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Pageof 12ZOOM + | >Question 8. Locate the cube marked "a" in each of the three figures on Figures 2: and 3 Compare cube "a" in the three figu...

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Pageof 12ZOOM + | >Question 8. Locate the cube marked "a" in each of the three figures on Figures 2: and 3 Compare cube "a" in the three figures: how many sides of each cube are actually exposed to the outside surface?Cube Figure 3 * 3 * 3 Figure 2 I > * 2 Figure 1 I1 I1Number of Sides ExposedQuestion 9. Referring the Question 8, if each cube Were a equal amount of living tissue which one would lose heat to cooler environment fastest ?Question 10. Referring to Question

Page of 12 ZOOM + | > Question 8. Locate the cube marked "a" in each of the three figures on Figures 2: and 3 Compare cube "a" in the three figures: how many sides of each cube are actually exposed to the outside surface? Cube Figure 3 * 3 * 3 Figure 2 I > * 2 Figure 1 I1 I1 Number of Sides Exposed Question 9. Referring the Question 8, if each cube Were a equal amount of living tissue which one would lose heat to cooler environment fastest ? Question 10. Referring to Question 8, if each cube were an equal amount of living tissue; Which one would need the fastest heat production to maintain homeostasis of its body temperature (Remember; Cubus quadrangularis is mammal ) Question 1l. As an animal grows larger; what do you expect to happen to its rate of heat production per gram ofbody mass Question 12_ Based On the reasoning above; You will formulate hypothesis for the following experiment. Small mice medium-Sized rats and large rats are available in the laboratory. We wrill measure their rate of orygen uptake per gram body mass



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Surface-area-to-volume ratio (SAV) In the design of solid objects (both artificial and natural), the ratio of the surface area to the volume of the object is important. Animals typically generate heat at a rate proportional to their volume and lose heat at a rate proportional to their surface area. Therefore, animals with a low SAV ratio tend to retain heat, whereas animals with a high SAV ratio (such as children and hummingbirds) lose heat relatively quickly. a. What is the SAV ratio of a cube with side lengths $R ?$ b. What is the SAV ratio of a ball with radius $R ?$ c. Use the result of Exercise 38 to find the SAV ratio of an ellipsoid whose long axis has length $2 R \sqrt[3]{4},$ for $R \geq 1$ and whose other two axes have half the length of the long axis. (This scaling is used so that, for a given value of $R,$ the volumes of the ellipsoid and the ball of radius $R$ are equal.) The volume of a general ellipsoid is $V=\frac{4 \pi}{3} A B C,$ where the axes have lengths $2 A, 2 B,$ and $2 C .$ d. Graph the SAV ratio of the ball of radius $R \geq 1$ as a function of $R$ (part (b)) and graph the SAV ratio of the ellipsoid described in part (c) on the same set of axes. Which object has the smaller SAV ratio? e. Among all ellipsoids of a fixed volume, which one would you choose for the shape of an animal if the goal were to minimize heat loss?

So in the given question we have auditorium A number of person is 800 sites of auditorium is 40 x 19 x eight, Which is 60 400 m. So mass of air, it will be volume into density, Which is 60 400 to 1.25 which becomes 8000 huge. Mhm. So number of moles. Oh, here will be 8000 upon. Mhm No, 29 points and power minus state. This is mall. One more Yeah value here would one more airport. It is given in the question. So this when he comes out to be 2.76-10 to the power fight. So this much amount of areas present. The second part is saying that We have 800 in auditorium. Just so delta heat generated will be This 802 61 because each person is generating 60 water feet. This becomes 48,000 in june per second. He degenerated. No, this old heap, we'll go to the air and increase the temperature of here. Right? So heat generated is possible be same as M. C. V. Then stop this. Delta Tito Ortiz. Heard of increase of temperature. Great or in please or thank nature. No. And we have calculated attempt should be in malls. So how much amount of moles was there? 2.716-24 5 into CV has given us 59. And the dot. We have to find out As opposed to 48,000 that we have calculated level But yet into Tender. Power three. So solving this, we will get to the articles 48-10 to our marriage .2.716- 22. Power five into 29. So this value comes out to be fine. 0599 degrees Celsius per second, Celsius per second. Yeah. In a round figure we can say It will be .06°. Yes. 12 seconds.

This question has five parts to it. This is the first part. We've been given some information and we're being asked to solve for how big would the cell appear? Uh huh. And so and back in 2000 times helping what it appear. Magnification is the size of the image, divided by the size of the object. So we have been given both the magnification and the size. So what you do is take the total size of image to find that you would take 10,000 times 50 to be 500,005 kilometers heartbeat. What's the number of act? Yeah, And within a mile site no attacked diameter of 3.6 for the radio. One point a volume is for third Pirates fire, third power. So what? You have 1.34 3rd times 3.1 more touch five point game for you. That's what. My name in the system. So when you get a 13.3, how much do you get the volume putting 50 micrometers. Yeah, your appearance with the cell being 50 micrometers, the radius is 25 micrometers 25. Cute, of course, is 15,625 and then times four thirds times pi, you get 63,781 0.25 So then the equation comes to 13.39416 size of one acting volume, times x You don't know how many is gonna be There equals volume of a cell 63.7. I'm sorry. 63,781 0.25 Divide both sides by 13.39416 x which is the number of active? Yes, Part two c Part C's where we have Okay, my country. And here is the final answer for part being 4761 0.87 Yeah, which is a 1.5. We are to assume a spear shape to it. So if the diameter is 1.5 on the radius is 0.75 take the 0.75 cube multiple applied by 3.14 and then also by 1.3. What you get is 1.7 2209375 This is the volume of one mitochondria. Now compare that with the volume of a single cell, which is the typical cell. 63,781 10.25 Do that comparison Onda Setting up your equation 63,781 0.25 equals 1.72 other numbers. Times X. Then you'll take X equals and you'll have 63,000 divided by 1.72 And what we get is 37,037 0.4 as the number of mitochondria if it's within that stuff. Yes, hurt thing is when you have the concentration of consciousness, one million more leaders in the question is asking how many molecules first thing is to understand. The other address number states that for every one bowl you have to explode on two types 10 to 20 1300 molecules. So the big thing is Thio brave Billy Bowl to a comparative mole compared for balls volumes. So what we're gonna do is take the one million mole and understand that this is over. Leaders understand the one million mole and then divide by 1000 million holes for everyone home and then take that number now that it's in bowls and converted into molecules by multiplied by 6.2 times. Attention car. So there is one of a couple of ways you could get a change. These two types Texas, with their power divided 5000 in the 1000 essentially as one times 10 to the third power. So 23 minus 30 20. So it's the same numbers because on the tops exporters here now it's times 10 to the 20th power. Alternatively, you can also write out all of the heroes and all the place that values have. A doctor has never We're not going to do that today. Car eyes relative Thio it essentially Get on this says you got 20 micrometers. I'm sorry. Uh huh. Close thing. This is in concentration. So basically, my God, is that and then you also have for the cellular concentration for the coast being one billion gold for later. So then you make a comparison, and then you're going to see well, how many molecules per Hexham, Kanye's molecules. So the way to do this is to take first of all, the 20 micro mole per leader and, uh, do that for later. In just a minute But the thing is talking about mole aspect. So 20 micro mole times one million mole divided by 1000 Micro moles times one mole This is again mold for later, divided by one million hole. And so, essentially, what you have is 20 divided by a million. And what you end up with his 0.2 or two times 10 to the negative Fifth. This would be in terms of molds and then taking that and converting it to molecules. You're gonna have point again. 00002 types, 6.2 times 10 to 23rd molecules. Since its Afghan dress number is 6.2 times 10 to 23rd molecules wherever one bowl would you do that? You have essentially that. You've got two times 6.2. That's gonna be 12.4. And then you have, uh, the expel its sits there being multiplied, they're gonna add together and negative five plus 23. So the exponent you'll have for 12, 24 times 10. 18. Then you've got to put that back into scientific notation. So will be 1.204 times 10 to the 19 power. So then the next step is comparing the amount of molecules that we found in G, which was the glucose being in the one million mole that you had 6.2 times 30th power number of molecules compared to the hex of hiding molecules. So 6.2 times 10 to 20 power divided by 1.204 times 10 to 19. Power that again. You can do this one of a couple ways. One way. It just simply take 6.2 divided by 1.204 and what you're gonna end up with, Yeah, six divided by 1.2. It's like, uh, 0.5 point because the decimal places it's gonna be a 0.0.5 and then you have the 20th power and then the advisor in the 19th powers Decision Adviser, they're going to subtract the SP and so 0.5 times 10 to the first power because 20 months, 19 1, and it ends up being 10.5 times 10 to the first power or that is able to find the alternative

Hi, everyone. Here it is. Given the cross section of cortical bone. Mhm. 4.8 into 10 to the power minus four. You can be square. Mask of the men is 70 kg pencil. Sprint is 100 into 10 to the power six nuclear per meter square in the first part because due to inside and upset diameter of humor, the region of cortical wound will increase Mhm mm, by a factor. 10. So our new becomes are into paint. So area new becomes Why are and to 20 square that is Hyundai. Mm. Right. Okay, that is 100 into 4.8 into 10 to the par minus four. Uh huh. Nutrition. Yeah, No second part. Mhm. The worry of the men will increase mhm, mhm by affected to an inch in each dimension. Yeah. Mm. So new volume building can chew into volume authorities. Yeah. Mhm. Yeah. No. Yeah. Yeah. March of old men upon the order Mars of new men. Oh, my substitute. The value mass of old men is 70. Behold mass of new men. We are finding mm people. So that is a mass of Newman. You will get 70,000 kitchens. Yeah, no new went after men. Yeah. 70,000 and 29.8. That is 6.86 10 to the power five Newton. So rejecting is press. Okay? Mhm. Yeah. Okay. 6.86 10 to the power five upon 4.8. 10 to the par minus two. So it is to be 1.43 trying to give our seven Newton parameters square. Mm. No friction of right and pencil. Sprint. Yeah. Sprint off. Human a ball inside of strength. 1.43 10 to the power seven back on hundreds. So it is to me 0.143 14.3%. There. So All right. Mhm. Yeah. No. Yeah. Thanks for watching it.

Look exactly the relative humidity in the container for part A. We're told that at 20 degrees Celsius, um, looking at the Souljah bility of any CEO. So the scalability, uh, any CEO is 35.9 grams of any CL in 100 grams of water. So let's find the mole fraction of water. So let's find first of all, the moles, uh, each too old, we're starting with 100 g of H 20 convert two moles, 18.2 g per mole. This would yield 5.549 moles of water and we have 35 bulls. Calculate moles of any CEO, 35.9 g of N A, C L and molar masses, 58.44 g of an A C l per mole and this would yield 0.614 moles of in a CEO. More fraction of water would work out to be 5.549 moles in the numerator and 5.549 moles, plus the 0.61 formals in this would yield a mole fraction. That's 0.9004 So the relative humanity is equal. The 90.4% for Part B. If the material placed on the platform is dry calcium chloride hex a hydrate will the solid Delic west since so for part B c a c l 2.6 h 20 Della questions If the relative Humira Lee is greater than 32%. Uh, so since the therefore, uh, it will deli since you you see it will Della quests as the relative humidity is 90% it's much greater than a 32%. And for part C, um, should the substance in the satyr dissolution in the bottom compartment B one with a higher low sigh ability. Um, so for part C if the substance, uh in the bottom of Destin caters as a high water, so the ability it's treated solution Well, uh, a lo more fraction H 20 which yields a low relative humidity. Uh, therefore, a relative community lower than 32% is required to keep the calcium chloride hex hydrate dry


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