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True-false questions. Write down T"in parenthesis if the statement is true: Write down Fin parenthesis if the statement is false. (3 scores per question, 15 sc...

Question

True-false questions. Write down T"in parenthesis if the statement is true: Write down Fin parenthesis if the statement is false. (3 scores per question, 15 scores in all) 1a f-'(x) T() 2 I x > X2 and f is decreasing funetion, then f (x1) < f(xz) 3.If f(x) is continuous at x = 3, then limx-3 f(x) f(3) Suppose that is continuous on [0,1] and / (0)f (1) < 0 then there exists a number c between 0 and such that f (c) 0 5 IC Y=es then y' 65 IFill-in-blanks questions (5 scores

True-false questions. Write down T"in parenthesis if the statement is true: Write down Fin parenthesis if the statement is false. (3 scores per question, 15 scores in all) 1a f-'(x) T() 2 I x > X2 and f is decreasing funetion, then f (x1) < f(xz) 3.If f(x) is continuous at x = 3, then limx-3 f(x) f(3) Suppose that is continuous on [0,1] and / (0)f (1) < 0 then there exists a number c between 0 and such that f (c) 0 5 IC Y=es then y' 65 IFill-in-blanks questions (5 scores per question, 25 scores in all) The radius of the circle with equation x? +y2 _ 2x + 8y = 0



Answers

Standardized Test Questions
You may use a graphing calculator to solve the following problems.
True or False If $f$ is continuous on an open interval $I$ containing $a,$ then $F$ defined by $F(x)=\int_{a}^{x} f(t) d t$ is continuous on $I .$ Justify your answer.

Hello. We have to the commander that given a statement to score because this treatment is limit expense too. Five Mondays. Yeah. Thanks. You can see that from the graph when the exit the approaches to the five from the left, the value of the function history. The given a statement is you, I told me initially. Thank you.

Uh, is that the Reeves? The end of June? Thanks. Well, we could you know that your ex itself the answer would be no. On early. Doesn't happen when have Agent X and then we're gonna go to agent exits. Time off from here for any base Jew. Thanks. If I need based, I off the remedy was to get into the X Times Atlanta I So, in this case, we have to our actually everything. So we should get you to the next time. And I'm a Jew, so this one will be forced.

Let's talk about a problem for you. This one says that if limit extending towards a off FX is five than the value of a fix near through part off A, it's somewhere but being minus 5.1 on minus 4.999 So this is actually a correct statement, because when we talk about, let's say, for example, this is a function on this is the value p and here we have five. Since the limit exists, it means that the parts which is towards the left side and the life, saith agree, also exist. This with limited six limit exists on Since the limit is five in the nearby, the value will be very close to fight. So what do the left and work with the right? It should be somewhere in the strange as we can see from the graph as well. These points are very near, So the statement is true

Sure falls if the graphical function have a tangent line. X equals a on the graph also has a normal line. It executes a so we must know that a normal line, he's just perpendicular to a tangent. So if we have a tangent line than were, of course, we have a normal line because that's all it means is just were particularly changing at the same point. A. So this is a sure statement.


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