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Drg-uc Cnenustr(CHM 314)0V2a/[7 Reucluns f Alkenes (Chaptcr B) piopuna Spcciucally explain the dilfurencet kelwccn addillon o[ HBr the ionic mcchanisn and by thc tr...

Question

Drg-uc Cnenustr(CHM 314)0V2a/[7 Reucluns f Alkenes (Chaptcr B) piopuna Spcciucally explain the dilfurencet kelwccn addillon o[ HBr the ionic mcchanisn and by thc trcc Iatlical Irinchanibt_ Dulerences shoud include: (a) Rcactarug (p)Mechanism (Whcn witina mechanisn_ WTile Du: Commlel Bmucnue3 Alhr- dTnwo 4you eneh) Product (may pcjobiLviAL -anal Peroxn (RaR) pcesent lvbon Free KeJ cl fecrerir" Wnea ndl Ore eat 115 ]OnkIerr-

Drg-uc Cnenustr (CHM 314) 0V2a/[7 Reucluns f Alkenes (Chaptcr B) piopuna Spcciucally explain the dilfurencet kelwccn addillon o[ HBr the ionic mcchanisn and by thc trcc Iatlical Irinchanibt_ Dulerences shoud include: (a) Rcactarug (p)Mechanism (Whcn witina mechanisn_ WTile Du: Commlel Bmucnue3 Alhr- dTnwo 4you eneh) Product (may pcjobiLviAL -anal Peroxn (RaR) pcesent lvbon Free KeJ cl fecrerir" Wnea ndl Ore eat 115 ]Onk Ierr-



Answers

What products would you expect from oxymercuration-demercuration of the following alkenes? (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{2}$ (b) $\mathrm{CH}_{3}$ $\quad \mathrm{CH}_{3} \mathrm{C}=\mathrm{CHCH}_{2} \mathrm{CH}_{3}$

And brahman is added to the solution of magazine one magazine Morning dew. This this and this reacted with that. We are too intimate in order. Right? So what will go protect the form so fast? This dollar bond with earth. We are two molecules I'd like this way and he will come positive chance. Now this one will break in this direction and here you will come positive charge at this positive charge. We are minus can attack and we will get help this hair coming and this here is going and mhm. In the reaction mixture, there is also present alcohol. So martin alcohol can attack also this car work time and after the elevation of express. We will get here is the grooming and here is the O. C. Yesterday. So we will get this product and this also makes it off goes back product we will get in that human reaction. So correct option will be C. Okay

Hello Today we're doing problem nine point forty six and this problem asks us to Java organic products formed when pro panel is treated with each of the following regent. So we'LL start from and work our way to eye. So hey, we have propane all reacting with a strong acid. The strong acid in this case is so fury acid. So as you guys know, I lie just to rewrite my strong acid is h A and you know, strong asset fully associates in solution to H plus and a minus. So when we see and alcohol with a strong acid, we know that a dehydration reaction will occur. So as before, as every single problem you'd identify, What is your new cool file? What is your electrified nuclear file being the source of electron? Some has very electron rich. The only thing that's electron rich here is your oxygen alcohol. So you know that's going nuclear. Quickly attack your hydrogen to pick up a proton and get pro nated into oh, age two plus. Now we know that always two plus is not favorable. Option is not like part of charge. It likes to be neutral or negative so this will want to fall off. But in order to fall off, we will use our A minus which is free and solution to Hera. Allow out dehydration reaction to occur to rember dehydration. You go from S P three carbons Espy too. So you lose a degree of saturation So essentially from Al cane, you goto al Keen. So the way you do that is by picking up one of these beta proton. So beta proton, meaning something that is actually adjacent to your leaving group. And as she saw, it's not these ones that debate a proton, the's air, the beta protons here. So if you see here, this alcohol group was attached to this which is called your Alfa Proton and right adjacent to that is this pro this carbon here, which is your beta proton. So your conjure get acid will pick up the protons from that beta carbon. So if I were to just I raised this and show that are conjugated base, I'm confident. I said sorry will pick up the proton making a bond. When you make a bond, you need to break a bond. So Sigma bond between the hydrogen and carbon will break forming our Al Kane, making you bond when you make a Bonnie's Break a bond. So that's Sigma Bond attached to our water will break to give out dehydration, product and free water plus age two. Oh, plus, we reform our strong acid. And because we reform our acid, we know that this is an asset catalyzed reaction because we reform the catalyst. So next for letter B, we see that we have the propane on reacted with sodium hydride, sodium hydrate associates, toe Saudi and plus an H minus story in plus being unexpected ion h minus. Being the hydride, you can act you, Khun. Imagine that H minus is very reactive and would want to pick up another hydrogen to become a TSH to gas. So the only hydrogen that is a label label meaning that is it's susceptible to nuclear Filic attack or to be ripped off is this hydrogen attached to her alcohol? So we make a bond between the two hydrants forming our age to gas and therefore the bond between Owen Rachel Break, giving those two electrons of that signal bon onto options nucleus to make a formal negatively charged. Oh, minus plus H two gas. And now, if you were to continue this reaction, that's all mine. And after the strong nuclear fall to attack any electro file that we add into the mix Sure. So below here we see that we have a primary alcohol with a strong acid. I would associate into h plus and C l minus so as similar to the first one, we know that we're going to protein eight are alcohol because it was nuclear Filic properties. And now because we know we have a primary I'LL call originally, we know that this is going to occur through s into mechanism in which our nuclear file will backside attack our electro hour No electoral Filic carbon making a new bond. And when you make a Bonnie to break upon So now that we broke that bond, we can draw our substitution product plus our age too. Next we have another strong acid. So this exactly going to be the same thing as what we did before HBR Associates in solution to H plus NPR minus oxygen having nuclear Filic properties will attack this proton to put Nate itself Oren always two plus and because the primary I'LL call We know that our BR minus with its nuclear Philip tendencies because of that formal negative charge giving it extra electrons making an electron rich we're gonna back side one eighty Attack that electoral Filic that electron poor carbon and former s into substitution product. When you make a bond, you need to break a bond and reform water as well. Next, it's another way to do a substitution. Been out with Sokal. So I draw out the structure of soccer here we see that we need to first identify a nickel fall. The nuclear fall, as in all these cases, is our oxygen and electro Felix center. Here is the sulfur Adam here. This is the very election poor electron deficit center here because of those electro negative chlorine ions pulling electron density away from the salt sulphur nucleus as well as this carbon. So we'LL attack our electoral filic sulfur making a bond we make about me to break upon the label group Is this carbon old that'LL pop up make giving us formal negative oxygen? An extra loan para lecture on those lone pairs will collapse back down to reformer Carbonell making bond when you make upon you break upon. So this chlorine being a good leaving group because it's a hail ID will pop off plus C l minus. But now we have positively charged oxygen, which once again is not favorable. So we will use period in in the mixture which it with its nuclear filic nitrogen to act as a proton mop. So this mops up any protons to neutralize all your molecules in your reaction vessel and really promotes reactions to go forward to completion. So now you have You're leaving Group, which was originally hi jocks all group that was converted into a very good, very strong leaving good. So now our nuclear file being the seal minus can back side attack that on pop off our leaving group. Next we have PBR three, so same thing occurs substitution reaction. But instead of chlorine, we're talking bro Ming. So we get our brominated product finally to start off with question with letter with letter G, we have our hydroxide with a tosel chlorides or Tosel Cloyd's once again make your leaving group into a poor living group of hydroxide which is very poor living group into something that is a very strong leading group. So if I were to draw the structure but my toss of chloride, we have this just like Sokal Sulfur is the electro file here. It's very electron poor while our nickel follows of election rich oxygen. So we know that we're in a nuclear physically attack that and eventually pop off our very good leading group, which is the chlorine. Now we have our tosel eight, but oxygen is still prone ated. So we use a proton mop with its nuclear filic nitrogen with those long pair electrons to pick up that extra proton to neutralize our product. So now we have something that is a very strong leading group which in future reactions, if you were to react this with a nuclear file, we would get Essen to reaction mechanism. Something to note up until this point, you're sterile. Chemistry is retained. There is no inversion stare chemistry yet. However, if you continue to reacts with your nuclear file, you will get an s into reaction, causing your inversion on stage chemistry. So if we want to question G, you have your sodium hydride that deep throat Nate, your oxygen just like we did before number and letter B. We had our own minus. And like I said, this can act as a very strong nickel foul to react with any electrifies you add in the mixture. And this is our left far. We added here and you see here, bro Ming being the very strong leaving group it is. We attacked the carbon that is bounded to the bro mean making bond When you make upon, you know, break upon So that bro Ming will break off giving us our either and bromide and ion the last question here we see that we have our alcohol reacted with tosel chloride. So just like before, we made hydroxide which was very bad, leaving group into something that is a very strong leaving group and oh tasa wait. Now we reacting it with a nuclear fall We've in sodium that forms a respected ion this assault. So we have any plus and hs minus sulfur being our nuclear file because of its election rich nature. So we can get an s into reaction mechanism from sulphur going to the carbon, making a bond when you make a pawn in its break up on. So now we have our Sile group here, plus our sodium spectator ion plus our tar soit

So this is a podcast series aimed at covering some of our basics in organic chemistry now, So we're looking specifically at nuclear filic reactions on this is where we have an electron rich source that attacks an electron deficient species in order to induce reactivity a swell as chemical change. So fastly we're looking to designate the nuclear file substrate leaving group in the following reactions. So, like we said, nuclear files are rich in electrons and they donate electrons to form co Vaillant bonds. They are normally they are molecules that have a lone pair or a formal negative charge. So our substrate to the molecules where that our nuclear file attacks on our leaving group will depart the newly formed molecule. So a net ionic equation shows all of our active chemical species on doesn't include our spectator irons. So, looking at the fast example, So this is our fast reaction written out on DSO here we have our nuclear file because there are formal negative charge, meaning that the other species is all substrate. Then you can see that Aydin has left. So I, Dean is are leaving group so moving on to our second example now. So, firstly, this is a nuclear file. Species with the formal negative charge or with lone pairs, it's easy to identify, meaning that the other species is our substrate. You can see that Roman has left. So, bro, mean is are leaving group moving on to the next one now so you can see we identify are far more negative charge. That's our nuclear file. Meaning that the other species that are substrate that is getting getting attacked, Also known as our electric filed, bro. Mean leaves are substrate. So that is our leaving group. Next, we are using cyanide so formal, negative charge identified. That's our nuclear file. Meaning that through a series of elimination, the other species is our substrate that is getting attacked. So here we will have an s and two reaction. Where will attack this carbon on? We will kick out broening therefore, bro. Mean is art leaving Group two more One more example here. So lastly, we have ammonia NH three. Now we have an aromatic with a bro mean that is an equilibrium with the same. Aromatic, however, was replaced the bro mean substitue int with the A mean So although we don't have a formal negative charge in our Amy. We do have a lone pair, so therefore we can identify. That is our nuclear file. Meaning that all substrate is Thea aromatic. And then because our mony is in excess, it will mop up the protons from our NH two group. So we have a formal neutral charge. So that are leaving group. Is the bro mean again?

Work with the fundamentals. Inorganic chemistry. We're looking at nuclear filic reactions. Where the nuclear file is to find us are electron rich source with either formal negative charge or perhaps even alone Pair. So looking at our first example here. So since there is an inversion of our configuration, we can conclude that is an S n two mechanism. So the group that that substitutes are bro Mean atom is an ATHOC side group, which means that the nuclear file is sodium athoc side. So as it is an S N to the solve, it needs to be polar a pro tech. So, for example, we can have acetone looking at our second example again, we have an inversion of configuration. It's s n two. This requires a polar a protect solvent. So, for example, we can use d m f. Where are nuclear file is sodium acetate again? We've got another sn two reaction where we have one step mechanism and an unstable intermediate. That is not just our transition state. So we have, in essence, is we need a Polaroid protect solvent such as D. M. S O. So the leaving group that substitutes are bro mean atom is the style group, which can be donated by our hydrogen sulfide. So looking at the last example here, one more rest and to reaction single step, unstable transition state that collapses. So our nuclear filers or sodium Mathon Asyl it on. We have a poll, a protect solvent again so we can use Aceto. So here what we've done is we've named the sort of mechanism s and one s n two the nuclear file as well as the conditions.


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