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The equilibrium constant; Kc; for the following reaction is 55.6 at 698 K:Hz(g) Iz(g) 2HI(g)Calculate the equilibrium concentrations of reactants and product when 0...

Question

The equilibrium constant; Kc; for the following reaction is 55.6 at 698 K:Hz(g) Iz(g) 2HI(g)Calculate the equilibrium concentrations of reactants and product when 0.270 moles of Hz and 0.270 moles of Iz are introduced into 1.OO L vessel at 698 K[Hz] [Iz] [HI]Submit Answerquestion attempt remaining

The equilibrium constant; Kc; for the following reaction is 55.6 at 698 K: Hz(g) Iz(g) 2HI(g) Calculate the equilibrium concentrations of reactants and product when 0.270 moles of Hz and 0.270 moles of Iz are introduced into 1.OO L vessel at 698 K [Hz] [Iz] [HI] Submit Answer question attempt remaining



Answers

For the reaction, Kc = 0.513 at 500 K.
If a reaction vessel initially contains an N2O4 concentration of
0.0500 M at 500 K, what are the equilibrium concentrations of
N2O4 and NO2 at 500 K?

Okay if we're looking at iodine and the bromide ion you're gonna want to reverse the half reaction for iodine because it is below and to the right of the bromide. So you're half reactions will look something like this. And then your electrons cancel. You add these two together. You're gonna get 55V and then if you're going to calculate your delta G we're gonna use negative N F. E. And then you've got two electrons that were transferred and then multiply that by Faraday's constant and then multiply that by your 0.55 the volts is the same thing as jewels per Coolum is gonna be negative 106,150 jewels. Now if you want to calculate the standard voltage it's going to be 0.592 over. End times the log of. Kay so you're gonna place this 0.55 here and your two moles of electrons is gonna be your end value. So this will be 20.55 equals 0.592 divided by two Times The log of K. figure out what this .0592 divided by two is and then you're gonna divide by that on both sides like this. So this cancels And then you're gonna have 18.58 is equal to the log of K. And then if you write this um an exponential notation which is the inverse of log notation. You're gonna get K. Is 10 to the 18.58 which is 3.8 times 10 to the 18th

Okay, so you're bromide is beneath the chlorine. So you would want to reverse that half reaction. So it looks like this changes the sign on your voltage. Leave the chlorine in the order that it's in at the voltages together. And then your delta G. Is going to be a negative N F. E. This is a minus two moles of electrons Times You're 96,500 for your constant. And then this is the same thing as jules per cool. Um so it's negative 50 to 110 jewels. Then your standard self potential is 0.592 divided by n times the log of K. You're gonna put this value here, you're to Mosul, electrons will be your end. So this is 0.27 is 0.592, divided by two times the log of K. Figure out what this is, divide both sides by it. You're gonna get 9.12 equals the log of K. Put it in an exponential notation, 10 to the 9.12, which is the inverse of log notation. You're gonna get 1.3 times 10 to the ninth.

23 The reaction given is B r he is We'll call br Those powerful feel good went to help with the standard free energy change that ideology Nord which is no which is n for the liturgy, not off all the problems you don't have off all the products minus and their stuff, do you not my older The evidence It is half Delta Gino D f Well, we are too plus half their touch. Do not have feel too minus day rejecting that ideology. Note of off the RC two They are They're little spheres in your home. So after putting all the values using Appendix Day, we're going to that 0.54 killer jewels five months. So with a relation between equilibrium, that is K and standard free energy, we're going to calculate K. Uh, okay, then care is started. Stuff she not by rt when she is 2.54 Kill a jewel Farmers. My art is a 0.314 going to tend to the power minus three. Just remove the Calvin. His killer Joel farm. All Calvin on there is to 90 days. He killed them. So it was a 1.2 So, Allen case Okay, will be Ellen inwards. Ellen, Inverse off. One point. There are two. Which will we eat? The bar minus 1.2 or chill turns out the base 0.36 This is a value off carriages. The equilibrium constant. The initial concentration on we are sale is obtained by taking ratio of the moles and volume. The little would be RC else. One point it is little moles. Well, they are CIA. My 10.0 liters, which will be 0.100. Come. They live in constant expression for the reaction. Can Britain s care we are to, huh? Sale due? Uh huh. By older? Yes, sir. That is their serial. They are still sealed, so Yeah, so we need to find a change in the concentration eggs. So when it is of strategic kilogram concentration in this reaction okay, will be point receive. Have my to that's where to? To the bar house. My 0.1. Double zero minus six. Therefore, from here we can find as physical stool 0.41 name to convert most from the majority will take lie. We need to multiply the morality with this volume in letters. So 0.419 moles into 10 point zero letters will be 0.4 to 0. Well, the initial amount off reaction the initials amount. Well, for the yes Turned is point for one little little M in tow. 10 liters, which is equals two one. Well, the equilibrium, all the equilibrium, most off B R C l is one point. There is a minus 1.0.42 more. They are cycles 2.58 more off B. R. C s. So another collision concentration off the are too. His 0.42 moles. No, they are my two, which is 20.21 Mole? No, the arto. Now they live them constant off the alto, which is 0.42 moles off sale toe by two. Which is you don't point to one. No field. Therefore the amount off their cell tow is Montel be are safe. How's this point? Five Admin. The amount off they are to and point to one mall and the amount of sales. So this point to one more

All right. So for this one, we're trying to find an equilibrium Constant K Ah, at 6 55 Kelvin for some reactions that we looked at earlier in problem 74. And so we'll start with the first reaction which is to And there, too going Tonto for And so the first thing I would do is I think back to how do we calculate the equilibrium, Constant K? And so you look at this formula Delta G. He goes, Don't the Jeannot plus r t ln okay, and so we can calculate Delta Do not. And we can't estimate Delta G if we know that the age not indulge us night and our is a constant and then t is 6 55 So from there, once we found Delta G, not in Delta G, we can get what K is by solving the algebra, and so that's what we'll do. So find a G night. You do Delta G A formation of the products might have still to g information of the reactant ce accounting for the molar ratios so you can find these values in your textbook. I'm just gonna write them down 99 eight minus two comes 51.3, and that equals minus 2.8. Killer Jules. So it's fine. Delta H not. He's the same process of non 0.16 Minus two terms. 33 queen too, equals minus 57.24 killed Jules. And we'll do. That s up here. Oh, quick. Don't. That s not equals Korea. Four 0.4 minus two times to 40.1. And that comes out to be, um, if you convert to kill a Jules, it's minus 0.175 A kill Jules per coven of values so we can plug in and find out estimate what Delta G is. So don't thingy is approximately still the age nine minus 6 55 which is the temperature comes that the s not. And so, if you plug those values in, you'll get approximately 57.9. And so from here we can solve the equation. The fine, the equilibrium constant K 77.9. Finessing killer Jules, he cools. Might is two point eight, plus, the constant are which in killer Joe lt's point 008 314 killed. Jules promote Kevin terms 6 55 times the natural log. Okay? And so we could just solve for this. And so me enough getting 60.7 equals 5.45 natural log. Okay? And so if you raise both powers to e k equals 66171.2. So that's reporting. RV was held the same way. Ah, little tricky part in the middle. So this is a grooming gas going to chlorine gas with chlorine gas going to through the e r c e o. It's a gas. So they give you Delta G, not a formation. Ah, just be our CEO. So if you multiply that by to account for the moles, you get minus two curdles, don't age not is also given for permission from B r c e o in delta h for B R. Two unsealed to above zero. So it's just two times that constant they give you, which is 14.6. And so you get 29.2. Killer Jules, don't as they didn't give you. But you can solve for it using the Gibbs equation. And since this is it standard temperature, you can do to 98 comes off the s not. And so you just plug in these values and you can sell for Delta s on Delta Ass night. Turns out to be and kill Jules 0.1, uh, killed Jules per Kelvin. And so again, you can take all these numbers in approximate what? Delta G at 6 55 Calvin is 29.2, minus 60 of times, dear. And so you get approximately minus 39.6 killer Jules and then completing this offer to equilibrium Constant K. So minus 39.6 equals minus two plus zero point. Uh uh, 831834 co jewels for Calvin terms 6 50 Mentor log. Okay. And so then you have you solved through the algebra you get minus 6.95 equals natural log of K. Raise both sides to e in K equals 0.1 And that's how you do this problem.


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