Question
SURVEY ADMINISTERED To THE TECHNICAL STAFF AT AN ELECTRONIC FIRM INDICATED THAT 23 INDIVIDUALS THOUGHT THEY TERE OVERPAID, 78 THOUGHT THEY WERE ADEQUATELY PAID, AND 63 THOUGHT THEY WERE UNDERPAID IF PERSON IS SELECTED AT RANDOM, WHAT IS THE PROBABILITY THAT THE PERSON SELECTED BELIEVES To BE ADEQUATELY PAIDTHE PROBABILITY THAT THE FOOTBALL TEAM WIN GAME IS IF THE TEAM HAS TWO GAMES THIS WEEK ASSUMING INDEPENDENCE OF EVENTS , WHAT IS THE PROBABILITY THAT THE TEAM WILL LOOSE BOTH GAMES?
SURVEY ADMINISTERED To THE TECHNICAL STAFF AT AN ELECTRONIC FIRM INDICATED THAT 23 INDIVIDUALS THOUGHT THEY TERE OVERPAID, 78 THOUGHT THEY WERE ADEQUATELY PAID, AND 63 THOUGHT THEY WERE UNDERPAID IF PERSON IS SELECTED AT RANDOM, WHAT IS THE PROBABILITY THAT THE PERSON SELECTED BELIEVES To BE ADEQUATELY PAID THE PROBABILITY THAT THE FOOTBALL TEAM WIN GAME IS IF THE TEAM HAS TWO GAMES THIS WEEK ASSUMING INDEPENDENCE OF EVENTS , WHAT IS THE PROBABILITY THAT THE TEAM WILL LOOSE BOTH GAMES?
Answers
A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are independent, what is the probability the team wins all its conference games?
All right. This question deals was sampling from a distribution of Size 10 where seven people prefer football while three prefer basketball. So first it wants for party the probability that a sample of two people out of three prefer football and that plugging into her hyper geometric formula we have. They're seven people that like football, and we want two of them. And then there are three people that prefer basketball, and we want one of them and they're 10 people, and we're choosing three of them for our sample. And that is 0.52 five. And then Part B asks, What is the probability that X equals two or X equals three, which is the same thing as P of two, which we already know, plus p of three, Which they're seven. That like football, we want three of them. There are three people that prefer basketball. We want zero of them and there are 10 people to pick from and we want three of them. And that works out to be 0.8167 because recall that this is 0.5 to 5, as calculated in party
Hello students. So, in the screaming question, we have to find the probability that belongs that the employee whose paycheck is lost belongs to the research department. So, I have made this table of the by collecting the data of the employees of the company. So let us uh answer according to the stable. So the total number of employees in research department. As we can see 54. All right, so, and the total number of employees in the company is 50 polite. We can say we can see so that E represents the event or that the employer whose paycheck is lost belong to the research department. The P equals two 54 upon total number. That is 2 52. All right. We will get three upon 14. So, that's the probability that the employee whose paycheck is lost along the We sold department is three x 14. And hands. It is our answer. Thank you.
Uh huh 79 of adults need eyesight correction according to data. If we select randomly a sample of 20 adults, What is the probability that at least 19 of them the eyesight correction To start off with, we need to make a note of the fact that this is a binomial distribution with n equals 20 trials and probably leave success .79 that we identify someone who needs eyesight correction. So because it's binomial we can use the binomial probability formula to solve this problem where P of X is given by the formula on the right note that Kfx determines the probability you find exactly X successes and end trials. So the probability of finding at least 19 means we're looking for P That acts is greater than or equal to 19. That means that both 19 and 20 people with Isaac correction will satisfy this problem. So we can re express this is the probability of 19 plus. The probability of 20 plugging in for B p f yields the following. And this simplifies down to our final evolution of 0.0566. This particular probability can be thought of as significantly high Because there's a one in 20 chance that 19 or 20 people out of 20 need I say correction, which is pretty astounding probability for the fact that all of these people need eyesight correction are all but one.
Are. So the employees of a company working six departments, 31 on Sil 31 our SOS and ah 54 are in the research. 42 are in the market team and 20 or the engineer e in far underneath. 47. Well, it's not the final. It's Ah, second final. Actually, it's in the finance. And finally, we have 58 that is, in ah, production department. All right, So which means the total number of employees of this company will be 31 plus 54 plus 42 plus 20 plus 47 plus 58 which is 252 Right? So that's the total number of employees in the company. So now one employee paycheck is lost. So we want to know that What is the probability that the employee works in the research department? Right? So we want to know that if it's in the research department, so we have 252 people in the department and 54 out of this 252 is from research Apartment RS. So the probability that that one person is from the research department will be 54 over 100 2 152 which, after simplifying will be three over 14