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Guen th e tolowing sef of nunbers find Ihe average and gamplt standard dcviation axcel ImparaN Orica You have ccncleled Your cucuiion rapon vour numtars separale...

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Guen th e tolowing sef of nunbers find Ihe average and gamplt standard dcviation axcel ImparaN Orica You have ccncleled Your cucuiion rapon vour numtars separale cell aml obey the rounding requiremonts frcrn Iast pre-Iao)Shttt

Guen th e tolowing sef of nunbers find Ihe average and gamplt standard dcviation axcel ImparaN Orica You have ccncleled Your cucuiion rapon vour numtars separale cell aml obey the rounding requiremonts frcrn Iast pre-Iao) Shttt



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Calculate $E^{\circ}$ for the following cells: (a) $\mathrm{Pb}\left|\mathrm{PbSO}_{4} \| \mathrm{Pb}^{2+}\right| \mathrm{Pb}$ (b) $\mathrm{Pt}\left|\mathrm{Cl}_{2}\right| \mathrm{ClO}_{3}^{-} \| \mathrm{O}_{2}\left|\mathrm{H}_{2} \mathrm{O}\right| \mathrm{Pt}$ (c) $\mathrm{Pt}\left|\mathrm{OH}^{-}\right| \mathrm{O}_{2} \| \mathrm{ClO}_{3}^{-}, \mathrm{Cl}^{-} \mid \mathrm{Pt} \quad$ (basic medium)

When determining the standard self potential for cells written in the shorthand notation or the line notation, we recognize the an ode is written first and then the catholic has written second. That's what we have to do. Is look up the reduction potential first for the cathode that's written on the right. We look up the reduction potential for hydrogen ion, going to hydrogen gas, which is zero. And then we'll look up the reduction potential for what the an ode is of Mn. Two plus. Going to Mn because its reaction is reversed and it's negative 1.182 So cell potential is positive 1.182 For the next one will look up the reduction potential first for the cathode, which is on the right, which will be C U three plus. Going to see you two plus at a reduction potential of 1.953 Then we'll subtract off the reduction potential for what's occurring at the anodes and that is the gold gold chloride complex, which is 1.1001 And we get a cell potential of 0.5 point 952 Then, for the last one, we'll look up the reduction potential for the half reaction that includes N NO. Three and No, which is 0.964 Then we'll look at the reduction potential for the half reaction that includes sulphide and sulphur, which is negative 0.445 and we get a cell potential of 1.409

For Problem 72 were given a table representing two baseball players. Fatal and call were also given their batting averages, the team batting average and their team standard deviation, and we are asked to find the value. But it's three standard deviations above the mean on below the mean so in order files. To do this, I used the team putting our village and the teams down a deviation and, as you can see, yeah, 0.16 things was the team average was the team batting average for Fredo and a zero comma zero ones. Who was the team standard deviation for fatal. So to find the value that is three standard deviations above the mean you simply take the team batting average. And then we add 0.12 multiplied by three because we're trying to find the value. But it's three Spanish deviations. I mean, so this gives us an answer off zero point so zero to exactly the same thing for a girl, and you'll find an answer off zero points with the four. So the 0.189 was the team average was the team patsy are visual for call. And the 0.15 was the same standard deviation for Karl. Whoever wants a question be, they ask us to find the values but our three standard deviations below the mean So you do exactly the same thing. And the only thing that you change is the sign instead of a plastic we ever mine is now because you're looking for the values that I've been. No. The mean off 0.166 and 0.189 Calculating these, calculating these numbers over here you will find an answer off 0.13 and 0.144 Well, that was easy to understand, guys. Thank you.

Okay, So in this problem, when we look at the blood platelets count for male and example. And instead of computing the mean using the raw data for every man in that sample, we're gonna use, um, the frequency table. So this problem is very similar to example, seven from this section of the books. Remember, when using a frequency table that mean is the sum of the frequency times the class midpoint divided by the total frequencies of the total amount of observations in a sample. So first, we're gonna figure out what are our classes? Mid points off classes, midpoint. So what's the in between zero in 99? Well, you can simply do zero plus 1995 divided by two, and you'll get 49.5 same thing for 100 100 99 you will get 100 and 49.5 and then so on. So you simply add 100 every time. So 249.5, 314 9 0.5, 449.5 549 0.5 and 649.5 Now we're going to compute it off, uh, number of men in our simple So by adding up every value in that column so one plus 51 plus 90 plus 10 plus zero plus zero plus one, which gives us 153 there were 153 males in that sample. And now we're gonna simply compute f times eggs for the frequency in each class multiplied by the class midpoint. So one times 49.5 is 49.5, 51 times 149.5 is 7000 624.5. 90 times 249.5 is 20 2455 10 times uh, for 10 times 349.5 is 3000 495 0 times 449.500 time 549.50 And one time, 649.5 is 649.5. And now we're gonna add up every value in the frequency times classman point column. So we have 49.5 plus 7624 0.5 plus 22,455 plus, uh, 3495 plus 649.5, which gives us 34,000 273 0.5. So we have everything we need to compute the main using the frequency table. So we simply divide 34,000 273.5 by 153 which gives us 224 0.1 So this is quite close to what we would have found had we used the raw data. So if we used, um mhm the blood pressure, the blood platelets count for every single male in that simple and added every different, uh, and every different single blood place that's constant, divided by 153 would have gotten 224 so extremely similar. So another case we're using a frequency table proved quite useful and, uh, easier to represent visualize while giving it's still very accurate results

So in this problem, which is problem 32. We look at the blood platelets, count and females you want to see the average the mean a blood platelets count for females in a certain sample of the population. So we need to find to information. There's some of the frequency times the men make a point for each class that we have and the total amount of divided by the total frequency. So the total amount of women or females to be more care to tell my females in that sample. So what's the total amount? Uh, it's the total frequency of female with you simply add every value in that column. We take inspiration from that table from example seven in your book. So 25 plus 92 plus 28 plus Hero Plus two. And we have 147. So we know that whatever we get on top, we're going to divide by 147 women. Uh huh. What's the class midpoint? So what's in the middle of 101 199 when you simply take 100? That's 199 divided by two, so you get 149.5 was the middle between the middle point between 202 119 90. Simply take 200 plus 299 divided by two, and you do the same for all the other class. It's because every class increases by 100. You can simply ah at 100 to every midway point. So 449 plus five now we're gonna multiply the frequency by the class midpoint for every class. So 25 times 149.5 is 3700 37 0.5, 92 times 229.5 is Ah, 22,000 954 28 times 349 points. Five is 9786 zero times whatever is zero and two times 449 549.5 is 1099. So if we have every value in that column, we will get 3000. Um, 3700 37 0.5 plus 22,954 plus 9786 plus 1000 and 99 which gives us 30 37,000 576 0.5. So here you have it. 37,000, 576.5. We divide that value by 147 and we get 255.62. So that's the mean. And if we had taken the raw data and the appendix table, we would have found that the blood pressure is 255 so it's, uh, slightly different. So this isn't the same as the me. So the frequent seemed Let me write it this way. The frequency mean isn't the same as the mean frequency isn't the same as the mean, which is 255 but 255 and 255.62 are are close enough. Uh, so it's not a big deal that we have a small difference, and it makes it's much easier to use a frequency table to visualize everything instead of imagine having a table of 147 many of them being 100 of a total of 147. So for visualization purposes, it's very useful to use this frequency table to find the me.


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