5

Chapter8Section2: Problem 9PreviousProblem ListNextpoint) Find the volume of the solid whose base is the region in the first quadrant bounded by y = 2" y = 1, ...

Question

Chapter8Section2: Problem 9PreviousProblem ListNextpoint) Find the volume of the solid whose base is the region in the first quadrant bounded by y = 2" y = 1, and the y-axis and whose cross-sections perpendicular to the axis are semicircles_Volume

Chapter8Section2: Problem 9 Previous Problem List Next point) Find the volume of the solid whose base is the region in the first quadrant bounded by y = 2" y = 1, and the y-axis and whose cross-sections perpendicular to the axis are semicircles_ Volume



Answers

Concern the region bounded by $y=x^{2}$, $y=1,$ and the $y$ -axis, for $x \geq 0 .$ Find the volume of the solid. The solid whose base is the region and whose crosssections perpendicular to the $x$ -axis are semicircles.

The question from the topic electronic conversations and productivity. In this question, They were asked to assign a carrot set of 400 miles for the electron in these admirable Diagram, let's look at the first one basically, we have to understand like what are the values of M L N L M L and M S signifies for 100 trump. But let's start with the first one here with the concept here reviews is what does it ever end L. M. Anonymous and is actually shell. It is actually suction Emily's orbital and spin. That is really the first one Oregon. And then we have an animal which is in four days and having I was still upgrade down but we have to talk about this particularly that is trying to assign me uh and and family values. So here since it's in the 4th shell and well before, as you can see you write it is unfortunate. Yes, dr Arden it has only one orbiters. It must be assumption it will be zero reception as we know and they left on here Is present in the zero. You know. Well because since L0 in the very last zero because it always starts from minus L two plus l -0-0 makes no sense. It is just zero and the second is upright. So I may assume it to be What's up are you know, club ways. That's how we can lighten Admit country alternate conversation or the economy numbers for this particular one leon and then we have please but we don't have talked about this one then we have creepy and that there's an electron what we got to discuss the configuration up. And so if you try to write the electronic confirmation for this since it began in the third period And would be three and L will be one because we're talking about the orbital mm Now, since it is The orbital Miami can go from -1 to plus one Management, zero personality values of which orbital directions presented minus one. So it would be my next one and howard M. S. And this is as you can see images here. This minus how because they're just going down. So that's how we're gonna explode. The second one, here's the third one, the third one. The electron that were too concerned with us what is but we won't be touching it with us. It's not abuse. That's the sort of not don't ask The next one is three and to me one, into its pair. We just talked about this particular don. So let's try to write the little all the gun owners for this particular electronics since there's belonging to through the or button And would be three because of 33 years. I don't want to you already. It should it should be one since at least engine we to this day. Let's do it would be two minus two -101. That is the values of but in what orbital it is presented, it is presenting the medal once. It would be zero. My name is will be and it would be. That's because it is going up. So this is the only consolation that we can have for the content. So they put this question to the quantum numbers for be in an electron For the 1st 1. These are the electrons For the 2nd 1. Is that the transact the third one. These are there. These are the answers what we were given question.

We have a region region bounded by Why I called it Swede and line We have a lying right to be able to when right to the equal to one we want to find a value. Oh, it's so early Only I seen that the sections have been deployed to the bees and parallel to the eggs and sealed with Lola Indeed sued day bees. And it's no so Parral. So day ace words chances. So this is a way Have so saints saves One is he said, that oh goods and Richwoods worry. That's beautiful, Zo, Why should we exert a little place than one? This is our words our insatiable you can done writes our folio G I wouldn't be here to be called so by they're excellent for Dane said Well, we have way. If if was worry the way which is records. What is every boy f off? Why here By good 01 beautiful boy. It was why screed, right? It's great! The way just okay, right? You the way. Let's find a in sever being situation. What do you have? You have Why incident for we're full from what zero to woods or if you simplify? Do I have? It was The one is buried up because deserves I have by one over words just people I full so base they is the folio. We're looking full civilian off a solid.

Okay, So for this problem, we're looking at the equations. Why equals X and why equals X squared? And we're looking for the volumes using squares cross sectional perpendicular squares across the X axis. And so the area is going to be X minus X squared squared. So in order to find the volume, we're going to look at the integral from 1 to 0 because that's where these two lines intersect and we're going to take X minus X squared square D X. And then, of course, it's going to be X squared minus two x to the third plus X to the fourth d X. And so, to find the integral, it's gonna be one third x to the third minus one half X to the fourth plus 1/5 X to the fifth from 1 to 0. And so if we look at this even further, we know if we put ones for all of these exes were simply looking at the coefficient. So one third, minus one half plus 1/5 and then we're going to subtract. If we put zero in all for all these exes, it's simply gonna be zero. So our final answer is going to be one 30th

Find the volume of solid whose spaces region in the first quarter it bounded by. Why couldn't do full negative X. Squire the X axis and the Y axis a cross section which is an equitable triangle perpendicular to X. Axis. Then side of the triangle equal to four negative X. Square. So here you can see that from the graph the area of an equitable triangle equal to Square root three upon four time is Squire. So now we put the will of a So here we get. It's crowded of three upon four time. Food negative X. Choir to the power two. So here volume of slice equal to square or three upon full. Okay, full negative X square to the power to There's the X. Now adding the volume of all slice. We help volume of solid equal to we approximate value sigma. It's quite all three upon 4 time four negative X squared to the power to time delta X delta X. The thickness of each slice Tends to zero. to obtain a definite into real well X equal to zeal and Ax equal to two. So here we equal to definite intrigue. All of It's got a 3.4 time four negative X squared to the power to time D X from 0 to 2. No we will do definite intrigue. All of Squared 3.4 time 16 negative eight times x choir for the two actually powerful D X From 0 to 2. So here we equal to Square three upon 4 time definite integral 16 negative 88 times actually power to plus actually about four D X from 0 to 2. So now here we have to find anti everybody of 16 98 times X choir plus extra the powerful is we equal to the square root three upon four time 16 X negative 8.3 Time XQ plus Actually power five upon 5 from 0 to 2. So now here we equal to opera value is too so we put your X equal to do So here we get It's Carol three upon full time 16 times too negative. 8.3 time 2 to the power three plus 2 to the power five upon five. Now you can see that here lower value is zero so I put your X equal to zero. So here we get Squared three upon 4 time seal. So now we simplify this. And here we get we could do eight times square three time 15 plus three negative 10 upon 15. So here we get we equal 64 time square root three upon 15. The cross section is equilateral triangle perpendicular to access. Access will be 64 Time Square three Upon 15. So it is a final answer.


Similar Solved Questions

5 answers
The volume of a lead ingot is measured to be 107 cm when the" lead is at temperature of 274 K The lead is now heated considerably, and its volume is (somehow) measured again, this time to be 114 cm? If the coefficient of linear expansion of lead is 29x10 ('C)- 1, what is the new temperature of the lead?Note: You shouldn't need to convert any units for this problem:
The volume of a lead ingot is measured to be 107 cm when the" lead is at temperature of 274 K The lead is now heated considerably, and its volume is (somehow) measured again, this time to be 114 cm? If the coefficient of linear expansion of lead is 29x10 ('C)- 1, what is the new temperatur...
5 answers
[2] Let A and B be sets. Show that the three sets A B, AnB, and B A are disjoint;, and that their union is AUB
[2] Let A and B be sets. Show that the three sets A B, AnB, and B A are disjoint;, and that their union is AUB...
1 answers
#1. SppossCa Hnvws Cv, X Ls Dusdy f)= 2 (i-x ), =LxaSxl c Axs E[x] Gxj Val
#1. Spposs Ca Hnvws Cv, X Ls Dusdy f)= 2 (i-x ), =Lxa Sxl c Axs E[x] Gxj Val...
5 answers
W;fh 4hi s NMr chary Wus (J}ef M ined 4k ckanicul fof fulu Wus C5 Hn 0, Tke Rrs} Por + 0 F 4k Strudlue below ;S Coffed, Con Soione show how H Cest of 4k Strudwe should look Ustny 4 Nm R chat;
W;fh 4hi s NMr chary Wus (J}ef M ined 4k ckanicul fof fulu Wus C5 Hn 0, Tke Rrs} Por + 0 F 4k Strudlue below ;S Coffed, Con Soione show how H Cest of 4k Strudwe should look Ustny 4 Nm R chat;...
4 answers
Let / : [0,0) - R such that /then Itglfl =R
Let / : [0,0) - R such that / then Itglfl =R...
5 answers
(a) Evaluateuiug = suxticutiou.0+5 +(L) EvaluntuIsiug partiul [ractiolns_(2 + 5 +
(a) Evaluate uiug = suxticutiou. 0+5 + (L) Evaluntu Isiug partiul [ractiolns_ (2 + 5 +...
5 answers
Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the equation:(a) $mathrm{NH}_{4}{ }^{+}(a q)+mathrm{OH}^{-}(a q) ightleftharpoons$(b) $mathrm{CH}_{3} mathrm{COO}^{-}(a q)+mathrm{H}_{3} mathrm{O}^{+}(a q) ightleftharpoons$(c) $mathrm{HCO}_{3}^{-}(a q)+mathrm{F}^{-}(a q) ightleftharpoons$
Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the equation: (a) $mathrm{NH}_{4}{ }^{+}(a q)+mathrm{OH}^{-}(a q) ightleftharpoons$ (b) $mathrm{CH}_{3} mathrm{COO}^{-}(a q)+mathrm{H}_{3} mathrm{O}^{+}(a q) ightlefth...
1 answers
Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If the augmented matrix corresponding to a system of three linear equations in three variables has a row of the form $\left[\begin{array}{lll|l}0 & 0 & 0 & a\end{array}\right]$, where $a$ is a nonzero number, then the system has no solution.
Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If the augmented matrix corresponding to a system of three linear equations in three variables has a row of the form $\left[\begin{array}{lll|l}0 & 0 ...
5 answers
Parucular golulonJunetrote LqualonLatnesLaln74)-> 04) -=Ar)
parucular golulon Junetrote Lqualon Latnes Laln 74)-> 04) -= Ar)...
1 answers
A load $W$ is to be placed on the 60 -lb plate of Prob. 4.97 . Determine the magnitude of $W$ and the point where it should be placed if the tension is to be $50 \mathrm{lb}$ in each of the three wires.
A load $W$ is to be placed on the 60 -lb plate of Prob. 4.97 . Determine the magnitude of $W$ and the point where it should be placed if the tension is to be $50 \mathrm{lb}$ in each of the three wires....
4 answers
Coursc dashboardTimie lelt 0.43.03Question l Not yet answered Marked out of 1.00 ~Flag questionCompute the COD of the methanol CH;OH in gram oxygen per = 'gram methanol: CH;OH+Oz-+HCHO+H,OzNcxt Paec30701 Matu-i
Coursc dashboard Timie lelt 0.43.03 Question l Not yet answered Marked out of 1.00 ~Flag question Compute the COD of the methanol CH;OH in gram oxygen per = 'gram methanol: CH;OH+Oz-+HCHO+H,Oz Ncxt Paec 30701 Matu-i...
4 answers
Simplify: (2ut)a(Vz"12)20Find tbe domain of f(x) = Vrand fnd f (14).
Simplify: (2ut)a (Vz"12)20 Find tbe domain of f(x) = Vr and fnd f (14)....
5 answers
Do the kinetic energy operator and potential energy operator commute once they are applied on f(x) =25X?0 a.Yes they do commute 0 b No clear conclusion could be drawn 0 c They don't commute0 d. None
Do the kinetic energy operator and potential energy operator commute once they are applied on f(x) =25X? 0 a. Yes they do commute 0 b No clear conclusion could be drawn 0 c They don't commute 0 d. None...
5 answers
If g()-x +3x+5 , then g(4) =
If g()-x +3x+5 , then g(4) =...

-- 0.019314--