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How 1 Oleslion equlvalent = resonance structures that follow the 1 rule can be drawn ior; carbonale 3 8 15 3...

Question

How 1 Oleslion equlvalent = resonance structures that follow the 1 rule can be drawn ior; carbonale 3 8 15 3

How 1 Oleslion equlvalent = resonance structures that follow the 1 rule can be drawn ior; carbonale 3 8 15 3



Answers

Draw three resonance structures for $\mathrm{SO}_{3}$

The first resident structure for N 03 minus can be found by saying that we have five valence electrons from the nitrogen plus three times six valence electrons from the oxygen plus one from the minus sign. So that gives you 24 valence electrons to play with. So we know nitrogen is Air Central, Adam, and what we're going to dio is we're going to give it a single bond to one oxygen, a single bond to another action in a single bond or third Austrian. Just to start with. Now, here we know that we need a net negative one charge because of this right? But the only way to get action to not have a charge on it is to give it to bonds and two lone pairs. If we try giving two of these actions, dough bonds will run out of octet electrons on our nitrogen so we can only give one action a double bond. And once we've done that, we may as well make it have no formal charge. 123456 six minus six is equal zero. So no formal charge in this one Now our nitrogen doesn't have room for a loan pair anymore. Which gives it 12 34 Valence electrons, formal elections and five minus four is equal the positive one. So it has a positive charge on it. Now, to balance out this positive and give us this net negative one up here, we know that both of these actions need to be negative. So to make an action negative in the lewis dot structure, you give it one bond and three lone pairs because that gives it one, 234567 form elections. So seven minus six minus seven is equal the negative one. So this auction has a negative charge and sort is this one? Now you get your resident structures here by saying, Why would nature favor this bottom oxygen here, as opposed to, say, this one with the double bond? See you then get a double bond to this action with the same two lone pairs than your other auctions. Just take up these negative charges and this nation is still remaining positive. So this is the only difference in these resident structures. So in the real structure here, each of these bonds would be functionally about one and 1/3. With these negative charges distributed across all three oxygen's

In this question will understand about the basic properties of P block elements. The question is we have to write the regency structures of carbonate and and hydrocarbons. Right. So no the danish structures of carbonate diane would be carbon which is bonded with oxygen. And this oxygen will have six electrons. Yeah. And this electron will have four. Mine is too late. The Genesee structure would be Mhm. Yeah. Yeah. Yeah. Right. So the double one has moved to another oxygen. The thought is in its structure would be mhm. Carmen Bonded with three oxygen's And this obsession will have six electrons. This oxygen will have six electrons and this oxygen will have six electrons -2. Right? So these are the same as on infrastructures of at one time now the indigenous structures of hydrocarbon. It and would be okay. Yeah minus. And another journalist structure would be Yeah. Yeah. So they started to the SAN infrastructures of hydrocarbon either Right.

We want to find out there as an instructor for S. 03 and 02 and then N. 03 So we'll begin with S. 03 years. So let's start with people have one double bond. So I'll place first double bonds. Okay. And this will be the double bonds on all the three. Alright. And then we'll have with our giving off electrons from Sanford. So we have given up electrons from Salford this way. I'm using the arrow to market. So we have this. Okay. Now we will use the electron placement. So 1, 2, 3, 45, 6 and two distinct from here. In this case it will be 1, 2, 3, 456. Right? This one actually will have four wider because you will be here which will bond with two and just make it in. Yeah, it will be 123456 And then two coming from sulfa here, this will have 123456 Yeah, be the same 123456 year. It will be 1234 Here will be 123456 Yeah, we have 123456 Here will have 1234 This is The resonant structure for S 03. Okay, now moving on to N or and or two. Okay, so I don't know. We'll have something like this from starting with single born and then I'll eventually converted according to the requirement. Alright, so first the well born let's say we'll be here and then second we'll be hearing the structure. This is these other loan structures. Now placing the electrons are there's a transfer nitrogen here, you can see that 123456 seven. Okay, so here we will have 1234 Yeah, we will have one like on here. And then you will have 1, 23456. And then you will have 1234. And I saw this one so 123456. Okay so this is a resonant structure for And auto. Now moving on to n. 0. 3. Let's move on to any three here. So any three will have the structure something like this. And I'll first again make an attribute all single ones and then can work it into the requirements. So I know three here because edited. So I'll do it again. We have oxygen oxygen wonderful one here. Wonderful one here. And the Wonderful born. Yeah. Okay now others will be As for the given. So then we have 123456. Okay I will have 1234 here will have 123456. Right? 123456123456 Yeah, we'll have 1234 Yeah, we'll have 123456 Yeah, we'll have 123456 And then you will have 1234 Okay, now let's check for the operator of LMC. Right here, oxygen has 123456 years seven years eight fulfill. For oxygen. For nitrogen. Let's check. 12345678 fulfilled. For this oxygen the same thing, 12345678 fulfilled. For this oxygen the same thing as this one. So fulfilled. For this oxygen is oxygen fulfilled? This fulfilled fulfilled, fulfilled. And fulfill this. These are all the resonance structures okay, For S. 03 and or two and no. Three. If you have any further doubts, please feel free to let me know. I'll be very happy to help. Thank you.

Operating resident structures are as follows. So first we have the rule that Adams don't move, and by this I mean the arrangement b. Adams. And if they do move, that means we have a nice summer and not a resident structure. Next on Lee move electrons in pi bonds or in lone pairs. Next, we have to make sure that the overall charge remains the same. The world charge of the system. You know, if we if we have a resident structure and we draw it so that the charge and took different, that means it's not a resident structure. It is different, the different molecule. Essentially next, we have to make sure that the bonding structure remains intact and all resident structures have the same number of valence electrons. So the resident structures of the same molecule we'll have the same number of valence electrons since all of the same Adams Turnbull for the same electric or the same elements are involved


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