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Light of wavelength 491 nm is incident upon a single slit with width 2.9 x 10-4 m. The figure below shows the pattern observed on a screen positioned 213 m from the...

Question

Light of wavelength 491 nm is incident upon a single slit with width 2.9 x 10-4 m. The figure below shows the pattern observed on a screen positioned 213 m from the slits What is the distance in cm. Please round your answer to two decimal places

Light of wavelength 491 nm is incident upon a single slit with width 2.9 x 10-4 m. The figure below shows the pattern observed on a screen positioned 213 m from the slits What is the distance in cm. Please round your answer to two decimal places



Answers

Light of wavelength 633 nm from a distant source is incident on a slit 0.750 mm wide, and the resulting diffraction pattern is observed on a screen 3.50 m away. What is the distance between
the two dark fringes on either side of the central bright fringe?

The wave optics chapter and have single slit diffraction pattern as shown in the figure and having wavelength lambda equals to 4 95 nanometer. The stream on which the pattern was projected is located at a distance L equals to 2.77 m from the split and the split has a width equals two 2.73 mm. So we have to calculate the width of the central maxima. W. So worth of the central maxima W. It is equal to two lambda capital L. D. Whereby small eight. So substituting values. So we get to market by lambda which is 4 95 10 to 10 to the power minus nine m and L, which is two point double seven m. They were by A which is 2.73 molecular weight into the power minus three m. So from here after solving we get with of the central maxima. W. This is equals two 5.63 mm. Okay, so this is the answer for the question. Okay, this is the work of the central maxima of the single slit diffraction pattern. Okay.

So this question belongs to the wave optics and have single diffraction pattern as shown in the diagram from the laser light. And we the pattern is located at a distance L equals to 3.17 m from the slit. And the birth of the slit a. It is equal to zero point triple five mm. The worth of the central maxima. W. It is equal to 5.81 Okay, so we have to calculate here the wavelength of the laser light used. Okay, so we have to calculate here linda. So we know that the worth of the uh worth of the central maximum for the central maxima, it is equals two lambda Hell. They were by a small a. So from here after rearranging wavelength λ,, this will be equals two wavelength lambda. This will be equal to W. A divided by two, multiplied by help. So substituting values of media to lambda calls to W which is 5.81 So 10 to the power minus three m, manipulated by A, which is zero point triple five mm. So 10 to the power minus three m divided by two and L, which is 3.17 m. So from here, after solving yet wavelength lambda equals 250990 m. So this becomes the answer for this question. Okay, This is the wavelength of the light used. Okay.

In this problem, the distance of the bright from from the central maximum Why is equal to M. Lynn Daddy by small day and is the order of fringe Lyme disease length and days the distance between sweet and a small distance between salutes? So I can write why one is equal to claim Daddy by small day? And, similarly, why two is equal to to blame Daddy by small day? No delta is equal to why to minus 51 which is required to two blame Daddy two blamed the by small D minus claimed to be by small D. Don't simplifying it further. I get the value edge claim that B by small d so blamed bicycle to tell Whitey by its capital d. So just putting the value in this expression I can write lame bicycle too. 0.76 multiplication and 10 to the par minus two m multiplication 0.15 Multiplication tend to depart minus two m Bye, 2.5 m on simplification I get blamed is equal to 456 multiplication 10 to the par minus nine m, changing it in nm. I can write the wavelength of light. I'd add 456 nm. This is the wavelength of the light

The defection pattern. Looks like here is a bright fringe. Christ burning. Um, it was zero. Then there's a second right fringe. This location corresponds to m. It was one on this location. Corresponds to M equals two. We are trying to find these distance s. So will you be using de sine theta equals m Zander, where emmick was too. And scientists will become yes, over sick to scream Distance equals M equals two Vander So s becomes ace becomes do lambda a park, a city over the Argus D You are the workers. These are so it goes to a generally a start arm used for the slate wit for singers it so that we correct that are these will be ese so two times the left and is 630 nanometer. The distance from the sick to screen is two meter or 2000 millimeter and a Z 0.4 millimeter. So this comes out to be two times 6 30 dimes. 2000 divided by 0.4. Nana Leader, which comes out to be 6.3 time stand to their six man a meter, which he's 6.3 millimeters


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