Okay, This is a question about power in electric circuits. So we're told that there's a heating element which is basically just to resist her and it has a resistance of 5.3 owns and a current with 25 cents is run through it for nine hours a day for the entirety of january, which is 31 days. And we're told that the price, which I'll uh do not with the lower case P. Is $12 or 12 cents her kilowatt hour. So we're supposed to find the total cost uh to run the heating element. So the cost is going to be uh the amount of two hours um times the price particular are so killer, ours is gonna be power times time. Uh powers and lots of course in time in hours. And then we're going to divide by process, which is dollars her p times t which is going to give us units of dollars. All right. So we have the price uh and we can figure out the power and we also need to figure out the time. The time is simple. That's just going to be 31 days times my hours, which is 279 hours. Uh, and power we know is equal to a squared times are and were given both I and our so we can play those in. This gives us three point 3125 kilowatt a lot. So, uh, to find our tool, um, energy use, we're gonna multiply this by this and we're just gonna divide by the price. Uh, so the cost is going to be 100 and $10 and 90 cents. That's true. What it works out to you when we plug in, uh, this for power this for time and put the price and five both price and move on.