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8"76A solution of hydrogen peroxide (H2Oz) in water with a volume of 50.0 mLis diluted by adding 70.0 mL of water: Calculate the sollltion's new concentra...

Question

8"76A solution of hydrogen peroxide (H2Oz) in water with a volume of 50.0 mLis diluted by adding 70.0 mL of water: Calculate the sollltion's new concentration given the following original concentrations: (Addition of 70.0 mL of water is equivalent to adding 70.0 g of water since the density of water is 1.00 g/mL) Enteria number only: Do not spell: Dolnot use scientific notation Calculate your answer to 3 significant figures20%(v/v)%lv/v) HzOz]2.0%(m/m)Ies(m /m) HzOz

8"76 A solution of hydrogen peroxide (H2Oz) in water with a volume of 50.0 mLis diluted by adding 70.0 mL of water: Calculate the sollltion's new concentration given the following original concentrations: (Addition of 70.0 mL of water is equivalent to adding 70.0 g of water since the density of water is 1.00 g/mL) Enteria number only: Do not spell: Dolnot use scientific notation Calculate your answer to 3 significant figures 20%(v/v) %lv/v) HzOz] 2.0%(m/m) Ies(m /m) HzOz



Answers

Houschold hydrogen peroxide is an aqueous solution containing 3.0$\%$
hydrogen peroxide by mass. What is the molarity of this solution?
(Assume a density of 1.01 g/mL.)

Okay, so we start with three grams of H 20 to divide that by 100 grams of our solution. Multiply that by tomorrow or math. Uh, H 202 And then multiply that by one girl. One over one little later. This is Graham. And then corrected. Two millimeters. So we get 0.89 polarity of H 202

So let's first start by finding moles of our permanganate ion. Okay, moles, osmolarity Times leaders. So we've been given that the polarity is .134 moller And we can change our volume two leaders .0148 leaders. So that's going to give us 00198 Malls of r M N O for minus. So now we can do a more ratio, we can change moles of permanganate ion. two moles are H202 And that ratio is 5- two. So that's going to give us with 00 496 moles Of our H 202 or hydrogen peroxide. And then polarity is just moles per liter. So we know that we have 10 mL. So point oh one oh leaders. So we have, the concentration of our solution is .496 moller H 202.

This problem involves, um, the chemical equation of for the decomposition of hydrogen peroxide into water and oxygen. So to H 20 yields to H 20 plus 02 were given the original balanced equation. And then we are also, um, given that the temperature is going to be 27 degrees Celsius, the pressure is 746 tour, and we're trying to figure out what volume of pure 02 will be collected when half of a 125 grams sample of hydrogen peroxide is decomposed. First thing we do is go ahead and convert our temperature into Calvin's. We have 27 plus 2 73 which gives us a temperature of 300. Calvin and we might as well go ahead and convert our tour into a T. M. So 746 tour times one a. T m. Over 760 Tour gives us an A t m of 0.98 a. T. M. So that is our pressure. Um, next, we want to go ahead and figure out how many moles of hydrogen peroxide is in that 62.5 on and again we got the 62.5 because it's 50% of a 125 grams sample. So if we have 62.5 grams of H 202 and we want to figure out the moles of H 202 we first need to figure out what one mole is equal to. So one more of age to 02 equals the Moler Mass. So it's going to be two times 1.0 08 plus two times 16 which will give us a Moler mass of 34.16 uh, Grams. So if we have 62.5 grams and one mole is 34.16 grams, then we have 1.84 mole of H 202 to work with. So and we also know that from this equation up here from our balance equation, we know that one mole of 02 is equal to two moles of H 202 So if we have 81.84 moles of H 202 0.84 mole H 202 and we get one more of 02 for every two moles of H 202 Then we have 0.92 moles of 02 Now it just comes down to using PV equals and Artie. Now that we have our number of moles and we're trying to solve for volume, so volume equals number of malls. Times are gas, constant times or temperature divided by our pressure. So we will have our number walls of 0.92 moles time 0.8206 for gas constant. And our temperature is 300. Kelvin, we're gonna divide all of that by 0.98 for our pressure and we get that our volume is going to be 23.11 leaders.

The first thing we're looking to do here is calculate the moles of H 202 stats. Hydrogen peroxide that is 1.8374 moles and then we can look at the malls to produced that is half of this value above. We have 9.9187 models. So it's just 1.837 45 by two so that we can convert pressure into the atmosphere. So we have 764 tour combated to 1.53 atmosphere. Then we can use our ideal gas equation. PV is able to nrt we're rearranging for volume. Volume is able to N r t of p can plug in values. Yeah, volume that is equal to 22 0.5 liters. Where we have volume is equal to 1.53 Moles is equal to 9.9187 Our gas constant because, as we know and the temperature is 300 Calvin


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