5

Mheducatlon com nm (orNanmencpoints10 Jicmnnic7Chcck my workBe sure 4uswera pantsI0.O-mL solution of 0.390 M NH, titruted with 0.1J0 M HCI solution. Calculate the p...

Question

Mheducatlon com nm (orNanmencpoints10 Jicmnnic7Chcck my workBe sure 4uswera pantsI0.O-mL solution of 0.390 M NH, titruted with 0.1J0 M HCI solution. Calculate the pH after the following additions = ofthr HCIcolution:(1) 0.00 mL(b) 10.0(c) 30.0 mL(d) 40.0 mLcBook ResourcesReferencesWWTB QuestionMacBook Pro

mheducatlon com nm (or Nanmenc points 10 Jicmnnic7 Chcck my work Be sure 4uswera pants I0.O-mL solution of 0.390 M NH, titruted with 0.1J0 M HCI solution. Calculate the pH after the following additions = ofthr HCIcolution: (1) 0.00 mL (b) 10.0 (c) 30.0 mL (d) 40.0 mL cBook Resources References WWTB Question MacBook Pro



Answers

Calculate the $\mathrm{pH}$ of each of the following solutions. a. $0.100 M$ HONH $_{2}\left(K_{\mathrm{b}}=1.1 \times 10^{-8}\right)$ b. $0.100 M$ HONH $_{3}$ Cl c. pure $\mathrm{H}_{2} \mathrm{O}$ d. a mixture containing 0.100 $M \mathrm{HONH}_{2}$ and $0.100 \mathrm{M}$ $\mathrm{HONH}_{3} \mathrm{Cl}$

Let me first warn you that the answer, though discussion is quite long, means extremely long so to solve the past day. But a We need a psychometric reaction between at U N its toe and edge tool. It's represented by this. Given is the value off baby in the ocean. We need to find the final change and finish on equilibrium. For this reaction, the baby can be determined the by the given formula. Therefore, by putting in all the values we can find that which concentration? No. We have to substitute the values in equation one and then find the concentration off x 30 positive iron substituting in the values we can find the B itch off the solution therefore, ph off point 100 m h o N h two is nine point 52 continuing to the second. But in the pod be First we need to find the association off a journo that your ministry seal Wasn't it given? Is this psychometric reaction? Well, we're here. We need to find decay A value off the equilibrium reaction Putting in the values here is the value final value off, eh? Nor substituting the value off K in the equation, first to find the Hydro Nehemiah in concentration. But again, all the values we have X three or positive concentration. We know that the pH is a call to negative log off X 30 positive. Hence we have the final pH off the solution in part three, repeating the above process. We have the pH of the Solution Off Edge tour that it's seven for the last and Final part D. We again need to find the initial change and equilibrium off the given dissociation reaction Again like the part first, we need to find the Gaby on or its species finalizing towards the pH of the solution, which comes out Toby 6.0 ful.

Question number 57 as a week base. Strong acid penetration problem where you are given eight different volumes during the Thai Trish in process and asked to calculate the pH at each of those eight volumes. To do this, we need to recognize that when we start with a weak base in solution, pH is determined using a K B week based calculation. Then, once the Thai tray shin begins and strong acid has been added, some of the strong acid will convert the week base into a weak acid, and we will have a buffer solution. So pre equivalents all pH calculations will be buffer solution calculations using the Henderson Hassle Baulch equation At the equivalence point, all of the week base will have become weak acid, and we will perform a K A or weak acid pH calculation. Then post equivalents. We will have excess strong acid, and we will determine the pH simply based upon the excess strong acid concentration or the excess hydro knee. Um, concentration. So let's get started. The first volume of strong acid added is zero mill leaders. If we have added 0 mL of strong acid, then all we have in solution is the weak base to carry out the pH of a weak base solution. We simply need to first solve for the hydroxide concentration the hydroxide concentration, as you recall for a week base is simply equal to the square root of K B 5.2 times 10 to the negative four multiplied by the concentration of the week base 40.1 Moeller, this is our hydroxide concentration. If we divide this into K W, we will get the hydro knee. Um, concentration. If we take the negative log of the hydro knee, um, concentration, we will get our ph of 11.86 Next, we have added 10 million liters of the strong acid to our weak base because we started with 20 mL at 200.1 Moeller of the week base and we're adding 0.1 molar hcl than we have a 20 million leader equivalents point. So if we are at 10 million, leaders were halfway to the equivalents point. And as you recall the pH at the equivalence point equals p. K. Pekka is simply k be divided into K w. This will give us our K a value. We take the negative log of that, we'll get our PK and will recognize that at half equivalents pH equals P K. If you didn't recognize this, you could still use the Henderson Hasselbach equation and you will get the same answer. PH will be equal to P. K. Plus the log of the moles of base. The moles of base will be equal to the moles of base we start with which is 20 mL or two leaders at 20.1 Mueller minus the moles of strong acid added which will be the 10 mill leaders, or 100.1 leaders multiplied by its morality of 0.1. This will be the moles of strong base left in solution after 10 mL. I'm sorry. Weak base left in solution after 10 mL of strong acid has been added. We divide that by the moles of weak acid formed. The moles of weak acid formed will be equal to the moles of a strong acid added which is our 10 mL one leaders at 10.1 Moeller. This also gives us our pH equal to Pekka at 10.72 The next calculation, see, is similar to the previous. We still have a buffer solution. We're still pre equivalents at 15 mL, where equivalence is 20 million liters. So we still used to Henderson Hassle Baulch equation P H is equal to P K, plus the log of moles of base, which will be the moles of weak base. We start with again 20 mL at 200.1 Moeller, minus the moles of strong acid added, which could be calculated by taking the volume of strong acid added 15 mL, or 150.15 leaders multiplied by the molar ity. We then divide that by the moles of weak acid formed, which will be equal to the moles of strong acid, added the same calculation as we did appear. This then gives us a pH of 10.24 Because we are adding strong acid, we should see an increase. I'm sorry, a decrease in Ph throughout these titrate Asian calculations, which we're currently seeing next. For Part D, we've added 19 million liters. We are still pre equivalents, so we are going to still use the Henderson Hassle Baulch equation because we still have a buffer solution. But this time, instead of the 15 mL added, we've added 19 million liters or 190.19 leaders at 0.1 Mueller. So we'll also change that down here in the denominator when we calculate the moles of weak acid formed. Other than that, the calculation is the same, and we get 9.44 as our pH still decreasing as we are expecting it to. For Part E, we are at 19.95 mL, so still pre equivalents still a buffer solution still using the Henderson Hasselbach equation. This time, however, we're using our 19.95 mL instead of the 19, or the 15 19.95 mL is 0.1995 leaders. This will be the decrease in the moles of weak base and the increase in the moles of weak acid, and we get a pH of 8.12 Now we're a 20 mL at 20 millimeters. All of the week base has been converted into weak acid. If all of the moles of weak base have now become molds weak acid, then we have a weak acid, or K. A calculation. To calculate pH. We need to know the hydro knee um concentration that is being produced from the weak acid. Ah, hydro knee. Um, concentration will be equal to the square root of the K a value which we don't have. But we do have the K B value. We can calculate the K a value by dividing the KB value into K W. So k b divided indicate W gives us k A. So the hydro knee, um, concentration is the square root of K A multiplied by the concentration of our weak acid. We started with 0.1 Moeller weak base. All the weak base has become weak acid, but we doubled the volume. So the concentration of the weak acid is half the concentration of the week base we started with because we doubled the volume. This will give us our hydro knee, um, concentration once we take the square root. Then if we take the negative log of this hydro knee, um, concentration, we will get our pH at 6.1, still decreasing, then going to part G. We are post equivalents. If we are post equivalents, we have excess strong acid because there's the strong acid. Is our tie trahant To calculate the pH, we simply need to figure out the excess strong acid concentration, which we can determine by first calculating the excess strong acid moles. These air the total moles of strong acid we have added at 25 mL or 2005 leaders 0.1 Moeller. We'll subtract off the moles of the strong acid that reacted, which will be equal to the moles of weak base. We started with 20 million liters 200.1 Moeller and then we divide by our new volume 20 million liters. Plus the 25 million liters is 45 million liters, or 450.4005 leaders. This then gives us our excess hydro knee, um, concentration. We take the negative log that to get our Ph 3.90 for the last one. It's the same calculation as we just did. But now we will be using 25 mL 0.25 leaders instead of 20.5 mL, or 0.2005 leaders and it and the new volume, of course, is going to be the 20 plus the 25 or the 250.5 total, and we get a pH of 1.95

In this question will assume that each base is a solid. So we need to figure out the mass of the solid that will be required to measure out in order to prepare the solution. If we're preparing 400 ml of a solution, We can convert the mill leaders into leaders by dividing by 1000 and then multiplied by the polarity of the solution in order to get the moles of the solute. In this case, sodium hydroxide and we have moles of sodium hydroxide will multiply by the molar mass sodium hydroxide to get the grams sodium hydroxide Will measure out 12.0 g sodium hydroxide and add it to enough water to prepare 400 ml solution. Next, we're preparing a one liter solution of a 10.71 Mueller barium hydroxide base will convert the leaders into moles of the barium hydroxide by multiplying by the polarity of the barium hydroxide solution. Then convert the moles barium hydroxide into grams by multiplying by the molar mass very similar to what we did up here. So we'll measure out 12.2 g of barium hydroxide and add it to enough water to prepare a leader of solution. Next we want to prepare 500 mL of a 5000.1 Mueller potassium hydroxide solution. So we'll convert our milliliters into leaders. Then use the polarity to convert the leaders into moles of potassium hydroxide. That would be required for this volume of solution at that concentration. And then we have moles potassium hydroxide. We multiplied by the molar mass to get the grams potassium hydroxide. We'll measure out 281g potassium hydroxide and added to enough water to prepare a 500 ml solution And the last one we want to prepare two ml of a .3 molar sodium acetate solution. So we'll convert the leaders to moles by multiplying by the polarity and then the moles to grams by multiplying by the molar mass will measure up 49.2 g sodium acetate and added to enough water to prepare a two liter solution.

For the given caution, we need to find the final pH off the solution. The volume off its seal is varied and iteration are performed. Toby calculate the pH deserting into the mixture For about it, we have the b. 00 H value off the solution, which is 0.20 m. We can find the pH value by the Formula 14 might 14.0 minus B 00 h concept value that comes out to be 13.30 one. No, it's it's seal is added into the solution. The concentration off solution. I miscalculated by the formula that is de presented by the bracket. It's over here, putting in the values we have, the concentration that turns out to before into 10 days to prom minus two. Now we can find the pH of the solution by using the same formula as we use in part A, which turns out to be 12.60 We have to use the same formula for part C on body. The formula is represented over here, substituting the values we have the people. Ohh value off the solution. PH value can be fined by the formula 14.0 minus the pos value. Same can be done for body. Also


Similar Solved Questions

5 answers
(10 points)f(r) =x +4.Sx2 ~12 +2a) Find the first and sacond derivatives_ f'(x) f"()b) Identify the graph that displays_ In blue and f In red.
(10 points) f(r) =x +4.Sx2 ~12 +2 a) Find the first and sacond derivatives_ f'(x) f"() b) Identify the graph that displays_ In blue and f In red....
5 answers
1) Triangle PQR is shown below where PQ= band PR=aRvectors In terms of b and Express the followingd) RQPQ
1) Triangle PQR is shown below where PQ= band PR=a R vectors In terms of b and Express the following d) RQ PQ...
5 answers
Determine whether two lines intersect each other and if sofind the point of intersection;lX =1+2,Y=2+4,2=1-2t; ~0 < [ < 0Izx=1-4,y =6+25,2=-5 _25; ~0 < 5 < 0
Determine whether two lines intersect each other and if sofind the point of intersection; lX =1+2,Y=2+4,2=1-2t; ~0 < [ < 0 Izx=1-4,y =6+25,2=-5 _25; ~0 < 5 < 0...
5 answers
PoinlStpS €10 6 4nortUy Notes 0 Ask YourMKtcEantderodenameTT ta aeIruntd 9ic4e 710 m' hrexunaolkti calatI cur; @#hreenerarHino[ruemhanrMeateArutiaAlttdTEEm dematy olAr0 C | Zoskolu ]Need [ (Hole?Lantln
poinl StpS €10 6 4nort Uy Notes 0 Ask Your MKtc Eant derodename TT ta ae Iruntd 9ic4e 710 m' hrexuna olkti calat I cur; @#hreenerarHino [ruemhanrMeate Arutia Alttd TEEm dematy olAr0 C | Zoskolu ] Need [ (Hole? Lantln...
5 answers
Show detailed solutions Use Gauss-Jordan to solve the resulting system and indicate elementary row operations used_Express C, if possible, as a linear combination of A and B. A = 3],8 = [? ,c = [9
Show detailed solutions Use Gauss-Jordan to solve the resulting system and indicate elementary row operations used_ Express C, if possible, as a linear combination of A and B. A = 3],8 = [? ,c = [9...
5 answers
D-vtap 1 83.C31 8,,C,1 Deermne (nL Yaive @elermine Ine "68F55 OlB 8 Ox[B8] VJle olLe L Dnine Inio Istti [ 3 JDIDEICJ 1 1 uipansion down IneIasi Substilule tne 11 1cunidialelor C2i
D-vtap 1 83.C31 8,,C,1 Deermne (nL Yaive @elermine Ine "68F55 OlB 8 Ox[B8] VJle olLe L Dnine Inio Istti [ 3 JDIDEICJ 1 1 uipansion down IneIasi Substilule tne 1 1 1 cunidiale lor C2i...
5 answers
AFirhea an (vogenbood of the tangent linesmooth curve 33 4
aFirhea an (vogenbood of the tangent line smooth curve 3 3 4...
5 answers
4UntClaeroor_ Inua Ifo HeatSciencein the ClassroomMacboc ProAa Dacecommand~corntantooton
4Unt Claeroor_ Inua Ifo Heat Sciencein the Classroom Macboc Pro Aa Dace command ~corntant ooton...
5 answers
Staphwlococcu: JUIcus Obentuntom EltAaaenee anaeharmrenadJueprocucurauulactioucntvalianuocitvulionobentvulonreulgCebulase HASLASIRE? IMtest LDAASLASTAPHIM IcSL
Staphwlococcu: JUIcus Obentuntom Elt Aaaenee anaeharmrenad Jueprocucurauulacti oucntvalian uocitvulion obentvulon reulg Cebulase HASLASIRE? IMtest LDAASLASTAPHIM IcSL...
5 answers
Find the value of4r?e ` 2' dc
Find the value of 4r?e ` 2' dc...
5 answers
Perform the operations. See Example 1 .$$3.1+(-5.2)$$
Perform the operations. See Example 1 . $$ 3.1+(-5.2) $$...
5 answers
Given Ln#A/e+ 42)" (i _ "4)4 express the limit as n definite integral, that is provide and f(c) in the expression f(r)dxa5 af(c)
Given Ln #A/e+ 42)" (i _ "4)4 express the limit as n definite integral, that is provide and f(c) in the expression f(r)dx a5 a f(c)...
5 answers
1389 1583 1744 1890 1716
1389 1583 1744 1890 1716...
5 answers
Laplace transform1. f(t) = e^(2t−5)2. f(t) = t^2 e^(−2t)
Laplace transform 1. f(t) = e^(2t−5) 2. f(t) = t^2 e^(−2t)...
5 answers
Un automovil de 750 kg acelera desde reposo hasta alcanzar una velccidad de 40 mph e un tempo de 10 segundos. Deterine fuerza que ejerce motor para canzar esa velocidad. (10 puntos)Rosualva:
Un automovil de 750 kg acelera desde reposo hasta alcanzar una velccidad de 40 mph e un tempo de 10 segundos. Deterine fuerza que ejerce motor para canzar esa velocidad. (10 puntos) Rosualva:...
5 answers
SHORT ANSWER Wrlle the word or phrase that best compleles each stalement or answers the questlon Provide an appropriale response. 1) The data below are Ihe average monihly lemperalures In "F.and Ihe monthly natural gas consumpllon; in ccI , (or household In northwuesiern Pennsylvania Calculate the correlallon coefilcient,Temperature Consumpiion169 248 134 7137 70o 19 % 12
SHORT ANSWER Wrlle the word or phrase that best compleles each stalement or answers the questlon Provide an appropriale response. 1) The data below are Ihe average monihly lemperalures In "F.and Ihe monthly natural gas consumpllon; in ccI , (or household In northwuesiern Pennsylvania Calculate ...
5 answers
Point) A certain typing agency employs two typists_ The average number of errors per article is 3.2 when typed by the first typist and 4.7 when typed by the second: If your article is equally likely to be typed by either typist, find the probability that it will have no errors.
point) A certain typing agency employs two typists_ The average number of errors per article is 3.2 when typed by the first typist and 4.7 when typed by the second: If your article is equally likely to be typed by either typist, find the probability that it will have no errors....

-- 0.021629--