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Complete each of the following nuclear equations:Part A{He + #'N-? +{H Express your answer as an isotope2 = 130SubmitPrevious AnswersCompletedPart B{He + {8K-?...

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Complete each of the following nuclear equations:Part A{He + #'N-? +{H Express your answer as an isotope2 = 130SubmitPrevious AnswersCompletedPart B{He + {8K-? + {H Express your answer as an isotope_AzdType here to search

Complete each of the following nuclear equations: Part A {He + #'N-? +{H Express your answer as an isotope 2 = 130 Submit Previous Answers Completed Part B {He + {8K-? + {H Express your answer as an isotope_ Azd Type here to search



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Complete each of the following nuclear equations by supplying the missing particle. a. $\quad \frac{226}{88} \mathrm{Ra} \rightarrow \frac{222}{86} \mathrm{Rn}+?$ b. $\frac{222}{86} \mathrm{Rn} \rightarrow_{84}^{218} \mathrm{Po}+?$ c. $_{1}^{2} \mathrm{H}+_{1}^{3} \mathrm{H} \rightarrow_{2}^{4} \mathrm{He}+?$

In this question, you're asked to complete the following nuclear equations and describe the type of radiation that is produced when balancing nuclear equation, All you need to do is make certain that the some of the mass numbers and the some of the atomic numbers are the same on both sides of the equation. So we have aluminum 28 producing a beta particle, so the mass number stays the same. The other product needs to have a mass number of 28 and an atomic number of 14, so 14 minus one gives us 13. Atomic number 14 corresponds to silicone with the beta particle being produced. This is beta emission or beta decay. For the next one, we have the a meta stable form of T. A. Producing a stable form of to the mass numbers and the atomic numbers are the same. Therefore, the only thing that would be emitted would be something with no mass and no charge, which would be a gamma particle. So this would be gamma radiation. Let me back up. And so the next one would be copper 66 producing zinc, 66 zinc with an atomic number of 13. So the additional product needs to have a mass of zero and an atomic number of minus one. So 30 minus one will give us 2 29. This is a beta particle resulting in beta decay. And for the next one we have something producing thorium 2 34 plus an alpha particle or a helium nucleus. So four plus 2 34 gives us 2 38 and two plus 90 gives us 92 92 is uranium. Yeah, and this is alpha decay. And for the last one we have mercury 1 88 producing a positron. So zero plus something gives us 1 88. That would be 1 88. 1 plus something gives us 80 so that would be 79 79 is gold. This is a positron emission

So we're given three nuclear equations here, and for this problem, we want to add the missing particle that completes them. So when ready nuclear equations, our main goal is to make sure that some of the numbers in the react inside equal the sum of the numbers. On the product side, this applies separately to the mass numbers and the atomic numbers. So let's take a look at the 1st 1 We'll see for the reactions. We have radium with a mass number of 226 and atomic number 88 and it is undergoing decay to form right on, which is a mass number of 222 and atomic number 86. Well, you notice that Reagan's mass number is four units less, then read on this number and radium is never sorry. But we want to make sure that they're equal. So this missing particle must have a mass number of four. Because 222 plus four is 226 and the atomic numbers we'll see that rate on is two units less than radium. So we know that this particles atomic number should be too now, a particle that hasn't mess. Number four and a time of number of two, we should know that it's an alpha particle or essentially just a helium atom. Okay, so now let's look at the 2nd 1 We have raid on again with the same mass number, and it's undergoing decay to form polonium, which has a mass number of 218 which, like the 1st 1 is also four units less than the reacting. So to balance it out, this particle is going to have a mass number four as well, and the atomic number polonium has atomic number 84 which is also two units less. So that means that this particle must also be an AFP article. So that was last one we see 100 Adam named deuterium because it has a mass number two has Neutron is being bombarded with this hydrogen atta named Trillium because it has a messenger. Three. It's two neutrons and they're forming an alpha particle and something else so sick of the reactor at the mass numbers in the reactions. So we have massive of two mass number three. You add them together mixed. Five. We just add this for clarity five. And we have a massive number of four on the product side. That means that to balance it out, this particle is going to have a mass number of one. Now, if we look at the atomic numbers, they're both once they add up to two. But then helium or this Alfa particle already has two here. So this that means this particle must have an atomic number of zero. A particle with no protons. But a mass number of one must mean that it's just a neutron. Is there a go? Mathematically? It checks out and there are answers for a We have an Alfa particle or helium atom. Same for B. We have an alpha particle en for see We have a neutron.

Almost a nuclearized dogs can undergo nuclear reactions in order to convert into stable dartanyon p I. In this process, particles such as of a particles beat a particles. Positrons are gamma radiation will be emitted. Let's look at some examples. Let's say we started bit see Element, which has a atomic mass six. If this Emmett did, uh, if this gave rise to ah boron at them with the mass number off live on and their atomic number five, what kind of radiation will it emit in the process? So in order to figure this out, we have to balance the mass numbers under estimate numbers on the two sides of the equation. Since the mass young boys, a lot of these islands, the particle emitted here has to have a mass numbers evil. Since the atomic number is not balanced in order for both sides to have a natale MC number daughter off six, this particle has to have a charge off run. So this has to be, uh, plus it drawn that was emitted in this case. So positrons are indicated or symbolized by E and has a mass off zero. The only difference from electron is that it has a positive one charge. Let's look at more examples. Let's say we had sorry for 35 with their atomic number 16. If this Emmy did an electron or beat a particle march village form but is the daughter nucleus, it will form in the process. So it has to have a mass number 35 because yet zero. And the atomic number has to be 17 for both sides. To have a total atomic number off 16 to this corresponds to clothing. Let's just get a couple of more examples. Not say they had a nuclear phone. A dream 90. Do you carry? Yeah, We dedicate what has to be the period on nuclear, in this case again, by balancing the master over on the two sides, it has to have a mass number off 90 I the night to make number off 38. This corresponds to throwing to him, so they had to make number 38. If you look at the PRD table, corresponds to start him. Let's look at a few more examples this month. Door town has a atomic number 83 If it emitted a have a particle, what is the daughter. No clear right it was from. So by balancing the mass number two sides, we get two or six. As the merest number off the doctor knew bliss 80 run has to be. It's at the make number, and this corresponds to Italian.

In this question, you will complete the nuclear equations and described the type of radiation. When completing the nuclear equation, you're simply making certain that the some of the mass number and atomic numbers are the same on both sides. So if this is what is provided in part a something plus 11 should give us 11. That would be zero and something plus five should give us six. So that would be one, something with no mass and a plus one charge would be a positron. So this is positron emission. For the next one we have sulfur 35 producing a beta particle. So zero plus something gives us 35. That would be 35 and minus one plus something gives us 16. So that would be 17 and 17 corresponds to the element chlorine because of this beta particle, this is beta emission. The next one we have something producing yatirim 90 plus a beta particle. So zero plus 90 should give us 90 and negative one plus 39 gives us 38 38 is strontium Because of the beta particle here, this is beta mission and for part D we have business to 10 with an atomic number of 83 producing an alpha particle, 84 2 is an alpha particle. So four plus something should give us to 10, that would be to six and two plus something should give us 83 that would be 81 81 is element Valium. And because of the alpha particle, this is alpha emission and for the last one we have something producing you trim 89 and a and a beta particle very similar to what we just did up here. But it's the atrium 90. So we're going to end up with strontium 89 instead of strontium 90. And this is still alpha mission. Mhm I'm sorry. This is beta mission because of the beta particle just like up here.


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