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19. What horsepower is developed by an engine with torque of 400 Ib. ft at 4500 rpm?...

Question

19. What horsepower is developed by an engine with torque of 400 Ib. ft at 4500 rpm?

19. What horsepower is developed by an engine with torque of 400 Ib. ft at 4500 rpm?



Answers

What horsepower is developed by an engine with torque $40 \overline{0}$ lb ft at $45 \overline{0} 0$ rpm?

Okay in this question, we have to find out the way density of the ammonia. Guess so. Weight is given us zero zero point 003 10 boned and volume. He's given us one handed in eight cubic inch, which is, who want cubic feet, divide by 1 7-8 so therefore the volume. Yes, Volume can be written has 0.06 25 cubic feet. And the way density equal to wait upon volume, Which is equal to find 003 10 paul Divide by volume is humans Prime 062 five cubic feet. Therefore the way density equal to find 05 on, but cubic.

So we want the power in horsepower. So we have, Ah, angular velocity of 48 100 rpm's. We're going to convert this to radiance per second. So to pi, radiance for everyone revolution. And then for every one minute there are 60 seconds and this is giving us 502.65 radiance per second. Now for the power. This is peopling the torque times the angular velocity. We know the torque is going to be 4.30 Newton meters and we know the angular velocity is 502.65 And we're going to have to multiply this by one horsepower for every 746 watts. And we're getting that. The power is equaling 2.90 horsepower. This will be our final answer. That is the end of the solution. Thank you for watching

Okay in this question we have to find out volume marty. I'll so mars equal to 3045. Good. And the very density of the I. Is equal to 870 K. G. Bird. You beat me there. Yes. We know that the when then state is equal to must, but in it volume, volume and volume is equal to mass apart mass density. So this we become 3045 kg divide by intended in the 70 crazy per cubic metre, therefore be equal to 3.5 to witness.

The problem states, what is the power output in horsepower of an electric motor turning out 4800 rpm And developing a torque of 4.3 Newton m? So from the chapter, we know that power equals torque times the angular velocity. Um we do need to get the angular velocity in the correct units, which is radiance per second. If you do that, you're going to get that the Angular velocity is equal 500-7 radiance per second. And that could easily be found just by knowing that there's two pi radiance in one revolution and of course 60 seconds in a minute. Um, so let's plug that in. We have power equals, So the torque is 4.30 newton meters And the angular velocities 500-7 radiance per second. So this is going to give us an answer in watts and they want the answer in horsepower. So the book tells us that there is a 746 watts in one horsepower. So we need to multiply all this by one horsepower, divided by 746 watts. So the lots are gonna cancel it from the bottom, because all of these units here make a lot, and we're gonna be left with horsepower. And the final answer when you multiply all this out is to 90 horse power. Thanks for watching.


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