"usrokkKam < 3J- enhanced with FeedbackCentanaUcmolullontculo MNkisu Ingelhut Io Aina sole Tele Lnu up solbliol Dale al 102m HCLLCOOh 0 1 mol Na,S ad 0 1 m...

. A mixture containing $0.05$ mole of $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ and $0.02$ mole of KMnU $_{4}$ was ueated excess of KI in acidic medium. The liberated iodine required $1.0 \mathrm{~L}$ of $\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}$ solution for titration. Concentration of $\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}$ solution was: $\begin{array}{lll}-1 & \text { (h) } 0\end{array}$ ? $-1$ (c) $0.25 \mathrm{~mol} \mathrm{~L}^{-1}$ (d) $0.30 \mathrm{~mol} \mathrm{~L}^{-1}$

In this question given the reaction to R. Plus three, asked us to products and the knowledge that its first order and our and second order and s. They want us to complete the table give. So given that its first order and our and second order in is we can determine that the rate expression should be rate equals K. Times are Times S to the 2nd. So then we simply plug things in. So if we're a we're looking for the rate. So rate equals K. Which is 1.49 Times are .2 times S, which is .2 squared. And we then get the rate in this case should be C zero point zero 119 For be still plugging things in. So the rate of 0.8 3 3 is equal to zero for two times are times S squared. And we get that are should be 4.94 98 See again we're still plugging these ends. The rate of 0.162 Equals K298 times. Are you quite once years ago times S squared solving that for us? You get that S should be 2.3316. And then finally for D. You get the rate of 0.00624 is equal to an unknown K. times. Time, squaring. And you get that K. In this case should be 15.0376.

As we all know that And at four plus irons are increased to odd, increased who supp res release of or H minus irons hands, hands, scalability, productive and solid ability. Product of F e. O. H. All three it attend colour of precipitated color up three C. B. Dead. It's different here, so according to the option of sandy, it correct.

His first plot or graph. Oh, Ln okay, viruses, one upon teeth. We have 3.1, then 3.23 point three and then 3.4. And we have Ellen K minus four, minus three, minus two in minus one. This is why Exterior Tex, Texas So d a graph will be There's the one That's another And the thought Oneness. Yeah. Sorry. Sorry. It's a straight line. So just greatly. So therefore, slow is a girl toe minus 3.19 We have this values given minus 1.85 upon three point for multiplied pattern to diploma industry minus trip on 14 minus three. So therefore slow physical toe minus 6370 Kelvin. But smarter, slow, physical too minus activation. Energy upon us is equal to minus X 370 They're off solving for activation. Energy, that is E eight is 6370 multiplied by. All right, we have 6370 r is a constant. That is 8.314 Therefore, activation energy is five 2960 jewels per more, which is equal to 53. Kill. Oh, Jewell, Per when this is our activation and

.5 more of the years yet owes much to the .22 more of anything beautiful. The maximum number of moles of food product with other facilities. So when we use the n. two is mixed with and it's beautiful that we will get B. A. Your four hotel is so three more are being sent to more of an issue for right So now we can observe their three more of these here reacting to talk to more of a tribute for two 0.59 moon of beings here too. Need to buy 3 25 9 mol Of any three p of food. That one comes out point Divide by 3406. Like. So as only only two more countries are available to the number of products as follows. So two more of any clipping of gives marmol of our face. So zero point to the moon gives him 0.20 point of anymore B. A. T. The 04 Corridors. Because in this reaction and thank you for your Forrester Liberty region. So Vivian more more the lesson ship with the help of any tree. Beautiful night