Okay, so this question wants us to find the equation of a tangent line to this function at the point X equals eight. So to do this, we'll use the definition of derivatives to fund our slope. So plugging in the values we know one over X plus h minus on over acts and just to avoid using a complex fraction, are gonna bring the won over H over there. And now let's get a common denominator. So the first term needs an axe in the second term, needs an X plus age, and we still have the one of her age in front. And now you can see that this axe cancels with that ex so you just get negative h over X times, X plus h and then we have our factor of one over h and front in these Cancel out. So we just get the limit as X Sorry as H as H approaches zero of negative one over X Times X plus H, which is if you plug in zero, this h goes away. So it's just negative. One over x. Times X was zero, which is just negative. One over X squared equals F prime of X. So to find the slope at X equals eight, you just plug in eight into the derivative, which is negative. One over eight squared, which is negative, one divided by 64. And to see where that point ISS on the graph, you just plug in eight f of axe. So it's one over eight and now we have everything we need to construct our line. So we use the point slope equation. Why minus 1/8 is our point on the graph times negative one over 64 times X minus The point of tendency, which in this case is eight. And if we want to simplify that MX plus B form, we get negative won over 64 times acts plus 1/8 plus 1/8 which simplifies to 1/4. And there's our tangent line.