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Name the following compound.CH? CH? Ch3 CHCH3 CHz3-bromo-3-heptanonebromo pentyl ethanoateethyl 3-bromopentanoate1-ethyl-3-bromopentanoateQuestion 4Name the followi...

Question

Name the following compound.CH? CH? Ch3 CHCH3 CHz3-bromo-3-heptanonebromo pentyl ethanoateethyl 3-bromopentanoate1-ethyl-3-bromopentanoateQuestion 4Name the following compound:OHCHa CH CHz CHOH

Name the following compound. CH? CH? Ch3 CH CH3 CHz 3-bromo-3-heptanone bromo pentyl ethanoate ethyl 3-bromopentanoate 1-ethyl-3-bromopentanoate Question 4 Name the following compound: OH CHa CH CHz CH OH



Answers

Name the following compound by the IUPAC system: $\mathrm{CH}_{3} \mathrm{CH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} .$ Draw a different constitutional isomer of this compound and give its correct IUPAC name.

This is the answer to Chapter 19 Problem number one from the Smith Organic Chemistry textbook. Ah, and this problem gives us four molecules and asks us to come up with the AIPAC names for each of these four molecules on. And so these four molecules are all carb oxalic acids. And so, in naming them, um, what we need to bear in mind eyes that we need to number the Corbin That's part of the carb oxalic acid as carbon number one. Ah, and then we need to be sure to find the longest chain on and then just name substitue Ince's. We would, uh, whenever we do. Are you packed? Naming s o for a, um, if we make, uh, the carbon, that's part of the carb. Oxalic acid, Carbon number one. Ah, we then have 23456 So this is gonna be Hexen oic acid, Um, and on carbon three here, we have to methyl groups. So this is, uh when when that's all put together, we get three three oof s 033 dime. Ethel Hexen. OIC asked. Ah, and so that's another point Is, um, since these air carb oxalic acids We named them as the longest chain and we add a week to it, Um and then call it an asset as it's a six carbon chain. So it's Hexindo Gassid on. There are two methods substitutes on the three position. So 33 dimethyl hexen oic acid for a s. So then for B will follow the exact same rules. So if carbon number one is there Ah, that makes this chlorine on carbon number four. Um, and the longest chain here is five. So this is gonna be a pension. Oic acid. Um And so, uh, when we assemble those pieces, we get four Chlor Oh, Penton oic acid. Okay. And so that's be so, then for see, um, we'll follow the exact same rules again. Eso won here. So substitutes at two and four. And they are Ethel substitute mints. Um and this is a six carbon chain. So it's gonna be Hexindo Gassid once again on So it's going to be 24 die Ethel Jackson Noah Gassid So 24 Oh, man. Okay, so 24 die assal hexen oic acid. Okay, um And so, uh, 11 other thing you might notice is a B and C were given to us in a different form. Um, you know, and, like, condensed letter notation. Ah. And so I drew these, uh, in skeletal mutation. I think it's much easier to work with. Ah, and I would I would always recommend doing that. Uh, so d was actually given to us in line notation or scalable notation. Um, yeah, and so d is ah, sort of more complicated, but not really. So if we named This is carbon one, um 34 So we have a nice, appropriate group from from carbon four. Um, and then on carbon six here. We have a meth a group because, remember, we do need to name this as the longest possible chain. Ah, and so Well, actually, end up calling this, um, a non OIC acid s 09 carbon acid. Um, and it's gonna be dime Ethel. So 68 dime Ethel. Um, And then remember, we put the substitutes in alphabetical order. So this is going to be four Ice of problem. Four ice. A problem. Six aids dime Ethel Nano gas it Non oic acid. Okay. And, ah, that's the answer here again. And remember, we just need to make the carb oxalic acid carbon number one number the longest chain, Uh, and then just name our substitute mints, Um, And where they are on the chain. And that's the answer to Chapter 19. Problem number one.

So in this podcast going to be taking a look at some different hydrocarbon structures and we will be determining there are you punk name. So firstly, we have following structure, so I'll draw the first one in full and we can the rationalized the name. So here you can see that with God. 123 carbons And the main chain. Some means we have propane. We have propane because we have only single bonds. And then on the second carbon, you can see that we have a florian atom. So we have to flora propane And that is how we do our naming system. So we'll take a look at the second one b. We have 23 dyke Laura Butane. Next, we have to miss a butane following on from this You got to Pantene. Next, we have quite a long names. Will starting Page E. We have six Roma. Call me style on octane. So from this name, for example, I can see I've got eight carbons in the backbone. I have one double bond on the first carbon one in, then on the fourth carbon. I have a ch three. Number six carbon. I have a Berlin. Next we have f So I got 44 diameter, one pen time. So again here, five carbons in the backbone, one triple bond on the first carbon to me file substitue INTs both on the fourth carbon.

We just have to draw the condensed structures off The given come Bones. The 1st 1 is for material to pending. It will be ch three c h w Born ch c h ch three. See, it's three options be. The name is Fif. 25 dime a tile. Three. Big scene. Okay, so it will be ch three c h. See. It's three c h c h c h ch three ch. Three. So the name is or two dime a tile. Benzene. Okay, this is relatively easier. You have C H three. So are you. So the name is so so. The name is one Be a time representation ist Okay, so lastly, we have drones to help Dean. This represented us. Th three double born carbon Gordon.

In this problem. We need to give the complete a ups the name for each of the following compounds. Okay, so here we are given with these problems. So here's the first, we will name it. So which is the nearest chain Like romain is nearer to This right inside carbon. So we will number it from here. So this will be 123 force carvings. Right? So this will make it as to to die bro, mobile tane. Alright, so now this becomes four carbons that makes butane, Right? And it is a single one. That means it is a aim. Right? So dia brahma means one diagram. A means to uh to brahmins are present. Right? Criminal present. And we can say there is the position of the brahmins is too right? So that's why we have written this uh are you basing name as to to dive Promo? You don't. So now moving forward for the part we it is said we are given with this rate. This is Treasury Treasury, Beautiful Flora you can say right but I'm writing for the I. U. P. C. Name. It should be uh let us let us number it from here. Can we number it from you? 123 Right. So there there are three carbon chain and this is of propane. Right? So uh the position of the chlor oh means chlorine or hello genes are given the priority. So that's quite the position of chloral is before the metal group. Right? So at second carbon we have one metal group and one floor a group. So first we will write the Position like position of department at which it is connected to 32 flora and two metal propane. Right? So this is how we name the, are you facing name of this form? For now moving ahead Some figures are not able to copy but I'll tell you all others, are you basing it? So, this is given to a straight. So here there are from where we can number it, first of all. So from here, because uh only triple ones are present and only uh this is given the priority because this is nearer to the change. Okay, this triple born is nearer to the chain from the right. So this will live first garment. This is 2nd, 3rd, four, quit 678 So that means there is opt but we cannot say that is in in or iron by because right now, this is a combination of into an iron too. So, that's why we have only written these. Uh Perfect. That is opt then. Let's see uh we're we're we can find it out that this is I'm trying is for triple born. Right? So this is dying. Why? Because there is uh there's a location for the iron that is triple one for uh, for the carbon number one and carbon number five. So this this will make it as completely off 15 die eine. Right, okay. So now moving ahead, we have one More party in party. We can see we are given the priority for the double bond here. So the numbering will be done from the right side 123 four. Okay, here, you can say There are four cabins, we can see but we can split it in this way. Right, let me right here. This can be speaker into this way. Twice means what this is again Here, it will be CH three and this is CS three. So that's why And that's why five carbons are present. Okay, so this is the five carbon chain already. So there will be a there will be society is given to the metal group when we are writing the are you basing him. But while numbering, we will just give the priority for the double bond here. So this will be given by four metal, that is 1234 at fourth carbon. There is a metal group that is four metal fend. Why we're not writing weapons in or pent came because there is uh there is a chain of elk into an elk into. So that's why we are writing bank one in. So this is how we name the I. O. P. S. In me. I hope you understood the concept. Thank you for watching. Yeah.


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