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Indicate the clectron pair geometry and the molecular geometry for each of the six compoundsCompoundElectron pair geometryMolecular geometry:6=o &:Ci-S-&::0...

Question

Indicate the clectron pair geometry and the molecular geometry for each of the six compoundsCompoundElectron pair geometryMolecular geometry:6=o &:Ci-S-&::0=C=o:ESF_B6=S=6:9: H H_C_H

Indicate the clectron pair geometry and the molecular geometry for each of the six compounds Compound Electron pair geometry Molecular geometry :6=o &: Ci-S-&: :0=C=o: ESF_B 6=S=6: 9: H H_C_H



Answers

Determine the molecular geometry about each interior atom and sketch each molecule.
\begin{equation}\begin{array}{l}{\text { a. } \mathrm{C}_{2} \mathrm{H}_{2} \text { (skeletal structure HCCH) }} \\ {\text { b. } \mathrm{C}_{2} \mathrm{H}_{4} \text { (skeletal structure } \mathrm{H}_{2} \mathrm{CCH}_{2} )} \\ {\text { c. } \mathrm{C}_{2} \mathrm{H}_{6} \text { (skeletal structure } \mathrm{H}_{3} \mathrm{CCH}_{3} )}\end{array}\end{equation}

For our first molecule, we have two carbons bound to two hydrogen ins. So this is what our structure will look like. We'll have a triple by between our center carbons, so each carbon has to electron groups and it has no lone pairs. So this means that the geometry around each carbon is linear. And this makes sense because when we look at it, this is completely 180 degrees. Now, our second molecule has two carbons, but now four hydrogen. So we're going to lose one bond between our carbons. So we'll have a double bond between our two carbons and a hydrogen or to hundreds coming off of each carbon. So what? This means that each carbon has three total electron regions, and again we have no lone pairs. So that means that the geometry around the carbon atoms is tribunal plainer. And now, for our third structure, we now have two carbons, but six hydrogen again will lose one bond between our carbons will have a single bond between our carbons and then three hydrogen is coming off of each carbon. So what this structure is telling us is that each carbon has four electron regions surrounding it, and that means that the geometry around the carbon atoms is tetra federal

Fresher off our core content at the very top I've discussed in detail in previous podcasts. I won't do so here just to save time. So we're gonna be drawing out some molecular geometries. So our fast one, we have C two h two. So this is all kind. I know this because off the number of protons hydrogen atoms that are bonded to my carbons when they have 100 you not some bonded. Then we have a triple bond between our carbons. But now, looking to my next structure, we have a double bond present because we have four carbons. So each carbon four protons so each carbon must be able to accommodate to each so that we have a double bond. And then my last example c two h six. This is just on. I'll key Al Cane where we just have a single bond. So it my fast structure I've drawn up is SP three hybridized. So that is mania. My second struck Dr drawn his SP to hybridize. So we have the geometry of tribunal playing art centers about our carbons are now this final structure I've drawn where we have SP three hybrid. I centers about our carbons. We have bonding uncles about 109.5 degrees. Because they have the geometry of Tetra, he drools. So we're going to come back to this very same material Podcast 72 where we will look out the bonding angles on each of these German trees.

Here. We've just got some structures drawn up on the screen and you can see we've got three here and we're just gonna be talking about potential geometries and angles that we may have, so it Firstly, if we look at our example on the far left, we have a tetra. He'd RL confirmation around this carbon here. That is because we haven't sp three hybridized carbon. It has four substantial INTs. We have bond angles of about 109.5 degrees. Next, moving on to our hydrogen peroxide example. We have all Ben structure here, and that is because off our lone pairs, which causes repulsion between our loan and bonding persons, So we close the bond angle from 180 degrees in a linear structure to about 100 4.5 degrees. Now moving on to our last structure here, however drawn, it isn't exactly how it is in terms of bonding. We need to consider our loan Parton's. So, if we were to consider are two lone pairs that would then cause our structure to be overall bent and we would observe bond angles similar to how I'm adjusting it on the screen so you can see again. Those two lone pairs caused proportions between our bonding pies, which forces are bonding angles from what would be or could millennia toe bent.

The first structure that we have to investigate is that of ch 30 h. And this is what our structural look like. Well, we'll have three hydrogen is bonded to the carbon and then we'll have a hydroxide group also monitored the carbon. And what this structure can tell us is that if we focus just on our carbon, Adam, we have four electoral regions around our carbon. So that means that our geometry with respect to Carvin is Tetra hydro. But now, if we consider the geometry with respect to oxygen, oxygen has to electron groups around it with two lone pairs. So that means that our geometry with respect to oxygen is bent in our second structure we have to look at is that of ch 30 ch three. And this is what our structure will look like. It's very similar to the one before. Well, again, have three. Hydrogen is coming off this carbon group and then we'll have ch three bothered with three hydrogen, and these groups will be attached with one oxygen atom. Now, if we look at the geometry of just our carbon. Adam, this is telling us we have four regions of electron density, so that means they're geometry with respect to this carbon. Adam is tetra huge role. But if we look at the geometry surrounding our oxygen atom, we have two regions of electron density with two lone pairs. So that means our geometry with respect to oxygen is bet. And now finally, we have the structure for H 202 which we also call hydrogen peroxide. This is what our structure will look like, so have to oxygen. And with 100 coming off of each each oxygen atom and this structure, we have two regions of electron density with two lone pairs surrounding our oxygen's. So that means our geometry of H 202 is been


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