5

Exprez> each Of Uhe Uhree torces acting O the support in Cartesian vcctor form and dctermine the magnitude of the nsultant loncc and its dircction neasuted clock...

Question

Exprez> each Of Uhe Uhree torces acting O the support in Cartesian vcctor form and dctermine the magnitude of the nsultant loncc and its dircction neasuted clockois [TOmnI pocilive FlSJNMn 20 degree

Exprez> each Of Uhe Uhree torces acting O the support in Cartesian vcctor form and dctermine the magnitude of the nsultant loncc and its dircction neasuted clockois [TOmnI pocilive FlS JN Mn 20 degree



Answers

Express each of the three forces acting on the support in Cartesian vector form and determine the magnitude of the resultant force and its direction, measured clockwise from positive $x$ axis.

In this question, we have to sell the resultant for each period of factors you and w with angled teamed up between them. More of that to you is well. More of the victories. 20 And Angle three days, 27° First people see what is a resultant. The resultant is the vector sum of two or more vectors. It is the result of adding two or more vectors together. Now we will throw this sketch. So here is our sketch. This is our new vector. This is a vector and this represents our data. So this is our scheduled result And director. Thank you.

So I'm going to continue with the previous work. Except we're now told the values of F one and data F one is 300 Newtons and data is 10 degrees. I don't need this anymore. All of this is still valid. That's not valid. That's not valid. Everything else is still valid and we just need the resultant So the resultant is just going to be is gonna put it in a calculator. Just redo everything on my calculator square root of F R X squared, which is going to be F one, which were told, is 300 co sign of 30 minus beta, which is 10 minus pro 13th of 180. Where that plus parentheses. 300 sign of 30 minus 10. Let's 5/13 of 180 plus 200 square That is me 389. Let's check if that's right. Yes, it is. And let's look at the angle. The inverse tangent of Well, why value over the X value and that gives me a weird number 72.7 degrees. First data. Ah, so, uh, what does that mean? If they do is that much? I think it would push the whole thing over here. Wait a minute. No, it wouldn't. So we were told that F one is that in 10? Wait a minute. We worth I need to pick a different. All right, I I think about this some more. Um, where we were told that data is 10. We're already told that Fada is 10. So how was Theda picked? That's the direction. Okay. All right. No. So this is data since data. I think there's 10. Thank you. The resultant force acting on the brackets. Wait a minute. Okay. All right. So this is a different angle here, so I'm gonna call this five, and FYI is the inverse tangent of fr y over off our X and 72.7. And so it's more like this where this is 72.7 degrees. All right, so if I take 30 off of that, then that is going to give me counterclockwise from the ex prime axis. So all I have to do is attract 30 and that gives me 42.7 degrees, which is the correct answer. My goodness, what is going on there?

So start by drawing a diagram here. Um, yeah. Here we go. X. Why Z And then what I like to dio is draw factors to a B and C So I'm seeing that a is up here. B is over here and see is down here. So you Hey, you hopes be a and see. All right, So let's get the components of you a ubi in you. See you a vector IHS, Where's it's up there. Looks like it is straight up z three and then in the negative. Wider action 0.75 So it's negative. 0.75 j plus three Z. Okay. I mean, okay, you be is Let's see here. It's got an X component and a Y component. The export component is too co sign 40 and the Why component would be to sign 40. They're both positive, You see. Let's see here. The X component is negative one the why component is zero. No, it's not. But the why component is negative one. All right. Just a minute. Getting my axes mixed up. The X component is too. And the why component is negative one, and there is no que component. All right, So Force a C is in the direction of a to C. So I need you a C which is gonna be u C minus you. A So to minus 0.75 is 1.25 minus one j and then minus three K u a. B is going to be B minus a. So it's gonna be too who signed 40 minus 0.70 wait. There's a different directions. B minus a to suit took did a to co sign 40 i plus to sign 40 minus 0.75 j minus three k. So we're told that and I'm gonna draw it on the diagram here. Force A B is 200 50 Newtons and force a C 400 news. So if I take let's go ahead and get a C first, the Force A C direction is going to be 400 times 1.25 over the square root of 1.25 squared plus one squared plus three squared that would be in the eye direction plus same type of thing. J direction plus same type of thing, que direction. So let's get these using a calculator 400 times 1.25 over the square roots of 1.25 squared was one squared less three. Weird. That gives me 100 47. I Now J is going to be negative one in the numerator right there. So I'm just gonna put a negative one in the numerator. That would give me Jay minus one hundreds, 17.6 j then for Kale after his put a negative three in the numerator 3 52.9 Okay, so a c I'm saying is in the negative J and negative k directions. And that makes sense was in the positive. Yeah. Okay. F A B is going to be 250 times to co sign 40 over the square root of two KUSA 40 squared plus to sign 40 minus 400.75 squared, plus three squared I plus same type of thing J plus same tape of thing K. So let's get this one 2 50 times to co sign 40 over square roots parentheses to coast. I'm 40 squared plus parentheses to sign 40 minus 400.75 squared plus nine. Yeah. Okay. That gives me 112.3. I, um, for J. I just have to put in to sign 40 minus 400.75 in the numerator. That gives me 30 9.3. And, um, I just have to put in negative three in the numerator. Negative. 219 degrees. What? That's weird. Okay, making sure I didn't make any mistakes. Six. It's a weird answer. Oh, it's not degrees. These air in ah Force units, What are units of Forced Newtons? I thought it would be strange to get an answer that's greater than 108. Okay, let's keep going. So I have to get the result in force, so you have to add f a C plus F A B. But, um, I want to make sure that f A B seems correct. It's neg, Negative, K, but ah, positive. I and J yeah, make sense. Okay, so if the add those two together So 147 plus 112.3 2 59 0.3 I. So now I've got negative 1 17 0.6 plus 39.3 negative. 78.3 j and then I've got negative 3 50 2.9 minus 2 19 0.9 5 72.8 Okay, news. Okay, let's get the magnitude square root to 59.3 squared plus 78.3 squared 5 72 between eight squared 6 33 0.6 Newton's. So let's verify that. That's correct. Ah, there's no answer in the back of the book. She didn't notice this asterisk, man, you get a Alfa the inverse co sign of that. Putting that into the equation. If our X just to 59.3 over our 6 33.6 65 0.8 degrees speed. Ah, and Gamma found in like ways. The numerator is negative. 78.3 and the numerator is negative. 5 72.8 Actually, I guess I'll just call out 155 degrees. So the answers are here

The X. Component of the resultant. The resulting tax component is written X component. This will be equals two. Yeah there's the eggs. Yes the X. So the value of X is equal to 100 Was 45°.. This value of V. X will be close to 100 course 1 35 Degree. This value of C. X is equal to 100 cost 313 degree. After solving you will get the result in tax component will come out to be 100 divided. Very similarly you can find out the result in my company. The resultant. Why component? So this will be equals two 145 degree. Yes 171 35 Degree. Just 100 I 315°.. After calculation we will get the network component. You come out to be 100 divided by room. No they need to calculate the resultant. Net value of the resultant. Are will be equal to the square root of our exes. Where that's our way is good. But it will come out to be 100. So this is the resultant value 100. And let us calculate the angle is a different angle with respect to X axis. So it will be alphas the question and it was the Y component of the resultant, Which is equal to 100 Divided by route to multiplied by the x component. It is 100 divided by. So it will come out to be 45 billion. So resultant, The resulting value is 100 and the resulting angle is 45 DB with XX at


Similar Solved Questions

5 answers
1 Tou can i 1 = I0 diagonalizabl Problem List Prodlem choose dorongoratteable mullpleily Next Problem MupucIJcrcumuio 8 corresponding 1
1 Tou can i 1 = I0 diagonalizabl Problem List Prodlem choose dorongoratteable mullpleily Next Problem MupucI Jcrcumuio 8 corresponding 1...
5 answers
987Each of the lettered dots at the corners of the cube shown represents positive charge moving with a velocity of magnitude in the direction indicated The region in the figure is in uniform magnetic field parallel to the X-axis and directed in the positive direction_ Copy the figure, find the magnitude and direction of the force on each charge, and show the force in your diagramalong diagonal of = cube
987 Each of the lettered dots at the corners of the cube shown represents positive charge moving with a velocity of magnitude in the direction indicated The region in the figure is in uniform magnetic field parallel to the X-axis and directed in the positive direction_ Copy the figure, find the magn...
5 answers
1 g are continuous on [a, b], then the area of the region between the curves of v=flx) g(x) over the interval [a , b] equals [f(x) g(x)Jdx]one:uelse
1 g are continuous on [a, b], then the area of the region between the curves of v=flx) g(x) over the interval [a , b] equals [f(x) g(x)Jdx] one: ue lse...
5 answers
Find the difference quotient f(xth)-flx) , 1) For f(x) = -Zx + 17, find hFind an equation of the secant line containing (1, f(1)) and (2, f(2)) in standard form. 2) f(x) = X+3
Find the difference quotient f(xth)-flx) , 1) For f(x) = -Zx + 17, find h Find an equation of the secant line containing (1, f(1)) and (2, f(2)) in standard form. 2) f(x) = X+3...
5 answers
C If the resolution of the droplets' speeds needs to be 1 mph, what is the smallest frequency shift sensitivity the radar system must achieve in units of Hz?f' = f 1+C = 1f 3.0 x 108m/s
C If the resolution of the droplets' speeds needs to be 1 mph, what is the smallest frequency shift sensitivity the radar system must achieve in units of Hz? f' = f 1+ C = 1f 3.0 x 108m/s...
1 answers
Calculate the flux integral. $\int_{S}(5 \vec{i}+5 \vec{j}+5 \vec{k}) \cdot d \vec{A}$ where $S$ is a disk of radius 3 in the plane $x+y+z=1,$ oriented upward.
Calculate the flux integral. $\int_{S}(5 \vec{i}+5 \vec{j}+5 \vec{k}) \cdot d \vec{A}$ where $S$ is a disk of radius 3 in the plane $x+y+z=1,$ oriented upward....
5 answers
In Exercises $1-62,$ perform the indicated operations and simplify your answer as completely as possible.$$ rac{9}{5 z}- rac{3}{5 z}- rac{1}{5 z}$$
In Exercises $1-62,$ perform the indicated operations and simplify your answer as completely as possible. $$\frac{9}{5 z}-\frac{3}{5 z}-\frac{1}{5 z}$$...
5 answers
Given the standard enthalpy changes for the following two reactions: (1) Ni(s) + Ch(g) ~NiChz(s) AH? =-305.3 kJ(2) Fe(s) ~ Cl-(g) ~FeClz(s) AH? =-341.8 kJwhat is the standard enthalpy change for the reaction (3) Ni(s) - FeClz(s) ~NiCl;(s) Fe(s) AH' = ?
Given the standard enthalpy changes for the following two reactions: (1) Ni(s) + Ch(g) ~NiChz(s) AH? =-305.3 kJ (2) Fe(s) ~ Cl-(g) ~FeClz(s) AH? =-341.8 kJ what is the standard enthalpy change for the reaction (3) Ni(s) - FeClz(s) ~NiCl;(s) Fe(s) AH' = ?...
5 answers
You want to obtain a sample to estimate a populationproportion. Based on previous evidence, you believe thepopulation proportion is approximately p=14%p=14%. Youwould like to be 90% confident that your esimate is within 2.5% ofthe true population proportion.
You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately p=14%p=14%. You would like to be 90% confident that your esimate is within 2.5% of the true population proportion....
5 answers
$ Sinusoidal waves 5.00 cm in amplitude are to be trans-mitted along a string that has a linear mass density of4.00102kg/m. If the source can deliver a maximumpower of 300 W and the string is under a tension of 100 N, what is the highest vibrational frequency atwhich the source can operate?$
$ Sinusoidal waves 5.00 cm in amplitude are to be trans-mitted along a string that has a linear mass density of4.00102kg/m. If the source can deliver a maximumpower of 300 W and the string is under a tension of 100 N, what is the highest vibrational frequency atwhich the source can operate?$...
5 answers
Uestion 122.5 points Save AnsweConsider the following two series24 7l 4-1(I)2 n? + 1 17n?Which of the following statements is true ? They are divergent The Root Test applied to (II) in b inconclusive. The Ratio Test applied to (I) in inconclusive. d.None of the statements They are convergent
uestion 12 2.5 points Save Answe Consider the following two series 24 7l 4-1 (I)2 n? + 1 17n? Which of the following statements is true ? They are divergent The Root Test applied to (II) in b inconclusive. The Ratio Test applied to (I) in inconclusive. d.None of the statements They are convergent...
5 answers
Question 2 () Consider the reaction between hydrochloric acid with pent- [-ynle; Name the two possible unsaturated products. Referring to carbocation stability, briefly explain which one of these two unsaturated products the major component:Answer Product Name:or Chemical formula:Product Name:or Chemical formula:Major component: underline: Froduct Reasoning:Froduct 2
Question 2 () Consider the reaction between hydrochloric acid with pent- [-ynle; Name the two possible unsaturated products. Referring to carbocation stability, briefly explain which one of these two unsaturated products the major component: Answer Product Name: or Chemical formula: Product Name: or...
5 answers
Blood flowing through an artery of radius 2.1 mm at rate of 42.0 cm/s. Determine the flow rate and the volume that passes through the artery in period of 10 Flow rate 5.54 cm ^ 3/sec Volume 166 cm 3Submit AnswerUnable to interpret units: Computer reads units as cm^3/sec" .Tries 0/10 Previous Ires
Blood flowing through an artery of radius 2.1 mm at rate of 42.0 cm/s. Determine the flow rate and the volume that passes through the artery in period of 10 Flow rate 5.54 cm ^ 3/sec Volume 166 cm 3 Submit Answer Unable to interpret units: Computer reads units as cm^3/sec" . Tries 0/10 Previous...

-- 0.022202--