5

Sncur che tiqure rectonavia Iooo FIth plane) magnet < fiek crdcimsJenocr orlentecwidth of 15,0 €m has Z0 {urns and Zinies 3nak Jf 65: reltive ~enoendicular...

Question

Sncur che tiqure rectonavia Iooo FIth plane) magnet < fiek crdcimsJenocr orlentecwidth of 15,0 €m has Z0 {urns and Zinies 3nak Jf 65: reltive ~enoendicularcurrent 0f 0,19 counterelockyise 3rounc Ocd "hen vieded from [ne posicive *3zg norizonta Ioara (the positiv? *-axis}. (essumethe eenoth and width are Teasured alonotha anavarac resdeciveky )ninne(a) FlnaZomdonenbmagnatk orcaActinacach Sudethe loopMaoneticfcrCe ictinogactlcntha bop-0C03 Adi cderthe Magneue nand (u magnenic Forces3ecud

sncur che tiqure rectonavia Iooo FIth plane) magnet < fiek crdcims Jenocr orlentec width of 15,0 €m has Z0 {urns and Zinies 3nak Jf 65: reltive ~enoendicular current 0f 0,19 counterelockyise 3rounc Ocd "hen vieded from [ne posicive *3zg norizonta Ioara (the positiv? *-axis}. (essumethe eenoth and width are Teasured alonotha anavarac resdeciveky ) ninne (a) Flna Zomdonenb magnatk orcaActina cach Sude the loop MaoneticfcrCe ictino gactlcn tha bop- 0C03 Adi cderthe Magneue nand (u magnenic Forces 3ecudn currentcarrying wire Jepenocn Ere cutrent Maonitud the magnetic field, eno-h determinetne direaticn mzgnetic Torce acing currect-carcying ice maonetic field? OJe Unre and orientabar tha wire thz magnetic field? OanYou rant Comdonents Feotom FEatom Fettom Ene moonerc tcrce wccino bettom Sectlon compcnents magneti TDrCd ictino L Cogden Flett Ftor F167 Ftj



Answers

ssM Figure $29-81$ shows a wire segment of length $\Delta s=3.0 \mathrm{~cm}$, centered at the origin, carrying current $i=2.0 \mathrm{~A}$ in the positive $y$ direction (as part of some complete circuit). To calculate the magnitude of the magnetic field $\vec{B}$ produced by the segment at a point several meters from the origin, we can use $B=\left(\mu_{0} / 4 \pi\right) i \Delta s(\sin \theta) / r^{2}$ as the Biot-Savart law. This is because $r$ Figure 29-81 Problem 75 . and $\theta$ are essentially constant over the segment. Calculate $\vec{B}$ (in unit-vector notation) at the $(x, y, z)$ coordinates (a) $(0,0,5.0 \mathrm{~m})$, (b) $(0,6.0 \mathrm{~m}, 0)$, (c) $(7.0 \mathrm{~m}, 7.0 \mathrm{~m}, 0)$, and (d) $(-3.0 \mathrm{~m},-4.0 \mathrm{~m}, 0)$

Hi the main problem magnetic field think through a single loop of wire burying with the time as even here. The form of a curve your time is on the X axis is measured in seconds. And magnetic food which is measuring to Tesla that is on the Y exit. Yeah, magnetic field first increases linearly from zero second to one second and from zero Tesla too. Zero point by Tesla. Then it remains constant for the next two seconds means up to 4.0 seconds means constant as 0.5 tests. After weeks reduces in the next two seconds in sub to expand zero seconds it again becomes zero. Yes, radius of the single loop of wire that is given as R is equal to well centimetre or we can say this is R is equal to the 0.1 two m and the net resistance of the circuit is 8.5. Uh huh. No. To find mm induced in this blue the single loop of fire at various given time. First of all. Rome a time even 102 E two 2.0 2nd mm Hindus in the magnet. You will be given by defy by TT is this is differentiation of I'm derivative or flux is given us be daughter Now as magnetic field is linked perpendicular to the plane of the loop area. Weather and magnified better will be parallel together. Oh they will be having an angle of zero degree between them. So it will become be a course zero degree and the value of 40 degrees just one. And area being constantly be taken out. The CMF India's will get an expression as or area. This is by RT square into DB by DT. Where this divide. It is nothing further. Hello of the P versus speaker. Hence for this range of time from 0 to 2 seconds, the slope will be particular one of these. Oh, here it will be or pipe. This is 3.14 radius, this is 0.12 a split of it. And for the slope DVD thi this is zero point why invited by two seconds. So finally here he pill I'm out of these. 0.0 11 old. Or we can say this is 11.3 believe world the magnitude of you. The given time on the second part of the problem? Well, the time interval is from E two, close to 2.0 seconds to in three, which is equal to 4.2 seconds. Using the same expression for the IMF indu as pie are square into tv by duty. But for the given time interval, there is no change in the magnetic field because it is strange that slope is zero as the low people be zero EMF induced in this given time interval and was induced in the coil in the loop will also be yeah, no. Third time segment wrong feet, feet close to 4.0 seconds to the 40 was to six points through. Second expression for the EMF induced again will be seen by our square into slow the slope. This time is negative, but we are taking the magnitude only. That's why again, this is 8.14 into 0.12 to the whole square into divided the This is again, 0.5. Tesla divided by 2.0 seconds. The magnitude of the EMF induced again will come out to be 11.3. Believe all. Which is the answer for that hurt. And the last part of this problem. Thank you.

You know that the magnetic force is given by I times a lacrosse being. But that's the case where the magnetic really is. Uniforms far. A case of magnetic field there is with the land. The change in force can entertain us. I times the magnetic fields. And this is the question that we are going to use on. We're going to apply this equation to eat side off the loop now for each side off the loop. The end is parallel to that side. Off the look on, if that isn't the direction off, right, since the loop is in the excellent plan, So Z zeros at the look on dh B y is zero because, uh, be light is basically we just plug is equal to zero in this equation. Then the director will be quarto. You see the light over end Thanks, Ski cap. Because this just God's Edo here. Now you're going to apply this on DH into this equation on DH. We're going tto do the first part now. So for the first part, the magnetic field lines in the plane Ah, to be sketched, son, it's true that so let's see. This is the X and this is the lie exits. As magnetic field is along, the positive key access on it varies with white. So there is no need for the X axis to be here. So you're gonna use why end, See, Axis? Because those are the only components contributing to the magnetic field Here Z is the direction on why he is a distance with which the magnitude ofthe magnetically changes on. You. See, that, uh, the magnet treated b is that is linear. Live it white. That means this is going to be like this. I'd for why? For the audition. Now, if the light changes, this is how it's going to look. Yeah, so that this part e now 45 we have to find the force. So let's find it for side one. Let's mark the site first. So this is side one. Elder's Phil. Let's call this toe beside mine this toe beside toe. This will be side three on DH. This to beside for and for side one. It's called a force to be F one. So this is given by this equation over here so messily integral over this equation. I Times deal Times B signed Fly and the integral with that. But sci fi is basically one because FIEs 90 degree as the magnetic field is hoping to go large. No, the segment here, basically magnetic field is perpendicular to the plane. Off the whole, it's a stone. So for every so far, every, um, case this was is going to Brazil. Sorry, this angle is going to be 90 victory. This gives So Isaac Constance So it comes out on. We know there's a constant Eliza. Lt's a constant. So they come out a cell on we have. Why on the l is basically the change in lentil on this directions or deal is going to be called to the why? Because this segment is along the lie Exes on the integration goes from single toe on my right and rule. So let's do that letter was Let's find the force that they're fantastical dough, half dimes, the knot for l times I on DH. We apply the right and rule, so that gives the force two words. Take AJ two lights, the positive exact sis, This is the force for the first segment. And for those who don't know what this integration is. So I'm just going to write it over here. So let's go on this way to the party and where Anderson in the jet other than negative one. So if this goes from a Toby to the integration of this is basically right at the part and plus one over N plus one on your slide animals from it. This Kips bay to the parent less one minus eight. A guard and place one forward and placement. That's what I did over you. And if n is minus one, the integration is just going, Toby, the lager them off. Why? And then you have to apply the limits too. So now we do the same for you. F door. So after is equal to integration over I b l b sci fi, this one on the limit side and my sins the limits are staying with told me to explicitly can't colored disentangle. This is Okay, so this this man old Sorry, it's Ah. Okay. So the way we have to see what the The surveillance Basically, Xia date, Because deal is a battle to the x axis. So Oh, our limits are going to be the limits off eggs and not the limits of Wei. That's going to be CTO do l Andi. I is a constant. We notice the constants. Also, l is that the limits off the end on deal is basically the eggs as myself. There on, we have a live from the magnetic field and we find this value. Toby, I thank thee not over l So the value ofthe y He's basically a constant here and is equal to Elsa. That comes out and we just have to integrate with the d X not. And this gives the value, Toby. My time's not times l on and off. The direction is given by right and rule being applied toe the direction of current and magnetic field on DH. You see that this direction is going to the towards now good day like the addiction. So I'm forces gonna hit this. Now we do the same thing for three of three. So far three we have I d being I'm sci fi is one on. So the constants come out off the integral on DH. We have revived from the magnetic field on. We have to find see what be Elise. So for the third segment here. Deal is basically negative. Why you again? Saudi deal is basically Dubai again. So you think that on DH is to be Quinto? I be not. And over too. This is basically same magnitude to what we found here on. Let's find the direction now. So they applied. I tend rule Andrei, get in direction. Toby along. Okay, so one thing to note this deal is actually negative way negative delight Because this is going towards the negative I exist, or so b l there's going to be negative off the light. So this is basically mimic on the direction If you apply if you apply the right and girls to see that direction is so I is, uh, okay, Cap Jake on DH, I'll be is cancer. Jacob Cross ski cap is basically I cap. We can also not include the negative sign on DH. Do the cross for that as negative. J cap cross pendant. It was stiff cake and you get killed in the same answer. So for the last part, we have I forgot to write. The elements of this is just a little over seal on DH. Let's make this place on the arrival of distress or so. But I think this is simpler, Dan. Whatever strange value you had to stake the limits As the current flows to zero and take the we control the white Now we find a Ford. So that is I times, Theo times be again on and on the constants come out ofthe day Cushion We have a life from the magnetic field on the l is the ex again And we have the limits from L. A to Theo So the at the system Now we get the value to be I be not Oh well on In this case you see that Why is see you So for this segment of food segment, that means that interval a zero and this gives the force to proceed next, the neck force is going to be Victor sunk off all the forces. So that gives if one the next F net to be equal do F one vector plus two. It's stored and the next page so f net and the corridor f one miss after less f three less before this is basically serial, as we calculated on F one and every have the same magnitude You on his three year, but they're there opposite in direction. So they add up to zero and we're just left with after. That is a negative. All high times they're not. Thanks. And this is the net force.

In this question is about finding the force on the current loop in a non uniformed magnetic field. Okay, so we are given the magnetic view is, uh be not Z or L J heads. Plus, you know why o l he had okay. And then you also given the current book eso currently mhm. So the current movies on the X Y plane, right? So it's a squared. Mhm. The silent is out, and then the current is ah, going Conway's Okay, so, in part, everyone to draw the car Benedict view on the why, Zach Plain white seaplane. Okay, actually passing this question. Okay, so it's guided such that you can find a medic force on the whole look. So in part area for stronger, uh, Benedict you y Z plane. Okay, so this how is going to look like Okay, so along the y z lie, okay? The beef, you will just be pointing along the diagonal. Yeah, and then starting from each axis. Okay. So, like, suppose on the Z axis? Um, the value of y zero. So you start off pointing to the right, and then you start going up Mhm. Same thing over here. start going up then on the Y axis. That's where the Z goes to zero. Right? So initially you start pointing along the K direction and then you start curving longer. Uh huh. Along the y causes Z lie. Hey. Yeah. So that's how the romantic view look like Alright. So longer in the y z pain. Okay. Okay. Now in, probably you want to find a force, The medic falls on each side of the current goal. Yeah, so being let me try the kind of again. Uh huh. Right. So to find a magnetic force you'll be using the formula f equals two. Uh, I across B I Cross key. Okay, since you have non uniformed magnetic field, so well, actually will be doing integration. So this is the equation that we will be working with ideal Crosby. Okay, then we'll do side one labor. Each side is 1234 Me? Yeah, we're just woke up the d l according me. Okay, So you're given that be iss. Um he not see overall j had Plus, uh, you know why l k had on the X Y plane the ego zero. So he is equal to be not. Why Over l Yeah, he had Okay, then. Foresight one, we have our d. L is along the jihad direction and d y. Okay, so, uh, we have we're going to have Jay had cross k had. Hey, this is going to give us I had. And so our f is going to be de Graaff. I Yeah. Cross being okay. So toward the constants, the I do not well, he and then the integrate from zero to l y d y then the direction is I had think so. We have half. I know l I had Yeah. So this is at one. The answer for Juan and they will do Repeat for act two before Cite tool E o D our is three x my head. Okay, so our cross being did you need vector, right? Eso yes. Uh, I had cross K hat is going to give minus jihad. Hey, so our actual is integral off. I, uh the across b you can put the constants. You should be, uh, not over out. I Okay, so the integrations from IHS along three x from zero to our minus jihad. Okay, so this is, um Oh, And also one thing. The y is equal to l. Okay, I forgot to mention why is it Goto? So there's actually known our term over here. Okay, not and get minus. I be not l jihad key. So this is F two is the top site, then for strike three. Hey, we had Yao is along the d y jihad, and then the yeah, across B. You knew better. Yes. Uh, J heads, crowds K heads. This is the go to I had, uh, here we have actually go to out, but it's not going to affect the equation because there's no ex turns inside the terms that we are given. Okay, so we get for the constants, I be not overwhelm. Okay, Then you are going to integrate. Why d y mhm now? It starts from l 20 Okay? Because he's going down, and then this is I had and then if you integrate, you get minus. Have, uh, I you know, l I hit. Okay, so this is F tree now. We do f four a f all both sites wall. Yeah. Now we have, uh why it goes to zero. So we is going to zero. Okay, so every is equal to zero. Hey, at four is equal to zero. Right? So that's all for part B. Now we want to find the net force in part C so f net. We just need some off other four forces that we found in party me. So you have, uh, house I you know, l I had my nurse. I know. L j had minus, have I e l I had as zero you can see that these two tons cancer out. So we are left with minus. I be not al Jihad. Okay, so this is the next force under current. Okay? And that's all for this question.

Hi everyone assumed and figure A for figure a magnetic field after center. Oh Due to segment one you can right You not I upon four pipe in two in by minus phi Do two segments to it is zero due to segment for it is zero and due to segment the three you will get You not I upon four by B. And to fight. So net magnetic field at center who will be resulted of Okay Magnetic field due to each segment. So it is to be be even plus B2 plus me three plus B. Full substitute the value. You know what I know about four by two x- Fight upon B. But let's fire upon me. Mm that's all. No second part. As soon as the figure be magnetic field up segment but you're not I Upon four by a. Into 35 x two. Due to segment to it is zero Due to be three. It is. You know what I don. four by B Sign of 45 and before Bilby you not I upon for HIV Sign off 45 And be 50. So net magnetic field at all. You will get We won Plus B two. Let me three Let's be four but let's we fight. So it is to be not upon for by I upon A. By way to zero. You not I upon 45 e. sign up 45 plus do not I upon foot by B sign of 45 plus zero. So after simplification net magnetic field at oh we will get you not I upon food by three point upon to a less two upon B. That's all. Thanks for watching it.


Similar Solved Questions

5 answers
Crh6 Cos C2t)6 sin (2+ 2 (n amputode5 Cr) pias € RormPetemnine no maxini Ve( Ur c aa euneri n 9 G) rom^ ne Prcv_ Par+ akd potcblcs alu & wlere_ 4 U attalned010 Pa_81 lzeve
crh 6 Cos C2t) 6 sin (2+ 2 (n amputode 5 Cr) pias € Rorm Petemnine no maxini Ve( Ur c aa euneri n 9 G) rom^ ne Prcv_ Par+ akd potcblcs alu & wlere_ 4 U attalned 010 Pa_ 81 lzeve...
5 answers
WORKSHEET-15,Q N:lawn 3: 26am You want to use the idea of electromagnetic induction to ma the bulb in your small flashlight glow; it glows when the potential difference across it is 1.5 V. You have a small bar magnet and a coil with 100 turns, each with area 3 x 104 m2. The magnitude of B -field at the front of bar magnet's north pole is 0.04 Tand reaches 0 when it is about 4 cm away from the pole. Can you make the bulb light explain:
WORKSHEET-15,Q N:lawn 3: 26am You want to use the idea of electromagnetic induction to ma the bulb in your small flashlight glow; it glows when the potential difference across it is 1.5 V. You have a small bar magnet and a coil with 100 turns, each with area 3 x 104 m2. The magnitude of B -field at ...
1 answers
Find the area of the surface by revolving the curve about the y-axis. 14. X=Cos y 0sy< 2
Find the area of the surface by revolving the curve about the y-axis. 14. X=Cos y 0sy< 2...
5 answers
Solve for U,X, Y, and in the given matrix equation_ 47
Solve for U,X, Y, and in the given matrix equation_ 47...
5 answers
LL 1 1onien11 1
L L 1 1 onien 1 1 1...
4 answers
Given r(t) = (tsint + cost)i + (tcost _ sint)j Find the curve's units tangent vector. Also find the length of the curve from t = V2 to t = 2
Given r(t) = (tsint + cost)i + (tcost _ sint)j Find the curve's units tangent vector. Also find the length of the curve from t = V2 to t = 2...
4 answers
A 1.0-L vessel initially contains 5.0 moles of NH; At equilibrium, it is found that the reaction vesscl contains 0.21 moles of Hz What the concentration of NH,at equilibrium?2NH_(g)Nzlg) + 3Hzl8)
A 1.0-L vessel initially contains 5.0 moles of NH; At equilibrium, it is found that the reaction vesscl contains 0.21 moles of Hz What the concentration of NH,at equilibrium? 2NH_(g) Nzlg) + 3Hzl8)...
5 answers
8. Let f(r) ={a I 4{-2,2} fe{-2,2} on thc interwl [-2,2: Then V(f) =
8. Let f(r) = {a I 4{-2,2} fe{-2,2} on thc interwl [-2,2: Then V(f) =...
5 answers
HI(aq)+O2(g)→H2O(l)+I2(s)Express your answer as a chemical equation. Identify all of thephases in your answer.
HI(aq)+O2(g)→H2O(l)+I2(s) Express your answer as a chemical equation. Identify all of the phases in your answer....
5 answers
AaunIcey Slon tcicoJverge person /5thenul hypothesis The dala I V Mque reported 510K5Entet Yoilt HNGAencn alino unsNelboxes
Aaun Icey Slon tcico Jverge person /5 thenul hypothesis The dala I V Mque reported 510K5 Entet Yoilt HNGA encn alino unsNelboxes...
5 answers
1 1 Two 8 hour; do1s 1534 2 Ja83 Tur JO4n U areine average Fdtc 0i 1 1 aui umOD nighayintne same dleOne (ravels
1 1 Two 8 hour; do1s 1534 2 Ja83 Tur JO4n U areine average Fdtc 0i 1 1 aui umOD nighayintne same dle One (ravels...
5 answers
Queation Completion Status;Is the following circuit correclly sotup?R= 1.5 kQThere Is not enough information to answer the question It depends on the power supply (battery) Yes
Queation Completion Status; Is the following circuit correclly sotup? R= 1.5 kQ There Is not enough information to answer the question It depends on the power supply (battery) Yes...
5 answers
Consider an AC power supply with the frequency f = 80 Hzconnected to an inductor (L = 0.2 H), capacitor (C = 2e-05 F) andresistor (R = 30 Ohm) in series. The maximum current in the ACcircuit Imax = 0.2 A. What is the maximum applied voltage?
Consider an AC power supply with the frequency f = 80 Hz connected to an inductor (L = 0.2 H), capacitor (C = 2e-05 F) and resistor (R = 30 Ohm) in series. The maximum current in the AC circuit Imax = 0.2 A. What is the maximum applied voltage?...
4 answers
Lji } H 8 ~ 1 [ T{ W W { 1 [ g 2 V L 4 2
Lji } H 8 ~ 1 [ T{ W W { 1 [ g 2 V L 4 2...
5 answers
Find the volume generated by revolving the region bounded by y lnx +2 y = and y Sketch the region _about the lineb) Suppose that f is continuous [unetion Such that f () =cf f(dt _ +r3 for all and f (a) = for some real muIber Find f' (a) in terIns 0f Only.
Find the volume generated by revolving the region bounded by y lnx +2 y = and y Sketch the region _ about the line b) Suppose that f is continuous [unetion Such that f () =cf f(dt _ +r3 for all and f (a) = for some real muIber Find f' (a) in terIns 0f Only....
5 answers
The curves f(z) =+ 21 2 and g(z)2 intersect at the point (-1,-3)Find the acute angle of intersection, in radians on the domain 0 < t < 2 to at least two decimal places_Question Help:VideoSubmit Question
The curves f(z) = + 21 2 and g(z) 2 intersect at the point (-1,-3) Find the acute angle of intersection, in radians on the domain 0 < t < 2 to at least two decimal places_ Question Help: Video Submit Question...

-- 0.018906--