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Question

Ji f=] cntains the pni8 An ana n 3u) 46-> aathe Aunt o J6)") " An aan punt @ hif) J(o 5) - 1

Ji f=] cntains the pni8 An ana n 3u) 46-> aathe Aunt o J6)") " An aan punt @ hif) J(o 5) - 1



Answers

Find $D_{\mathfrak{u}} f$ at $P$. $$ f(x, y)=\frac{c x+d y}{x-y} ; P(3,4) ; \mathbf{u}=\frac{4}{5} \mathbf{i}+\frac{3}{5} \mathbf{j} $$

So we're giving these two functions F. Of A. And G. Of A. And what we're gonna do is we're going to find the composite function G. Of F. Of A. And all we have to do is we plug in the equation Or the function sorry? five for every value of A. In the function G. A. B. So this would be equal to F. Of a Squared. Since we plug in five for every value of A. Here. And if we want to actually plug in What are five is equal to This would be equal to 1/5 a. Squared. Which is then just equal to 1/25 A square. Mhm. For part B. What we're gonna find is F. Of G. Of A. And so again what we're gonna want to do is we're gonna plug in G. Of a. Into every value of A. And R. Function F. Of A. So if we look at our function f of its equal to 1/5 a. So this would be equal to 1/5 gov. Just then equal to 1/5 A squared, Yes, A squared. And lastly in part C, we're gonna find the value of the composite function G of F. Of A. At A is equal to negative two. And so if we look at the function we found in part a, it was equal to 1/25 a square. So this would be equal to 1/25 times negative two squared. Which is then equal to 1/25. Yeah, times four. Mhm. Which is equal to one over 100. So the value of the composite function G of F five at A is equal to negative two is equal to one over 100.

With potassium Fellows I night Sweet potassium Barbados I night with potassium pharaoh Sign I'd solution. See you two platforms. See You. two platforms. See you too. F E. CN six chocolate colored PPT. Chocolate Good lad PPT. So according to the option in this problem, Option C option C Eat correct. And said for this problem with potassium Ferdowsi night solution, see you two plus form. See you to Ephesians six chocolate colored PPT. So I hope you understand the solution of this problem.

Feats. Clearasil on rain here. So, for part A, we're gonna use the product rule. Let me get F G. Derivative five is equal to derivative of F five GF five less five derivative of G of five. You plug it in and you get six times negative. Three plus one times two, which is equal to negative 16. We have part being f departed by G. The derivative of five is equal to the drill bit it, uh, the five g of five minus F five. The derivative of chief of Fly all over G of five square and you get six times negative. Three minus one times two over a negative three square, giving us negative. 20 over nine For part C, you have Jeanne divided by s the derivative five, which is equal to the derivative of G of five. Yes, a five minus g of five. The derivative of F of five all over five square. This is equal to two time one minus negative. Three. I'm six over one square, which is equal to 20

Yeah, yeah, we can compute F of the -3 is equal to five times -3 sq -7. And this is five times 9 97. It is 45 97 will be 38. So if screen Echo 25 times three sq -7 in this echo 25 time 9 97 so the answer will be the same six. Today into F a is equal to five a square minus seven. So if minus, they will be five times minus a square minus seven into five a square 97. So here we can see this equal to this and this equal to this because the function here is X square. So it's a even function. So that means if they will always equal to if minus. So this is some side information you can use to check your answer.


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