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ProblemAn ECE mechanism is similar to that in Problem 7.3, except the product of the chemical step is electroactive and is able to undergo further electrontransfe...

Question

ProblemAn ECE mechanism is similar to that in Problem 7.3, except the product of the chemical step is electroactive and is able to undergo further electrontransfer: An example of this is found with the reduction of p-chlorobenzonitrile (CI-CHy-CN) which is able to undergo the following mechanism:Cl-C6H4-CN + e = Cl-CoH4-CN Cl-CoHy-CN" +H 4 CbHs-CN + Cl- C6Hs-CN + e = CsHs-CN"E? = -1.96 VE7 = -2.32Vwhere H: is abstracted from the solvent: The chemical step is highly thermody- namicall

Problem An ECE mechanism is similar to that in Problem 7.3, except the product of the chemical step is electroactive and is able to undergo further electron transfer: An example of this is found with the reduction of p-chlorobenzonitrile (CI-CHy-CN) which is able to undergo the following mechanism: Cl-C6H4-CN + e = Cl-CoH4-CN Cl-CoHy-CN" +H 4 CbHs-CN + Cl- C6Hs-CN + e = CsHs-CN" E? = -1.96 V E7 = -2.32V where H: is abstracted from the solvent: The chemical step is highly thermody- namically driven and its kinetics are fast: Sketch the voltammetry for the reduction of Cl-CbH4-CN at high; medium and low scan rates (relative to the rate of the chemical step).



Answers

You mix the following components in a solution. Assuming that the electrons must follow the path specified in Figure $14-14,$ in which experiments would you expect a net transfer of electrons to cytochrome c? Discuss why electron transfer does not occur in the other experiments. A. reduced ubiquinone and oxidized cytochrome $c$ B. oxidized ubiquinone and oxidized cytochrome $c$ C. reduced ubiquinone and reduced cytochrome $c$ D. oxidized ubiquinone and reduced cytochrome $c$ E. reduced ubiquinone, oxidized cytochrome $c,$ and cytochrome c reductase complex F. oxidized ubiquinone, oxidized cytochrome $c,$ and cytochrome c reductase complex G. reduced ubiquinone, reduced cytochrome $c,$ and cytochrome c reductase complex H. oxidized ubiquinone, reduced cytochrome $c,$ and cytochrome c reductase complex

So this question is asking about the conditions required for net transfer of electrons to cytochrome C, and those positions are a reduced ubiquitous on oxidized cytochrome C and cytochrome C. Reductase complex. And the in the options for answers, the only answer that satisfies all of the requirements is option E.

Hi, everyone. So, in this question, uh, they have given, uh, elemental analysis. Carbon at 71.9% and hydrogen, 12.1%. Then mass spectroscopy. Best big 800 other big 8. 43 than you know, carbon in carbon absorption. Sound different direction or H 2900 to 2000. Okay, then they have given a, uh c 13 animal spectroscopic data, and, uh, you know, this component reduction gears, uh, alcohol. And this from this, you have to elucidate the structure of the compound A. So let's begin. You know, first one needs there is a large image. There is percentage than atomic ratio. So 11 to include carbon, hydrogen oxygen. So passengers 71.9. Then this is 12.1. Option is 16. Yeah. Then atomic ratio of carbon. Are you blind? 992 That top erosion is 12.1, actually. Is one no, you know, phone numbers. So this is six. Well, and one now, since carbon is to hydrogen is to oxygen ratio is six h to 12 h 21 and therefore empirical formula of the compound is C six h 12 0 now. I think I'm better with this. You know, uh, you'll find, uh, no matter off and saturation is equal to one. Uh, this can be found out there is, uh, you know, parental king. There is. Action is taken s c H two. So you'll get C seven h 14. So C seven h 14 plus two. So see seven yet 16. Should be They're okay, but, uh, 16 minus 14. So we'll get to point to one side self and rich saturation. Secondly, we know that that is therefore, the structure of the probable structure of the compound is CS three cw one oh ch two ch two ch two Mhm ch two. Yeah, that is a exam tone. So, you know, this shows a best big in mass spectrometer at 100. The name of this compound is Exam two. Examine two on our three metal pendant tour exam. Doing okay? Yeah. Now. So this is where the compound A This will become bound E Yeah. Come, Bondi. Now this social, uh, mass spectrometer fragment and a message she is called to 43 due to formation of CS three C double bond. Oh, yes. No. Uh, no. It's social. A carbon frequent scene. Yeah, that is ch three c w bond. Oh, then ch two ch two ch two ch three. So this carbon group shows frequency in the iron at 2. 1718 per centimeter. Yeah, okay. Many my new dances, etc. You can say, See that is this compound CS three c, double one? Oh, yeah, ch three. So the sound reduction with and maybe age four goods CS three ch, please. Yeah, then mhm ch two ch two ch two ch three. So this is secondary exile. Alcohol, secondary exile. I'll go home then. Divan. There is so my spectroscopic the carbon 13 NMR spectroscopy data. Okay. C o ch two ch two ch two ch three. So this is happening around 43 point for you. This carbon in carbon around 209 Then this is around 1 22.4. Then they says 29.8. When this is 26.1. And this is 13.7. And I saw the structure of compound. Is this

Okay from the question on Lee were provided with the activation energy already so straight away. Moving to part A. We have K 25 degrees sensors equals converting into kill. When it is 298 Kelvin equals a e negative activation energy divided by rt straightaway. Substituting the values we have. Six multiply 10 days to power aid E raised to power. Negative. 6.3 10 days to power eight divided by 8.314 multiplied with 298 kelvin. And the answer turns out to be 4.71 Multiply 10 days to power seven. So this is the rate constant off the reaction. Um, moving on to the second part, but being let me write the reaction first, we have nitrogen mono oxide plus serene dioxide. We have n mm f last f. So in the in this case, product N o. F. Is bent because the hybridization off product is s p two going on to the next part. Okay, I have to represent the reaction. Okay. It will be like oxygen. Double bond with nitrogen plus floor. Een and Floren leads to formation off oxygen double born nitrogen. There's a partial born formation between the reactant, which leads to formation off intermediate compound. On the final born will be final point will be oxygen double point, nitrogen, serene plus story and last. The reaction has a low activation energy because off the greater proportions off the collision between reactant, since this leads toe ah, higher rate off reactions.

You guys did the street problem? 15 In this problem in the electrical potential into the energy change for the reduction of GDP plus my credit oxen, the reaction of any D P plus to any DPH has, uh, electrical protection of negative 0.32 fold. And the reaction of reduced production to its obsidian storm has a electrical potential of all the 20.43 world. Therefore, the electrical attention for the reduction of any DP class by paradox in hell electrical importance and of positive 0.43 volt plus negative 012321 which gives us positive. So your 0.11 Next, we need to develop the energy change. You know the relationship between energy change and the potential is N g. This is a country negative n f electrical attention. In this case, the value of a number of the transit is too. The financial constant is 96.48 killed June morning person involved in verse one into the electric importance and these 0.1 around the world, which gives us 21 point three Tina June per month, therefore them energy changes. Now you do 21.3 kg more


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