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A magnet moves inside a coil Consider the following factors: I. Strength of the magnet II Number of turns in the coil III. Speed at which the magnet moves Which c...

Question

A magnet moves inside a coil Consider the following factors: I. Strength of the magnet II Number of turns in the coil III. Speed at which the magnet moves Which can affect the emf induced in the coil?1.All of them2. III only3. II only4. I and II only5. [ only

A magnet moves inside a coil Consider the following factors: I. Strength of the magnet II Number of turns in the coil III. Speed at which the magnet moves Which can affect the emf induced in the coil? 1.All of them 2. III only 3. II only 4. I and II only 5. [ only



Answers

A coil having n turns $\&$ resistance $R \Omega$ is connected with a galvanometer of resistance $4 \mathrm{R} \Omega$. This combination is moved from a magnetic field $\mathrm{W}_{1} \mathrm{~Wb}$ to $\mathrm{W}_{2} \mathrm{~Wb}$ in $\mathrm{t}$ second. The induced current in the circuit is.... (a) $-\left[\left\{\mathrm{W}_{2}-\mathrm{W}_{1}\right\} /\{5 \mathrm{Rnt}\}\right]$ (b) $-\mathrm{n}\left[\left\{\mathrm{W}_{2}-\mathrm{W}_{1}\right\} /\{5 \mathrm{Rt}\}\right]$ (c) $-\left[\left\{\mathrm{W}_{2}-\mathrm{W}_{1}\right\} /\{\mathrm{Rnt}\}\right]$ (d) $-\mathrm{n}\left[\left\{\mathrm{W}_{2}-\mathrm{W}_{1}\right\} /\{\mathrm{Rt}\}\right]$

We were asked to find four factors which can change the induced MF and a coil of wire. The induced EMF is equal to the negative of the change in the magnetic flux over the change in time. The magnetic flocks just FYI, is equal to the amount of magnetic field going through the coil. We can calculate it from the product of be the magnitude of the magnetic field A, which is the area the cross sectional area of the coil times in which is the number of a number of turns in the coil times co sign of Fada, where theta is the angle between the magnetic field and the surface of the coil, the circular surface of the coil, so four ways that we can change the induced. If we change the area, the magnetic flux will increase because it would be a large area for the magnetic field to travel through. Also, if we change the magnetic field more quickly, the strength of magnetic field. This will also increase the MF. Additionally, if we change number of turns, it will increase the total magnetic flux which will then increase the IMF or we can also change the angle between the coil and the magnetic field

In this problem on the topic of induction were given two coils, the first of which has an conductance of 25 million Henry's and 100 tons while is coiled too has an induction of 40 million Henry's and 200 tons. The coils are fixed in place and have a mutual induction of three million hendry's a current in the coil one is six million peers, changing at a rate of four mps per second. And we want to find the magnetic flux fire one to the self induced PMF appearing in coil one, the magnetic flux 5 to 1. And the mutually induced E. M. F. Appearing in coil too. Now, firstly the flux appearing in coil one is the induct in L one times the current I one divided by the number of turns in coil one, which is N. One. And so this is 25 millie Henry's times the current of six million peers, divided by the number of turns 100, which gives us the Flux to be one 0.5 micro weapons. Yeah, the magnitude of the self induced E. M. F. In coil one is L one times direct. Which the current is changing. In coil one D I one D. T. So this is 25 million Henry's times the rate of change of current given to before mps per second. And so we get this MF the south India CMF and coil one to be one Times 10 to the power two million balls. Now in coil to we find the flux 5-1 to be the mutual induction. M Times the current through. I won over the number of turns in Quail two and 2. Yeah, This is a mutual induction of three millie Henry's times a Current income in coil one of 6 million peers Divided by the number of turns in Coil two, which is 200. This gives a flux of 90 Nano Weber's. Yeah. And for part D, the mutually induced e m f. Absalon to one is equal to the mutual inductions, m Times The I one DT. And so this is three molly Henry's times for mm pia's per second, Which gives an m. f. of 12 milli volts.

So here for part A, we can find the the flux and coil one. So essentially we can say the magnetic flux and Coyle. One would be equal to else of one ice of one divided by and someone This is equaling 25,000,000 Henry's multiplied by 6.0 milli amps, divided by 100. And so this would give us 1.5 Micro Weber's Ah, for part B, we confined the magnitude of the self induced E M F. So essentially we can say the IMF because they AMs of one equals the inducted, its ally else of one, multiplied by the change in the current someone with respect to time. So this would be again 25. Miller Henry's multiplied by 4.0 and peers per second, and this is giving us 1.0 times 10 to the second Millet bolts. Now, for part C, we can say in coil to we're doing the exact same thing so we can say that of magnetics. Yield in the magnetic fields up to would be equal to M m times i sub one divided by and so to this is equaling again. 3.0 Miller Henry's multiplied by 6.0 milli amps, divided by 200 instead of 100. And this is equaling 90. Nana whoever. So this would be your answer for part c. Your answer for a part b Your answer for a part. Ay and finally, four part D. We want to find the induced IMF in essentially coil, too. This would be equal to M times the change in the current in coil one with respect the time solicit again be 3.0 Miller Henry's multiplied by 4.0 and peers per second. This is giving us 12 Mila volts. This would be our answer for a party That is the end of the solution. Thank you for watching.

As we know that the MFN duty in acquittal of singleton is given by E, Which is equal to minor D five bye 18, which is required to minus D by d t A. Crosby. Now solving it further, I can write the value of the f minus A, maybe by DT. So putting the value in this expression, I can write equal to -2, multiplication 4 -1 x two, which is equal to today minus TDP So model fee Is according to 3B according to the option option B. The correct answer for this problem, I hope you understand the solution of this problem.


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