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(4) Find th: Valut o sinele ctupacitor to runice the three cmdiciurs the diagram What the potential diffcrence across Ihe 12 pF capacilorli ) the Ieft side ol the d...

Question

(4) Find th: Valut o sinele ctupacitor to runice the three cmdiciurs the diagram What the potential diffcrence across Ihe 12 pF capacilorli ) the Ieft side ol the diagram? (c)What Ahet charge un the 12 /F chpacitor(BH) to the far right side of the circuit? [JMFCA'TndJZNE

(4) Find th: Valut o sinele ctupacitor to runice the three cmdiciurs the diagram What the potential diffcrence across Ihe 12 pF capacilorli ) the Ieft side ol the diagram? (c)What Ahet charge un the 12 /F chpacitor(BH) to the far right side of the circuit? [JMFCA' Tnd JZNE



Answers

Find the potential at points $P_{1}, P_{2}, P_{3},$ and $P_{4}$ in the diagram due to the two given charges.

In this question. The circuit diagram is given in which the four capacitors are connected like this with an EMF of voltage fivefold. And it's a dollar. It's just is one. Uh huh. With an internal linguistics Here. I wish the one ambassador nine. This this is the circle. Yeah. Ireland are too our treat. And these are the capacitors and the capacitance C. So first of all we will learn the values we have given. He is faithful. Internal resistance of the M factory is one of them are too is for. Uh huh. Ireland is equal to three. Is equal to one or Okay and the capacitance of all the capacitors is given us three micro pepper. So first we will consider that in a steady state condition. In the steady state condition none of the current will be flowing to these capacitors only the current will be flowing towards the point in these points these two points only the prentice flowing through the resistance are too. So we will find the current would be equal to eat what? All right. Plus art. He's value is 5. 1 bless four. So we will have one M. M pare current will be flowing to the resistance or two. So we will find the potential go across the resistance as we is equal to Ir one into 4 is equal to for me four world is the potential difference across these two points once and cool this is the potential drop. So and we know that in this condition the charge Q. It's flowing from all the capacity. You consider that the same Judge Q. Is going in all the capacitors. So we will find the total potential US you by sea. Q B C Is equal to four. On that. We will get two. Q. Capacitance value is three microcredit equal to four. So from this we will get usually based six micro cooler. So on this answer, C. Is the right option. That is the Q6 microfiber charge would flow from all the capacitors. Thank you.

According to Joe, through some of the potential difference across the element in the circuit around any clothes. Forget movie view. That is the mission off. Luke. They're tabby physical studio. According to Jumpshare ruled the sum of all current into the junction in a market is because to some off the current, out off the junction in the circuit that permission in Got it. But the truth commission out buttered. Okay, Now what does that get? Diagram as shown in the figure by applying the no rule as junction rule, we can write to to I want plus gaiety Music was toe I toe and we can write I is you two minus even minus. I do are two minus. I want our one. Majestic was true. Deal you two minus I three rt miners I to our tow. It was 20 He want that? Even if the coastal three prime zero to do with the course traffic find the level are one is a close bullpen. Arms are to Are you Is it close to 20 home and are three in the close balls? Not be old. We have no I because I buy one last I three medical toe pence Levi, not dont I toe t minus 20 i to minus 10. I won in the courtroom Little six minus party I three minus 20 i to it was your deal after scoldings picket Ivan Intercoastal three by 110 MPs I do. It equals two one fight upon 110 MPs and I three it was to develop on 110 MPs. Okay, Therefore the sudden shot three by 11 10 amperes 15 by 11 10 ampere and 12 by 11 10 MPs. Now it will be part V. The potential difference A across the potential difference between a and B Delta b a If it was to be a minus, their baby tense, we can die. Jitter my nestles r two r two plus commission Ito and substitute of aloof current A for I to 20 only four through 15 by 110 a. M. Pierre for I to 20 own four r tau and explained Available for into hands, Dubbie, be It is a portal minus being by 110 MPR into dont own plus 6.0 cold and big it 3.27 world. Therefore, the potential difference between A and B is 3.27 world. Now, the potential difference between a envy with a different parts through even is with a different part through Even if Derrick up the baby is supposed to be a minus that baby we did the whole truth even. Plus I want our one. Okay, so you're 3.0 hold or even three by 110 ampere for I will intend home the distance for our fans. We get equine beetle at board, see by 110 and peer into 10 0 and bigger. 3.27 goals. Therefore, the given statement. This group No, the graph now the graph Portis location graph in different loop as shown no graph four location work you know will be like this. Here we have Bryant. If e be I think e it g and be here. We have good potential here. We have locations. No, The potential was the location Braga for different flutes. It grabbed. It is in the potential artists location Draft for different look as shown in figure. Thank you. Another graft. Yet here we have locations. Be be that's e won't be be that e see be be no one more graph being of between potential worsens Location graph for different blue Here we have, yes e the locations and prevention.

Hi the given problem here, there is a combination of resistors. The first one having a value of 50 home, then it is having a loo. The upper branch of the loop Is having two resistors in series Which are having the values for 40 home and 20 Home. The lower branch of this loop is also having two resistors in series which are having the values of 70 zero, Ohm and 20 home. Then There is one more resistance in series Having a value of 20 home. And at last a battery providing an e M f of 120 world. Now, in the first part of the problem we have to find the current coming out of this battery. Let it be I if we mark these terminals of the loop as A and B, then the same current will be divided into two parts in this loop I want in the upper branch and I to India lower branch. In the first part of the problem, we have to find the value of this I for which we will have to find the net resistance of this combination. So as the Upper two resistors are in Syria's combination here. This to what. So we will assume their net resistance to b. r. s. one. Similarly here, these two resistors are also in cities. Maybe I assume them to be RS2. So simply their values will be given by for R. S. One disease. 40 plus 20. Oh, means it comes out to be 60. Oh, similarly for R. S. to this is 70 plus 20 on Which comes out to be 90 home. Now these two are Essman and Rs two are in parallel. So they're parallel combination means resistance between the terminals A and B will be given by the rules of parallel accommodation. Product of the two resistors in numerator and their addition in the denominator. So here it is 60 on, Multiplied by 90 home and divided by 60 plus 90 home canceling this one on. Finally we get this are ready to be equal to 100. This is just 36. Oh Now this our baby is in series with 50 and 2000. So finally effective resistance of this combination is given by 20 Home Plus 50 home plus. This are a b. Which we have found to be 36.0 Oh and it comes out to be 106 homes. Therefore current given by the battery. Using homes law I is equal to we buy our effective so this is I is equal to 120 volt divided by 106 home. So the answer for the first part of the problem is one 13 mps. No. In the second part of this problem we have to find the potential drop taking place across the parallel combination means across this A. B. For which as the current remains the same in series combination. So the current passing through this parallel combination, I E B Will be actually equal to the total circuit current means 1.13 and here therefore, potential job taking place across this parallel combination means we a be using again Homes Law that will be given by I A B. Multiplied by R.A.B. resistance of this parallel combination means this is 1.13 Multiplied by 36. Oh so Finally this V8 potential drop taking place across this parallel combination comes out to be 40.8 wall, which is the answer for the second part of this problem. Now, in the third part of the problem we have to find the currents passing through the upper branch of the loop and the lower branch of the loop. So for this we will use the concept as potential remains same in parallel, so the upper and lower branches of the little, both will be having the same potential across them. Therefore I won. The current passing through upper branch will be given by the the same potential Divided by RS1. It's not resistance. So here it is 40.8 divided by 60. So finally decide when comes out to be 0.68 MP. Here, first to answer for the third part of the problem and then through the lower branch I do is equal to same B. A. B. But divided by RS2. So this is 40.8 divided by 90 oh. Hence Decances who comes out with 0.4 by NPR second answer for that 3rd part of this problem. Finally, We have to find in the 4th part of the problem. The power consumed in 40 home resistor. So that power consumed will be given by physical too. I square into our for I this will be I two. Sorry, this will be Ivan. The current passing to 40 on register when the square into our So for Ivan disease 0.68 to the whole square Multiplied by 40. So finally this power consumed comes out to be 18 fight what? Which becomes answer for the 4th and the last part of this problem. Thank you.

So we have barred Who else, Michael, fatter over here on then we have to us onto, as in paradise. So that is equivalent to two other Over here and in battle. They adds up. So that becomes 24. So now the equivalent capacity over here is one of what he says. That's one of about 24 in verse. Of that, it was eight Michael Farrell. Now, since in this diagram that said this point to be a on this point is be on this got this 0.2 b. C. So we will have the potential difference. We will have some bull just over here on with some Buddhist over here. Clearly what did that? Because the 12 home register, the Kappas eater, is just because the capacitance is this we will have. Let's say we have the potential difference over here. Is everyone on potential different That series we do now. The charge across name is the same. So we know that you it was CV It Wes 12 times you are, it was 24 times we too. So we have we want equals to veto. However, if you want us veto is the battery that is being connected with these. Ready? Fine Ford. So we have bought using video. It was half everyone. We have got 1.5. You are. It was 25 volt. So we want comes out to be 25 times two is 50/3 fold equals 16.67 world.


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