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Do hanMirdhamJecureCnon https / wwmathxLcom/Student/PlayerHomEfhomeworkId 486685767 &questionld= 1& fluched2018 Summer Math 1342.87 Dr; Robinsonabinailuundh...

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Do hanMirdhamJecureCnon https / wwmathxLcom/Student/PlayerHomEfhomeworkId 486685767 &questionld= 1& fluched2018 Summer Math 1342.87 Dr; Robinsonabinailuundham6/26/18 5.03 PM Homework: Section 7.2 Estimating a Population Proportion Score: 0 of 1 pt 8 0 15 cotrinkele HW Score: 29,3398, 4.4 0l 15 pls 2.25 Question Hc ? Usa iho data Ihe tahle Ihe nght Io Jniwer Ictjwta Weighe , (q)ol a Sample Bag = Cacdy qul_uony Brotn Ceen Ycr Find the sample proporlcn cant ahle Mcty Cla M I xn 0 (DJ F F E

Do han Mirdham Jecure Cnon https / wwmathxLcom/Student/PlayerHom EfhomeworkId 486685767 &questionld= 1& fluched 2018 Summer Math 1342.87 Dr; Robinson abinailuundham 6/26/18 5.03 PM Homework: Section 7.2 Estimating a Population Proportion Score: 0 of 1 pt 8 0 15 cotrinkele HW Score: 29,3398, 4.4 0l 15 pls 2.25 Question Hc ? Usa iho data Ihe tahle Ihe nght Io Jniwer Ictjwta Weighe , (q)ol a Sample Bag = Cacdy qul_uony Brotn Ceen Ycr Find the sample proporlcn cant ahle Mcty Cla M I xn 0 (DJ F F Ei proporion ofred candy= 0 8/2 0 -d8 0,841 tan 0 915 (Type Inie 02r decimal fouded I0 tnret decimnul plucus45 0 969 0,{01 ordnd 0,872 0,655 0.815 0.903 0.06 0 80? Conu 0,844 0 937 A 04753 0-(6B snlc: V-- Ining: Gala 4d0 heueula



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Please provide the following information. (a) What is the level of significance? State the null and alternate hypotheses. (b) Find the value of the chi-square statistic for the sample. Are all the expected frequencies greater than $5 ?$ What sampling distribution will you use? What are the degrees of freedom? (c) Find or estimate the $P$ -value of the sample test statistic. (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories? (e) Interpret your conclusion in the context of the application. The types of raw materials used to construct stone tools found at the archaeological site Casa del Rito are shown below (Bandelier Archaeological Excavation Project, edited by Kohler and Root). A random sample of 1486 stone tools was obtained from a current excavation site. Use a $1 \%$ level of significance to test the claim that the regional distribution of raw materials fits the distribution at the current excavation site.

For the match pairs given on the right. We want to conduct a sign tested matched pairs testing P does not equal 0.5 at alpha equals 0.5 significance. This question is testing our understanding of non parametric tests in particular how to conduct a scientist of matched pairs. We proceed there steps A through D below to solve. So first, in a we stayed alpha hypotheses, this gives alpha equals 0.5 H. And r P does not equal five. H. A P does not equal five. So the no hypothesis P is equal to have, the alternative is not A and B. We compute the test out. So are signs for these matched pairs are as follows and equals 12 is the total number of matched pairs. So X equals the number of plus or the total number plus and minus which is 4/12. Thus we have seen it equals x minus 5/45 over and equals negative 1.155 Thus the p value is for a normal distribution, P equals two PZ greater than zero equals 248 Thus we conclude that we fail to reject asian off because he is greater than alpha, which means that we lack evidence to support the claim P does not equal five.

We have data sets A and B on the right. We want to utilize these data sets to test the claim that there is no difference in the underlying distributions for A and B it out the equals 0.1 significance. This question is testing an understanding of non parametric tests, particularly how to take perform the ranks on tests we proceed through steps A through G to solve. So first we see the outside of hypotheses. These are alpha equals 0.1 hypotheses. H. And distributions are saying hk distribution are different and be we can be the test at the sampling distribution which is normal and check the requirements which are met. So their ranks are for A and B. As follows That we have and one equals 11 and two equals 12. You are sigma are 1 30 to 16.2 from this, we have our equals and summer range from a 1 73 so Z equals ar minus. Moreover signal articles 2.53 thus received complete the P value. As for normal distribution two PZ greater than 0.114 Thus, we conclude, indeed, that we fail to reject nation on since P is greater than alpha, which means we lack evidence for AJ.

We have the following matched pairs and we want to conduct a sign tested matched pairs, testing the claim P does not equal five at alpha equals 50.1 significance. This question is testing an understanding of how to implement statistical non parametric texts. In particular the scientists and matched pairs. We proceed the steps A through D to solve so first and a. We see our alpha and hypotheses alpha is 0.1 H and r S p 0.5 AJ is the claim P does not equal five and B. We compute the test at so your population A to B. We have the following signs thus and equals 20. The total number of pluses and minuses and X is the number of plus over. The total number 10/20. Thus our Zenon is x minus point 5/2 0.0.25 over and a zero because 00.5 minutes 0.50 Thus from a normal distribution, r p value is one because the probability at Z is greater than 0.5 times two is one. Thus, we conclude for this test that we fail to reject because P is greater than alpha, which means that we lack evidence to support the alternative hypothesis.

In this video we will be making a box and whisker plot, finding the inter quartile range and then answering a question in regards to our information. So I have put the numbers here in front of us. There are 50 items in this particular situation. So that means My median will actually, let's start with us. Let's start with our low value. They're already in order from least to greatest. So my lowest value part of my five number summary will be five and my highest value will be 15. I also need Q. one, the median and Q two. So because there are 50 items that means the median will be 25 units from either side. So 123 And then if I count 25 back from 15, I'll also end up here at 10. So that makes it pretty easy to find the median because even though it's I would normally average the two because they're both 10 just means the median is 10. So now I need to find the middle of the bottom quarter or the lower quartile. So now I've got 25 items and 25 divided by two is 12.5. So that means I'm going to count up 12 so one And then I'm going to circle the next one because that's gonna be my Q1. And just to make sure 34. Okay So nine will be my Q. one, my lower quartile. And then I'm going to do the same thing on the upper quartile and then just make sure sure enough yep there's the 12. So on my number line I see my low values is five. My high value is 15. So I could just start my number line at five 10 15 so I could do that. So I'm going to put a. five. A data about 15. Then Q nine or Q one is 9. So that would be here 11 12. My meeting is 10. Make a box whiskers and draw my bar to represent the medium. Now I need to find the inter quartile range and remember that's the difference between these two or the length of my box. So the inter quartile range will be three. And then finally I am told that Wyoming has a dropout rate That's 7% or around 7%. And I want to know where that is on my graph. So I look at my graph and I see 7% would be right here. So that would fall in what we would call the first quartile because it's below Q one so 7% is in the first quartile.


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