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The solubility of sodium chloride in water is due toion-dipole interactionH-bondsionic bondsdipole-dipole forces...

Question

The solubility of sodium chloride in water is due toion-dipole interactionH-bondsionic bondsdipole-dipole forces

The solubility of sodium chloride in water is due to ion-dipole interaction H-bonds ionic bonds dipole-dipole forces



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What types of intermolecular forces give rise to hydration shells in an aqueous solution of sodium chloride?

Answer for the question. All molecule self expression forces in them. Apart from it. If the molecule is polar, then it contains typo type all forces and hydrogen bombs exist if the molecule contains hydrogen and if that hydrogen atom is politically wanted to electron negative atom so engaged off production color rate he had production. Plowright is in. I am the compound with contains Okay, present you protection get I am end chlorine and I while water is polar hands in a mixture off Put a sham, Collaborate and water Yeah, I'm di Paul Forces and hydrogen bonds exist.

To describe how K. C. L. Dissolves in water and why ion disciple forces helped to bring the potassium chloride solid into solution. We need to understand what is happening between the water and the solid potassium chloride. There's a first a strong attraction between the potassium cat I and and the chloride. An ion. In order for this to dissolve as free potassium and chloride ions. The water molecules need to overcome this strong force of attraction. They can do that by surrounding the chloride with their partial positive ends. The partial positive ends of the water molecules are the hydrogen ins. These then come in and create these ion dipole forces the disciple of the water and the ion in this case chloride. If we get enough water molecules to come in and create the strong the create enough of an ion disciple attraction to overcome the ion ion attraction, then the chloride will come into solution, leaving behind the potassium which will then also be surrounded with water molecules, creating additional ion disciple forces of attraction. Where the negative ends of the water molecules are attracted to the positive potassium ion.

If we have silver chloride and recognize that it is not soluble in water, then what must be the relative strength of the inter molecular forces between the silver ion and the chloride ions and the water molecules? That is a force by itself as compared to the inter molecular forces between the water molecules themselves and the silver cat eye on and the chloride an ion in the solid. Well, if it's not going to dissolve, then that means the attractive forces between the cat I. And and anti on. Plus the attractive forces between the two water molecules is going to be greater, keeping both of them together so that they don't mix. Then the forces associated with them mixing, namely the silver combining with the water and the chloride being attracted to her, combining with the water. So essentially the answer is, these forces must be less than these forces.

All right, guys doing problem 26 of chapter 11 in chemistry 2017. No, first time closes over water. A small amount of energy must be added during solution information. It's not energetically favourable. So why is that a c l so soluble in water order? So when you're so look at this energy diagram. So when we have a reaction action, we go from one the energy state of reactions to the end to the energy state of our products. Bright crossing, the higher energy they can also be That's a practice. Be higher energy. Or they could be lower an energy if their prices are higher. And angie, the processes end of them inputting That means we have to input energy into ours. The energy of our system is increasing. If our from is there a lower energy that means energy is being released from her sister. However, you'll notice that in both these cases they have this bump here. This bump is no as our activation energy, energy. I'll just designate this as e a for every single reaction like your reactions and your products are not going to react out of nowhere. They you need to in put some energy into your reaction into input a small amount of energy into reaction just to just to get it going. It's kind of like, uh, like rolling the rolling the ball down the hill. The boat will roll by itself down a hill, but you gotta push it towards the edge for it to do that. So although that be the so even though your products are gonna be in a lower energy level when you dissolve an A C. L. U serve the input a small amount of initial energy A to past the activation energy energy barrier. There, you have to input some amount of energy just to start the reaction. But even though the overall process is favor, yes is favorable because even though you are increasing your energy when energy when this reaction occurs, you're you're making up for it by the total decrease in your energy when you form your products


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