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Be sure to answer all parts.Calculate AH Tor thc following reaction, Alter it is properly balanced with smallest whole-number TX cocfficients:CzHo(g) 02(g) C0z(g) +...

Question

Be sure to answer all parts.Calculate AH Tor thc following reaction, Alter it is properly balanced with smallest whole-number TX cocfficients:CzHo(g) 02(g) C0z(g) + H,O(g)[unbalanced]AH , [CzH,(g)] 84.667 kWuolAH . [CO,(g)] 393.5 kJ/molAH , [CO,(4q)] 412.9 kJlmolAH [H,O(g)l241.826 kJImolAH , [HzO()] 285.840 kImol

Be sure to answer all parts. Calculate AH Tor thc following reaction, Alter it is properly balanced with smallest whole-number TX cocfficients: CzHo(g) 02(g) C0z(g) + H,O(g) [unbalanced] AH , [CzH,(g)] 84.667 kWuol AH . [CO,(g)] 393.5 kJ/mol AH , [CO,(4q)] 412.9 kJlmol AH [H,O(g)l 241.826 kJImol AH , [HzO()] 285.840 kImol



Answers

Use data from Appendix IIB to calculate $\Delta S_{\mathrm{rnn}}^{\circ}$ for each of the reactions. In each case, try to rationalize the sign of $\Delta S_{\mathrm{rxn}}^{\circ}$ a. $\mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{6}(g)$ b. $\mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CO}(g)+\mathrm{H}_{2}(g)$ c. $\mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g)$ d. $2 \mathrm{H}_{2} \mathrm{~S}(g)+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{SO}_{2}(g)$

To determine whether or not these are reactant, favorite or product favored. We simply need to go to table 14.1 and look up their equilibrium constants for the first reaction. This one here, the equilibrium constant in table 14.1 is 1.7 times 10 to the two because it is relatively large than this would be product favored For the next one. The equilibrium constant In table 14 1 is 43 times 10 to the -7 because it's relatively small with a negative coefficient. Then this is reactant favored. So at equilibrium we have mostly reactant, mhm and for the neck. But for the last one we've got silver iodide dissociated into silver Ryan and iodide an ion with a K value of 8.3 times 10 to the negative 17. Also very small. So it's reactant favored. We then need to place these reactions in order of most reactant favored. This one being the most reactant favored than this one being less reactant favored and this one being the least react and favored. That would be the order, the least reactant favored. Now being the most product favored

So here we can calculate the standard entropy change using the following equation delta S. Nor is equal to the sum of the malls multiplied by the entropic values of the products. Subtract the some of the malls multiplied by the entropic values of the reactant. That's the equation that we should be using here to calculate our delta S. Not changes depending whether we might get a positive or a negative Delta S. Snort tells us if entropy is increasing or decreasing. So with this first example, what we get is a negative and tropic value -332 Joules per Kelvin. So that tells me that disorder is decreasing When we form our product. And likewise with the second example negative 816 jules, part Calvin disorder is decreasing as we form our product. Final example, one more negative value negative 97.4 joules per kelvin. So here we've identified for negative delta S, not reactions where the entropy is decreasing. So the disorder of the system is decreasing in each of the three reactions

So here we are calculating the standard and should be changed. Using the following equation, we have dealt as not. You change in entropy is equal to the sum of the moles multiplied by the entropy of the products. Subtract the some of the moles multiplied by the entropy of the reactant. So with the fast example we have negative 332 jules per kelvin. So here we have a negative delta S. So this tells me that the disorder of the system is decreasing. With the second example, again we have another negative value 816 joules per kelvin. So we have a negative delta S. And this tells me that again the disorder, the randomness of the system is decreasing as we form the products. So this is associated with the non spontaneous reaction. Because the universe is always pushing to increase the disorder, we always find that the entropy is always increasing. For the final example, we have negative 97.4 jewels per kelvin. Again, another negative delta S. The entropy is decreasing as the reaction moves forward so that randomness is decreasing

I would even saw in this reaction. Uh Do either of the following reaction go to completion? If so what factor causes uh H. To do? So H. M. C. S. Or three X plus two? It seems like we're skills this hell to acquiesce pluses. So to guess plus water liquid and being three B. Oy strikes like this brush twice a three piece for us to be a threepio for toys. Valley. That's six H. Two. No, you know a parties. Yeah. For the eggs reaction uh M. C. S. 03 solid last to excel At Weirs Gilles McCool to eight years. Right? Yeah. Acquiesce plus a sort of gas plus a risotto. Gas plus water is a liquid. The formation of gas a sort of. Mhm. Okay. The formation of gas and unfortunately, formation of a guess. I saw it too. Support party party party. S or do How are you going to 21? And of um of a normally played water non elect drops light. Mhm. Water really? Cause the reaction. Okay. Okay. Cause the reaction to go to completion. God we go to Yeah, completion then be park. Oh try is the wage toys? Yeah. Plus ties. H. Three P. 04 acquiesce. Yeah. Girls be a three powerful price d'oise son lead Plus six H. Door like fred formation of thank you formation of question talking about something with recipe tanked. Mhm. Yeah of vary um for spade every possible and of non electrolyte and off a non electoral lined we hope. Yeah electro light and water. Will cards? What will cards the reaction, the reaction to go to completion? Mhm. Of one of them completion. Yeah. Thank


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