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Lengter Ienses that _ are lensDeterMTINC 9 ? magnification distance from quaidiverging apant nd dSeds foca length image, Snotn figure ensfinal image.converging puef...

Question

Lengter Ienses that _ are lensDeterMTINC 9 ? magnification distance from quaidiverging apant nd dSeds foca length image, Snotn figure ensfinal image.converging puefocal

lengter Ienses that _ are lens DeterMTINC 9 ? magnification distance from quai diverging apant nd dSeds foca length image, Snotn figure ens final image. converging pue focal



Answers

Consider the simple model of the zoom lens shown in Fig. 34.43a. The converging lens has focal length $f_1$ = 12 cm, and the diverging lens has focal length $f_2 = -$12 cm. The lenses are separated by 4 cm as shown in Fig. 34.43a. (a) For a distant object, where is the image of the converging lens? (b) The image of the converging lens serves as the object for the diverging lens. What is the object distance for the diverging lens? (c) Where is the final image? Compare your answer to Fig. 34.43a. (d) Repeat parts (a), (b), and (c) for the situation shown in Fig. 34.43b, in which the lenses are separated by 8 cm.

High. In the given problem, you're having a combination off two lenses. The first one is are diverging lens having a focal landfall, if one and the second one is converging lines having a pope, a lamp or two. And the gap between this school has been given as d. No, an object has been kept in print. Off this diverging lands can extend. So me. So, first of all, we will find the position off in age formed by this diverging lens. For this purpose, we use England's Formula four diverging Let's which phase one bike you their fewest. Our distance off image from this Die Virginians minus one by B. The objective stance is equal toe bone by F one. So finally, this one by Q comes out to be one bite be plus one by one or picking LCN we get, and this is speedy into F one. Be less every month. So finally, the Magne judo distance off the image you comes out to be B F one by B less F one. This is their distance off the image, and it is obvious by the rules off the image formation by diverging lens that the image will be formed towards left So this distance is cute. No, we want the final in H formed by this convergence to be at infinity for that purpose. This distance off the virtual object as the image formed by diverging lands you match formed by diverging lands will serve as ah what you an object were converging lens So for the final in age don't be impunity This work your object for converging lands should be at its because so we can say this q plus D Should people toe to this Q A McGriddle off you plus d. The distance between the lenses should be equal to after the focal and off convergence. And we know the magnitude of this queues B F one by B plus f one plus de is equal toe f toe. So finally, the magnitude of this deep comes out early at two, minus B F one by the less F one. So taking an LLC in here it becomes B plus F one have to in tow be less f one minus B. They're fun and expanding the terms. Finally, yet B can be taken out in the numerator after expending the bracket. So it began speed F to minus F one in a single break it unless f one in two F two and divided by be less if one. So this should be the distance between the two lenses. So that the final in age maybe that in many day thank you.

Everybody. So we want to draw a ray. Diagram showing are looking image, an estimate. The magnitude of the diet. Okay, so for this about this and our breaking ones here. So the ray diagram given situations where the object is situated in the midway through the focal point, the center of the conversion lying. Okay, they have a focal point here on this side of the left hand side and one that's on the right hand side. And so you're given this entity half way on. So we have this go this this way. Okay. On the next plan is this blood and it goes this way and then hits the F every day. It's the focal point here on that. We have one that goes here. Okay. And the parents local wine you have about a year on. And this here and you have this here. So as object inside the focal point image appears on the same started lives in the distribution virtual. So the image formed at the focal point and everyone's is twice as large is of the object. So that next year that here's is twice as large as objects. Okay, so the meditation of the giving birth. And it's the diagram. How so? It's this way Here. It kind of here twice as large here. Like this. Guys, Thank you.

Everyone as we know for it's very confident relation between object distance and it means distance Can we burn upon Afghan? Say Christian von that is going upon infinitely has been upon has been dis is called Hogan upon 12 focal length is getting 12 as one does you will get 12 centimeters They sit Answer off a part Now be part e stupid b T plus after four plus minus 20 So it is going minus eight. Scent emitted Yeah, no one upon has to bless one upon has to Death is called one upon After substituting the value as two is minus eight centimeter as to as we are calculating for connect this square so as to do as you will get 24 scent emitted that sort Thanks for about chicken. Sorry, we have deep part again Sorry, Extremely sorry parrot Now far be part born upon infinitely Lisbon Upon as one deaths it's called Togo invite toe husband as baby square centimeter So as stupid to be Do you be blessed? Have to that is ap minus bird that is minus four scent emitted now applying the military question but upon has to plus burn upon as two days it's called to burn upon have to from minus poor plus going upon as two days, it startle minus one by 12. So as two days you will get six intuitive. They're so thanks for my chicken.

In this problem we have the magnification with respect to the object distance B as am equals two F upon if minus B. The problem we have S6cm So this is nothing but six upon six minus now we need em to be at least three times as large. So we need em Greater than equal to three, which means that six upon 6 -7 Should be greater than equal to three. This is the inequality that needs to be solved. This is six Upon 6 -7 minus three With greater than nuclear 20 six minus taking the L. C. And this is 36 minus B. Directed by 6 -4 To be greater than equal to zero. This becomes three p minus 18 minus minus 18 plus six is minus 12 Upon 6 -7. To dictate that equal to No, Let us make a sign jug for three p -12.6 -7. Before that we will first find the critical numbers or the partition of most partition numbers will correspond to three p minus b. Three b minus 12 Upon 6 -7 as either zero or not defined. So we get be us either four where 0 art six where it's not defined so lets me go san chuck, it says start from zero, this is four and six. So we have three regions starting from zero in which it is defined from 0 to 4, then from 4 to 6 and then from six to infinity. Let's take some best numbers in each of these regions and check the value In 0-4. Let's take 1, 4-6, let's take five and then here will take seven. So when it's one it is three into one which is three minus 12 is minus nine divided by six minus one is five, so minus nine but five this means this is a negative decent right now. At five this is three into five inches. 15 minus 12 is three divided by six minus five is one. This is a positive vision. And at seven This is 3721 -12 is nine, divided by 6 -7 is -1, So this is negative at six it is not defined and at four, but this zero. So we need the region in which three t minus 12 upon six minus B is greater than equal to zero, so we need Greater than equal to zero, which means that he belongs to A close record for two open market Six, that's all.


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