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LhieenehraletSou UtinahaNneAattFlt uEcWM-LEtnn {ElalneslchestnlnInkork Mea uneenaaranaLStep IL: De-pruteinizationTransfer 50 ml of filtratc into clean 250 ml coni...

Question

LhieenehraletSou UtinahaNneAattFlt uEcWM-LEtnn {ElalneslchestnlnInkork Mea uneenaaranaLStep IL: De-pruteinizationTransfer 50 ml of filtratc into clean 250 ml conical flask.10. Add 10 ml chloroform into the conical flask You should sce layer of chloroform scparated from the homogenate at the boltomthe flask:contenle of the flask few limncs- DO NOT M. Gently swirl theVIGOROUSLY MIX SOLUTION:What happens this stage4nts

Lhieene hralet Sou Utina ha NneAatt Flt uEc WM-LEtnn {Elalnesl chestnln Inkork Mea uneenaaranaL Step IL: De-pruteinization Transfer 50 ml of filtratc into clean 250 ml conical flask. 10. Add 10 ml chloroform into the conical flask You should sce layer of chloroform scparated from the homogenate at the boltom the flask: contenle of the flask few limncs- DO NOT M. Gently swirl the VIGOROUSLY MIX SOLUTION: What happens this stage 4nts



Answers

A quantity of liquid chloroform is placed in an open, transparent, three-liter flask and boiled long enough to purge all air from the vapor space. The flask is then sealed and allowed to equilibrate at $30^{\circ} \mathrm{C},$ at which temperature chloroform has a vapor pressure of $243 \mathrm{mm} \mathrm{Hg} .$ Visual inspection shows 10 mL of liquid chloroform present. (a) What is the pressure in the flask at equilibrium? Explain your reasoning. (b) What is the total mass (grams) of chloroform in the flask? What fraction is in the vapor phase at equilibrium?

Hi, everyone. So for super really given data now what they're given, you know they had given pressure 1 95 most millimeter of mercury millimeter off, etc. That is equal to 1 95 a bomb 7 16 that is equal to zero by two for you. 658 Atmosphere then temperature is 25 degrees Celsius. That is 25 plus 2 73. Nothing but 298 Calvin the next they provided density. Density is 1.25 g per ml. The next are they provided R is equal to 0.8 to 0 for you 75 leader atmosphere or can win Paramount the next Mueller Masked ask then we know PVC called toe tonality. So the physical toe the blue charity upon m and therefore no physical to w rt upon RV in tow Em and therefore yeah, me sequel do w rt upon fleeing to pee and therefore your music will do your music will do d rt upon being certain cities. 1.25 into 0.0 0.0 820575 in 2 30 to 98 divided by P zero Quain two for you. 658 So therefore young is equal to 30 people in 566 41 875 A bomb zero point to file 658 And therefore yeah, musical, too. 119.13. Graham are mall. This is where the modern moskovic chloroform Thanks.

Problem. 26 is asking about chloroform, which the book feels is necessary dimension that it is a common ingredient found in laboratories, Not for what you're thinking. We used as a solvent not for kidnapping people. It vaporizes quite easily, which means if you want to get your Salyut out of your solvent, um, they're out of your solution. You can simply vaporizes it on. That's an easy way to extract something out of your solution. To that end, they have failed to provide something. Ah, which is the chemical formula? Are the molecular formula for chloroform? This is because they would like us to find the molar mass. And if they gave us the molecular formula, we could just go to our periodic table and figured out that way. No. Instead, they would like us to go, Ah, slightly more roundabout method and make use of our ideal gas law. Now, unfortunately, you'll notice that there is no molar mass aspect of the idea. LaGrassa, there's only moles, but ah, they've given us the density, which you'll notice also doesn't exist in our ideal gas laws. We're gonna have to rewrite this slightly differently. Here's how we're going to go about this. I'm gonna take this portion, the moles of gas. And I'm gonna write that as the mass of our sample of gas divided by that samples Molar mass. So this is how much chloroform is in our sample. And this is our, uh, unknown. The thing that we're looking for are molar mass of chloroform, and this will allow us to do something quite nice if I write this PV equals ah, massive RGs divided by the molar mass times the gas constant and temperature. What you'll notice this allows us to do is I can divide the volume over and get mass divided by volume. In other words, a density and that will let a shoehorn are density measurement in. We can also bring our molar mass to the other side, allowing us to isolate and solve for it. Let's go ahead and do that. Um, in order to do so, I have to multiply both sides by the molar mass. And to get it all on its own, I will be dividing both sides by pressure times Volume. There we go. Let's clean this up. Go away. Go away, Go away, Go away All right, And now we'll make it look purty the molar mass he's gonna be equal to. I'm gonna write the density separate. Don't forget, we still need to divide by pressure. So I will write that here. Times are gas constant times the temperature in Calvin divided by pressure. Here we go. We still have Ah, a couple of things with that we need to do before we'll be able to plug this indoor calculator. We need to make use of some unit conversions because you'll notice we have. Well, you'll see we have a hot mess of incompatible units relative to our gas constant here, but we can at least get started. Our molar mass is equal to our, uh, density right here. That's our density, which we know is 1.25 grams for leader. And I'm gonna be using for my gas constant this version 0.8 to 05 the units for which are, um, leaders Times atmospheres. Well, listen, that's not Nam. The ads and M divided by moles times. Kelvin. Brilliant. So you can see with these leaders and the leaders here, those will cancel and go away, which is what we want multiplying by the temperature, which will be ah, converted to Kelvin. So 25 degrees Celsius plus 2 73 that will turn this into Kelvin and that will cancel with this Calvin here. So we might as well put it open the county outside the prince, see where it belongs. And all of this is divided by our pressure, which you'll notice needs to be in atmospheres, at least for this version of the ideal gas Constant are extremely the gas constant to do. This will take our pressure in millimeters of mercury and divide that by our conversion factor, which is there are 760 millimeters of mercury for everyone atmosphere. We can see how the units will cancel here. Thes two millimeters of mercury will go away. Then you'll have one over atmospheres on the bottom of refraction. When you divide by a fraction, you multiply that reciprocal, making the units of this whole thing in atmospheres which is what we want. Excellent. Those atmospheres will cancel here. Um, and things are starting to shape up quite nicely. So it's plug this into our calculator and we see that our molar mass is equal to about 119 point 12 grams per mole, which is pretty close to what you'd get using the periodic table. It's about point. Ah, 0.0.2 grams off roughly. But with our sig figs, our largest is going to be three. When we convert our excuse me, our smallest is three across all these. When we convert this to Calvin, that becomes three. I put Miller leaders Go away. Millie. GIs, You've grown up. Now you're a big boy. Leaders areas are sig figs for this problem are going 119. Uh, they shouldn't even be leaders issue be moles. Let's make that real fast. Sorry about that, Grams for leaders. I'm getting my densities and my, uh, molar masses confused in my head. But at the end of the day, it's all good

All right, So, for this reaction, let's just first add up all the steps, like algebra. So we have cl two and then we have that nowhere else. So we'll just write one here in our final reaction. Uh to cl can start with the cl in this cl so that's going to be gone. And then CH three Cl is present only once. All right. And then we have CCL three is gone. And then hcl plus CCL four, the ones that we crossed out that are formed in one step and used up in the next step. Those are intermediates. So we can just write those out now. The intermediate for this reaction, R C L and CCL three. All right now, the second step here, which is slow, is going to be the rate determining step, the RDS. And so the rate for the overall reaction is going to depend on that. So, it's going to be K times the concentration of cl Times The concentration of CH three cl But we can't leave it like that because cl is an intermediate And it can't be in the overall rate expression. Then we'll go to step one which is fast and reversible. And that means that the first K times the concentration of cl two is going to be the inverse. K. I'm sorry. This should be K2 times uh C. L. And then that's gonna be squared like. So so to solve for C. L, we will divide both sides by okay to the negative one and then we're going to take the square root of everything and then that cancels out and not cancels out and we're just left with Cl then we can plug it back into the overall rate expression. So the rate is going to be K two times the square root of K. One over K. Negative one. That's our overall rate constant. Which we can factor into just a general K. And then the concentration of C. L two to the square roots of the one half power And then the concentration of CH three cl. That's our oops. There we go. That's our overall right. All right. Let's see what else did they want. So, we have the overall reaction, the intermediates, the rate determining step in the right lot. Um the molecular charity of each reaction. So let's go back here. Um And step one is going to be unique molecular because there's one reactant, step two has to react and so that's by molecular and step three has to react in. So that's by molecular.

So the first part is CN do gashes bombing. Do you see in gas tendency and gas let's see HCS Yes, home exterior riga's Well CCS 3? Yes CN gas flows CCS three gas feet fall to feel four dashes. Right, so the overall reaction will look like CN Russia's Moscow Museum vast the CH three C A Sorry, I'm just summing everything that is written CFCs three Last Cco three Gas gifts. Do you see any gas plus F cl Gas less easy and three gasp The Cco 40 Mouse Trade. Overall the option was C R D Last CFC and three forming xbl Yeah, less easier for right. It's just that final one on the overall reaction. Mhm disk use from the boss. It's asking you intermediates are CN Yes, I am six years. Yes. Do you fall step one is obviously in the molecular step two is by molecular scale up to the actions. Step three is again by molecular Yes, So depart step two is this lowest step here. So this will be the reading the mind Minister. Oh, okay. If step two is yeah, the rate determinants there. Yes, did you can do K two CFCs three. Ceo ceo descending from the deer formed in step one. Can it really dream. Right? So if anyone is going to be built forward step this will be a backwards step right? The L two. So CM two will be 14 K one over the rate of the backward reaction into the reactant. So this will be incredible. Do you them to have C 02 Under eight and 12 therefore weight is equal to. Are you doing to do you run? Can you help is that your street study CH serial three into CL two? So this will be K into CH CH three th to 12. Right? Therefore, overall orders Is three x 2.


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