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An m 8.00kg block sits on frictionless 309 incline: The block is connected by thin rope to block of mass M 20.0kg The rope runs over cylindrical pully of mass mp 2....

Question

An m 8.00kg block sits on frictionless 309 incline: The block is connected by thin rope to block of mass M 20.0kg The rope runs over cylindrical pully of mass mp 2.00kg and radius 0.30m _Draw and label free body diagram of the two blocks and torque diagram of

An m 8.00kg block sits on frictionless 309 incline: The block is connected by thin rope to block of mass M 20.0kg The rope runs over cylindrical pully of mass mp 2.00kg and radius 0.30m _ Draw and label free body diagram of the two blocks and torque diagram of



Answers

Two blocks connected by a rope of negligible mass are being dragged by a horizontal force (Fig. P5. 43). Suppose $F=68.0 \mathrm{N}, m_{1}=12.0 \mathrm{kg}, m_{2}=18.0 \mathrm{kg},$ and the coefficient of kinetic friction between each block and the surface is 0.100 . (a) Draw a free-body diagram for each block. (b) Determine the tension $T$ and the magnitude of the acceleration of the system.

There are two blocks kept on our ruffles on the surface. You're as shown in the figure. This is a hospital and this is second. Look, your muscles are given. Ask em one and I'm horizontal. Force is being applied on them and the tube laws are connected to the line in extensive ill massless of spring attention. T will be developed. The string the leads off the block. Uh, mtg. So the normal reaction off the ground or the block maybe enter. And here it is. And when did you so here. The normal reaction on the ground or the block? Maybe anyone refuse. Normal reactions are given us. And when G and M Doje respectively as a system off the blocks is moving right work. So both of loss will experience forces or friction in backward direction like this. So, first of all the data given then in the values Force IHS 68 120 Newton Mosque M one Yes. Well 0.0 k g mosque M two is 18.0 k g and the coefficient of Canada. Friction between both the blocks in the surface is mucus 0.100 in the first part, we have to draw a free body diagram for each law. So most of all, a free body diagram. F b d all m one and it re meeting on ass. The two forces are acting on it. In that direction of motion, there are only two forces. One is this tension industry and oppose it. Print? Yes, it is the force of friction. F one most fun lies new gay into any. They're more forces acting on the block and one g in the normal reaction. Anyone but these are not considered in the recreation off everybody that because both of them cancel each other. And the motion is along Horizontal No F b deep, all empty again for this. This is the block and there is a force applied on it. Yeah, and in the leftward direction one is ancient p in the spring and never tease the force of friction F two, which is gonna seem you gay into Enter. This is a bitch. I'm g off the block, and this is the normal reaction off the ground. Order the block. So these are the two everybody diagrams blocks Now in the second bar, we have to find the acceleration off the system. So go find acceleration. We simply make the equations of motion. So for the second block force F minus tension D and minus or so friction, we went toe empty. And for the first block, the question will become I see minus just F one. It's going toe m one into it if I add the's Immigration's the Pension we began the fourth this 68 10 Newton minus F one means there's a 0.1 because f one waas new gay into anyone. So and it comes up to be you don't find one into well in tow. 9.8. This is for F one and now have toe new doing to enter mewing toe mu contento so nuclear again, 0.1 in tow, getting for him to planning to 9.8 and equal store by addition of these two and 1% toe well plus city. Okay, so it comes off will be 68 minus 17.64 minus 11.76 Musical 30 A. So the acceleration comes out to be equal to 1.29 nature, but a second a square. This is the answer of the second part of the question. No, The third part. We have to find tension in the strength. Find it. The use This equation t minus F one is going toe and money. Or we can say D minus new G LNG. You see Acquittal M one. Okay, so it becomes day is a particle me, Okay. And McGee Plus and went into it. What? Began? CF 0.1 into 12 in 29 point it less well again into acceleration 1.29 Finally, this answer comes up to be 27.2. Noonan, this is the answer or the third party. Thank you.

Hi, I have driven. This is the problem. Based on Newton's second up. Here it is given Pa blogged off last night. Katie. It's hanging vertically. Attest to that spring as soon as the figure there is a friction between her gentle surface and brow. That is 0.0, Marshall, the block is given fight getting We have to fight the tension in the district. It surveyed a munge evil act particular downward. Intentionally he attention t it's obeyed. I'm to d will act in this direction Normal force in this direction and hear the friction bill act It is moving downward with acceleration A It will move towards right with acceleration A so f feeding Oh, a month Be care, right? Um, Monge e minus tree is called to Amun A. You can draw here if you like. And what Amandeep Attention, Take on moving downward. Similarly f video off am to blow up. I do. This is empty and duty normal reaction patient friction so and will be is going toe m two g Friction will be mute K in tow that is mu kick em to enter ji so t minus f will be skull tow am toe into a fiction is pointing and took five into nine point cage. It's called five into it. See question toe from one we can write and Mandy that is 9 to 9.8 minus team. It's called Tau 9 to 8. Solving equation toe entry to wealth reform. Attention, You will get 37.8 Newton there, so thanks for much.

Mhm. Discussion covers the concept of the 10 2nd law of motion, and for part a We need to draw the free body diagram. So for M1 if we don't draw the free boil diagram, the forces acting on a minus the tension t along the horizontal direction, the weight along the vertical downward direction, and a normal reaction falls from the ground. That is anyone along the vertical airport direction and a kinetic friction. That is a curable into Milky Times and what? Okay, And if we draw the free word, a ground for them to the forces acting on m toys the force along the right direction, the weight along the world grid downward direction and a normal reaction force and to around the upward direction and the tension along the left. And our kinetic friction also on the left, which is equivalent to Milker times the normal reaction force. And so if you write the uh Newton's second law of motion along the vertical direction for Em Win, that is sigma, F. Y equals zero because the block are in equilibrium along the vertical direction. And from this we get and one is equivalent to and one time she and along the horizontal direction The net force is equivalent to Hamas. M one times the acceleration, the tension minus milk A. Times and one that is M one G. Is the Cuban bento And one times the acceleration. And similarly for Mass M. two, we can write and two is a Cuban into M. Two G. And from the net force along the X direction is the Cuban into M. Two times A. We can right the force managed attention minus milk A times M two G is equivalent to M. Two A. Let's say this is a question one and this is a question. If we add one with two, we get the force minus milky times and one G Plus M two G. Is it cuba into I am one plus M two times the acceleration. Or the acceleration is equivalent to f minus milk kg until someone plus M two A bomb. I'm one plus empty. Now we can substitute the values to find the acceleration of the system and this is the solution of part B. And that is equivalent to the net falls. F is equivalent to 68. Newton minus Milk a is 0.1 into G. That is 9.8 m/s sq into M one plus M two. And that is 12 plus 18 kg upon 12 plus 18 kg or the acceleration of the system is uh 1.29 m 4 2nd square. Now from a question when the tension is equivalent to I am one into the acceleration. Yes, Milker times G We can substitute the value to find attention and and one is 12 KK Into 1.29 m for 2nd square plus 0.1 in 29.8 m per second squared Are the tension is equivalent to 27.2 notice.


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