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If a on the person moon has 52 kg mass on the earth, a) 8.7 how many kilograms ' masa would that peraon have b) 11.3 kg The removal ' 9) 13.6 kg d) 52 kg ...

Question

If a on the person moon has 52 kg mass on the earth, a) 8.7 how many kilograms ' masa would that peraon have b) 11.3 kg The removal ' 9) 13.6 kg d) 52 kg 91 68 kg electron ' from an atom Is binding called, aftinity atomizing ionization electron affinity none of the above Plutonium - can be produced mining from plutonium Processing uranium in - thermonuciear reactor breeder reactor from chemical reaction in all of calorimeter the aboveAssuming no friction 4.0 what is the work (in

If a on the person moon has 52 kg mass on the earth, a) 8.7 how many kilograms ' masa would that peraon have b) 11.3 kg The removal ' 9) 13.6 kg d) 52 kg 91 68 kg electron ' from an atom Is binding called, aftinity atomizing ionization electron affinity none of the above Plutonium - can be produced mining from plutonium Processing uranium in - thermonuciear reactor breeder reactor from chemical reaction in all of calorimeter the above Assuming no friction 4.0 what is the work (in Joules) required to give - 20 kg mass velocity of mls on leveled surface? a) 30 J b) 60 J c) 45 J d) 160 J e) 90 J 5. A side of a square shape is measured with ruler as 14 mm: Which one of the following answers is the best representation of the area of this square ? a) 14 mm? b) 1.90x10? mm? c) 20 mm? d) 196 mm? 2.0x10? mm? Age of the Universe is calculated from: Carbon dating, Uranium dating; Age of rocks, Hubble's constant; Fossils What is the weight of a 100 kg person on the Earth? 50 N b) 490 N c) 980 N 9.8 N a) many kilocalories of heat is needed to bring kg ice at 0 %C to boiling point 50 points): How a) 120 kcal b) 956 kcal c) 80 kcal 50 kcal e) 130 kcal



Answers

Sphere $A$ with mass $80 \mathrm{~kg}$ is located at the origin of an $x y$ coordinate system; sphere $B$ with mass $60 \mathrm{~kg}$ is located at coordinates $(0.25 \mathrm{~m}, 0) ;$ sphere $C$ with mass $0.20 \mathrm{~kg}$ is located in the first quadrant $0.20 \mathrm{~m}$ from $A$ and $0.15 \mathrm{~m}$ from $B$. In unit-vector notation, what is the gravitational force on $C$ due to $A$ and $B ?$nitrocellulose to a speed of $11 \mathrm{~km} / \mathrm{s}$ along the gun barrel's length of $220 \mathrm{~m}$. (a) In $g$ units, what is the average acceleration of the capsule and astronauts in the gun barrel? (b) Is that acceleration tolerable or deadly to the astronauts?
A modern version of such gun-launched spacecraft (although without passengers) has been proposed. In this modern version, called the SHARP (Super High Altitude Research Project) gun, ignition of methane and air shoves a piston along the gun's tube, compressing hydrogen gas that then launches a rocket. During this launch, the rocket moves $3.5 \mathrm{~km}$ and reaches a speed of $7.0 \mathrm{~km} / \mathrm{s}$ Once launched, the rocket can be fired to gain additional speed. (c) In $g$ units, what would be the average acceleration of the rocket within the launcher? (d) How much additional speed is needed (via the rocket engine) if the rocket is to orbit Earth at an altitude of $700 \mathrm{~km} ?$

I support a little rickety. So given the release of the proton mass of the proton, which is standard on the proton, must restore this into tour where R is the radius of the proton. That's what we know from party. Since it was a long question, I felt like that was important. So from the lost constellation Energy, you know that the energy that the initial step has to be equal to the finals. So I think, over the expression for the initial wishes to there's two protons times two times one over the mass of the proton, masses of the proton times velocity. Since it's completely and at the end gonna be okay, times the charge of the time, which is this he squared because it's again just use you to represent the charge terms to are. So now we know the results of the varsity so iffy, isolated for the variable be. We know that this will cancel on so I only need to do is divide by m and then sprayed with the whole thing So it becomes to our and tree lined by them is here and now it s very because of us here in the square. Another see talking all the values that we know today, So it wishes So These are all bodies that we know so we can just jump up. We can just substitute device for the variables. So a coon consummate nine times 10 to the comer nine times a charge that the proton, which is on 0.6 times sent negative 19. And this is all over two times the radius of the hotel, which is 1.67 kind. 10 to the native trace. Remember these aero standard units of escape? This is just cool points and this is cool on. This is K G on. This is 27. Makes clear that this is 167 in P G's hands on this condition. This 1.2 and to the negative 15 Big Six to ask yourself. But he just compute this account. There we can get that velocity is 7.58 There's central in front of eight. That's not just meters. Send me five times into the 6 m per second and that's for a party. They were given the center to this does it, given the additions the center of the helium nuclei giving the mash the nucleus and from the conservation of energy. Uh, you know that once again, Yunus ot will be final. Soc used this expression once again. So let me just bring it down. Uh, no, that's all right. All right, There we go. I had enough of this here. First, let's bring this over. Yeah. So let's bring that down here. Yeah, so, once again, it's the same equation. But this time you're just using. You have four. Uh, it's too to hear about trans systemic union. Yes. So this is a two. So there's just the two here because of the heat in here we are. Once again, it's the same bath works out to the same equation than if we just instead of writing, they could have the variable Centrino is gonna be, uh it's actually going to be slightly differently just to hear. So it can be for if he saw from velocities industrial finding again. Okay, Times t squared over the mass of the proton tax radius. And if you saw for this, I don't think I need to write off the Value Street. Each of these variables the same question so 7.26 seven points 26 attend to the six years per second. Now she would want to part C. So when reminded Jovan, uh, the different trend averaged Organizational, frantic energy of a particle with mass m in a gas at absolute temperature is 300 KT. That's just the former and case Boston's constant in this case, the once again with the law Conservation energy. You know that three over to Katie, since the gas party is equal to one over and B squared. So if he's ultra TV, you get that expression is and times, uh, velocity squared sensor. Just isolating for the tea on you need to do is multiplied by their typical of this On Qi, I would divide by K to the other side. So the next time streak a So these are all causes, you know? So she struggled, and we don't need to plug it instance. This is straight from the question. So you should be able to plug this in if you can be to settle careers and 2.3 times 10 to the power nine. Tell them that's gonna be the temperature. Actually, I want to party. The calculations are based on the particles average feed. The distribution of feed ensures that there certain percentages with greater speed than the average speed. And these particles can undergo the necessary reactions in the some court to the kinetic. And he's required for the fusion reactor reactions correspond at to very high temperatures. So very high temperatures, that's it for this question.

Okay, so we know the do with the energy conservation law, the potential and she must be equal to the canary Angelo particles. So therefore, have cake. You score over to ours, you go to two times what happened when you want to work. So the distance between the party goes to art is because the party has a radius are it's just a tool particles. This in between these two are which is the diameter. Okay. And the reason why is two times 1/2 and where you want square here is because they are true particles and each particle has any kinetic energy we justify won't have everyone's we're okay and m is the mass of a proton. M v wants his speed of proton. So therefore if to some arrangement here we men should have be We want people to ah, square root kick you square over to m r and K. Here's the cooling constant. So these under the condition we know final question. So we know the charge on the protons 1.6 times tender upon igniting cool. The massive programs 1.67 has 10 reporting 27 Children radio given as 1.2 with Has tender partner, 15 meter in colon. Constance nine times Tend opponent in Utah Transmitters were because we're so therefore we did when everyone is just simply equal to square root. Um, do you see NI Times 10 to the power of nine Newton Times meter square Her Acquittal Square and times 1.6 times potential partners in 19 cool on square over two times 1.67 times Central Park next 1 27 killer work end times 1.2 times tend to apart in 18 15 meter and it will give us the Speedo. Proton is about so employing by a times 10 to a part of six, you know, for second okay, and for question, be well, which is the same formula. And this is the formula with the right found last question by an interest in his case is the case is different because the last time was a Proton proton collision and in question, be the cases here in here in collision, so therefore the charge must be different. In the distant between, the heating is deprives wall and the masses different as well. So therefore we're happy to a single square. Okay, Q square of MD. So we know que in this case is to eat, which is two times 1.6 times 10 to Ponting. 19. Quill, which is here with a 3.2, has tend to opening night inkwell and the mass. In his case, it was described in the question, which is 2.9 times the mass of a proton, so have five times tens upon in 27 Q Aware and this is was given us 3.5 times tender pounding 15 meter. So therefore, when the terminal B two now. So the speed of a heating, um, is about square root nine times 10 to the power nine Newton past meter square vocal elsewhere at end times 3.2 times tend to apartment in 19 Cool on and with square here and this thing here over by times £10.27 killed. Where end times 3.5 times potential power off next 15 meter and this will give us be truly is about some point to six times 10 through power, six meter per second for questions. See, while we know they translational energy origins, national community energy can be able to to really go to latimes Katie and the K in his case is the Bozeman Constant. Okay. And he's the absolute temperature. So let's look at the first South case, which is Proton proton collision. Therefore have Katie. One is equal to three over to Katie one. So therefore Web t y is equal to to over three times. Kate, you won over Kate, and we know the translation of banana. Angie, can you go to kinetic energy, which is want happened? You you want square therefore eventually wept. He wants equal to number. You want square over three quick three k. Okay, then we know. OK, which is the Bozeman? Constantly seek with 1.38 has tens of parting 23 June broke help and we won't worry no around. The first question, which is some point by it has turned to politics were per sec so therefore could determine the absolute tent temperature or the case one so t one can be equal. Teoh one point 67 times 10 to the power off. 10 to the power off. Never 27 because it is just a massive proton kilograms and then times Ah, some point by a times 10 to power six. Meet her per second full house where? Okay. And over three times 1.38 times central power of 23 juco Calvin. And this will give us the absolute temperature for the first case is about to a point 32 times tend to appall Renai Calvin as techno candy. You didn't get in collusion, so we should use the same formula. And eventually we know teeth. Who can we go to over threes? Has Katie too? Okay. It was okay to easy with Wyatt. And we two square capital m here is the mass of the heating nuclear. Okay, so eventually, Tito is ableto capital m we two square over three K. We know being to the some point to a £6 tender politics meter per second and the massive heat a nucleus about five times tend to partner Nick next to, uh, 27 kilo brain. So therefore, we'll have t two is equal to by times 10 to the power off number 27. You know where and times 7.26 times 10 to the power off six, You're per second square over. Three times 1.38 times 10 to the power part off number 23 ju per Calvin. And this will give us t two is people who ah, six point 37 times tend to a power of nine. Calvin. So for the last question, well, apparently the temperature we just calculated its way higher than the 10 during the sun's core. Okay, so well, all these calculation, we just It was based on the particles ever speak, which means that the distributions off speed to ensure that it is always greater. Then I ever speak with a survey among Okay, any energy that was generated by party coz ensure that particles can undergo unnecessary reaction in the sounds case. Okay. And, uh, these are my answers for this question.

Hello, everyone. This is the problem based on nuclear fusion. Enderson end up some of the energy they need to do to use the knob hydrogen into helium and in the court kill. You mean tow car. But you hear me upto calculate I'm not going to read complete. Better get up. This is quite many so directly. We're discussing the problem. A Yet it is off. What if the programs are moving? Because they misspeak and they collide head on. So this is one of the brutal. This is another pro toad. If they're polite ng head on, Big Tim Maliti even is going to veto The release of the proton is given when I went to in tow 10 to the power off minus tip images. What is the minimum of spirit required for you sent to occur? So, basically, except to solve this problem is a continuation of energy When they're polite, carded technology convert into potential energy. So I kind of took initial Innogy. It's kinda tick on kind of chicken or you must be equal toe potential energy off interaction when fusion will take me. So it will be how and b squared for one photo half MV squared for other promote and that will be gate. You want you to weigh our potential energy off inflection. So from here we can fight the validity that will be okay. E square garden Proton is blessing. Start on and report pro. Tony, let's eat. Okay. He square divided by aumento substitute. You will get down to que ella prostrated force posture night and turned to the bubble nine is jarred on photo and Marcia brutal separation between them it so what? To win toe 1.2 in 10 to the power off, minus trip images. The arms are doing it. You will get their street to be 7.26 in tow. Tend to live our 6 m per ticket. So this is the onset off part eight? No, we start solving the party in the park. Needed us for nearly a million billion blocks. B I speak. So what exactly solve it? Same. Hey, livable. Be part for you. You know, helium nucleus start on helium nucleus, lest we month is four times up that up. No good. That is according to 1.67 in 27. Katie on the radius it is given three point pipe into 10 to the power off minus 50 m. So conceptually does it if both are moving towards each of it. But symbology then carried technology should be equal to potential energy off introduction. So how? MV squared plus half and be square. We okay, so I stopped he quite off me upon our so from here you will not think the velocity off and provide ticket by this A polite nine in 10 to devour nine it 1.6 to 10 to the power off minus 90 your M Marcel helium nucleus pour into a 1.67 and 10 to the power bi miss 27 Katie. And this is the separation that is doing toe key 0.5 into 10 to the power on solving it. The velocity o this practical ability 11.5 it 47.26 x 10 to the power six Nieto per second. So this is the answer off. Be part of this problem? No, In the sea part we have to calculate that picture of protons and helium so that they fuse together. So in c part we have to find the temperature by which no one I'm you didn't are will be accelerated so that the fuse together. So here, kinetic energy gained by the pro bono or Bob Articulate three get you a toe and that should be skull toe and the square by two. So from your temperature we will get and the square by three k Your kids, boatman constant. So for protection, you can find that average marched off for 1.67 by Let CTV have already completed. They've been went private and you can devour six leapt up our second square three in towards my constant but 138 to 10 to the power minus one Petri All solving it complete. You will get 0.3 and 10 to the power minus. Sorry. Tentative. Overnight, Calvin. So this is that temperature required to accelerate capital? No, for alphabetical or helium nucleus or in tow? Just a moment. I have toe correct. A little bit here in substitution. I have computer mistake. I'm correcting it. Just a moment, please. The speed off medium. It would be 6.4 day if you have your big question and we have to discuss just a moment. How would these reactions can occur can be defined in the interior. Off this. See you you can pollution where we store. Why are you could average stay? The distribution is big in source that get out of it asserting there are always certain percentages. I speak great today. Average speed. Best of particulate unlivable Under who, If you would get the action in the port of listen any thought.

Hello. And then this question here, we're going to be talking about energy released in a nuclear decay. So to begin with, were asked to write an expression for the heat needed to melt a massive water or massive ice. And okay, and that is just equal to the very first pride party. So the energy required is E. And it's equal to the mass of the water that we're trying the mass. The ELT my ice that we're trying to melt multiplied by the latent heat. This l here is the latent heat of fusion And it's the amount of heat or amount of energy required to turn something from a solid to a liquid without a change in temperature. And for water it has a value of L. is equal to 3.3 Times 10 to the five jewels per kilogram. Now the second paris is asking us, what is the um when a nucleus disintegrates by an alpha decay? How is the change in mouse related to the energy? So? Well, the change of mass is delta. M. And if we multiply this by C squared, we get the energy from Einstein's equation E equals M C squared. So the change in mass because there is a change in mass of the products of the nuclear reaction, this change of mass can be converted into energy and this energy will be the kinetic energy of the of the particle. Now, if we have any of these reactions or with any of these, the case and each decay gives a tope gives E energy. The total energy from n decays will be N multiplied by the energy in one decay. And finally with the final concept question that if we If the number of radioactive nuclear present is initially um N0, let's say After one half life. How many nuclear I would remain? Well by definition, if we have N0 initially after one half life, it is just going to be n 0/2. And that is the definition of a half life. So we are now asked to calculate how much ice Would um one g of radium melt after 1/2 life. Okay, Well after 1/2 life we're going to have um we're going to have uh sorry, we're going to have and 0/2 reactions. Okay, so the total energy emitted, but the total energy released by this nuclear decays will be the energy in released in one nuclear decay times the number of nuclear decays which will be N 0/2. We're told that N zero is equal to 2.69 times 10 to the 21 nuclei. Yeah. And yes. Um so we have then we want to calculate what this delta E. Or what this energy released in a single reaction is. So by the conservation of energy, the initial energy is the mass of the radium atom times C squared. And that is equal to the final energy which is the mass of the alpha particle times C squared plus the mass of the radio Radan times C squared plus the energy that's going to be released in the collision in the decade. So this means that E. Is equal to the mass of raden minus the mass of the alpha particle minus, sir, the massive radium minus the mass of the alpha particle minus the mass of raden times C squared. And were given to these three masses from the question. So this is equal to 2.22, sorry, Should be 224 .062 0186 U -4.00: 603 U -220.011368. You and that's all multiplied by c squared. So adding these three numbers together, We get this is equal to 0.006 um 215 You time see and this is the energy released in one single decay. Now you is defined as 1/12 the mass of the carbon 12 atom. And it has a numerical value of 1.66 times 10 to the minus 27 kg. C is the speed of light. And that has a value of three times 10 to the eight m/s. So this all means that the energy released in one nuclear reaction is for one nuclear decay is equal to 9.285 times 10 to the minus 13 of a jewel. Why? So if we have and 0/2 of these nuclear reactions and each produces this 9.2 a five time sentiment minus 13 of the jew. The total energy is multiply is that energy in one reaction released? Multiplied by the number of the case that occurred. The case reactions. And using the word interchangeably. So we have a zero from above. So we had it somewhere up here and zero is here. We now know what the energy released in one decay is. So we can determine that the total energy is equal to 1.24 times 1.24 times head to the nine jewels. Mhm. And now we're going to make the assumption that all of this energy is converted, so all converted into melting the ice. In reality, that's not going to be true. There's gonna be some energy losses to interacting with the environment, whatever. But we're going to just assume all of this energy here goes to melting the ice. So the kinetic energy of the alpha particles goes to melting ice. So going back from the very first equation we wrote, this is the energy. To me, this is the energy required to melt em kilo grams of ice. So if we have this much energy, we can rearrange to determine the amount of mass that we have, and this is given by so the amount of mass is equal to the energy that we have. So the total energy divided by the latent heat, we define what the value of the latent heat was at the beginning of the question and Filling these two numbers in, we get 3,757 kg of ice, and that's the amount of ice that can be melted within one half life of this nuclear decay. Yes.


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