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Solve (41 In(ax logarithmic equation X) uI...

Question

Solve (41 In(ax logarithmic equation X) uI

Solve (41 In(ax logarithmic equation X) uI



Answers

Solve the logarithmic equation. $$\log (x+40)=-9.2$$

Like the very logarithmic function is log X plus 40 equals two minus 9.2. Now we have to solve it. Now we can see that this equation has a single algorithmic in the left hand side that is already isolated. Now by using the property log base B of C equals to A. Which can be written us Beer is to the power A. Equals to see. Now here in this function our base equals two. And now apply this rule. Our function can be. Returners 10. Raised to the power minus 9.2 equals two. X plus 40. Now solve for X. We get X equals two and raised to the power minus 9.2 -40. Now to check for X put X equals to 10 degrees to the power minus 9.2 minus 40. In the original function. So we get logged 10 raised to the power -9.2 -40 less, 40 Equals 2 -9.2. Now cancel out 40. We get log 10 degrees to the power minus 9.2 equals two minus 9.2. Now, by property we know that minus 9.2 equals two minus 9.2, and this is true. For X equals two, 10 raised to the power -9.2 -40, so this is our final answer.

We need to solve the logarithmic equation. Log based and X is equal to minus one upon for we can rewrite this equation as 10 log Basten X is equal to 10 to the power minus one upon full. So using the invest property, we get X is equal to 10 to the power minus one upon four and hence the value off X is one upon turned to the power of one upon for.

Log off X equal to minus four. I have to solve this longer. Miggy question. Now I can see here basis not mentioned, so basis not mentioned, means base. I have to take 10. So simply this is the bitterness. Log off extra. The best 10 is a photo minus for What does it mean? I'll convert into exponential form and I'll have excellent Louie called toe tenders to the par minus four, which is nothing worth one by tenders to the power, for I can convert it and write it as X equal to 0.1 So that's the solution off this longer McGee question that they have.

Hello? So here we have the equation log of X over 10 to negative third power is equal to 4.7. Okay so how do we solve this? Well this is first of all what this is going to be while log base 10 right? There's no base written. Therefore this is a common log. So this is log base ted. Remember a log is the next point. This means that 10 to 4.7 power is equal to X over 10 to the minus three but X over 10 to the minus three or that minus three is gonna push that upstairs. That's really 10 to the third times X attended the third is really well 1000 This is 1000 X. I'm gonna leave it written as 10 to the third. So we have 10-4.7 is equal to 10 to the third times X. Not to solve for X which is divide through by well 1000 or 10 to the third power. So dividing through by 10 to the third power. While now we that X is going to be equal to whoops. X is going to be equal to well 10 to 4 point 7/10 to the third. He at the same base We're dividing you subtract the exponents. So we have 10 to the 4.7 -3. Well 4.7 -3 is 1.7. Therefore we have that X is equal to 10 To the 1.7 power. Take care


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