€) 22 cos(r) cos? (2) c) h' (.) D) h' (1) 2 sin(€) 22 sin(2) Sin '(2)...
5 answers
Maunacom StudentplaverHometton as0i7homskld-567075611&questionld elushed falsee cld 6041976&back-https Iman-mMath 2009 52Leplmmar 20201Homework: Section 2.1 HomeworkScore: of 1 pt15 &i8complate)"3.4.35Fndi tna X-valuols Khem tne Gruph dol5 Jolhav OetranThe X-valuc(s) whurg Ihe funiclion 0ou9 not hava Oeivou 0 Iva * = (Uso comna ccarale an840n nelidEntor your nnowyor Iha anexor boxIhan click Chuchanixtpant ahowlnp
maunacom StudentplaverHometton as0i7hom skld-567075611&questionld elushed falsee cld 6041976&back-https Iman-m Math 2009 52L eplmmar 20201 Homework: Section 2.1 Homework Score: of 1 pt 15 &i8 complate) "3.4.35 Fndi tna X-valuols Khem tne Gruph dol5 Jolhav Oetran The X-valuc(s) whurg...
5 answers
Suppose that $ /00 initully invnsted nccouni Tucd Iriaet MotiGY the uccount S1SS , Find (hc ctehl ratc Vani Wnte Vouc HAat [ percrtitaoc: Da nat Icund(huraltriEantMar 4nennautHutdreaunpeltul
suppose that $ /00 initully invnsted nccouni Tucd Iriaet MotiGY the uccount S1SS , Find (hc ctehl ratc Vani Wnte Vouc HAat [ percrtitaoc: Da nat Icund (huraltri Eant Mar 4 nennautHutdreaun peltul...
5 answers
When $r$ is a positive number, the population size is (a) stable (b) increasing (c) decreasing (d) either increasing or decreasing, depending on interference competition (e) either increasing or stable, depending on whether the species is semelparous
When $r$ is a positive number, the population size is (a) stable (b) increasing (c) decreasing (d) either increasing or decreasing, depending on interference competition (e) either increasing or stable, depending on whether the species is semelparous...
5 answers
= 2 { 5 1 H 11 L 2? L 0 0 | 2 1 j 0 1 } { 2 1 V [ F 0 1 Ii}
= 2 { 5 1 H 11 L 2? L 0 0 | 2 1 j 0 1 } { 2 1 V [ F 0 1 Ii}...
5 answers
Find the area of the surface obtained by rotating the circle +1 {
Find the area of the surface obtained by rotating the circle + 1 {...
5 answers
(8+4}-819.{*-3+4=-820. Vz -5=4377
(8+4}-8 19.{*-3+4=-8 20. Vz -5=4377...
1 answers
When [2- IG: Pathway of 14 $\mathrm{C}, 15$ N]glutamate undergoes oxidative degradation in the liver of a rat, in which atoms of the following metabolites will each isotope be found: (a) urea, (b) succinate, (c) arginine, (d) citrulline, (e) ornithine, (f) aspartate? (EQUATION CAN'T COPY)
When [2- IG: Pathway of 14 $\mathrm{C}, 15$ N]glutamate undergoes oxidative degradation in the liver of a rat, in which atoms of the following metabolites will each isotope be found: (a) urea, (b) succinate, (c) arginine, (d) citrulline, (e) ornithine, (f) aspartate? (EQUATION CAN'T COPY)...
5 answers
Consider the function f defined by f(x)-4x?-3x2-6x+2,determine the points on the curve representing f where the tangent is horizontal.Your answerConsider the function f(x)-ax'+bxtc determine a, b and c such that the x-intercept is 1 and it is a minimum and the Y-intercept is 2.
Consider the function f defined by f(x)-4x?-3x2-6x+2,determine the points on the curve representing f where the tangent is horizontal. Your answer Consider the function f(x)-ax'+bxtc determine a, b and c such that the x-intercept is 1 and it is a minimum and the Y-intercept is 2....
5 answers
Describing Function Behavior, determine the intervals on which the function is increasing, decreasing, or constant.$$f(x)= rac{x^{2}+x+1}{x+1}$$(GRAPH CANNOT COPY)
Describing Function Behavior, determine the intervals on which the function is increasing, decreasing, or constant. $$f(x)=\frac{x^{2}+x+1}{x+1}$$ (GRAPH CANNOT COPY)...
5 answers
[8 merks| Assummng y u function of > . find all pomts on {Y Sxy #hece tke 'nrgcni huxrizuntal and whcte !hc tangcnt Icntical Sho# all work.
[8 merks| Assummng y u function of > . find all pomts on {Y Sxy #hece tke 'nrgcni huxrizuntal and whcte !hc tangcnt Icntical Sho# all work....
5 answers
Regression analysis was applied betwcen sales and $ major international corporation. advertising The following across all the branches of a regression fuuction WAS obtained. SO00 + 7.251 (a) Predict the amount for sales where the advertising amount is $ OQ0,000.00(b) Kthe advertising budgets of two brunches of tho the preclicted dillerencu Iu tlieiv sales? corporation dliller by 830.(O, thn wlnt will bo
Regression analysis was applied betwcen sales and $ major international corporation. advertising The following across all the branches of a regression fuuction WAS obtained. SO00 + 7.251 (a) Predict the amount for sales where the advertising amount is $ OQ0,000.00 (b) Kthe advertising budgets of two...
5 answers
6.40 It is known from experience that 2% of the calls received by switchboard are wrong numbers. Use the Poisson approximation t0 the binomial distribution to determine the probability thalamong 250 calls received by the switchboard, 4 will be wrong numbers_ CCr
6.40 It is known from experience that 2% of the calls received by switchboard are wrong numbers. Use the Poisson approximation t0 the binomial distribution to determine the probability thalamong 250 calls received by the switchboard, 4 will be wrong numbers_ CCr...
5 answers
Encuentre el area de la superficie obtenida por la curva zY = 02 entre 0 < t < 2 que gira sobre eje %.Find the area of the surface obtained by the curve I =t y =+ between 0 < t < 2 when rotates on the raxis:
Encuentre el area de la superficie obtenida por la curva z Y = 02 entre 0 < t < 2 que gira sobre eje %. Find the area of the surface obtained by the curve I =t y =+ between 0 < t < 2 when rotates on the raxis:...
5 answers
Question 18 (4 points) made up ofNz. Clz and Ar Eascs; where the mole fraction of A gas mixture at STP in a 5.0 L container How many molccules of Clz ac present? N2is 0.65 and the mole fraction of Ar 1s 0.20,
Question 18 (4 points) made up ofNz. Clz and Ar Eascs; where the mole fraction of A gas mixture at STP in a 5.0 L container How many molccules of Clz ac present? N2is 0.65 and the mole fraction of Ar 1s 0.20,...
5 answers
2. Find the chiral centers in the following compound; label them with asterisks and assign the absolute configuration (R or S). Be sure to clearly connect the configurations with the chiral centers: (16 pts)OH
2. Find the chiral centers in the following compound; label them with asterisks and assign the absolute configuration (R or S). Be sure to clearly connect the configurations with the chiral centers: (16 pts) OH...

-- 0.020832--