5

Kx)=3x cos6xK()e((3x )...

Question

Kx)=3x cos6xK()e((3x )

Kx)=3x cos6x K()e ( (3x )



Answers

$3 x \cdot 3 x \cdot 3 x \cdot 3 x \cdot 3 x$

This problem asks us to multiply two by no meals The binomial that were given our X plus three and X minus three. We're gonna do this by repeated distribution. That means we're going to take the first binomial and distributed into the second. So that will look something like this. X plus three times eggs minus X plus three times three. Remember to keep your minus sign. Here. It's very important Dead. Either it's a minus Sign here or a plus sign and a negative three. We can't drop that. So now that we have, we've distributed this. We're gonna take these what we just distributed and no distribute again. This is the repeated part of repeated distribution. So expose three Times X is just going to be X squared plus three X. And I remember that we're subtracting this whole product, not just the first term. So minus three exports three times three is gonna be three x plus nine. And now to distribute that minus sign out, we'll have X squared plus three X minus three eggs minus nine. Now we just need to combine like terms and then we're done here are like terms are plus three x and minus three x of course, plus three Exit minus three X is just gonna equals zero. So those will cancel each other out, and we're just left with X squared minus nine, and that is our final answer.

So we have X minus three into X plus three. Here. These two are congregates. So this is just X squared minus nine.

And this problem we're being asked to simplify the given expression. So we have the quantity of three X. Being raised to the K. Power. Well remember three X. is a product and K is our experiment. So this is an example of our power of a product fool. And here's how it works. It says if we have the product eight times b. And let's say it's getting raised to the empower according to our rule, it says that we have to raise each part of that product to our exponents. So in other words, will have a being raised to the empower and be also has to get raised to the same exponents. So we can apply this to our problem because three eggs is a product. We're multiplying three times X. So if we use this rule, we have to raise both three and s to our exponents. So if we were going to rewrite this, we would first have to take three and raise it to the K power. And then we would have to multiply it by X rays to that same power of K. So our answer is three to the Cape Our times X to the K power.

Any number times its reciprocal on the opposite. Three times. 1/3. Just give us one. We bring down the variable X, and we don't need the one in front of X seven. Simpler. And through that we get it's just


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