5

3 6 41. 4 and 5 If A ans falsc properties 3 3 2 41-9 In 3 2 EJ W03 F(B) 10 UI D X then 'Teest be and In 31 12 all 2 8 1 In F(B) JHi 2 Jo and froro x Determine ...

Question

3 6 41. 4 and 5 If A ans falsc properties 3 3 2 41-9 In 3 2 EJ W03 F(B) 10 UI D X then 'Teest be and In 31 12 all 2 8 1 In F(B) JHi 2 Jo and froro x Determine 2q 01 to any 5 W8 2 2 2 X

3 6 41. 4 and 5 If A ans falsc properties 3 3 2 41-9 In 3 2 EJ W03 F(B) 10 UI D X then 'Teest be and In 31 12 all 2 8 1 In F(B) JHi 2 Jo and froro x Determine 2q 01 to any 5 W8 2 2 2 X



Answers

If $\frac{3 x^{2}+14 x+10}{x^{2}(x+2)}=\frac{A}{x}+\frac{B}{x^{2}}+\frac{C}{x+2}$, then $A, B$ and $C$ are respectively are (1) $9 / 2,-5,3 / 2$ (2) $9 / 2,5,-3 / 2$ (3) $9 / 2,3 / 2,-5$ (4) $-9 / 2,-3 / 2,5$

Okay, guys. So in this problem, we're giving the equation for over three. B minus two minus seven over three B plus two equals one over nine B squared, minus four. Our goal is to solve for the variable B and plus and verify that what we get for B is correct by plugging back into this equation and checking if the left hand side and right hand side are equivalent. So let's take a look at what our first step is gonna be. Now, before we get started, I'm gonna write a little fact down here that's gonna make our lives a lot easier. And that fact is, the factory ization of the nine B squared minus four is willing to write that at the bottom. Right? Right here. So we know that nine B squared minus four is equal to three. B minus two Ah, times three B plus two. Now, this fact is gonna be useful, because when we multiply by nine b squared minus for on both sides were gonna multiply by this factory ization on the left hand side and we're gonna multiply by nine B squared minus one on the right hand side. But explain that as I write out the next step. But the reason why we will be multiplying by nine B squared minus score is because we want to get all the B terms out of the denominator and multiplying by. This term right here is gonna is gonna let us do that. So let's start. So, like I said before, we're gonna be multiplying both sides by nine B squared minus four. On the right hand side, we're just gonna be using nine B squared minus four. But on the right hand side, we're going to be multiplying by three B minus two times the quantity three b plus two. Now, since three B minus two, tie three B minus, two times three plus three b plus two is the same thing as nine. B squared minus four. This is a valid step. And so let's take a look at the right hand side on the right hand side, the nine B squared minus four is cancel out and we're left with one on the right hand side. We're going to distribute first the three reminders two times three B plus two to the first term, and that's gonna leave us leave us with four times to re B plus two. And similarly, if we distribute this toothy, so let's do it right the second term right year. That's gonna leave us with seven times three B minus two. Because in this in the first case, the three B minus twos cancel out and in the second term, that three plus two cancels out. And so now we just have a simple equation. So let's just true. Let's simple five. By using the distributive property, this is gonna be equal to 12 B plus eight minus 21 B plus 14 and that's gonna be equal toe one. Now, let's group like terms the 12 B in the minus 21 B. If you subtract 12 B minus 21 be you're gonna be left with minus, uh, eight minus nine B. And then if you group the eight and the 14 you're gonna get 22. Just add the two terms together, and so you're gonna be left with minus nine. B plus 22 equals one. Now we're going to subtract by 22 on both sides, so we get the be turned by itself. So we have minus nine B is equal to minus 21. We divide by nine on both sides and we're left with B is equal to 21 over nine or 7/3. Now, now is our chance to verify that this is correct. So what we're going to do when or in order to verify something, just block this off. We're gonna verify our left hand side, and then we're gonna verify our right hand side. So let's plug in what we have in our equation to our left hand side corner, left hand side we're gonna get is running at four over three times 7/3. That's a seven right there. Minus two minus seven over three times 7/3 plus two. In both cases, the threes cancel out here and what we're left with is four over seven, minus two minus seven over seven plus two. That's gonna be equal to 4/5 minus 79 Now we're gonna find the common denominator, And that common denominator is 45. So for 4/5 will be multiplied with 36 not 36 by nine on the numerator, the denominator. So that's gonna give us 36 over 45 and on the left and on the for the 7/9 who are gonna be multiplied by five on the new, More in the denominator. And that's gonna give us 35 over 45 just to get the common denominator 45 we see that are left hand side is equal to one over 45. Now on our second right, Bored, I'm going to be doing the left hand side us. I mean the right hand side. So let's go back to our green marker. So our right hand side has won over nine B squared minus four. We said our B was equal to 7/3 squared minus four. We said, Oh, are we set or be with 7/3? So I plugged in the 7/3 and we have hour when we keep when we square, 7/3 were beginning. We're going to get 49 over nine, and that's what this simplifies to. And we see here that the nines cancels out. So we're left with one over 49 minus four, which is the same thing as one over 45 this is the right hand side. Let's write that better and this is the right. This is what the right hand side is equal to you. And as you can see, the right hand side is equal to one over 45. And the left hand side is also equal to one over 45. This isn't an ambulance. And by the way, this is an equal to you. Right here. So we see that the left hand side, right hand side or Cleveland? So be it. Pools. 7/3 is the correct answer. Thanks for listening eyes. And I hope this hoped so.

Hello. So the question is taken from the partial friction of Class 10. So in this case we need to convert a large expression, a large mathematical expression in terms of its parts. So uh here we need to evaluate the coefficient of this, A, B, C and D. So let me start it. So let me initially ride the statement we need to convert. So we need to convert the statement X cube over. Sorry, over X -1 in two. X -2 is equal to a X plus B plus See over X -1 plus D. Over x minus two. We need to evaluate the value of A. B, C and D. Okay so let me initially right sorry. So let me initially. Right so take the L C M. On the right hand side, we get A X into X- Run into X -2. Okay and be Also multiply X- went into X -2 plus c x minus two. And the x minus one is equal to is equal to x cubed. Denominator will be canceled out on both of side. Okay? So let us multiply this time. A X into X square minus three. X plus two plus B into x square minus three. X plus two plus c x minus two plus D. X minus D. Is equal to X. Q. Let us multiply further we get X q -3 x square plus two eggs plus bx square -3. b. x. Sorry? Plus to be plus C plus D into x minus two. So that must be C -2. C minus D. Is equal to X cube. Now let us uh equate the coefficient of cube square and all of terms on the right hand and left hand side. So the coefficient of x cube is a. So a must be equal to one. Now let us Equals the coefficient or scared them so that it will remind us three plus B is equal to zero because there is not any X square to him on the right hand side. So and is equal to one. So be is eventually equal to three. Now equate the coefficient of Ekstrom or lastly with without any extra. Um Okay, so two a minus three, B plus C plus D is equal to zero and the value of phases one and B three, so that will be two minus nine plus C plus D is equal to zero. So from here C plus D will be equal to seven. Okay, the value of surplus, he now comes out and now the value of finally own strength coefficient is to see plus D is equal to zero and from here D is equal to minus two. C substituting the value of D. On this expression C plus B is equal to seven. We get minus is equal to seven, so eventually C is equal to minus seven and the is equal to 14 by substituting the value of C. So these are required really of A, B, C and D B three And a is one. So these are all value, so these are all required value. Okay, so hold this clears your doubt and thank you.

Yes. Yeah. You want to multiply matrices C. D. And A. Together. Where matrix C. Is a three by three matrix negative 1024 negative 31 negative 235 Matrix D. is 3 -2. 0 -112 and a is 2 -1. 304 -2. All right. So let's start by multiplying see with the We can because the inside dimensions match the result of this will be A three x 2. Matrix. Okay. Row one. Column one would be negative three plus zero plus two or negative one grow one column two would be two plus zero plus four or six. Road to column one would be 12 plus zero plus one or 13. Row two column to would be negative eight plus three plus two. Or negative eight plus three is negative five plus two is negative three, row three. Column one would be negative six plus zero plus five. Or negative one in row three column to would be four plus negative three was 10 or 11. And now we can multiply that with matrix a Row one, Column 1. Well let's analyze dimensions. This is a three by two and a two by three. So the result will be a three by three matrix row one, column one would be negative two plus zero or negative too. Row one column to would be one plus 10. Are going to be 1-plus 24 or 25. Roll one, column three would be negative three plus negative 12 or negative 15. Road to column Wannabe 26.0 or 26 row two, column one. There'll be negative 13 plus negative 12 or negative 25. Row two, Column 1 would be 39 Plus six or 45. Row three, column one would be negative two plus zero or negative too one plus 44 or 45. And row three, column three would be negative three. Um Plus -22 or -25.

So we have the equation. Negative. 34 Be modest. Can equal to 1/2. 24 b 1 60 And so, if we want to solve this problem, we're gonna do some distribution first. So negative three times negative or is negative? 12 B negative. Three times negative. 10 is positive. 30 1/2 times 24 is 12 b. One halftime. 60 is 30. So if we subtract r 12 b from both sides or we add or 12 B but rather keep that is a positive number. Let's go to give me 24 b. It's attracting 30 is gonna give me zero. And when I divide zero by anything, I get zero. So to see if this checks, we're gonna plug it in. So we have negative three times. Four times zero I'm honest and equal to 1/2. 24 time zero plus 60 four times zero is zero so negative three times negative. 10 is positive. 30 24 times zero is 0.5 of 60 is 30. Still, that checks. My answer is be equal to zebra


Similar Solved Questions

5 answers
AcetophenoneTarget ATarget B
acetophenone Target A Target B...
5 answers
2) transformation would not always produce an imagc that Which would be congnient to thc original figure? (1) translation (3) rotation (2) dilation (4) reflection3)N21 angle, cos A - What is sin B? In AABC , where LC is & right (3) (1) 3 4 (2) J2l (4) 3 2
2) transformation would not always produce an imagc that Which would be congnient to thc original figure? (1) translation (3) rotation (2) dilation (4) reflection 3) N21 angle, cos A - What is sin B? In AABC , where LC is & right (3) (1) 3 4 (2) J2l (4) 3 2...
5 answers
Problem 2. LetV1 = (3,_7,-3,-1), V2 = (_1,9,3,3) , V3 = (1,1,0,1), V4 = (6,-4,-3,2)Find a subset of these vectors that forms a basis for the space spanned by these vectors , andthen express each vector that is not in the basis as linear combination of the basis vectors_
Problem 2. Let V1 = (3,_7,-3,-1), V2 = (_1,9,3,3) , V3 = (1,1,0,1), V4 = (6,-4,-3,2) Find a subset of these vectors that forms a basis for the space spanned by these vectors , and then express each vector that is not in the basis as linear combination of the basis vectors_...
5 answers
What is the hybridization of S in SO3 2-7
What is the hybridization of S in SO3 2-7...
1 answers
For a weak diprotic acid $\mathrm{H}_{2} \mathrm{X},$ what is the relationship between $\left[\mathrm{X}^{2-}\right]$ and $K_{\mathrm{a} 2} ?$ Under what conditions does this relationship exist?
For a weak diprotic acid $\mathrm{H}_{2} \mathrm{X},$ what is the relationship between $\left[\mathrm{X}^{2-}\right]$ and $K_{\mathrm{a} 2} ?$ Under what conditions does this relationship exist?...
5 answers
Fll In tre mlssing value s0 that the folloning table represents probability distribution;Roo
Fll In tre mlssing value s0 that the folloning table represents probability distribution; Roo...
1 answers
An electron is traveling near a current-carrying wire as shown in Figure $\mathrm{P} 20.4 .$ If the magnetic force $\overrightarrow{\boldsymbol{F}}_{B}$ is directed as shown, what is the direction of the current in the wire? counterclockwise) on bar magnet 2 about an axis perpendicular to the plane of the drawing and through the bar magnet's center?
An electron is traveling near a current-carrying wire as shown in Figure $\mathrm{P} 20.4 .$ If the magnetic force $\overrightarrow{\boldsymbol{F}}_{B}$ is directed as shown, what is the direction of the current in the wire? counterclockwise) on bar magnet 2 about an axis perpendicular to the plane ...
5 answers
Question 14 (2 points) Perform the following calculation using proper significant figures. Upload your workings. 26.1X 423.187 22.15Question 15 (2 points) Perform the following calculation using proper significant figures. Upload your workings: 22.559 0.007 92.4
Question 14 (2 points) Perform the following calculation using proper significant figures. Upload your workings. 26.1X 423.187 22.15 Question 15 (2 points) Perform the following calculation using proper significant figures. Upload your workings: 22.559 0.007 92.4...
5 answers
Express cach of the elements of the sets in Exercises 2.2.I t0 2.2.12 in the form & + bi, where and b are rcal numbers:Vi+i Ji N-i I0. Yioo 37i J2-1+2ci Vicd ~2(2 _ 4)i3 V5-4i V8 - 30i Resolve the following paradox: 1=vi-V(-1J-I)-V-Iv-Ti-i=i'=-1.
Express cach of the elements of the sets in Exercises 2.2.I t0 2.2.12 in the form & + bi, where and b are rcal numbers: Vi+i Ji N-i I0. Yioo 37i J2-1+2ci Vicd ~2(2 _ 4)i 3 V5-4i V8 - 30i Resolve the following paradox: 1=vi-V(-1J-I)-V-Iv-Ti-i=i'=-1....
5 answers
Caw #e Ca(redt Sfuchures fclCowing Isabutyl beazeaeO- dicllocobeazeneCs- j - c; Pheryl GyckoE hexan e4 Cllovo 42 - dielylbeazene5_bromo; 2_nikobeazeic_ac4
Caw #e Ca(redt Sfuchures fclCowing Isabutyl beazeae O- dicllocobeazene Cs- j - c; Pheryl GyckoE hexan e 4 Cllovo 42 - dielylbeazene 5_bromo; 2_nikobeazeic_ac4...
5 answers
(6 pts) Letxbe & rindom vanable that represents the length of timt It takcs _ student t0 wtitc term paper for Dr. Adam SOCID logy class. After interviewing many students, WS found thalx nS anptoximate normal @stouton With mcin 6.8 hours und standard dcvuutor rowrsConven the_ Intenal >stenderdi InteralConvert the Z-scon Inietvil 42<sconinter]_
(6 pts) Letxbe & rindom vanable that represents the length of timt It takcs _ student t0 wtitc term paper for Dr. Adam SOCID logy class. After interviewing many students, WS found thalx nS anptoximate normal @stouton With mcin 6.8 hours und standard dcvuutor rowrs Conven the_ Intenal > stend...
5 answers
Emnt Kkct atbaaer plus aspirin Ioleru of aspifin noltn nck aspirin aehoi tc calculation }Obscnrd color of slitylic acid 19 FeCl}Obsendcoloraspirin - 196 Fquestions aspirin You Iccovered puIt the tudcnce?cunuminantd with salicylic acid?Gnethter tic [4t6[19 Gcient) from the why the mass of asplrin Ancoretlcal nccovered Field different (or might aspirin:
emnt Kkct atbaaer plus aspirin Ioleru of aspifin noltn nck aspirin aehoi tc calculation } Obscnrd color of slitylic acid 19 FeCl} Obsendcolor aspirin - 196 F questions aspirin You Iccovered puIt the tudcnce? cunuminantd with salicylic acid? Gnethter tic [4t6[19 Gcient) from the why the mass of asplr...
5 answers
Font CCParagraph Styles a VuLLIV5 (Cu"picnCiGT }g strand:A-T-G-G-C-C-T-A-G-C-A-T-T-AT-A-C-C-G-G-A-T-C-G-T-A-A-T-'eplication
Font CC Paragraph Styles a VuLLIV5 (Cu"picnCiGT } g strand: A-T-G-G-C-C-T-A-G-C-A-T-T-A T-A-C-C-G-G-A-T-C-G-T-A-A-T- 'eplication...
5 answers
Use table A-} to find range of values for the P-value: 06. The claim is that for the nicotine amounts in king ~size cigarettes 0 > 1.10 mg The sample size n 25 and the test statistic is 3.349Q7, The claim is that for pulse rates of' women, p = 73. The sample size is n = 40 and the test statistics is 2.463.
Use table A-} to find range of values for the P-value: 06. The claim is that for the nicotine amounts in king ~size cigarettes 0 > 1.10 mg The sample size n 25 and the test statistic is 3.349 Q7, The claim is that for pulse rates of' women, p = 73. The sample size is n = 40 and the test stat...

-- 0.022058--