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:"a Draw the products formed when each alcohol is oxidized 14.70 with KzCrzOz. In some cases, no reaction occurs 67 'A OH CHzOH ~CHa b. CH3(CHz)8CHzOH d. ...

Question

:"a Draw the products formed when each alcohol is oxidized 14.70 with KzCrzOz. In some cases, no reaction occurs 67 'A OH CHzOH ~CHa b. CH3(CHz)8CHzOH d. (CHaCHzJaCOH3-C ` .' 01

:"a Draw the products formed when each alcohol is oxidized 14.70 with KzCrzOz. In some cases, no reaction occurs 67 'A OH CHzOH ~CHa b. CH3(CHz)8CHzOH d. (CHaCHzJaCOH 3-C ` .' 01



Answers

Draw the structure and name the product formed if the following alcohols are oxidized. Assume that an excess of the oxidizing agent is used. If the alcohol is not expected to react with a chemical oxidizing agent, write NR (no reaction). (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}$ (b) 2-butanol (c) 2-methyl-2-propanol (d) 2 -methyl-1-propanol

In this problem, only this reaction, which I am writing here, just look at it carefully. Here it is. MdBR plus an triple born see will not produced alcohol. Aggie Media product, while all the other reaction will produce alcohol as a major product according to the option. In this problem, Option B, option C, option B. Uh, correct answer for this problem. I hope you understand the solution of this problem.

Okay. So when you get the products for the following reactions and they're treated with both Stadium decree mate as well as the region's for sore and oxidation. And sodium bicarbonate is an example of strong oxidizing agent and sword oxidation is mild. So it's similar to using P. C. C. Or D. S. Martin parodied and um The first one is going to be three pattern all. So the ol ending positive and alcohol and pensions five And the three indicates with the alcohol is located in this case on carbon three. Is there any at the structure We got from left to right or right to left carpet three. So if we treat this first with City Mac Grammy, it's a strong oxidizing agent. So it's going to convert it into a kitten. You have a secondary alcohol. If we have primary alcohol we'd get a car bustle acid. But secondary alcohols can we be oxidized to kittens? And this time with the region's first sworn oxidation. So the first one is oxy chloride and then this far by dimethyl so Fox Hood and the next one is going to be try a full immune. So you're going to have three ethnic groups attached to the nation. And the last one is going to be decorum, methane, two CH 2 cl to and again this is an example of a mild oxidizing agent. But because we have a secondary alcohol, we're only gonna get a cute turn. X one is going to be one panel. So I'm just gonna put this as region two and to be region one. So first reacting with Regent one, your primary alcohol. And if you react the primary alcohol with a strong oxidizing agent, get a car basal acid And then with three Agent too, we're getting out ahead. Next one is two metal to Patna. So pence. In this fire we have an alcohol and method on the same carbon and this is an example that's tertiary alcohol. This carbon is bound to three groups to methods right here as well as this purple suggestion and tertiary alcohols can be oxidized to a key tune because I mean if we were we'd have too many bombs in the carbon, we have a dove onto the oxygen. We still this massacre right here. So we have too many bonds and doesn't work for the reaction mechanism. Is it gonna have no reaction here? If you use three agents, one or 2 and next one is 24 hexen, dial so dials to alcohol in the same structure And some carbon two and 4. So, first you're acting with Ridge one, which was the system diagram it And it's going to give us a key tune. And it's also gonna oxides both alcohols. This is very important to So because of this, if we wanted to protect the one alcohol, we'd have to use TMS and doing it with sweat oxidation. It's going to Produce two key tones as well. X one is Cyclo Hexane, all secondary alcohol. So we just gotta keep tune and same for sworn oxidation to oops. Okay, S one is 1, four butin dial and we're going to get a dyke are bostock acid. This is that his beauty queen dialect acid. And it can be used in compensation reactions or compensation polarization actions. And then with sword oxidation, let's get two out of huts. So even though we get outta heads, this could also be oxides further to car myself acid. So now to hide is really just the first step in oxidation and carbolic acid is the second we get that

During structures for some oxidation reactions. We have alcohol. Starting materials have got to me Sale one Penton ALS. We meet all to pentagonal. Enough bus, Two examples. I've already drawn out the products. As you can see from this primary alcohol we generate a car broke Cilic Asset in the oxidation reaction. I'm from the secondary alcohol. We generate this key tone in the oxidation reaction. So not just a finish on these last two examples or we're doing is drawing out the same structure. However, we're gonna be adding some carbon aisles. So again, we're just making some more complex Ilic assets from these primary alcohols. So that's the first example done, and not just to look at the 2nd 1 We haven't aiming Functional group on an alcohol functional group. However, we're only adding a carbon I'll to our alcohol functional group in this oxidation reaction on the A mean functional group stays the same

I. In the given problem from the chapter, alcohol eaters and potholes, we have to write the product which is formed by oxidation of these alcohols when these are oxidized. Using quotation decree, mate. Yeah. So the first molecules cyclo hexane, all the structure of cyclo hexane. All is this where there is a ring of six carbon atoms with one of the carbon atom having oh extra bonded to it. This alcohol is a second real coral where the carbon atom having oh, age group is bonded to two carbon atoms. So when this is subjected to oxidation by petitioned I cremate. Then the product farm is our ketone where the structure of this product business. Yes and the name of the skin tone is psychlo hags in on since the alcohol was a secondary alcohol, it converts into ketone on oxidation. Then we have the reactant to Pantanal. The structure of this is CH three ch having for each group, Ch two, Ch 2, Ch three. Now again we see that this is a secondary alcohol where this carbon having always group is bonded to two other carbon atoms. So when this is subjected to oxidation, using quotation, dicho mate, The product, formed again is a key tone, having structures CH three C double bond, oh, Ch two, Ch 2, Ch three, and the name of this product is two and 10 on. So these are the products, along with their structures, which are obtained by the oxidation of the given alcohols with rotation discriminate.


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