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Question 31 (1 point) Use the list of quantities to answer the question:Volume of base used 2. Moles of base used 3. Volume of acid used Mass of acid usedIn a titra...

Question

Question 31 (1 point) Use the list of quantities to answer the question:Volume of base used 2. Moles of base used 3. Volume of acid used Mass of acid usedIn a titration experiment involving sodium hydroxide and hydrochloric acid solutions, in which hydrochloric acid is the standard solution, which quantities must be recorded?A) 2 and 3 B) 1and 3C) 2 and 4 D) 1 and-

Question 31 (1 point) Use the list of quantities to answer the question: Volume of base used 2. Moles of base used 3. Volume of acid used Mass of acid used In a titration experiment involving sodium hydroxide and hydrochloric acid solutions, in which hydrochloric acid is the standard solution, which quantities must be recorded? A) 2 and 3 B) 1and 3 C) 2 and 4 D) 1 and-



Answers

For each of the following acid-base titration combinations, determine the number of moles of the first substance listed that would be the chemically equivalent amount of the second substance.
a. NaOH with 1.0 $\mathrm{mol} \mathrm{HCl}$
b. $\mathrm{HNO}_{3}$ with 0.75 $\mathrm{mol} \mathrm{KOH}$
c. $\mathrm{Ba}(\mathrm{OH})_{2}$ with 0.20 $\mathrm{mol} \mathrm{HF}$
d. $\mathrm{H}_{2} \mathrm{SO}_{4}$ with 0.90 $\mathrm{mol} \mathrm{Mg}(\mathrm{OH})_{2}$

Okay. So Concentration of sample one will be higher than concentration of sample To buy the concentration of sample three. So the largest, Yeah, concentration has the least by new did okay solution. The in every solution there's the same amount of acid. Therefore the same amount of annuals would be required for deterioration. So same amount of acid. Mhm. Mhm. So, Oh oh. Would be required to neutralize blessed. Yeah.

Okay, So the question is asking for the p k B of methadone army, and what you want to use is this zone right here, because you know that this is the buffer. Because the fluctuation in the pH is so small and this value is approximately, I would say 10.5. So we use his buffer region, right? And this formula associated with the buffer region to solve for the peak eight a. The acid, he can't ask it of metal. I mean, and what will fit we'll find out, is by plugging in all the numbers 10.5 from the graph and 10 from the X axis right here, we can figure out that the peak A of metal Amin is around 10.5. This means that if you and P k must p k b or the the ph of the asset versus the ph of the base, you'll have to get 14. And if you do, ah, little subtraction. Here you'll get 3.5, which is exactly the answer you want

The reaction we're looking at is the following equation We have N h N 03 at n H is in equilibrium with n a n 03 at h tour with a 1 to 1 molar ratio. Just a note. So the concentration of H and 03 is what will consider first. So the moles of any wages concentration times volume generates the mullah value off 1.17 that is in Miller moles. So then the moles of H 03 is the moles of sodium hydroxide, which is the same value. So then we can determine concentration by most divided by volume. So we get a concentration of not point, not one for six. Next door, looking at the number of moles of sodium hydroxide that were in excess after the first edition. So the moles of sodium hydroxide needed where at that were added Sorry where 1.4 million moles, however, the molds that were needed were not 0.7 to 7 million moles, so the moles in excess was not. 70.275 millimeters by simply having the moles off added sodium hydroxide and subtracting. The moles are needed sodium hydroxide that tells us the miles of access

So this question is asking, What happened to it? Hydration curve. If you use a strong, he's a strong base instead of weak base. And what is special about Ah, strong base, like sodium hydroxide is that it completely associates into sodium ions and hydroxide I owns. And so when you have ah, strong base for the initial condition, you're going to have, ah, lots more hydroxide ions, which means that the pH is higher, an equilibrium as well. The 10 mils of strong acid. Well, let's carry through for the for both the strong base and the weak base, right, and then, since you end up with 10 mils of both weak base and strong base, the strong beads strong base will also have ah higher pH as a result, since you have equal parts since if you compare a weak base to a strong base and they both have the same volume, the strong base will have ah higher pH because it completely dissociated and the week basted it. And for the end, the ending pH, the weak base and strong base are completely used up. That means all high droning on my own. Hydroxide ions are completely gone. So all you consider it is this from the strong acid. Right? And the strong acid was the same for both in the end. So then that means the pH is equal for both cases and that will give you answer choice B.


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