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A reaction has the following rate law rate Mjs) =k[A] [B]-[c] when [AJ [B] = [c] = 1.0 JV the rate is 3.0 M/s. What would the rate be when [A] [8J = [c]= 2.0 M?Typ...

Question

A reaction has the following rate law rate Mjs) =k[A] [B]-[c] when [AJ [B] = [c] = 1.0 JV the rate is 3.0 M/s. What would the rate be when [A] [8J = [c]= 2.0 M?Type your response

A reaction has the following rate law rate Mjs) =k[A] [B]-[c] when [AJ [B] = [c] = 1.0 JV the rate is 3.0 M/s. What would the rate be when [A] [8J = [c]= 2.0 M? Type your response



Answers

For the reaction $A \longrightarrow B+C,$ the following data were obtained at $30^{\circ} \mathrm{C}$ : (a) What is the order of the reaction with respect to $[A]$, and what is the rate law? (b) What is the rate constant?

So for the reaction of ah, from A to B and C so that we have forwarding data are opting affair Adidas houses. So first of always, the older lash in second will be a waite's equation. And then what would be the way constant? So again, we just stopped you felt we follow general roads. Um, wait, you equation. So we have a two powerful friends. And first of all, where to find the powerful am Seriously, although we Asher who get us Pekarek sperm one Experiment one and she was here for a through C zero increased to ah syrah pouring 356 So that we have 7.35 60 Wipe Lassie or foreign to three. We should be able to finance warfare around 1.55 times Inquiries. Okay, How above with the weight. So for the waitress should be able to find that ihsaa if they're on to a point. Ah, for Ciro ah timed increase. Okay, so you voted the way show between, um, Indian cuisine, the, uh, concentration and the weight. You should be able to find that the defendant ref forever and 1.55 times as well between the wait between the increase the virgin quiz challenging the concentration and also took to the weight. So from here, we can see that Ah, the order of reaction over here should be equals to two. Should be closer to the reason he is. So Okay, so if you sequence to two, we can just try to see what would be the change in the, um in the in the weight. So you know that you do increase by 1.55 times in the concentration we multiplied went from 55 times. We should expect the change in the weight of reaction is 2.4 seal. We exactly show over here. So that's why the older the older reaction will be equal to two so yourself of that. Okay, so what would be the weight equation and this system really equation over here? So if we close to K concentration of eight of power to okay for beat of away constant. So the re constant. We just need to were Wishart equation, We have a weight. Do you live by the concentration off, um 80 to the power of to So that's just pick the first Ah, experiments were swapping 17 time 10 to do that for they were still point to 30 to the power of to And then we should be beautified as equals to 47.88 I intend to left we? No, that one leader and time of seconds, uh, to power that foot. And this is the, um we constant.

So we're told that the reaction is going to be third order in a. And there's no be in, the expression means it's zero order in B. So that means whatever you do to the concentration of B. Whether you double it or have it or whatever you're going to have no change in the rate. Since the rate is independent of the concentration of of B. Um You don't have no change in the rate or in the no change in the rate constant as well. The rate constant is going to um change with temperature but not with changes in concentration of anything. All right. And then the reaction orders Our 3rd order in a. And zero order N. B. Based on the exponents. And the overall reaction order is going to be the sum of 3-plus 0. So it's gonna be third order overall. And then the units of the rate constant. So you can figure it out just by saying the rate is going to be the change of the Mueller concentration over time and that's gonna be K times the um units of um concentration of a cubed. So then we'll divide both sides by m cubed. To get that we have 1/1 minus one minus three is negative two. So we have I M squared times us. And that's going to be the units of k inverse seconds times square inverse of polarity.

So in this example we're trying to find out the rate of the reaction. So we know that the rate of the reaction escaped correct constant went to planned by the concentration of curious to the power of them. The name is the order of the reaction. Which we do not really know so many ways of doing this. If you take the logs of both sides, you get like a log of rate, is it going to K. This belongs okay. Plus M. Times I love the concentration of Q. Or Ellen. Sorry Ellen concentration of cuba. Yeah. Now if you just substitute uh actually you could draw it so this is almost like Y equals Mx plus E. Where the slope will give you the Ellen. So one way you can do this is by just calculating the law of the rates and calculating the uh the love of cube. So you can convert this into L. N. Q. And Ellen rates. And you can see if it's a straight line, it's a straight line. The slope will give you the order. But the easier way to do this is to consider any two points here. You could also consider and then you can check with the third point. So let's consider at this point here and plug it in into this situation. So we know that 1.04 multiplied batteries power -2 equals key .2 & two. It is two part of em. And then you can consider let's say this one And then you can divide the two and you get the ratios Which you will yet 1.557. Okay, is equal to 1.27 Mr. And and if you take a thugs on both sides. Yeah. Yeah. Mhm. And so you'll eventually get have equals two. So you can say that the rate of this equation is equal to k times Q is quit. And you can verify that the third point if you want to to calculate K. You simply have to take the rate and divided by accuse concentration of cube square. So let's take any one of these. Let's say we take the 3rd 1 So we know that the rate is 2.94 interchanges. Part of mine is too do I didn't buy .557 Sorry .357. Go ahead. And if you solve this you get rid of .231 and therefore you can put the whole equation down as rate. Is he going to .231 concentration of Q square. That is your ready wish?

For this question, we have a generic reaction of A plus B. Goes to see. The question tells us that it follows. The rate law rate is equal to K, multiplied by the be concentration squared. Thus, if we were to double the A concentration, because is part of not is not part of the rate law, the rate will not change with the change to the concentration of A. Only a change to the concentration of being changing the concentration of A will also do nothing to the rate constant. The rate constant is constant and only changes with temperature. Part B asks what are the reaction orders than for A. And B. Because a is not part of the reaction, then the reaction is zero order with respect to a. And the superscript on B tells us the order with respect to be namely second order. The overall will then be the sum of the two orders zero plus two. So it will be second order overall. A second order reaction overall has units on K. of one over polarity time. So be which one squared will have units of molar IT E squared. If we multiply that by K with units of one over polarity time, one of the most charities will cancel and we will end up with rate being polarity per unit time.


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