5

I Utta ! 1 11331 Acl uliug > uneIiin oirl umd tstccn #WuI...

Question

I Utta ! 1 11331 Acl uliug > uneIiin oirl umd tstccn #WuI

i Utta ! 1 1 1 331 Acl uliug > uneIiin oirl umd tstccn #WuI



Answers

$\left[ \begin{array}{lll}{1} & {1} & {1} \\ {1} & {2} & {3} \\ {0} & {1} & {1}\end{array}\right]$

In discussion. We need to find out the universal forgiven metrics A which is a three by three automatics having the first row elements 111 in second row, one minus 10 in third row 12 and three. Ah So first of all we will consider the metrics Here a metrics which is 111, 1 -10 one 23. And here Identity Medics of Order 3, 100 010 001. And so first we will now use the row reduction method to convert these medics to identity. And this one will be converted to another metrics by applying same operations. Then this will be the universe of these metrics. So first of all we will apply the operations on, I wrote to Andrew three as the road to will store wrote to Minister Through 2- through one And the road three will store Row 3- Roman. So here we will get the robot will be as same as it is and road to will be zero to minus Robin. So one minus 10 minus one minus one minus two. 0 -1 will be here minus one. For oh 31 minus one will be zero to minus one will be 13 minus one will be too. And for this identity metrics we will have 100 here and zero minus one will be here minus one as a zero to minus seven. And now here's one minus zero will be 10 minus zero will be zero. Now for oh 303 minus Robin will be zero minus one is minus one ba zero minus 00, 1 0 has one. See So we got the medics after applying these operations now we will apply the operation on, I wrote one as Robin minus row three. That is our 1 -R3. So we will get here as roman stores Are 1- Artery And we will get here as 1 0 will be 1, -1 will be zero and 1 -2 will become -1. And here's second row as it is zero minus two minus one, 012. No for for this metrics we will get here as when one minus -1. This will become 1-plus 1 which is to hear and two 0 0 will become 0, -1 will be -1. And here this second Rintaro has seen -1, 1, 0 And -101. Now we will apply the operation on row three as rotary stores. Ah Twice of rotary plus the road to has twice of row three plus throw to. We will get here as First row same 1, -1. And here a second role also same 0 -2 and -1 for rotary, we will get twice of rotary will be twice of zero plus against zero. So this will become zero Now, twice off rotary will tour price of one plus minus of two. Twice someone will be to -2 will become zero. And here twice off to will be four and a plus plus or minus one will be four minus one, that is three. And for this metrics the faster and second drug will be same. There is 20-1 And -1. 10 here minus one. And minus When ties of -1 will be -2 plus Of -1 will become -2 -1. That is -3. Now twice of zero plus one will be one only and twice of one plus zero. This will become too Yeah. Now applying the operation in rocketry as Rotary will store one by 3rd off or a tree. This will Result into here has 1, -1 And 0 -2 -1. And here this will become 00 and one x 33 will be one. And for this medics this will become 2, -1 -1, 1, 0. And my when my third off -3 will be here minus one and here one x 3 And he had to buy three. So we got this metric says And now we will apply the operation to row one and row two. As the Robin will store Robin plus row three and wrote to will store Rodeo Plus Row three. Now this will result into the metrics one plus zero will be 10 plus zero will be zero and minus one plus one will be zero. And here zero plus zero will be zero minus two plus zero will be minus two and minus one plus one will be against zero. Here are 001. And for these metrics this will become R two Plus -1. There will be 2 -1 which is one now zero Plus one x 3. This will become one x 3 And my husband plus two x 3. This will become a uh minus three plus 2/3. That will be minus 1/2. And here for a road to this will become uh minus one plus minus one. Again minus one minus one will be minus two when Plus one x 3. This will become four x 3 and zero plus two by three will become two by three. Now for rotary wing same minus 11 by three And two x 3. We got this. Magic says this. Now We will divide the road two x -2. So Rhoda will store minus half of rodeo. So this will become 100 0 -2 divided by -2 will become here as one and here zero 001. This became the identity medics. And here this will become one, 1/3 -1/2. Yeah this will become -2/-2 will be one, four x 3 divided by our multiplied by -1 but it will be -2 x three. And here to buy three multiplied by minus one by two will be -1 x three. Here being the rotary a same -1, 1 x three And two x 3. So we got this metrics as identity and hence this matters must be the university of metrics. A. So a universe will be called to Mavericks one, 1/3 -1/3. Here one -2/3. Yeah -1/3. And here -1, one over T. And to over three. So we got the metrics mhm. Which is the universe of metrics. E no we will we will check whether these metrics is character or not correct universe or not By multiplying these two metrics. A if we get the identity matrix then it is correct inverse of medics. So now we will multiply medics a to a universe as the metrics. He was 1111 minus 10 and 123. So one 11. Run My next 10. And here is 123. Multiplying this to the universe. What we got in the last step. This was one, 1/3 -1/3. And here 1 -2/3 -1/3 minus one. Von over three and 2 or three. Now we will multiply these mattresses. So by multiplying the first row to the first column of these metrics we will get here as eight times a universe will be called to one times one will be here one plus Here one times 1 again, one and one times minus one will be minus one. So this will become one plus one minus one. This will become one. Only normal deploying first road to the second column of these metrics. We will get one times one by three years one by three and uh one times minus two by three will be minus two by three and one times one x 3. This will become plus one x 3. So this will result into two x 3 -2 x three, which will be zero. Now by deploying the first row to the third column of this metric. So this will become one times minus one by three as minus one by three. One times minus one by three will be again minus one by 31 times two by three will be plus two by three. This will again result to minus two by three plus two or three. This will be zero. Now multiplying these same way as we multiply the first. True to the three columns of the universe of metrics. A. We will multiply second road to these three columns and we will get three elements of this second row, which will will be 01 and zero. Similarly for this hard road, we will get zero, zero and 1. We can check. So we got the product of metrics A and uh universe which is an identity matrix of order three, So eight times a university's identity medics of Order tea.

In discussion, we need to find out the universe of the given metrics by using roll reduction method, the given matrixes equals two, which is a three by three matrix having the elements of Castro as one minus one, three zero in the second row, 013. And in the third row, 11 and one. So first of all, we will consider the metrics mm Having a metrics and identity matrix as follows. 1 -1, three 013, 111. And here is the identity matrix of order three, 100 010 001. Now we will use row reduction method to reduce the left hand side metrics to the identity matrix and uh the right hand side metrics. Whatever we will uh Garda metrics by using the same row operations as we will apply on the left hand side and the metrics we will get at the right hand side will be the universe of these metrics. So, first of all, we will use the row operation for uh and for these metrics as Robin stores Robin minus road to. And now by this operation we will get 1 0, it will be 1 -1 one. This will become -2. Here are 3 -3 will be zero. Yeah, these two rows will be as it is 01 and three. Here is 1 1, 1 here on this identity matrix. The change will be here are one minus Otto. This will become 1 0, has 1, -1 will be -1 and 0 0 will be zero And he has 010. And now he has 00 and one. Now we will use the row operation on the road 3rd as artie stores. I'll C -R. one. So here the road operation will be our three stores are three minus R. One. And we will get here is faster and second role will be unchanged. So here this will be zero And one and 3. And in our three this will be 1 -1 which will be zero. And here one minus minus two. This will become one plus two. That will be three here and 1 0 will be one for this identity metrics. The first two rows will be same and here in the third row this will become zero minus one. This will be minus one, zero minus of minus one. This will be plus one and one minus zero will be one. Now apply operation to the road to as I wrote to his stores, I wrote to our two tries of artery and this will give here is the metrics. This will become faster, will be seen one minus 20. And in second or this will become zero minus tries of zero will be zero and one minus tries of three. This will be one minus nine which is minus eight. He had 3- tries of when this will be 3 -3 which is zero. Aarti will be as same as it is. So this will be 03 and one. And here in the identity matics for struggle be the same. Uh And in second row this will become zero minus tries of minus one. This will become zero minus of minus three which will be plus three and one minus tries of one. This will be one minus three which is minus two. This will be zero minus try someone. This will be minus street. Tomorrow will be the same. It is ah So this will become here now we will apply the operation uh on route Ruben as Ruben stores Arvind -1 x 4th of Our two. So this will store Are one. Will store are one minus one x 4th of Our Do. And hence we will get these metrics as one minus one by fourth of zero will be one minus two minus one. Fourth of minus it. This will become minus two plus to this will be zero and he has zero minus one by fourth of zero will be zero And this is 0 -8 and zero Here in the 3rd row, zero 31. And here in the identity matrix we will get one minus one by fourth of three. This will become one minus three by four which will be one by four and minus one minus of -1 by 4th of Well done by 4th of -2. This will become -1 and plus one x 2, that will be -1 over to only. And here the you know minus ah minus one by zero minus one by fourth of minus street. This will become Plus 3/4 And R two and R three will be will remain the same 3 -2 and -3 Here -1, 1 and one. Now we will use raw operation in row two, row two will store -1/8 of Rodeo. And this will give Here, Robin will be unchanged. This will be 100. And here this will be 0 -8/1 -8 times R -1 over it will give it one and this will be zero. And here in the top 003, one On this identity metrics, this will be 1/4 minus 1/2 and your 3/4. And this will become -3/8. So this will be -3/8 -2/-8 will be -1/4 And -3 times minus 1/8. This will become 3/8. And here in our series will be -1, 1 and one. Now we will apply row operation in the rotary, the rotary stores, row three minus tries of road to. And this will uh you Here these metrics will become 100 and here 010 in rotary. This will become zero minus tries of zero will be 03 minus five. Someone will be three minus 301 minus three times zero will be one. This and here in this uh medics, this will become 1/4 -1/2 3/4 -3/8, 1/4 and 3/8. And in rotary this will become -1 minus tries of minus trio it, this will be gone 1/8. And here uh 1- tries of 1/4. This will become AH 1/4. And here 1- tries off 3/8. This will become -1 over it. So we got these metrics uh transformed to the identity matrix and therefore these metrics on the right hand side must be the universe of the given metrics. A. So we got the universe of metrics A. Which is as follows universities, Medics having elements 1/4 minus 1/2, 3/4 -3/8, 1/4, 3/8, one over it. 1/4. And my next 1/8. So this is the university of the given metrics. Now we can check whether this in versus character, not by multiplying this to the metrics. A And if we get the metrics identity metrics of already then this is the correct inverse of that metrics. So now we will multiply metrics 8 to a universe. And we know the metrics is uh having the elements 1 -1, 3 In the 2nd row, 0, 1 and three In two, 01, one and 1 In the universe. This is 1/4 minus 1/2, 3/4 -3/8, 1/4 to over eight Here, 1/8, 1/4 and my next 1/8. Now, by multiplying first row of this aim attacks to the first column of a universe. We will get eight times saying verses Here. This will be one times one x 4 will be one by four. I'm solving this only this right hand side. The calculations are here, so one times one by four will be won by four only Plus -1 times -3 by it will be Plus T by eight and three times one x 8 will be again plus 3/8. And by adding these, we will get here eight x 8, this will be one. So His first element will be one. And now multiplying fast road to the second column of this matter. We will get at one times minus one by two, which will be minus 1/2 And -1, times one x 4. This will become -1/4 and uh three times 1/4. This will be plus three over four. And here we will get minus 3/4 plus three before which will be zero. So the second element here will be zero. And normally applying first row to the third column of cosmetics, we will get one times three by four, which will be three by four and minus one. Times three by eight will be minus three by eight and three times -1 by it will be uh minus tree by it. And by adding these we will get 08, that will be against zero. So the start element will be zero and multiplying similarly at the other rows to the other columns of these matters. We will get the elements here as uh zero 10 From 001. So this is the identity matrix we got by multiplying here to the universe. So here we verified that the universe is the correct inverse of matrix A. I hope all of you go discussion. Thank you.

In discussion. We need to find out the universal forgiven metrics A which is three by three matrix having the entries in first. True as 111 in second row. As 102 in third row as one minus one and one. So first of all we will consider the metrics as the medics of a here 111 And 102 And 1 -11. And with the identity medics of uh order three. This will be 100 010 And 001. Now we will use the road reduction method to convert this a metrics to the identity matrix and uh these metrics, this identity metrics to metrics whatever it comes, uh applying the same operation, what we apply to these a metrics. So first of all we will apply the operation for the road to As wrote to Bill Store, wrote to -3. So we'll get here as fast through same as it was one, And here 1 -1 are 2 -1 will produce 1 -1. is zero 0 -1. Here -1 and 2 -1. Ah as one. So Archie will be same as 1 -11. And for this identity metrics this will be one 00 and 40 to 0 minus one will be minus one. Here, one minus zero will be 10 minus zero will be zero. This will be Taro as same. 001. Now we got these metrics. Now we will apply uh the operation in Robin which we can apply Iran stores R n minus R. Two. So this will be are we in stores are one minus Arto and what we will get here as one minus zero will be one and one minus of minus one. Well will become one plus one which is to And 1 -1 will be zero. And this here these two rows are same. Do you know my next 1? one And 1 -1 1 for this Identity Matic this will become one minus of minus one will become one plus one which is to And 0 -1 will become -1. Do you know zero will be one and other to Rosa's saying it well -110001. So we got this metrics now we will apply the operation ah to the road three as our three minus R. Three stores are three minus R one. So we will get rotary stores R. 03 Rohan. And we will get here as 1- zero as the first true as it was 0 -11. And here 1 -1 will become zero -1 -2 will become -3 and 1 0 will be one here. So And for these identity metrics R one and R two has seen two minus 10 minus 110. And here zero minus two this will become minus two and zero minus of minus one will become plus one And 1 -1 0 will be one only. So we got these metrics are here now we will apply operation too. Medics are too as a to minus R. T. So we will get we will get here our two minus R. Two stores are two minus R. Three and we will get this. Merrick says 1 to 0. And here zero minus zero will be zero minus one minus of minus three will become minus one plus three. That is to and one minus one will be zero for third row, this will be zero minus three and one. And for this identity metrics Sorry these metrics we will get our two minus R. Three and first two will be the same as two minus 10 and minus one minus of minus two will be minus one plus two which will be one, 1 -1. This will become zero and 0 -1 will be minus one. Tito has seen -21. Right now Now we will apply the operation in a row are one which will be our urban stores are 1 -22 and we will get this metric says one minus zero will be one to minus two, will be 00 minus zero will be zero and second row as it is 0 to 0 and same. Taro 0 -31. And for this matics we will apply our one Minnesota which is two minus one will be one minus one minus zero will be minus 10 minus of minus one will be plus one And other two rows remaining same 10 -1. Ar minus two 11. Now we will apply the operation to the road to which will be our two stores half of our two. So we will apply this operation to road to and we will get here as in the first row remaining same 100 2nd, row zero by two will be 02 by two will be one and zero by two will be zero again Here 0 -3 and one. And this for these medics this will be ah 1 -1 and one In the 2nd row. This will be one x 2. The eyes road to is divided by two and he has zero by two will be zero and here minus one by two For the row three this will be -2, 1 and one. So now we will apply the operation to row three which will be I wrote three stores. Our three stores are three plus triceps are too and here we will get no one has seen 100 and wrote to also same 010 in row three. We will get zero plus tries of zero will be zero minus three plus try someone will be minus three plus three which is zero and one plus three tries of zero will be one. So we got this and for these matters we will get faster and second row Aseem one minus 11 half, zero and minus half. Now we will apply This operation to row three as -2 Plus tries of half. So this will be -2 plus three by two. So we will get here as -1 x two. And now for this element we will get one plus price of zero. So this will be one only. And here one plus tress of minus one by two. So this will be one minus three by two. So one minus three by two will be again minus one by two. So this will be -1 x two. Now we got these metrics and now we got this a matter is converted to identity metrics. And does this metrics must be inverse of matrix. A. So in verse of medics A should be a university calls to here one minus 11 And one x 2. Zero -1 x two. Here -1 x two. one and -1 x two. So this must be the universe of metrics. A. Now we will verify whether it is correct or not by multiplying it to metrics A. Ah We got the universe of medics. E Now multiplying the metrics 8 2 metrics. Universe. We must get the identity matrix. So here medics should be uh medics is 1, 1, 1 and 102 111102. And in the third road is one minus 11, 1 -11. And we got the medics universes one minus one fine. And here 1/2, 0. My next went over to And here -1 over to one and -1/2. Now we will multiply these medics to universe. First of all we will multiply first road to the americans to the first column of medics universe. So we will get here as uh one times one. So this will be one plus one times half. This will be plus half and one times minus off. So this will be minus off. So this will become one here and now we will multiply first through to the second column of universe. 1st 12, 8 to the second column of the universe. This will become one times minus one. So this will be one times minus one will be minus one. one. Time 0 will be plus zero and one times one will be plus one. So minus one plus zero plus one will be will result to zero. Now multiplying this first row to the third column of universe. So we will get one times one will be plus one. One times minus half will result into minus half and one times again minus half. So this will be minus half. So one minus half minus half will result in 20. Now the multiplying similarly the 2nd row of the metrics to the university. Subsequently by column one, column two and column tree, we will get here as zero And here one and here zero. And multiplying similarly 3rd row to the all, all these three columns of medics universe. We will get zero here and zero and 1 here. So we got the product of a and the universe as an identity matrix, so we got a dot universe as identity matrix of order, etc. So we verified that universe is the correct universe of metrics. E I hope all of you got discussion. Thank you.

To find these two matrices together. Here. First thing we need to do is check the dimensions will work. Okay? First matrix we've got is two rows three columns. That's a two by three. The second matrix is a three row one column matrix. These inner two dimensions have to match which they do. That means is a resulting matrix will be dimension the outer dimensions. Okay, So we're gonna have to buy one. Matrix is our answer just two spots here. Okay, we'll fill in the first spot. This is gonna be row one. Column one. Okay, so everything in row one thinks everything in column one negative one times six plus zero times negative four plus seven. Thanks one. Okay, this should give us negative six plus zero plus seven. That should give us a one in that first little spot right there. Okay, The second guy this is gonna be row two column one. Okay, so we're gonna take everything in row two times that same column right there. So three times six less negative five that was negative for plus two times one spent 18 plus 20 plus two should give us 40. Okay? So one in the first row, 40 in the second round, and that is the result of this modification.


Similar Solved Questions

5 answers
Eithuet give AH CIAHexplain why the follownguraiule4 5nontruangular MLTX wilnDiv0s6x6 elimination matrix applicdl thc matrix whosc firt column is [" in order to elirinate all entries under its first pivotAn invertible matrix with 4t least one of its eigenvalueFcur linecrly independent vectors in R'eguelues ce af wich Dezeztedl Je} R3* '"zir 7izh tc
Eithuet give AH CIAH explain why the followng uraiule 4 5 nontruangular MLTX wiln Div0s 6x6 elimination matrix applicdl thc matrix whosc firt column is [" in order to elirinate all entries under its first pivot An invertible matrix with 4t least one of its eigenvalue Fcur linecrly independent v...
5 answers
Use Cramer's Rule to solve (if possible) the system of Iinear equations_ (If not possible, enter IMPOSSIBLE: )4x1 2X1 + 2X2 Sx1 2x23X3 6X3(Xi, Xz, Xs) =
Use Cramer's Rule to solve (if possible) the system of Iinear equations_ (If not possible, enter IMPOSSIBLE: ) 4x1 2X1 + 2X2 Sx1 2x2 3X3 6X3 (Xi, Xz, Xs) =...
5 answers
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y Then find the area of the region: y = 7x2 , y = c? + 3PreviewPoints possible: 1Licens
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y Then find the area of the region: y = 7x2 , y = c? + 3 Preview Points possible: 1 Licens...
5 answers
AMERICAN UNIVERSITYGhcn'f22 6vv #drdy Revnetne Inepral olt cocnn;n Evalvatc the integr4l obtained in part alF Fe @nDO
AMERICAN UNIVERSITY Ghcn 'f22 6vv #drdy Revnetne Inepral olt cocnn;n Evalvatc the integr4l obtained in part al F Fe @n DO...
5 answers
Grven the following values for the changes enthalpy and ention; Mnich ol Ihe folluing mol -200 mol K1 AH=+51kJ mor mol- LH -+51kJ mor +120 mol AH=-S1kJmor +200 mol None of tie ansivers couacvidlaWidSocond LiThammodeneemttn
Grven the following values for the changes enthalpy and ention; Mnich ol Ihe folluing mol -200 mol K1 AH=+51kJ mor mol- LH -+51kJ mor +120 mol AH=-S1kJmor +200 mol None of tie ansivers couac vidlaWid Socond Li Thammodeneemttn...
5 answers
26.The immune system has plenty of time to generate protective antibody response in which vaccine?AIIYellow fever Hepatitis B virus Hemophilus Influenza type B NoneCLEAR MY CHOICE
26.The immune system has plenty of time to generate protective antibody response in which vaccine? AII Yellow fever Hepatitis B virus Hemophilus Influenza type B None CLEAR MY CHOICE...
5 answers
Find Dxo, and 4GO for the dissolving of silver chloride water under standard conditions_ Use the results t0 answer the qucstions that follow: AgCi(s) Ag* (aq) a(aq)GchUcal S lnueaCtoa"Falo4H"?Lhe absolute tolerance +/-0.1In Tnat450?JKthe absolute tolerance +/-0.1Tn T0G"?the absolute tolerance I "/-0.1Is this spontaneous reaction?Does release energy?Tn MTTTDoes the amount of order In the chemical system increase?
Find Dxo, and 4GO for the dissolving of silver chloride water under standard conditions_ Use the results t0 answer the qucstions that follow: AgCi(s) Ag* (aq) a(aq) GchUcal S lnuea Ctoa" Falo 4H"? Lhe absolute tolerance +/-0.1 In Tnat 450? JK the absolute tolerance +/-0.1 Tn T 0G"? th...
5 answers
Quesion 21A conidium isa A narrow spectrum antibioticb A fungicide A dormant asoxual non-reproduclive sttuctured An asexually-produced tungal spore
Quesion 21 A conidium is a A narrow spectrum antibiotic b A fungicide A dormant asoxual non-reproduclive sttucture d An asexually-produced tungal spore...
5 answers
QUESTION 19 Check conditions usinO~distributionunahaCheck all statements that apply You should have thtoe iun checken have fully The sample size Is large Ins FeC Ihis question enough [nat the shape nat pa Tucl arly ocntant Tne samp size not Iarge enough for uS t0 disregara SJape, The shape reasonably close symmetric ano bell-shaped The shape NOT close to symmetric and bell-shaped Conditions are met; Conditions are not metOUESTION 20
QUESTION 19 Check conditions usinO ~distribution unaha Check all statements that apply You should have thtoe iun checken have fully The sample size Is large Ins FeC Ihis question enough [nat the shape nat pa Tucl arly ocntant Tne samp size not Iarge enough for uS t0 disregara SJape, The shape reas...
5 answers
Lyt-:0? ##* bec c [imctsr dcna onusiico Such Utcf 3122}284 +62}- Firo % such %us: Tfx) = (2281.
Lyt-:0? ##* bec c [imctsr dcna onusiico Such Utcf 3122} 284 +62}- Firo % such %us: Tfx) = ( 2281....
5 answers
2n" For exactly what values of the constant p does the series converge? nP 4n + 3 n=] O A pz2 B. p < 3 C. p > 2 D. p s 3 E: p > 3
2n" For exactly what values of the constant p does the series converge? nP 4n + 3 n=] O A pz2 B. p < 3 C. p > 2 D. p s 3 E: p > 3...
5 answers
Part Abetween the two chair conformers of trans-1,2-dimethylcyclohexane Calculate the energy dilierence Express your answer using three slgnificant figures.Azd110"AE = 2.70kcal/ molSubmitPrevious_Answers Request_AnswerIncorrect; Try Again Review your calculalions; YoU may have made rounding error Or Used Ine wrong number of significant figures_
Part A between the two chair conformers of trans-1,2-dimethylcyclohexane Calculate the energy dilierence Express your answer using three slgnificant figures. Azd 110" AE = 2.70 kcal/ mol Submit Previous_Answers Request_Answer Incorrect; Try Again Review your calculalions; YoU may have made roun...
5 answers
CDDtRecalllng thc Coulombys Law describes (he (orco on a chargcd particlc due t0 wnother charged particle_k7Uslla ths relatlonshlp, lu noint charges,each with 0,1 Cof charge; 10"N calculate Lhe force between the charges in newtOrks10,mn Jpart,and the (act that the constanchtlonshlp equMli
CDDt Recalllng thc Coulombys Law describes (he (orco on a chargcd particlc due t0 wnother charged particle_ k7 Uslla ths relatlonshlp, lu noint charges,each with 0,1 Cof charge; 10"N calculate Lhe force between the charges in newtOrks 10,mn Jpart,and the (act that the constan chtlonshlp equMli...
5 answers
PROBLEM 6 Consider the integral JG/4(31*+31+1)+a sin(2r)ds,a € R: Use the midpoint rule with five points For what value of a is the error minimal?
PROBLEM 6 Consider the integral JG/4(31*+31+1)+a sin(2r)ds,a € R: Use the midpoint rule with five points For what value of a is the error minimal?...
5 answers
Zh 10" ns-1 Al 7G0(Omt 0,41U206 ALn mol-) K-1 10~' Lmn#'6-|4,8 ms-?6,626 1013257 1kp m? 0-"63170 * 10-i ALMI 00125 ban Icu -+18| 602AMn7601 mnlIg #SM4 mol-1 k-'KttwAtsth 051kmf1Kunarri LK6 K m
Zh 10" ns-1 Al 7G0(Omt 0,41U206 ALn mol-) K-1 10~' Lmn#'6-| 4,8 ms-? 6,626 1013257 1kp m? 0-"6 3170 * 10-i ALMI 00125 ban Icu -+18| 602 AMn 7601 mnlIg #SM4 mol-1 k-' KttwAtsth 051kmf1 Kunarri LK6 K m...
5 answers
Etmnbd murd LlttnaarYouoenkund ulontnntinncolrtlpuleenao)Lnci dTT DiunamjitteGDtn Tae eeenrJufid nantn-tr ln En ictaunfmchanieretett5 ppo #l Da Fabera @nao4 Dinlo? Hul Tpee enrn nmusiF0n(oapartmenithatdhinnelteaatDan Ttnamu
Et mnbd murd Llttnaar Youoenku nd ulontn ntin ncolrtl puleenao) Lnci dTT Diunamjitte GDtn Tae eeenr Jufid nantn-tr ln En ictaunfmchanieretett 5 ppo #l Da Fabera @nao4 Dinlo? Hul Tpee enrn n musiF0n (oapartmenithat dhinn elteaat Dan Ttnamu...
1 answers
Use appropriate algebra and Theorem 7.2.1 to find the given inverse Laplace transform. (Write your answer as a function of t.) 2X(8-4)}Need Help?ReadIt
Use appropriate algebra and Theorem 7.2.1 to find the given inverse Laplace transform. (Write your answer as a function of t.) 2X(8-4)} Need Help? ReadIt...
5 answers
Consider the adjacent circuit, where RI=R3-RL=2 kilo-Ohms, R2-=7.3 kilo-Ohms, VI= 1OV, and V2-8 V. The Thevenin equivalent voltage between points A and B (in Volts) is:R2R3a. 6.46 b. 0.88 c.3.92 d. 10.00 5.00
Consider the adjacent circuit, where RI=R3-RL=2 kilo-Ohms, R2-=7.3 kilo-Ohms, VI= 1OV, and V2-8 V. The Thevenin equivalent voltage between points A and B (in Volts) is: R2 R3 a. 6.46 b. 0.88 c.3.92 d. 10.00 5.00...
5 answers
Describe the convection, conduction, and radiation involved inboiling a pot of water over a fire
Describe the convection, conduction, and radiation involved in boiling a pot of water over a fire...
5 answers
Chapter 11, Section 11.4, Question 007Your answer is partially correct Try aqain.Let u = (2,-1,3) , v = (0,4,6) , and w = (1,5,6) . Find(aju *6Xw)(b)(uxv)Xw(c)(uxn)xlxW)-62(d)vxw)xluxv)342Click if you would like to Show Work for this question: Qpen Show Work
Chapter 11, Section 11.4, Question 007 Your answer is partially correct Try aqain. Let u = (2,-1,3) , v = (0,4,6) , and w = (1,5,6) . Find (aju *6Xw) (b)(uxv)Xw (c)(uxn)xlxW) -62 (d)vxw)xluxv) 342 Click if you would like to Show Work for this question: Qpen Show Work...

-- 0.023322--