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0l CainisFmunis 4msoft Tanentah;My NotcsAGk Yaur TnachctmanagemeImanan-e Ccmf?JetenttinzgJlan-icTencedSudeiesiCepMtc OcLY IneacioichenMezeume _dcllaMezelredMoIZtousard tan "m hakevallablethe marke:CrCFL2leCcrelme? surpIino the producars"Tetyelunit Dace2muicmMn-Mkouro your arevernea est cjar:consunutusF ccucer suipiusrltlctNeed Help?Ea FutddileJuliiit ~iGMvl ?iumePrisliz X4rd Yeiijr

0l Cainis Fmunis 4msoft Tanentah; My Notcs AGk Yaur Tnachct manageme Imanan-e Ccmf? Jetenttinzg Jlan-ic Tenced Sudei esiCep Mtc Oc LY Ine acioi chen Mezeume _ dclla Mezelred MoIZ tousard tan "m hake vallable the marke: CrCF L2le Ccrelme? surpI ino the producars" Tetyelunit Dace 2muicmMn- Mkouro your arever nea est cjar: consun utus F ccucer suipius rltlct Need Help? Ea Futddile Juliiit ~i GMvl ?iume Prisliz X4rd Yeiijr



Answers

Microcosmic salr ant horax are uscd in the idcntification of cations by dry rosts. They arc, respccrively (a) $\mathrm{Na}_{2} \mathrm{~B}_{A} \mathrm{O}_{7}$ and $\mathrm{NaNH}_{1} \mathrm{HPO}_{4}$ (b) $\mathrm{NaPO}_{3}$ and $\mathrm{NaBO}_{2}$ (c) $\mathrm{NaNI} 1, \mathrm{HPO}_{4} .411_{2} \mathrm{O}$ ant $\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{2}, 101 \mathrm{l}_{2} \mathrm{O}$ (d) $\mathrm{NaBO}_{2}$ sand $\mathrm{NaPO}_{3}$

As we know that, as we know that under root burk is equal to and is equal to reflective index is equal to reflective index, which is demands. And lace. Richard diamonds and diamonds and Elise went pretty so diamonds and so diamonds and will be equal to am not L not he not option D is the correct answer for this problem. I hope you understand the solution.

In this problem, I can write DDX in it see http CH two C 00 H. This compound in pageants of Cl two A red P. That to be dad reaction. It will give the compound edge, see http C h C L C. O AT and this compound in perchance of alcoholic kO edge. The hydro chlorination happened here and the compound formed the CH two double 1 C h c o egg. Therefore, according to the option of indeed correct option, the is correct answer. I hope you understand the solution.

In this problem, the salt Maybe K I add the salt age. Okay. I add potassium Qattan as potassium as potassium, get diane as potassium katyn in parts, in parts a violet in parts they violet colored to board X bead aged. Also. From this question, we can say that the correct answer will only be K I two Option A it corrected.

In this problem, I'm writing the reactions. So just look at it carefully. OK. FECN six came food, FT CN six plus six. He S CN k s c N will react to form, get to the f e SCN six and now I'm going to write the second reaction. They just look at it carefully Or FECL three. That's pretty careful. F E CN six, then it will give 54 F e CN six plus two old KCL. So option age correct here.


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