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5 Problem (2+2 points) Consider the following sets A={1,2,3}, B = {1,3,5} , C = 0, D = {0}; E = {1, {2,3}}.Find the union of A,B, then A,C , then A,D, then A,E.(b) ...

Question

5 Problem (2+2 points) Consider the following sets A={1,2,3}, B = {1,3,5} , C = 0, D = {0}; E = {1, {2,3}}.Find the union of A,B, then A,C , then A,D, then A,E.(b) Find the intersection of A, B, then A,C, then A,E, then C,D.

5 Problem (2+2 points) Consider the following sets A={1,2,3}, B = {1,3,5} , C = 0, D = {0}; E = {1, {2,3}}. Find the union of A,B, then A,C , then A,D, then A,E. (b) Find the intersection of A, B, then A,C, then A,E, then C,D.



Answers

Determine the intersection and union of sets $A, B, C$, and $D$ as indicated, given $A=\{-3,-2,-1,0,1,2,3\}$ $B=\{2,4,6,8\}, C=\{-4,-2,0,2,4\},$ and $D=\{4,5,6,7\}$. $$A \cap B \text{ and } A U B$$

So here we want to find a into sector C and a union See so a into sexy means. We're talking about all the numbers that are in both A and C, so the common numbers are negative, too. Zero in two now for a union. See, we just combine both of the sense we have negative floor negative three from a negative two from both of them. Negative one from a zero from both. One from a two from both three from day and four from C.

To find b intersect to see we need to find all the numbers that have been both a from from both B and C So you see that they have two and four in common for being union. See, you combine the two sets together So we have negative for negative to zero from SETC. Give me a two and four from both of them and there were six and eight from set B.

In this problem we have given that what A. That set A. There's nothing but 1234 said to be is 24 five and eight said C. S 34 56 cents six. Now, first we have to find be union. See the union serious. All the elements that coming BNC. This is 234 567 and Mhm. Next you have to find a intersection B. In this section. We are the common elements between you and me which is two weren't full. Next we have to find A minus C. Which is the elements which are there in A but not in C. Which is one. And don't let's look at part B. We are given that the universal set S. S E, B, C, the E. And S M E. D. B S B D E and and Beyonce subsets of. Yes. First you have to find mm intersection B compliment. So intersection. We are the common elements between A and B. Which is B. N. D. Complement of which will be the elements which are not being me. So see. And next we have to find a union. Be intersection A union be there's nothing but E B. D. E. And not on. That means the elements in the universal set, which are not evD, which is just suit That's all.

To find the set that his be intersected t. That means we're looking for the numbers than in both B and E. So we hav they share four and six in common. So were four and six for be union de. You want all the numbers from both of them. So we have to for where we also have five. So we have to four in both. Um, there were five from D six. Rumble with them, Senator from D and eight from B.


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