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Which of the following aqueous solutions has the smallest ATfreezing'0.227 m AgNOz0.468 m CaClz0.310 m glycerine (CzHgO3), a non-volatile, non-electrolyte0.097...

Question

Which of the following aqueous solutions has the smallest ATfreezing'0.227 m AgNOz0.468 m CaClz0.310 m glycerine (CzHgO3), a non-volatile, non-electrolyte0.0975 m Al(C,H;02)3

Which of the following aqueous solutions has the smallest ATfreezing' 0.227 m AgNOz 0.468 m CaClz 0.310 m glycerine (CzHgO3), a non-volatile, non-electrolyte 0.0975 m Al(C,H;02)3



Answers

Consider the following aqueous solutions: (i) $0.20 m \mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH}$ (nonvolatile, nonelectrolyte); (ii) 0.10 $m$ CaCl_i (iii) 0.12 $m$ KBr; and (iv) $0.12 \mathrm{m} \mathrm{Na}_{2} \mathrm{SO}_{4}$ (a) Which solution has the highest boiling point? (b) Which solution has the lowest freezing point? (c) Which solution has the highest water vapor pressure?

Problem 72 order of decreasing prison point host zero point 030 mm Penal after that zero point 040 M. Glycerine and Equals to zero 0 to 0 mm potassium bromide. Okay, fennel is very slightly organized in water. Okay, But not enough to mess the number of particles in a 0.040 am glittering solution. And the potassium bromide solution is 0.040 amateur particle. So it had some painting point at 0.40 and glistening, which is non electrolyte. Okay, this is our final answer for this question.

Okay, problem 72. We are arranging the following quays solutions. Um, in order of decreasing freezing point. So when Riyadh These the water received, We have glass ring and phenol, but since those air not made of ions, they're not going to associate and further so we're only just gonna have the original given for the mill adity of used to. Okay, so for fashion bromide, however, it does associate further when you put it in water. Okay, so does associates into papers. And your minus okay. And each of those ions would be 0.20 k And when we put that in water, we had those and it gives us a total of zero point zero for zero m. Okay, so now here's the point where we used the freezing point Depression constant for water. So KF the f is 1.86 degrees Sasha's per m for water. Okay, so at this point, in order to get the, um, freezing point depression, we multiply. Okay, uh, by being Mileti. So let's start with glycerine. Put it down here. No glass ring. We have 1.86. The grease saw cious for, um times 0.40 So that gives us zero point 074 degrees Celsius. Next, we have KBR. So same thing 1.86 degrees sauces. We're, um, times the morality of KBR, which is also 0.40 m, which means we'll get the same Answer it as glycerine. Right. You get 0.74 Last one. We hear we got phenol, which I'm just gonna put up here in all. So we got 1.86 the grease, luscious. Burn em and we multiply it by zero point 030 Um, which gives us 0.56 degrees sauces. OK, so in order to we have the three answers. So we're arranging them in decreasing freezing point oppression. So all these numbers would be subtracted from 100. Okay, so that means after subtracting them from 100 your highest freezing point will be where will be for the nol? Okay, because you're subtracting a smaller value. So if in all would be number one and then you'll have glassine and KBR equal in position to so it would be in all has a greater freezing point. Done. Glycerine, which will be equal to give the art

In this problem were given four atheist solutions and asked to determine which has the highest boiling point, lowest freezing point and highest water vapor pressure. We can start first by determining the effective concentration of each of our Equus solutions, starting first with their ethylene glycol. We know that this is a non electrolyte, which means that the effective concentration will be equal to the concentration we were given in the problem statement. Next, when we look at our calcium chloride, we see that this dissociates into three different ions. So we have a factor of three that we can multiply the morality by and this gives us an effective concentration equal to 0.3. We can repeat this with our potassium bromide and see that it associates into two i on. So we have a factor of two and therefore the effective concentration will be equal 2.24 Finally, when we look at our sodium sulfate here we see that it also dissociates into three i on. So we have a factor of three that we're going to multiply by and this gives us an overall effective concentration equal 2.36 Now that we've determined all of our effective concentrations. We can go ahead and categorize them to determine the highest boiling point, lowest freezing point and highest water vapor pressure, starting with the highest boiling point. We see if this correlates with the highest effective concentration. So this means that our sodium sulfate solution will have the highest boiling point. And similarly, when we look at our lowest freezing point, this also corresponds to the highest effective concentration. So again, our sodium selfie will have the lowest freezing point. And finally, our highest water vapor pressure correlates with lowest effective concentration. So if we look at that, that means that our ethylene glycol is going to have the highest vapor pressure of water.


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