So once again welcome to new problem. This time we have ah born that's sitting on this office and it houses office area, cross sectional area given by, um, 3.6 centimeters squared and we always want to transform the two middle squared by multiplying by, um bye. One meter squared of ah, 100 centimeters squared. And this is gonna give us 3.6 times 10 to the negative. Four. Be two squared. Also the heights off the bone is 22 centimeters. Original height off the bone is 22 centimeters. We want to change that to meters. So it becomes one meter 100 senator unit conversion and we end up getting zero point to two meters. This is the information that's given in the problem. Also, another thing that happens is these air force being applied in the course sectional area. That force f we call it in Newton's 3.3 times turned to the for mutants. That's the force being applied. Our goal, in part, is to determine if the born well, the born break. Um, if the stress sigma is greater than the compressive strength off the bone, then obviously the bone is gonna break? Absolutely. The compressive strength of the bone is 170. The mega Paschal's You can see that. So that's the first thing I wanna find out in the problem. The second thing we're looking for in the problem is that if the, um the bone does not break, what's the change in length that we have? It's the bone does not break so in, but a We have to compute the stress, which is the force by unit area. Well, given the forces 3.3 time stand to the four Newtons and we divide that by 3.6 time. Stand to the negative for minutes wed. When you simplify that, we get the stress. A cz being equivalent to 91.67 Newton Amita squared Then obviously, if you compare that 270 it's less than that. So the stress is less Thune, the compressive strength. Um so say the born mmm does not break, you know, because the forces bottoms out. I mean, you know, this this force that's being applied is less than the compressive strength that the bone can take. So the bone itself doesn't. It doesn't. Kevin doesn't break on the next page, we're gonna see by how much does the land change given that these air force being applied on the bone itself. Now, this is a relationship between stress and Young's modules that's connected to the change in land and original men. So sigma he this is the stress. And this is the Youngs modular. So of elasticity and the Youngs modular us off elasticity. It's given us The value of start is 15 times 10 to the nine Newton Mideast squared. This is gonna help us Compute Doubt L, which is Sigma over times l note and this becomes signifies simmers 91 0.67 Newton meter squared. And then, uh hell, not his Sam was a 0.22 meters and then Young's model asses 15 times 10 to the nine new committee squared. That gives us the change in length as being equivalent to one point 33 millimeters or rather, 1.3 millimeters. You know, we can round it off if you change it to millimeters. So I hope you enjoy the problem. Feel free to send any questions or comments and have a wonderful day. Okay, thanks. Bye.