5

Enol tautomers of the ketone shown below? Which of the following areCH3CCH2CH3Select one_ CH3C =CHCH3 and CH3CHCH=CH2OH CH3C CHCH3 ,OHand CH2: FCCH2CH3 CH3CHCH =CH2...

Question

Enol tautomers of the ketone shown below? Which of the following areCH3CCH2CH3Select one_ CH3C =CHCH3 and CH3CHCH=CH2OH CH3C CHCH3 ,OHand CH2: FCCH2CH3 CH3CHCH =CH2OHOH OH CH3C CHCH 3 and CH2 CCH2CH3OHOHCH3CHCH2CH3 and CH3C =CHCH3OHOHCH3CHCHCH2 and CH2=CCH2CH3OHOH

enol tautomers of the ketone shown below? Which of the following are CH3CCH2CH3 Select one_ CH3C =CHCH3 and CH3CHCH=CH2 OH CH3C CHCH3 , OH and CH2: FCCH2CH3 CH3CHCH =CH2 OH OH OH CH3C CHCH 3 and CH2 CCH2CH3 OH OH CH3CHCH2CH3 and CH3C =CHCH3 OH OH CH3CHCHCH2 and CH2=CCH2CH3 OH OH



Answers

Classify each of the following molecules as alcohol, aldehyde, ketone, carboxylic acid, or amine:
(a) $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{NH}_{2}$ (b) (c) (d) (e) $\mathrm{CH}_{3}-\mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{OH}$

Problem. 68. We are identifying the carbon in little groups on all of this structures that are given. So starting with part, eh? I think part a pretty clear right here. Okay. So what? We just have the We just have a key thrown right here. All right, so part a would just be a key tone. Okay, Part B, we'll be right here. Maybe a little bit tricky. Um, first of all, it's terminal, meaning it's it's connected to the very end. Carbon. Hey, so we have two choices here. It could either be an alcohol could either be an alcohol for another heart. Okay. And so the safest way here is to just count how many things are attached attached to carbon. So we got one. This is attached to our carbon, and then we have one hydrogen. Right? So it has two things attached to it so that oxygen has to be double bonded carbon in order to fill, um, kill those four bonds to carbon. Right? So that means sensory. Since we have a double bond, that means we have another heart. Okay. And another easier way or faster way to, um, identify if it's an alcohol or another hard is that on? Alcohol? Would be would always be written as Ohh! Right. And all the Hyde would always be h okay or C h o. Okay, so it's Ohh. Definitely alcohol. If it's written, asked Tho, then it Well, the height. Okay, court. See? So here's years our you're so we're auctions. You in right here and again. This this questions them already tells us we have a carbon your group. But if it doesn't tell you that, um, this this oxygen could either be an ether or, um, because it's summer in the middle of the molecule, it could be a key toe. Okay, so, um, as discussed in a previous previous problem, Carbonell Group. And somewhere in the middle of a molecule, then it is a key. So, Bart, see, here would be would be a key tone. Hey, since we know it is a carbon Lee Carbonell group, if you want to make sure it's not that, either then you can go ahead and count. Found the bonds connected to carbon in. You'll see that it needs to be double bonded to Oxygen party parties right here. And I think it's pretty clear. We know that this is a carbon Neil group, right? So it's going to be a C double bonded to oxygen, and we have that nitrogen in there. So that makes this That makes this group our am I OK on to our last part, part D. We got two oxygen's. Okay, so we really only know, too. Functional groups were to oxygen's in it. One would be a car book. Selic acid. That's a That's a hydrogen rewrite. It are books like acid or on Esther, right? The only difference would be either you have a hydrogen connected to your oxygen or another carbon. Okay, In this case, as we see, we have this carbon connected to our oxygen, right? Meaning our functional group here would be okay.

High school. It solve problems. 3.24. You need to cope with the structure from Ford. Before then, Compounds force twenties of Gaetan and then four couples we know didn't has. The function group has this home and these companies, I don't to another to convince on board signs and maybe four hours. So one do 34 this place on the hydrogen bomb. And let's count the hydrogen tree here to here and down the tree, which means we have eight hydrogen is and one oxygen. Okay, then comes a nitwit. My dreams have got one and nitrogen Triple one, Do you five continents displeased with my performance? 12345 And now we need to. And this on the hydrogen is with the problems. So if we can't, we see that we have 900 Jin's three here and other six years. So nine hydrogen send from Diane de head and behind Functional Group has this instruction. I won't is bunker hydrogen and double wounded with oxygen and on the other side is open. And in this case, we have drew and they hide groups because it says I m d Hanks. So one and head is going to be in the beginning of the component at the end of the chain and then four problems Still space. The four problems because it is strange and rehang. Another empty handed is going to win in the end. And, let's know, please probably hide regions, and we have 600 Jin's Let's count 12 Beautiful Line six and do oxygen simplest from one from one against our functional comp averages. Having this growing function and and this kind of problem don't want and compassion on a group, it's draw the simplest one. If six kind ones destroyed the six carbon chain, since it is the banking system and can govern commendable wonder in the beginning and leaves space from roaming here now we can place on the hydrogen. Let's count the hydrogen. Three. Fine. Six. Let's count again. Three Fine 6 70 9 10 11 So this is several milking Next. Just it is a simple elkin so we can draw six com. Bridging simple elkin and lips, please the head regions. It's going to the head regions fine. Seven nine, 11 40. Now we need to dress. I click saturated hydrocarbon, Cy Creek means it is going to have Ah, closed cycle instruction off carbon and saturated means there is going to be no double bond on Triple One on the carbon following ones are going to be seeing that one. And we have six governments so live strong. This is a cycling structure of six carbon, and we need to close on the hive illusions. Each one is going to have 200 Jin's six couples with 207 700 this year. Oh, a simple way we can draw this Next use died in poppy dying son come poems reach hands carbon, carbon double want out and to double to carbon, carbon, double one and in between days going to first single bond which is going to join this to cover for double ones. Okay, now we have five problems. So let's draw the five by one chain first and these die things School head, please the hydrogen Islam. We can count that there. Five religions three 4.678 Menelik Ito King Keep Belkin's this wanting to functional groups the skin tone functional group and double double warm. And we have five presents. So I destroyed 5 17 Let's face it from here and the carbon carbon double here, and that will drive the hydrogen. So if we do the information, we will see that there are eight hydrogen full fine, Andy.

This is the answer to Chapter 21. Problem number five from the Smith Organic Chemistry textbook. In this problem, we're asked Thio come up with the AIPAC name for these three key tones that we've been given. Um, okay. And so the rules for naming key tones. Um, so for a and C, the open chain key tones, um, we need to find the longest chain that contains the key tone on change. The ending to own, um and then you need to number, uh, that change so that the key tone has the lowest number. Okay, um and so for a that's going to look like this. So 123 So the key tones of carbon 34 56 78 So this is gonna be an Octa known. Ah, and it looks like we have an ethel group at carbon five and a metal group at carbon four. Um, and so when we put all of that information together, this becomes five Ethel for meth A ll. Because, remember, it's in alphabetical order for substitute mints. Ah, so five ethel form Ethel three Octa known and again that O N e ending signifies key tone okay. S o B is a cyclic key tone so that the rules a little different. We just need to name the ring. Um, and so this is a five member ring, so it's gonna be a cyclo plantain, but again will change the ending to own, So it's gonna be Psychlo pent and known. Um, and then we need to number this ring such that the key tone is carbon number one. Um, and then we want the substitue INTs. The other substitutes toe have the lowest possible numbers. So that is gonna look like this Carbon one carbon to carbon three. Ah, And then remember, for alphabetical purposes, we ignore, uh, TERT. So, uh, the the beautiful takes precedence. So this is gonna be three hurt beautiful to me, Ethel Psychlo pent and own. So three turns beautiful to me, Ethel Psychlo Penton own. Okay. Ah, and then for see, we're back to a, uh, an open chain key tone. Um, see was given to us in ah, lettering notation. So I would always just rewrite that in skeletal notation because it's so much easier to see in to work with, um And so since this molecule was cement. You're gonna symmetric through the key tone. We can start numbering at either side. It doesn't matter it Either way that we do it. The key tones gonna be a carbon three. It's gonna be a pain tain derivative on. We're gonna have to method groups at carbons two and four, uh, or rather to metal groups each at carbons tuned for. And so this is gonna be As I said, a paint ain't derivative. So it'll be Penton known. Little free time to known because that's where the key toe news, Um and then we just need to account for those four methods. Substitute INTs. So it's gonna be too, too. Four four. Hedstrom. Ethel. Three. Pent unknown. Okay. All right, so that's it. Um, and these rules, if you need to review them, can be found immediately above this problem in the textbook. Ah, and that's the answer to Chapter 21. Problem number five

Now we'LL talk about problems seventy six from chapter twenty one here we're given four names of compounds and were asked to draw their structure. So these are our behinds and key tones. So the first name that were given his Hexham. Now okay, we know from the hex prefix that we're going to have six carbons, and we know from the suffix that it's going to be an olive so we can go ahead and draw our Alva hide on the right side. So we'LL draw our carbon chain and we know that an Alba hide is this carbon with a double bond. Oh, and also a hydrogen that has to be on the terminal the terminal carbon in the carbon chain to accommodate this hydrogen here. So let's go ahead and move to part B. Excuse me in this part were given to Penton own, so we know that this molecule has to be five carbons long because of the PMT prefix. And then because of the O. N e at the end is should be, eh, Skeeto And for key tones because they're on the inside of the carbon chain, we need to be given the position and here we're given the position as to so we can go ahead and put it on the second car and that's just a double bond. Oh, and then we write the rest of the carbon chain five. Five carbons long. So that's the structure of two Pantanal now for part C were given to metal Beauty. Now we know that the carbon chain should be four carbons long. We have an hour to hide and we have a metal group opposition to which should be the carbon right next to the Al ified. So we can go ahead and draw that on their left side. Now Hey, Jon, are Alba. Hi. We draw in our carbon which should have them Ethel Group And then we continue on with the rest of our carbon chain and that's a structure for part, see? And then lastly, they give us for hep to known. The hep part of this name tells us that it has seven Korans in the many suffix tells us that it is a key tone and that's the on ly functionality. So we draw in our hydrocarbon chain and position for we put our key tone and then we finish up the hydration hydrocarbon chain with seven carbons, and that's a structure for four


Similar Solved Questions

5 answers
Part 2: Determination ofthe Intensity ofthe Electric Field)Plot the voltmetcr reading V versus the distance d. 2) Find the slope from this graph. How is it related to the electric field?
Part 2: Determination ofthe Intensity ofthe Electric Field )Plot the voltmetcr reading V versus the distance d. 2) Find the slope from this graph. How is it related to the electric field?...
5 answers
HWT 6.2 v2: Problem 9 Prev Up Next(1 pt) Fina the volume of the solid generated by revolving the described region about the given axis:The region in the first quadrant enclosed by the curves y = 4r ad y = x2 rotated about:a. The :-axis:Answer:The y-axis: Answer:Note: You can earn partial credit on this problem:Preview AnswersSubmit Answers
HWT 6.2 v2: Problem 9 Prev Up Next (1 pt) Fina the volume of the solid generated by revolving the described region about the given axis: The region in the first quadrant enclosed by the curves y = 4r ad y = x2 rotated about: a. The :-axis: Answer: The y-axis: Answer: Note: You can earn partial credi...
3 answers
HlnnnlProblem 1+-10Asttal manulactunnataolm Ele ICkT MC €bcm)einutalWcuayntheauamar nunacn) tacmtntloalktt 4lne culcni plntsJn cDotdnaNneoa aenulemensalomnVmiFLANT LOCATION PentllccorninaIeSumIFAAISFERTENUcritond Iretad loc"ininrbuel bocalion *0t Ilins (ea Facdny (Rounj Yone JobatitMcimiacaatterencetcontherU ChalkmeHrotim *16INEt nclc (0 *aichEaPu Fnnaut
Hlnnnl Problem 1+-10 Asttal manulactunnataolm Ele ICkT MC € bcm)einutal Wcuaynt heauamar nunacn) tacmtnt loalktt 4lne culcni plnts Jn cDotdnaNneoa aenulemensalomn Vmi FLANT LOCATION Pentll ccorninaIeSum IFAAISFERTENU critond Iretad loc"ininr buel bocalion *0t Ilins (ea Facdny (Rounj Yone ...
5 answers
QUESTION 15Determine where the graph of the function f(x)=x 9x is concave upward and where it is concave downward, Also, find all inflection points of the function_CU on (-V5,_1, CD on (-x -l 'I(-V5,6v5)CU on (V,~|CD o(- ~.VSl 65,-613)CU on (0,00). CD on (~o, 0). IP (0, 0) CU on(-V5,VS) CD on x ~VS)and (V,x)IP (-v5, 6,3) and (V5 , 6,5)
QUESTION 15 Determine where the graph of the function f(x)=x 9x is concave upward and where it is concave downward, Also, find all inflection points of the function_ CU on (-V5,_1, CD on (-x -l 'I(-V5,6v5) CU on (V,~|CD o(- ~.VSl 65,-613) CU on (0,00). CD on (~o, 0). IP (0, 0) CU on(-V5,VS) CD ...
5 answers
Lab Conservation of Momentum Inelastic Collisions Activity 1 Moving cart hits stationary cart ad they attach on impact Equal masses Empty carts Cart Mass Velocity (m/s) Momentum (kg m/s) Kinetic Energy (J) (kg) Initial Final Initial Final Initial Final 0,1539 0-1504 pomis 0.21 Totals
Lab Conservation of Momentum Inelastic Collisions Activity 1 Moving cart hits stationary cart ad they attach on impact Equal masses Empty carts Cart Mass Velocity (m/s) Momentum (kg m/s) Kinetic Energy (J) (kg) Initial Final Initial Final Initial Final 0,1539 0-1504 pomis 0.21 Totals...
5 answers
What kind of waves do you think will travel down horizontal metal rod if you strike itsendvertically from above. (I mark] horizontally parallel to its length: (I mark]Determine the wavelength of a 5800 Hz sound wave traveling along an iron rod. (Bulk modulus of iron 100 x1O9 N/m" Density of iron 7.8xio} kg/m') (2 marks]
What kind of waves do you think will travel down horizontal metal rod if you strike its end vertically from above. (I mark] horizontally parallel to its length: (I mark] Determine the wavelength of a 5800 Hz sound wave traveling along an iron rod. (Bulk modulus of iron 100 x1O9 N/m" Density of ...
5 answers
(10 points) Use Vewton '$ method to find the third approximation Ts; to the root of the following equation 2 - 1] =0with the initial approximation € = 1
(10 points) Use Vewton '$ method to find the third approximation Ts; to the root of the following equation 2 - 1] =0 with the initial approximation € = 1...
5 answers
Question 15"To sterilize heat-sensitive solutions such as culture media, enzymes, and vaccines, one should use' filtration. dry heat an autoclave pasteurization low temperatures
Question 15 "To sterilize heat-sensitive solutions such as culture media, enzymes, and vaccines, one should use' filtration. dry heat an autoclave pasteurization low temperatures...
5 answers
A 300 60o 90o triangle has hypotenuse 48. What is the length of the shorter leg?
A 300 60o 90o triangle has hypotenuse 48. What is the length of the shorter leg?...
5 answers
3) Prove the following equation is true for all differentiable curves from (0,1) to (1,7), Or give an example showing it is false:sin(r) sin(ry) drcos(z) cos(ry) dyy cos(T) cos(ry) dr.
3) Prove the following equation is true for all differentiable curves from (0,1) to (1,7), Or give an example showing it is false: sin(r) sin(ry) dr cos(z) cos(ry) dy y cos(T) cos(ry) dr....
5 answers
Suppose is invertible. andL AB = AC. Show that B = C Suppose invertible. show that (2A) - 24-'
Suppose is invertible. andL AB = AC. Show that B = C Suppose invertible. show that (2A) - 24-'...
1 answers
Use the Multiplication Property of Probabilities. If $P(A)=0.3$ and $P(B | A)=0.6,$ find $P(A \cap B)$
Use the Multiplication Property of Probabilities. If $P(A)=0.3$ and $P(B | A)=0.6,$ find $P(A \cap B)$...
5 answers
4.3 g of Vitamin B12 is dissolved in 73.9 g of ether (C3H10O,molar mass = 74.12 g/mol) at 25C. The resulting vapor pressure ofthe solution was found to be 314 torr. Calculate the molar mass ofthis vitamin. The pressure of ether at 25C is 315 torr.
4.3 g of Vitamin B12 is dissolved in 73.9 g of ether (C3H10O, molar mass = 74.12 g/mol) at 25C. The resulting vapor pressure of the solution was found to be 314 torr. Calculate the molar mass of this vitamin. The pressure of ether at 25C is 315 torr....
5 answers
Question 71 pisDetermine the molarity of a solution formed by dissolving 12.5 gof NaCl inenough water to yield 4.5Lof solution:0.0784M0.0475 M7.84*10^-5 M4.75x10^-5MQuestion 81ptsHowe many Erams _ of CzHsOH (MM= 46.07 g/mol) are contained in 50.0mL of 0.180 M solution?230E CzHsOH0.415&C_HsOH415 BCzH;OH2303BC_HLOH
Question 7 1 pis Determine the molarity of a solution formed by dissolving 12.5 gof NaCl inenough water to yield 4.5Lof solution: 0.0784M 0.0475 M 7.84*10^-5 M 4.75x10^-5M Question 8 1pts Howe many Erams _ of CzHsOH (MM= 46.07 g/mol) are contained in 50.0mL of 0.180 M solution? 230E CzHsOH 0.415&...

-- 0.019945--