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Question 2 0f 17How many moles of Agl will be formed when: 75.0 ML0.300AgNOscompletely reacted according to the balanced chemical reaction:AgNO_(aq) Calz(aq)(Agl(s)...

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Question 2 0f 17How many moles of Agl will be formed when: 75.0 ML0.300AgNOscompletely reacted according to the balanced chemical reaction:AgNO_(aq) Calz(aq)(Agl(s) - Ca(NO,)(aq)LliexFFYEAddeacon20.0010.02251000169.8875.00.044234.770,2506.022 1030.30022.5AglmL Aglmol AgNO; mol AglAgNO, mL AgNOsg AglAgNO,AgNOs

Question 2 0f 17 How many moles of Agl will be formed when: 75.0 ML 0.300 AgNOs completely reacted according to the balanced chemical reaction: AgNO_(aq) Calz(aq) (Agl(s) - Ca(NO,)(aq) Lliex FFYE Addeacon 2 0.001 0.0225 1000 169.88 75.0 0.044 234.77 0,250 6.022 103 0.300 22.5 Agl mL Agl mol AgNO; mol Agl AgNO, mL AgNOs g Agl AgNO, AgNOs



Answers

Consider the hypothetical reaction $$ 2 \mathrm{R}_{2} \mathrm{X}_{5}+2 \mathrm{Z}_{8} \longrightarrow 5 \mathrm{X}_{2}+4 \mathrm{RZ}_{4} $$ When $25.00 \mathrm{~g}$ of $\mathrm{Z}_{8}(\mathrm{MM}=197.4 \mathrm{~g} / \mathrm{mol})$ react with an excess of $\mathrm{R}_{2} \mathrm{X}_{5}, 21.72 \mathrm{~g}$ of $\mathrm{X}_{2}$ are produced. (a) How many moles of $\mathrm{X}_{2}$ are produced? (b) What is the molar mass of $\mathrm{X}_{2}$ ?

Because the formula of polarity is the moles of solute over the leaders of solution. If you multiply by leaders on both sides, it's going to cancel out on this side and you'll just be left with moles. So all you have to do is multiply the leader of the dissolution by the polarity and you'll get the mold of the select for part A. We have 12.5 millimeters, which is equal to 0.125 liters, and the solution is 0.104 Mueller. I'll set up parts B, C and D before I actually do the math out For Part B, you have 27.3 millimeters divide by 1000 to get 0.0 273 leaders, and your concentration is point 2 to 3. Mueller for part C 36.8 millilitres gives you 0.0 368 leaders and your polarity is 3680.501 mhm. And lastly, for Part D, we have 47.5 mL, which is 0.0 475 It doesn't look like a seven leaders. There we go, and our concentration is 0.749 Mueller. So when we do all of this math out, mhm, we are going to get the malls of Sally in each case. So we have 0.125 times. 0.104 gives you 0.0 13 malls. Report 0.273 times 0.2 to 3 is 0.0 609 Moles for part B mhm 0.368 times 0.501 is point 0184 boss and lastly 0.475 times 0.749 is point 03 56 Yeah, moles. All of them rounded to three significant figures. Yeah, yeah.

Okay, so in the first part of this problem, we are as find out How many me Later self. This much Moeller is seal are needed to completely neutralized fifty mil on this much Mueller barium hydroxide solution. So to find that but will do first is will find a number ofthe malls for these Follow him and this malarial barium hydroxide From there using the balanced equation forthis reaction, we will find out how many moles off eight c l which we will We need to neutralize that much moola, barium hydroxide and from there using the more clarity and and the calculated number of malls will be able to find out how many milliliters off a cell are needed to completely neutralize thiss. So first, we'Ll find the number of multiple barium hydroxide So member of mall so barium hydroxide will be equal to it's morality Time's volume in later. So the modernity here is zero one one one Mueller are more per liter times the volume in later we have fifty millimeter so well, right, fifty times gender. The bar minus three later And from here we will get a value off. Zero bond is he was five more. So this is the number of more for the barium Hydro st. Now we will write down the balanced equation for this creation. So the balanced equation we're writing in the ministry question directly, it should be to its hell, no. Well, great. Great one. Very, um hydroxide, Yeah, to give us very, um, Claridge and to h to own. So from the balance to question, we can see that one more Bayon hydroxide will react with two more off a seal. So you all right? One more barium hydroxide will be neutralized by all by Unical toe tumult. It's seal. That means, um, Mr Point, Syria zero five mall. Very, um hydro side will be neutralized by two times zero point zero zero five more. Its seal, which is equal to zero point his serial. One more sl. So this is the number of malls for a seal which will be needed. So from here, we're going to find and followem off. It's elegant. Using them is in the minority. So the volume off its seal needed number of malls off. It's hell over, Um, a small charity. So you know that way. Just calculated the number of malls at zero point serial one mall and the morality is given as point one two zero Mueller So we'LL write it as point one two zero more bar later and this will give us a value off zero point zero eight three later And we need to find out that same Millie later Sail Convert this two million later One liter is one thousand million Later on DH From here we'LL get eighty three point tree militar So this is the volume of a seal in militar which will be needed to completely neutralize this much Mariam hundred side Now we'LL goto our next problem in this problem where has to find out how many milliliters off point one toe find molars Sulfuric acid are needed to neutralize thiss mass of sodium hydroxide again what we will do we will find a number of malls off. Sorry, um, hydroxide four point two grams sodium hydroxide and from the balanced regression we'LL find how many moles off extras afore we will need to completely neutralize this much more low sodium hydroxide and from the number of moola sulphuric acid. Using this minority, we can find out the volume in millilitres first offer, you guess it. So first, you find the number ofthe malls off sodium hydroxide, which is mass over molar Mass. So the mass Siri's point two zero zero grams and the molar mass of sodium hydroxide is forty point one. Grandpa are more, and it will give us a fellow of five time's gender. The bar minus three more. So this is the number of Mall of sodium hydroxide now. Well, right, the balanced equation for this reaction. So the balance to question will be each to us of four, and AC Woz will react to it to sodium hydroxide to give us sodium self that and to each tool. So now from here, we can see that, too. Mono sodium hydroxide will be neutralized by one mole of histories of four. So to Mel's, sodium hydroxide will be neutralized by our equal toe. One mullets just off for that men's this much Matloff sodium hydroxide will be neutralized by one over two times five times ten to the bar minus three more, and this delivers a blow off two point five times ten to the minus three more So this is the number of mole off sulphuric acid too. We shall we needed So now from this fellow and using the morality, we can find out the volume of sulphuric acid needed. So PhDs of four will be number of malls office just for over the morality of histories of four and the number of mosey of just calculated as two point five times to the four minus three more. Yeah, and ah, morality is Zira Point Oneto fight more per liter, so it it will give us a valve off zero point zero two later. So we have to find out the value in militar children and then one thousand million later as one liter universe of L A off twenty militar. So this is the volume of sulphuric acid in millilitres which will be needed to neutralize the sodium hydroxide. God, Yes. So the sodium hydroxide. Now, in the hard part of this question, we have to find out if this much military buryem chloride is needed to precipitate all the sulfur down in seven fifty two milligram off. Sorry. Um self it What is the morality of the barium? Correct. So again, first we'Ll find out the number of malls for seven. Fifty to Graham sodium sulfite. From there we'Ll find the number of most of the inquiry And then, using the balanced equation, we'LL find out the majority of the very great. So first, we'll find a number of mall of an address of floor, which would be, ah, the massive arm alarm us So seven. Fifty two million Grammys zero point seven five to Graham over the molar mass of Saudi himself, which is one forty two Grandpa Ramon. And this will give us the value ofthe five point three time. Still department is three mall. Now we have found a number of Moloch sort himself out. Now we'LL write the balance the question So the balanced equation for discretion is I am Claridge reacting with sodium self it giving us very himself at and doing a seal. No. From here you can see one bowl of Saudi himself. We've been neutralized by one more herb am chloride. That means this much more love Saudi himself. It will be neutralized by the same number off um, the seal to herbarium correct. So we can write down the number of full of barium crate as this So NBS sailed to or the number of months of years lt weighs five point three times Get over minus three more now From here we can find out Um I know the minority from Bankrate which will be number of most of our volume Number of Moses This one over the volume is fifty five point a militar We'LL write it as litter this multiplying waiting or minus three And this will give us a bell off zero point zero nine five Mueller I said this is there, um morality off man creates solution now in last problem we have to find out if forty one seven millimeter off this much Mona is seal is needed to neutralize solution off calcium hydroxide How many grounds The calcium hydroxide has been the solution So again what we will do first you will find out the number of malls off itself from its volume and morality From there is in the balance situation we'LL find out the number of all of calcium hydroxide Ah she'll be needed And then from that number of malls using the molar mass we confined how many grams of calcium hydroxide needed So first we'll find out the number of mall off eight seal which will be in the morning eighty times for Liam on the morning of the hair is zero point two eight more per later times The follow me in later forty two point seven times Junior government is three later and this will give us a hello off the point zero zero nine more So this is the number of more of calcium hydroxide Now what we'LL do is we'LL find out the balanced equation From there we'LL find out the number ofthe most ofthe eight c require So the balanced equation is two It's c l will react with one calcium hydroxide to give us one girl sham chloride and two is tool Now from here we can see one more of calcium hydroxide will be neutralised by two more off a C l one more calcium hydroxide sign will be neutralized My are identical to Touma Let's seal that wins our s o We have find out the number of one ofthe It's hell. So what we'LL do is well, write it down the other way to Molly's cell Well needed will be needed Require will need it too Neutralised One mole of culture My drug side. That means zero point zero zero nine more C l will be required to neutralize halftimes sirah planned zero zero nine mall and she'LL be equal to zero point zero zero four more. So this is the number of molds off calcium hydroxide, which will be neutralized. Now, from here, we're going to find a massive catching my drug sign. Samantha ve calcium hydroxide will be, ah, the number of malls. Times the molecular weight to the number of mole is zero point zero zero for more times. The Mueller math. A molecular weight off. Get your mind off sandwiches. Zero point two nine six. Um, grandpa or more. And this will give us a bell off zero point two nine six gram. So this is the mass of calcium hydroxide, um, which must be in the solution.

Every human question. 23. Okay, Yeah. Do B b s mhm. Okay, they act with three moles of oxygen. Yeah, giving two p b o. There's two more yourself self. They'll tear gas. How many moles off each product? Wow, When given amount off each reacted completely Riyadh's So we have 2.4 moles off. Let sulfate 2.4 Moore's off. Let's sulfide is completely reacting the bond, the rock. So we have to find out how many moles off each of these properties off or something. So two modes we produced two moles off let oxygen. So 2.4 modes will produce 214 more days off the boat sailing and also do one foremost off. So but they all seem because it is the real issue. This one is 21 2.4 Moles of Oxygen. Now, in the case of oxygen three most of all, she informs to most of the doc said So the conversion fact there's two a 13 So we have the multiply 2.4 in the two divided by three that tons of people 1.6 months off the dogs on 1.6 months off today. Also the third case, 5.3 modes of legs elevated 5.3 moors of Mexicans. How here again it will find 5.3 modes off lead outside because it is one is to one on 15 countries. Also serving, they'll say, on the last case by 13 Moles of Oxygen. He's in double address for more than so. Here again, we have to multiply by to a pawn three. So we will get 1.5 months off a deep on five. Moore's off. The doctor did. 315 Yeah, that's it. Okay. Yeah. 315 Moles of the dark side. Yeah, I'm 3.5 moles off, so pronounce it.

If we have the mole arat e of a substance and its volume, we can figure out how many moles we have of our salute and how many grams we have. So, for example, we have 325 millimeters or a 0.3 to 5 leaders and Armel Arat E is 8.23 times 10 to the negative fifth. Then, to get the moles, we just multiply those two numbers together. 8.23 So the negative fifth times 0.3 to 5. That gives me two point 67 times 10 to the negative fifth moles. And then to convert that 2 g, I need the Mueller Mass of K I, which is 1 66. Why 002 and I just multiply those and I get 0.4 grams of K I. If I have 75 mL or where is 075 leaders and I want moles. I will also multiply by the morality. So if my morality is 2.2 times 10 to the negative fifth Mueller H two s 04 So 2.2 times 10 to the negative fifth. That was 2.75 gives me 1.65 times 10 to the negative six moles. And again I need D the Mueller Mass. And for H two s 04 that's 98.78 g per mole. Oops, I did this backwards. Moles should be on bottom and the mass will be on top. So we're going to multiply and we get one point 62 times 10 to the negative force grams of sulfuric acid if I'm starting with 0.2500 leaders and my mil Arat e is 0.1135 of K two c r 04 again we'll multiplies the 0.1135 times 0.2500 and we get 0.2 8375 moles And again we want to convert that to ah Graham. So I need the molar Mass 1 94 point 188 is equal toe. One more my Multiply those and I get 5.51 grams of k two c r 04 and last. If I have 10.5 leaders confirm ALS here Armel Arat e. It has 3.716 Mueller. So multiply those. We get 39.18 moles and this is N. H four two and so forth. And so we will convert that 2 g using the Mueller Mass. One mole is equal to 132 0.14 g, and so I multiply and I get 5155 point 8 g of our compound.


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