5

Withoul moving reuding Jhe groundprobe; find another Continue ' location find additioral Khere you can determine the line that Points (approximately &-10)...

Question

Withoul moving reuding Jhe groundprobe; find another Continue ' location find additioral Khere you can determine the line that Points (approximately &-10) until equipotential, because cornects the points. This line there is no change culled of the points on the line- clectric potential between any [0.Once you have finished your nmdoc another location first line (und rot before} move the ground ICreate Then ; npr4t additional lines the process cieile ecnclc chaie (approximately 7-9 tot

Withoul moving reuding Jhe groundprobe; find another Continue ' location find additioral Khere you can determine the line that Points (approximately &-10) until equipotential, because cornects the points. This line there is no change culled of the points on the line- clectric potential between any [0.Once you have finished your nmdoc another location first line (und rot before} move the ground ICreate Then ; npr4t additional lines the process cieile ecnclc chaie (approximately 7-9 total), some close and somt the middle: 12 Disconnect the battery utlue reconncc Repeat the entire prOCEss supply ) switch out the sheet, ud Anabysix: The equipotential lines indicute where Ete chng? pucntul cncng} travel and remain at the or cquul Meniiall Imagine plccing chatee m the shzet and moving Equnotential ines Aona Iow much wozk of the dore' on Ein the test churge? What the fonula Ior Wutk' W Jw 2.Iv List al the cases vhen the #ork Lne I chatee caeu Imouing sx pao Sl LELes Waak 2eL#s EELle AL In our experiment; which of these casts are nGt possible? Why ? So, in which direction the electric force DI Inc (Csl charge? which direction the electric field? tell just from the equipotentials whether the electric field points Can You i How can You = tell? lefi-to-right or right-to-len? draw electric field lines on each of the eraphs. Using this information label on each of the graphs = any locations Using the electric field lines; constant (if = 'applicable): where the electric field is gnatest; weakest,



Answers

In one experiment the electric field is measured for points at distances $r$ from a uniform line of charge that has charge per unit length $\lambda$ and length $l,$ where $l \gg r .$ In a second experiment the electric field is measured for points at distances $r$ from the center of a uniformly charged insulating sphere that has volume charge density $\rho$ and radius $R=8.00 \mathrm{~mm},$ where $r>R .$ The results of the two measurements are listed in the table, but you aren't told which set of data applies to which experiment: $$ \begin{array}{lcc} r(\mathrm{~cm}) & \text { Measurement A } & \text { Measurement B } \\ \hline 1.00 & 2.72 & 5.45 \\ 1.50 & 1.79 & 2.42 \\ 2.00 & 1.34 & 1.34 \\ 2.50 & 1.07 & 0.861 \\ 3.00 & 0.902 & 0.605 \\ 3.50 & 0.770 & 0.443 \\ 4.00 & 0.677 & 0.335 \end{array} $$ For each set of data, draw two graphs: one for $E r^{2}$ versus $r$ and one for $E r$ versus $r$. (a) Use these graphs to determine which data set, A or B, is for the uniform line of charge and which set is for the uniformly charged sphere. Explain your reasoning. (b) Use the graphs in part (a) to calculate $\lambda$ for the uniform line of charge and $\rho$ for the uniformly charged sphere.

In this problem. We're thinking off a fish. Bye. We obstructed tow a cylinder. Now we know that the cylinder has length ofthe 20 centimeters, which is they don't want to meters has And in India Krasic malaria off one centimeter square and has a voltage difference of three world. Now we want to find out. We also know that it is basically made off. See order on the the festivity ofthe sea water. Is there a 0.13 o meter for party? If you want to find out the current passing through deficient for that we need to go. I know they're resistant first so that we can use home slaw that we buy Our is our existence, as we know, is ruined by simple attacked on role is 0.13 Lent Is there 12 meters and area is one centimeter squared. Remember that a centimeter is 100 off major that is once individuals to four minus two meters on the whole square which is zero point 0 to 6. Divided by 10 4 minus four. It is 260. Oh, now that we have this current is simply what is by assistance. That is three World by 2 60 which is 11 point 5,000,000 ampere. Now question bees is interesting. We have another cylinder off half the land parle into it. Andi also has half the festivity now we want on. This replaces this half off the original cylinder, so we have the original cylinder for half the land on the new cylinder for the rest of them. So now let's say the resistance off this whole cylinder was R, which is to 60 home now. The resistance off this half surrender will obviously be our guy, too, because resistance is proportional relent and half the length would help have to resistance. Now, as you can see, these two cylinders are identical. They have the same length and area and only the rhesus. Studious changing. He resisted the off. This one is half. There isn't Studi off this cylinder, and their assistants off the cylinder will Also we have the resistance off this cylinder, giving us the resistance off the cylinder. Toby are, too. I do, which is already full, and this system is equal in tow. A toast to our sisters in Siri's with resistance is our by two on our rightful hands. The total assistance. Now we comes our way to place our way for because they're in serious which is three are for which is three by four times to 60 which is 195. Hence, In this new guest, the current will be wi I I be by our side which is three world by 195 which is 15 point for me. Happier be Lord Resistance increases the gallant and the change in current is one fifteen 15 point 4,000,000 amperes minus 11 point 5,000,000 years which is so you find 9,000,000 years. The current increases by three point 9,000,000 years.

Hello. Everyone here is given electric Put incidentally yet it is given Hey, after square minus three by square. But there it's quick, their age constant we have to find Or did I the electric tree at the point in chicken. But if well done, when the a judge cure off 1 50 Micro problem from a point. Do you know Do you know while the doodle to fight meter Cool origin. Okay, six in 10 to the power minus five. Dude. Fine. Hey, see? But be required in a field at you. Don't you? Don't. I went to fight Meter Day. What is the release off? You have to find a radius off e que pretension counters circuits corresponding toe. But reaching up We went toe a durable on Dwight school toe to meet the letters. Start solving it. First part Electric field is defined It they'll be upon deluxe. I guess they'll be upon Bill by Jacob. We have two different it. What changed it? Partially with respect to X. Why inject? Then we will get electric. Really long exceptions by accident. Alexis So negative off potential. Radiant is equal to electric queen. So bill over deluxe you will get Hey and X squared minus three Vice square My blessed Jerry Square I kept but let's deal over there. Right and active. Square minus three Vice Square plus Jerry Square Plus you, noble daily, Get a access. Quit minus three by square. Bless Jerry Square Guica No differentiated Partially so we can like electric feel at a given point. Is he? We can take comment when we difference it partially with respect to X, then by injured will be common. So it will be two x icapp here X injectable becoming minus six by dick up and accent by his comments of bullets who get a kick up. So this is the answer off first. But no for me part, we have to find a well done is given. Uh, Bogdan is given of Ogden is defined as e dot s You You just force into displacement Q Is one be my problem Electrically Wicks x is you know why is you know dead is given? Why five you in tow, Jiro, I kept dot Correct. This is the daughter up the white cap. Let's judo jacked up. Let's 0.25 You don't cake up on solving it. Well, you walk a well done. You will get. Bargain is given six in tow. 10 to the power off, minus fight. Divided white, two in tow. 20.25 and to find five. So you would have yet just a moment. I've sort like little bit properly. Just a moment, please. So where you off? You will get wagon. What? Done it. Six in tow. 10 to the power off minus five 1 50 in tow. Tend to the par minus six and toe two in tow. Wine to five and 2.25 on solving it. This valuable be 6 40 bull per meter square. So this is the answer up. Beeper on. Set up cheaper electric. Feel at point. Get a unit minus people. Do you know ICAP bless Geo Jacob in 6. 40 Unless two in tow Line to fight. You kept so electric. Read Bilby my nuts. You don't see bull per meter Cake up de a crippling parallel to x by please. It's got spent so and every play Their little X jet plane by it. What strange so attention you could square you see it? Three bodies square. So at the square Bless Jerry Square. It's going to be blessed see upon a and that is a our square, which is the question of that. Our question. So we have a question potential on this place. It is that you Grishin up circuit. The sense are it's constant. If what intelligent, constant. Anybody for a teacher up oneto, durable and why it's goingto cool meter. We will get actor Square blessed very square because three A 6 40 You ready to play 6. 40? So we will get Actually Square Jerry Square is equal to 14.0 m sweat on request of the circulates who got 40? That is 3.74 m. So this is Don Tello e part off this problem. Thanks for watching it.

Hi there. So for this problem we are given the function of a potential of electric potential. And there are some constants and we need to determine by the information given in this table. So the first thing that we can obtain is the constants A, B, C. And D. Without given points. And then with the at the electorate field we can calculate the constance L. M. And N. And so the electric field or the better of the electric field is defined as minus the partial derivative of the electric potential in each component. So that when we obtain each of this company this is that as this is at Y. And this is at seton. So it will be that the as companies minus and sure. So we can see in the function or the electric potential that um when we deliver partially verified that um only the first term is the one that we are going to verify with respect to X. Because the other ones are just constance. So we will cough minus A. Of S. Held over S. A. A circumstance and can be taken out of the derivative and we will have the following my news. ELT A. S. L. To the- and adds to to L to the -1. So this is for this first company. So for the other company something similar happens. And is in this case is B. Y am over. So this will be M. B. M. Y. Sorry why in here why why am minus out and for the seated part again something similar. Oh minus that part. So it will be minus and man same see See to her and -1. So with this set we can start by obtaining the values of circumstance A, B, C and D. So to find that we first use them electric potential. So we have a way to let your potential at the first point which is 000. So the electric potential 000. As you can say looking here double give us all these terms are zero and we are left with the because I'm going to be like just explicitly zero and lost see seat and zero and plus theme all of these zero. So we will have that tea is equal to the value of the potential at this point which is 10. We can see it in the table. So this is equal to tend. So we have obtained the first the first constant these people to tend. No. Also this should be bold shoes. Um No we use the second point to find other bibles Other constant. So in this will have 100 100. And we will have that for that point electric the electric potential is to So this should be equal to two. And putting those values. We will have a 1 to the eld. Plus the other terms are zero and plasticity which is 10 bulges. Remember that this is two bulges. So want elevated to any number is one. So just a is equal to two voltages -10 voltages which is -8 voltages. So this is it comes to a. So we did a similar procedure to find The other constants we use now this point which has a value of four. So 010 or bold use. So in this case the only term that survives is B To the 1 to the M. Um plus D. Which is 10 volt shoes. So that B is equal to -6 bold use. And okay, let's keep going. So this is theme. No finally or 001. We will have a value of the electric potential of specs. It's volunteers. So that this should be equal to the only third of survive. It's the 1 to the end. This is one Last 10 vultures. So see Is equal to -4 Bullet IBS. And then we just have obtained all these values. And no. We can say that as far as now we know that. And um electric potential is minus eight volunteers adds duty held well. Um also we'll have B. Which is my next sits add to the L. And minus four port you steps to the end. So now we need to find the values of the um. Constance L. M. An end. And for that we will use the power to use of this table. But for the companies of the electric field which art is in here. And we already have what are the um as precious for each company sell for Yes or the X company of the electric field. We will have this in here minus. ELT A. X. To the L -1. We know that this yes In the .100. This this only depends on on ads. We're gonna put it in here. We are and avoided this and the point 100. So this will be minus. ELT Okay zero L- Want. We know the value for A Which is -8. So with these minus councils that we will have eight out equal to 14. That's the value in here. 14. So if we sold for L'd will obtain 14/8 weekend simplify this and we will have 7/4. So this is the value for health 20. And now to find about you or the other exponents, we have quarrel the white company of the electric potential minus B. Um Sorry um evaluated in 010010. We will have that this is minus M me And evaluated in want because it only depends on why anyone company and this is M -1. This is want and this also should be 14 because that's the body of that company at that point. So we will have war team and we know the value for B which is minus six. This is minus sets with this minus council. So we will have this issue be equal to sits and so um It's equal to 14 over sits that can be simplify as this seven over three. And similarly leave for The city component will have the disability 00 want this will be minus and C. Um one and one this is The rules so we will have that again. We go to the table again is 14. The value of the electric potential at that point So we'll have 14 And we know the value for C. Which is -4. So this is minus four again with the minus sign council. So we will have working is equal to or so dead and its people to 14/4 which we can simplify A 7/2. So these are the values for L. N. And M. So we can just substitute that into the electric potential function and we will have this in here But with the values that we just have obtained for L. M. and end so it will have it will be -8 answer two. The eld which is Mhm and L'd. Is 11 on her 4th minus six bulges abs two. My nurse for Pollock use that's 2 7/2. And for the electric field we will have or D. Um This is um I bet you're So we'll have for the X. Company will be this turning here so we will have minus seven over fourth. Ain't old news um At L -1. Yes mm 7/4 minus one. For the white company will have minus and and we know that is 73 minus. So here is -2 in -6 coaches. Um it's 73 but when this one oh this is why sorry this is why and for the seat apart will have minus 7/2 minus four seat her. So this will give us simply find the following this expression for the electric field. So part B of this um problem. We don't have much, I don't have more space in here. But um the final is to obtain the magnitude of B. And the magnitude of e. At some given zero. And So there are three points so gonna like make some space in here that will be uh huh It will be for the first point First point is 000. So that this is party of this problem. So for this point we'll have yeah If we put 00 out I almost forget in here we have plus 10 volt ease of DM of the D constants that we will have. That if we put zero in all of this All of these are zero And we obtain 10 vultures for the electric field. If we bit 000 we can see that that will be zero And well this is a back door. 000. And if we take the magnitude of that door at that point is just zero. Now at the point 0.5 0.5. 0.5. That will be you need to build all of those values in here. So it's something a little 0.5. 0.5. So it will be minus eight 0.5. and my nurse sits 0.5 Judas. Uh huh. More rhinos four. Yeah, 0.5. Last 10 bolt use. And this is if we put all these into the calculator six point 08 bulges. And you did the same procedure for the electric field. And for the order given point That is 1 1, 12. So for that .111, I'm going to like erase this. So for that .1, 1 want point of what want Want want. It will be We want want want. This will be -8 -6 -4. Last hand. So this will be -8 vultures at this point. And I like to feel at that point will be -111. He will be 14, 14, 14, 14. If you take the The magnitude of that debt tour, it will be 14 because it is the sum of the square of beach. Oh no, it will be, let me put it in here. It will be the magnitude. It would be the square Route of three times 14 squared. So that will be 24 Warren two. Um, and this is the values or the electric potential at different points. Thank you.

So, for part a, um, we know that the strength of the magnetic field produced by current carrying wire from the wire at some distance from the wire is two times 10 the native seventh times the current in the wire divided by the distance. So we can say that the magnetic field would be to times 10 to the negative seventh Tesla's meters per amps multiplied by the current divided by the separation D. And so we can say that then the magnetic field is equaling 22 times 10 something of seventh Tesla's meters per amps. This will be multiplied by 10 EMS divided by half a meter, and this is giving us four points. There are times 10 to the negative. Sixth, Tesla's Now the strength of Earth's magnetic field is equaling 5.0 times, 10 to the negative fifth Tesla's So we can say that, then be divided by B C E. It's simply equaling point 08 Therefore, the magnetic field in your house is only 8% of the magnetic field due to earth. So for part B, um, here Now we have a a power line, essentially, and so here the magnitude is equaling 22 times, 10 to the negative seventh Tesla's meters per amps and this will be multiplied by 200 amps divided by 20 meters high. And this is giving us 2.0 times. Tend to the negative sixth Tesla's. And as you can see, we have 4.0 times tense and they have six Tesla's. So essentially we can say that then the magnetic field from the ah transmission line. It simply is Onley equal to the magnetic field of your house, divided by two and it's ah, the reason why they do this is because the magnetic field is dependent. More, of course, is dependent on the current and not the voltage. So you could have really high voltages, um, and not results in high magnetic fields simply because you're simply because the current is sufficiently low such that, um, the magnetic field is low as well. Also placing them 20 meters, uh, above the ah placing them 20 meters high above the sidewalk is also beneficial in the sense that that also reduces the magnitude of the magnetic field that you're experiencing. Walking down the sidewalk for part C, we have that pregnant pregnancy magnets. The magazines suggests that Ah, placing your baby within an electric blanket might not be comfortable rather safe, simply because the magnetic fields induced through the through the electric blanket my harm the development of the baby. But as we can see here for part C, we're going to assume that the distance if you're using a blanket, the distance from the blanket to the fetus or a child or whatever, maybe, um, would be five centimeters so very, very small. We can say 50.5 meters, and we know that then the magnetic field be would be going to to times 10 to the negative seventh Tesla's meters per amps. Now the current running through these electric blankets is not too large. It simply one amp this will be divided by 0.5 meters, and we find out that the magnetic field is equaling 4.0 times, 10 to the negative six Tesla's. So again the same exact answer that we found in part A and so we can see that. Then the deal. The magnetic field from the electric blanket is equaling two again. Only 8% of the magnetic field of earth and so we can you concede that it won't harm the baby? Using electric blanket will climb the baby The baby's already subject to magnetic fields that are much larger than the magnetic field imparted by the blanket. Earth's magnetic field is again 5.0 times, 10 to the negative fifth Tesla's That is the end of the solution. Thank you for watching.


Similar Solved Questions

5 answers
Question 11Below is a distribution for number of visits to dentists in one year:P(X-x) 0.29 0.41 0.16 0.05 0.09Calculate the following probabilities:P(X < 2) =b. P(X 2 3) =P(< X s3) = d.P(3 sX<5) =P(3 < X <5) =Question 12Time_Tracker Nan doc
Question 11 Below is a distribution for number of visits to dentists in one year: P(X-x) 0.29 0.41 0.16 0.05 0.09 Calculate the following probabilities: P(X < 2) = b. P(X 2 3) = P(< X s3) = d.P(3 sX<5) = P(3 < X <5) = Question 12 Time_Tracker Nan doc...
5 answers
Which of the following is not an exploitative interaction?mosquito sucking blood from a hostwolf killing deerdeer eating grasshuman eating a hamburgerfungus digesting dead leaves
Which of the following is not an exploitative interaction? mosquito sucking blood from a host wolf killing deer deer eating grass human eating a hamburger fungus digesting dead leaves...
2 answers
(6) Suppose X,,XzsX, are independent and identically distributed random variables such the Xj and Var(X,) = 02 i=1,2, Let T = be an estimator for 0 E(X,) = 0 n+1 Show that T is asymptotically unbiased for 0 ii) Find the MSE of T: What d you expect for MSE(T) when you use a large sample? (iii) Find the minimum MSE of Tif Var(X;) =C02 . 4
(6) Suppose X,,XzsX, are independent and identically distributed random variables such the Xj and Var(X,) = 02 i=1,2, Let T = be an estimator for 0 E(X,) = 0 n+1 Show that T is asymptotically unbiased for 0 ii) Find the MSE of T: What d you expect for MSE(T) when you use a large sample? (iii) Find ...
5 answers
Question 10You are performing a two-tailed z test:If & = .02, find the positive critical value rounded to two decimal places2a/2Next Question
Question 10 You are performing a two-tailed z test: If & = .02, find the positive critical value rounded to two decimal places 2a/2 Next Question...
4 answers
Let V = {(a + 2b - c a + 3c;, a +4 a -6 a + 26+c) € Rs a,b,c€ R}. Show that S = {(1,1,1,0,1), (0,2,0,_1,2), (2,-2,0,1,0)} is basis forPerform Gram Schmidt process on S to obtain an orthogonal basis for V. (Do not use MATLAB command. Show your steps: ) (iii) Find all vectors that are orthogonal to V.
Let V = {(a + 2b - c a + 3c;, a +4 a -6 a + 26+c) € Rs a,b,c€ R}. Show that S = {(1,1,1,0,1), (0,2,0,_1,2), (2,-2,0,1,0)} is basis for Perform Gram Schmidt process on S to obtain an orthogonal basis for V. (Do not use MATLAB command. Show your steps: ) (iii) Find all vectors that are ort...
5 answers
Helpful definitions: A sel A is finite if there is a bijection from set A to the natural numbers, {0, 1,2,--} Ifno bijection exists, the set is infiniteSets A and B have the same cardinality (IAI-IBI) if and only if there is a bijection from set A to set B.Clearly define bijection from set A to set B A= (x:* is box of k donuts chosen from n types} B= {Y: Y is a way t0 place n-1 boards Into the spaces before, after; and between k donuts}
Helpful definitions: A sel A is finite if there is a bijection from set A to the natural numbers, {0, 1,2,--} Ifno bijection exists, the set is infinite Sets A and B have the same cardinality (IAI-IBI) if and only if there is a bijection from set A to set B. Clearly define bijection from set A to se...
5 answers
The Ax = b system is Solvable" only if h is 4of A_Explain why the linear system Ax = b whereandis not solvable_[Hint: Examine the dot product of the vector b and the column vectors of A:|
The Ax = b system is Solvable" only if h is 4 of A_ Explain why the linear system Ax = b where and is not solvable_ [Hint: Examine the dot product of the vector b and the column vectors of A:|...
5 answers
Problemcauits period T be usae [ pendulum physicist with 4sudinpuod on the string 767 the of length Whaere period_ the supporting What acceleration near mass mass 82? and the Jil Lm has around TanngMoon
Problem cauits period T be usae [ pendulum physicist with 4sudinpuod on the string 767 the of length Whaere period_ the supporting What acceleration near mass mass 82? and the Jil Lm has around Tanng Moon...
5 answers
Hint; Check your snsts "6Jinst thc &r*phUslng this equstion lind thc Iollomin ntorm IlonTio pllac*8 manimum haightRound your answte {0 ? Uctimj Dugc norriun(5 autempts rcmuining
Hint; Check your snsts "6Jinst thc &r*ph Uslng this equstion lind thc Iollomin ntorm Ilon Tio pllac*8 manimum haight Round your answte {0 ? Uctimj Dugc norriun (5 autempts rcmuining...
5 answers
Find the general solution of the following DE: xy" - (t+I)y' +y = 2202 , ify1=e; Yz = t+1 XatytZe-' Compute the solution of the IVP by given the following initial conditions: X(0) = 0 Y =4r+y+te ') y(0) = 0
Find the general solution of the following DE: xy" - (t+I)y' +y = 2202 , ify1=e; Yz = t+1 XatytZe-' Compute the solution of the IVP by given the following initial conditions: X(0) = 0 Y =4r+y+te ') y(0) = 0...
1 answers
Coherent electromagnetic waves with wavelength $\lambda=500 \mathrm{nm}$ pass through two identical slits. The width of each slit is $a,$ and the distance between the centers of the slits is $d=9.00 \mathrm{~mm}$. (a) What is the smallest possible width $a$ of the slits if the $m=3 \max -$ imum in the interference pattern is not present? (b) What is the next larger value of the slit width for which the $m=3$ maximum is absent?
Coherent electromagnetic waves with wavelength $\lambda=500 \mathrm{nm}$ pass through two identical slits. The width of each slit is $a,$ and the distance between the centers of the slits is $d=9.00 \mathrm{~mm}$. (a) What is the smallest possible width $a$ of the slits if the $m=3 \max -$ imum in t...
5 answers
+2Q3Q330Q1) (30 pts)- Three particles are located at (O,a), (a,0) and (-a,0) with charges shown in the figure: Assuming a= m; Q= 1pC and k= 9xlO? N.m?/c?(10 pts) Find the force on particle namely the magnitude and direction of the force vector. (10 pts) Find the electric field vector at point 0,. (10 pts) Find the electrostatic potential at point 0_
+2Q 3Q 330 Q1) (30 pts)- Three particles are located at (O,a), (a,0) and (-a,0) with charges shown in the figure: Assuming a= m; Q= 1pC and k= 9xlO? N.m?/c? (10 pts) Find the force on particle namely the magnitude and direction of the force vector. (10 pts) Find the electric field vector at point 0,...
5 answers
"C NMR Spectrum (I50 MFJ, COCh solin)DEPT Ch!Ch'Chpolon decoupndsahient2001601208040(ppm)'HNMR Spectrum (400 VKz CDOL suton)@"PansionexpansionsFomFamTuS106 (Ppm)
"C NMR Spectrum (I50 MFJ, COCh solin) DEPT Ch!Ch'Ch polon decoupnd sahient 200 160 120 80 40 (ppm) 'HNMR Spectrum (400 VKz CDOL suton) @"Pansion expansions Fom Fam TuS 10 6 (Ppm)...
1 answers
In Exercises $1-10,$ verify the identity. $$ \cos ^{2} \beta-\sin ^{2} \beta=1-2 \sin ^{2} \beta $$
In Exercises $1-10,$ verify the identity. $$ \cos ^{2} \beta-\sin ^{2} \beta=1-2 \sin ^{2} \beta $$...
5 answers
47FThree forces, F1-10 N, F2-22 Nand F3-15 N are acting on the block with mass m =3 kg as shown in the figure. How much work is done on the block if the block has moved a distance ofx-3 m from point K to L, assuming that there is no friction between the surface and the block?30 J20 J15 J141J
47 F Three forces, F1-10 N, F2-22 Nand F3-15 N are acting on the block with mass m =3 kg as shown in the figure. How much work is done on the block if the block has moved a distance ofx-3 m from point K to L, assuming that there is no friction between the surface and the block? 30 J 20 J 15 J 141J...
5 answers
GondetWinules Sanatany day 030 308 D0a 0#Mel Reneb253576Z03045451604 Pvalue < 0.0oS OB 005 < Pvalue < 0.10 00 Pxoluo > 0 10 Od 0075 * P xn <005
Gondet Winules Sanatany day 030 308 D0a 0# Mel Reneb 25 35 76 Z0 30 45 45 16 04 Pvalue < 0.0oS OB 005 < Pvalue < 0.10 00 Pxoluo > 0 10 Od 0075 * P xn <005...

-- 0.024921--