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# Prove the following theorem: for every integer n, there is positive integer a and negative integer b for which a +b = n. (The easiest way to do this is by cases_ ...

## Question

###### Prove the following theorem: for every integer n, there is positive integer a and negative integer b for which a +b = n. (The easiest way to do this is by cases_ There are three: n is positive, n = 0, 0r n is negative: In all cases; your a and b will depend on n!)

Prove the following theorem: for every integer n, there is positive integer a and negative integer b for which a +b = n. (The easiest way to do this is by cases_ There are three: n is positive, n = 0, 0r n is negative: In all cases; your a and b will depend on n!)

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