5

Using conservation principles, write stoichiometric relationships for the precipitation of 0 2 ? as Mg2P2O7 (abai 2) Mg 2+ MgzPz01les 0 2- = 7 moles MgzPzO1oles 0 2...

Question

Using conservation principles, write stoichiometric relationships for the precipitation of 0 2 ? as Mg2P2O7 (abai 2) Mg 2+ MgzPz01les 0 2- = 7 moles MgzPzO1oles 0 2-moles MgzP20noles 02-moles MgzPz01Mg 2+ = 2 moles MgzPz01

Using conservation principles, write stoichiometric relationships for the precipitation of 0 2 ? as Mg2P2O7 (abai 2) Mg 2+ MgzPz01 les 0 2- = 7 moles MgzPzO1 oles 0 2- moles MgzP20n oles 02- moles MgzPz01 Mg 2+ = 2 moles MgzPz01



Answers

Calculate how many moles of $\mathrm{NO}_{2}$ form when each each quantity of reactant completely reacts.
$$2 \mathrm{N}_{2} \mathrm{O}_{\mathrm{s}}(g) \longrightarrow 4 \mathrm{NO}_{2}(g)+\mathrm{O}_{2}(g)$$
\begin{equation}
\begin{array}{ll}{\text { a. } 2.5 \mathrm{mol} \mathrm{N}_{2} \mathrm{O}_{\mathrm{s}}} & {\text { b. } 6.8 \mathrm{mol} \mathrm{N}_{2} \mathrm{O}_{5}} \\ {\text { c. } 15.2 \mathrm{g} \mathrm{N}_{2} \mathrm{O}_{5}} & {\text { d. } 2.87 \mathrm{kg} \mathrm{N}_{2} \mathrm{O}_{\mathrm{S}}}\end{array}
\end{equation}

In this question, we need to interpret three violence to chemical equations in terms off particles most on must. And then we have to show that the low off conservation off mast is observed in each one of them. So this first work. So let me pick your also law off my conservation. No off mass conservation. Okay, so first is a reaction between nitrogen. I'm hydrogen again. These equations are given already balanced, giving rise to I mourn you. Okay, so there's interpret this in terms off because this is a question is telling us that one molecule off molecule right molecules so that you don't get confused with moles. Okay. One molecule off nitrogen react with three molecules off hydrogen to obtain two molecules off ammonia. Okay, now, in terms off more way. Have that one mole off nitrogen react with three moles off high beginning because we're using unit. We don't have toe right. Moles. Yes, am. Oil cause is the symbol of the unit three most of hydrogen to obtain two moles off ammonia. Now, in terms of must. For that, we need to calculate the mass off each one off them. The molar mass. So the molar mass off a molecule off nitrogen east. True times 14 which is the atomic weight that you find in the table. Good. Los three times the massive hydro you molecule with cheese to artoms off hydrating times that must that atomic weight of fighter you, which is one if rise to to monikers of ammonia. So we have to calculate the mass of two molecules of ammonia, which is two for two months to multiply by one nitrogen, which is 14 plus three hydrogen. And they are totally weight is one uh So when we made the cut, this calculation we have 28 plus three times to six people still tool times 17 14 plus 3 17 Okay. Which means I we have 28 plus six 34 on to fix the four here, 34 on two times 17 is also 34. These also shows the mask off the law off mask conservation. They love muskets of mass conservation is is that it implies that the mass of the reactor has to be the same as that mask off the product. The total mass of the reactor has to be the same as a total mask you both with the front. Um next. So we don't with this one. The next one is hiding in a hydrochloric acid is an a quick solution off. I'd uploaded castle plus an April solution off. Potassium hydroxide give rise to fashion chloride in solution plus water. So we're gonna do exactly the same three interpretation that we did above. If I'm gonna do here first, we say on the question is given already balanced. So we don't have to worry about balancing the equation. This the reputation Is that one more like you? No. In these guys, we don't talk about molecule one hydrating iron on one glow, right iron reacts with one Otash in iron plus one hydroxide Aryan to give rise to one. Ah, young off. What assume? Plus one chloride iron plus one molecule of water. In terms of mole, we say one mole off I uploaded gossip React with one more off potassium hydroxide to produce one more Well dashing chloride plus one mole Most water now intense off must And then we show not wait Show the law off Mass conservation. So what do we say? We say that the massive hydrochloric acid, which is one plus the atomic weight off gloating 35.45 reacts with the the molar mass of potassium hydroxide, which is what passion is 39.1 plus tell me weight of oxygen plus the weight of hydrogen. So these Moscow's our fighter clothing. Kosit, when react with these mass off potassium hydroxide, will produce these mass off makashin karate. Well, Dawson this study night bring one clothing 35.45 plus these mice off water tool times one tool times one plus 16 They told me weight off oxygen. I think we made this leader calculation here, and this is 35 40 45 plus 39.1 plus 16 plus 1 56.1 now 39.1 plus 35 long 35.45. That's 74 1 55 plus to plus 16 18. And then we'll when I make sure that the total mass of the reaction equals in Turin, mask off the product. So for the reactive 35 sorry, it's not 35 city six year because he's one plus 35.45. OK, just 36.45 plus 56.1. That's 92.55 for the reactors. Now let's verify the products. 74.55 plus 18 92 warning. 55 OK, on August. Obviously, all of this is ground sperm over here. Also up here. Graspable all of this. Okay, The last one, the last one is magnesium. Magnesium, reacting with oxygen to produce, not a nation. Looks Ike. Okay, so the interpretation in terms off particle, we say that two atoms off ignition okay, Reacts with one molecule off oxygen to produce two units. But I know it's new. It's because this is a unique compound. But Mr Assad oxide solid back mission of bauxite is on a unit compounded for they phone units. Crystals, not molecule, no. Um, atoms. But units two units off. Magnesia folk site. Intense off moles. Two moans off. Mike. Mission react with one mole off oxygen to produce two moles off magnesium oxide on Finally the in terms off months, I'm to show the law off mass conservation interpretation in terms of mass on to show that no off mass conservation. Wow. Here. So, to magnus, you two times the atomic weight off nation, which is 24.30. Let me fix it 24 24.30 plus to our two times the atomic weight off boxing, which is extend. So these mass off magnesia when react with these mass off oxygen, we'll use two times one McNish in which is 24.30 plus one oxygen, which is 60. Okay, so here we have two times 24.30 is 48 0.60. So 48.60 grants Let's say off Magnus in react with 32 grams. I'm not gonna put you in it because it could be any unit. As long as you have the same proportion, you know it's must so. 48.60 a grants, for example, Off Mike Nation react with 4 32 brands off oxygen to produce two times 24.30 plus 16 which is 80.6, 80.6 for 80.6. So to show their mass conservation again, the tournaments of the reactor must be equal to the mass of the product. The mass of the reaction is 48 foreign six plus 32 That's 80.60 which is equal to the mass of the reaction of the product, which is 80.60 on this is grounds for more. Okay, with this, we answer this question.

Let's interpret the following chemical equations in terms of particles, moles and mass, and show that the Law of Conservation of Mass is observed for a we have and to gas and three each to gas, which produces two NH three gas. In terms of particles, we have one molecule of and to plus three molecules of H two to produce two molecules of N H. Three in terms of moles. One more event too, plus three moles of H two to produce two moles of an inch, three in terms of mass and to it's a massive to ah two moles times Moeller Mouse nitrogen 14 007 grams per mole, which were yield 28.14 g. A massive three h two with six moles of hydrogen hydration has a mullah massive 1.0 8 g per mole. It's would yield 6.48 g and the mouse of two and H three. We have two moles of hydrogen or nitrogen. Sorry, 14.7 God's promote plus six malls of hydrogen and this would yield 34 point 062 g of NH three. 28.14 g of and to plus 6.48 grams of h two would yield 34 0.62 g of NH three. Therefore, the Law of Conservation of Mass 34.62 g in the reactant is equal to 34 0.62 g of the products and the law of Conservation of Mass is observed for be we have HCL plus K o h yields K C O in each two of in terms of particles. Yeah one molecule reach CEO plus one molecule qh yields one molecule K c o plus one molecule h 20 terms of moles One mole of HCL plus one more KH will produce one more k c l plus one more A bridge too. In terms of mouse, HCL has a mass of 34 or sorry, 36 point for 61 g. K. O. H has a massive 56.105 g. So for the reactant, since this will be equal to 92.566 g for the products, K C L has a mass of 74 point 551 g and H 20 It's a mess of 18.15 g, so for the products, mass works out to 92.566 g. So Law of Conservation of Mass it is observed as the mass of the reactant is equal to the mass of the products. For C reaction is to magnesium solid plus o two to produce to m g o solid. In terms of particles, we have two molecules. We are sorry dot molecules two atoms of magnesium plus one molecule of 02 to produce two molecules of M g o. In terms of moles, we have two moles of magnesium plus one mole of oxygen to produce two moles of M g o. In terms of mass, the mass of magnesium. We have two moles of magnesium, so this works out to 48.610 g. One mole of oxygen yields 31.998 g. So for the reactant, since this would yield a total of 80.608 g and the M two moles of M G O for the products works out to 80.608 grams. It's a products 80.608 g and therefore the mass of the reactant since is equal to the mass of the products.

Yeah, for each of the following. That's calculate how many moles of N O to form with each quantity completely reacts. He started with 2.5 moles and 25 from the start geometry. Moles bend to five on four moles of 02 and this would yield an answer of five points. Your moles n 02 for be starting with 6.8 moos of into a five times two moles. Eventual five 24 moles of any two and to the correct number six pigs to Sig figs will get an answer. 14 moles of 02 for C, starting with 15.2 grams and 25 Let's convert this two moles. Molar Mass is 108.0 grams into a five. One more been to a five two moles of into five for more zaventem to and 23 Sig figs. This would work out to 0.281 moles of 02 and lastly for deep. We're starting with 2.7 kilograms and 25 pictograms. 1st 1 kilogram of 1 to 1000 grams molar mass 108.7 grams of into five in one model into a five in our strike geometry two moles of end to five to formals of N 02 and we'll find that this will be equal to three sig figs 53.1 moles of n 02

The balanced chemical nation is from the Venice Chemical reaction to more so make magnesium produces two moles of magnesium oxide. Does the mood Lazio used for the conversion is still more magnesium oxide? Yeah, I did buy two more magnesia. Use this conversion factor to calculate the number of more supporter or sorry of products from from Europe. 0.1 pipe More late than so. Kilcoyne 15 more make make this year into, um one magnesium. Thanks. Divided by no more making this year, the answer will be you know, here, boy, one fight more magnesium. So therefore the number of Mosul of magnesium oxide. From this you know 0.15 more Next balance Chemical reaction is from these bands. Chemical reaction to more so of men guarantee importance. Sorry to one more oxygen produces two more. So magnesium oxide. That's the more recent use for the conviction. Is two more magnesium oxide? If I did well, one more oxygen. Use this conversion factor to concluded a number of moles of product form from 0.15 more later. So 0.15 and more. Okay, then into do more magnesium oxide wherever by one more oxygen. This is equals two 0.30 more magnesium oxide. Therefore, the number of moles Oops of magnesium oxide form Yes. 0.30 more Next balance reaction is from the balanced chemical action. Four modes of Iran produces two modes of medical center. Does the more ratio use for the conversion is two more very conceived, divided by on what either use this conversion factor to calculate the number of months or product form from 0.15 more Latin A little 0.1 right one I don't. You do do more Very good. We waited by four months. Fine. An investor 0.0 75. No, Very good. Therefore the number of that looks safe. So the number of more So there you go on this, you know point, You know, 75 more that does the fairest Immigration is yeah, from the balanced chemical reaction she most of oxygen produces two. Most of ferric oxide does. The more recent huge for the conversion is I don't want very good site divided right Seymour opinion He was from Russian factor to calculate the number of motor product formed from 0.15 more reactant, the front room. Buy more oxygen. This Uh huh. Medical state divided by three more oxygen. This is equal to zero point 10 more records. Therefore, the number of no so very toxic from this 0.10 more.


Similar Solved Questions

5 answers
5) Gauss's Law_SphericaL Gaussian Surface_Conductors (Ch 6)Determine the electric flux through the closed surface where the cross section inside the plane surface is shown in Figure on the left: Determine the electric field inside and outside the conductor: (Figure is from OpenStax)Endcn Mn 4o 4me2 0=20 * 10 ' Clm?
5) Gauss's Law_SphericaL Gaussian Surface_Conductors (Ch 6) Determine the electric flux through the closed surface where the cross section inside the plane surface is shown in Figure on the left: Determine the electric field inside and outside the conductor: (Figure is from OpenStax) Endcn Mn 4...
5 answers
Use Green's Theoremn to calculate the circulation of F Ty52 j around the unit circle; oricnted counterclockwiseEnter an exact answer:Equation EditorCommonMatrixsin(4) sec(@) sin '()cos(n) csc(0)tan(a) cot(e)J sd2 f;d=V I @lcoStanJ7.47 =
Use Green's Theoremn to calculate the circulation of F Ty 52 j around the unit circle; oricnted counterclockwise Enter an exact answer: Equation Editor Common Matrix sin(4) sec(@) sin '() cos(n) csc(0) tan(a) cot(e) J sd2 f;d= V I @l coS tan J7.47 =...
5 answers
(irom 7.1) A random sample 0l 36 Palrents had %7 Bverage sysiolic blood preseurd Lnai the 959u confidanc& Inierval tar the pcoulation me8n?mm Hg; It tne populatlon standerd deviatlcn = mm Ha_(122, (108_ 143. (123,2.128.21 (121,
(irom 7.1) A random sample 0l 36 Palrents had %7 Bverage sysiolic blood preseurd Lnai the 959u confidanc& Inierval tar the pcoulation me8n? mm Hg; It tne populatlon standerd deviatlcn = mm Ha_ (122, (108_ 143. (123,2.128.21 (121,...
4 answers
Germanium had not been discovered when Mendeleev formulated his ideas of chemical periodicity. He predicted its existence, however, and germanium was found in 1886 by Winkler. Write the electron configuration of germanium.
Germanium had not been discovered when Mendeleev formulated his ideas of chemical periodicity. He predicted its existence, however, and germanium was found in 1886 by Winkler. Write the electron configuration of germanium....
5 answers
An organism's heredity is encoded in (a) DNA; (b) ATP; (c) lipids.
An organism's heredity is encoded in (a) DNA; (b) ATP; (c) lipids....
1 answers
Find the indefinite integral and check the result by differentiation. $$\int\left(\tan ^{2} y+1\right) d y$$
Find the indefinite integral and check the result by differentiation. $$\int\left(\tan ^{2} y+1\right) d y$$...
1 answers
Using the results of Exercise $1,$ determine the Möbius transformations that map: (a) $1,2,3$ to $2 i, \infty, 3$ (b) $\infty, 1, i$ to $\quad i,-i, \infty$ (c) $2 i, \infty, 3$ to $\quad \infty, 1, i ; \quad$ (d) $i,-i, \infty$ to $\quad 1,2,3$
Using the results of Exercise $1,$ determine the Möbius transformations that map: (a) $1,2,3$ to $2 i, \infty, 3$ (b) $\infty, 1, i$ to $\quad i,-i, \infty$ (c) $2 i, \infty, 3$ to $\quad \infty, 1, i ; \quad$ (d) $i,-i, \infty$ to $\quad 1,2,3$...
5 answers
When the followIng cquation haluncrd properly ndet acidic conditions; Whlare Ihe coefficientsthe specins shown?Cro4?Waler appears In the balanced equation 4(reactart; product; nehhee) with coeincient ul(Enier for neither:)How' MaV clectons ant translerred in thle IC4c Uon?Sutinie AnsvotTry Aneut Motakan
When the followIng cquation haluncrd properly ndet acidic conditions; Whlare Ihe coefficients the specins shown? Cro4? Waler appears In the balanced equation 4 (reactart; product; nehhee) with coeincient ul (Enier for neither:) How' MaV clectons ant translerred in thle IC4c Uon? Sutinie Ansvot ...
5 answers
Let y=x Ax+2 Find the following: Find all critical points. the function is increasing and decreasing; Justify your b. Find the intervals where answer_ Determine the intervals where the function is concave up Or concave down: Also, indicate the points = of inflection. Justify your answer.
Let y=x Ax+2 Find the following: Find all critical points. the function is increasing and decreasing; Justify your b. Find the intervals where answer_ Determine the intervals where the function is concave up Or concave down: Also, indicate the points = of inflection. Justify your answer....
5 answers
Q4. A trapezoidal land with vertices at the points (0,1),(0,2),(2,0),and (1,0). If we need to cover it with a plastic material of hight given by h(x,y)= eblxy) where glx,y)- Y-x Find the volume of the air above the y+x land and below the plastic cover. Show all your work: Sketch: (Smarks)
Q4. A trapezoidal land with vertices at the points (0,1),(0,2),(2,0),and (1,0). If we need to cover it with a plastic material of hight given by h(x,y)= eblxy) where glx,y)- Y-x Find the volume of the air above the y+x land and below the plastic cover. Show all your work: Sketch: (Smarks)...
5 answers
Use backward-difference formula to evaluate the first derivative of y = cos(z) at z h { using a value of # 9v2 3 9 % Vu42_40_)
Use backward-difference formula to evaluate the first derivative of y = cos(z) at z h { using a value of # 9v2 3 9 % Vu 42_ 40_)...
3 answers
H7.11 - Level 1Answered Incorrectattempt leftPredict the major product for the following reaction:CHEEHn
H7.11 - Level 1 Answered Incorrect attempt left Predict the major product for the following reaction: CH EEHn...
5 answers
Write balanced half-reactions for the following redox reaction:Fe? + (aq)+NO_(g)+2OH (aq)Fe? (aq)+NO3 (aq)+HzO()reduction:oxidation:
Write balanced half-reactions for the following redox reaction: Fe? + (aq)+NO_(g)+2OH (aq) Fe? (aq)+NO3 (aq)+HzO() reduction: oxidation:...
5 answers
Unfon baam matg 8.00k9 end Iength erhar ed &l tha baan I0cmn = Enot supporlod by sbing: diogram: Obled point 35.0 cm E Inabi 400kq: trom I ight erd Oblects _ baam end @ tre arached oquilbnum, wnalis tha mass 0i coletl StringBeam35.0 cm100 cmObjects220 K9 00 ko0.108 [
unfon baam matg 8.00k9 end Iength erhar ed &l tha baan I0cmn = Enot supporlod by sbing: diogram: Obled point 35.0 cm E Inabi 400kq: trom I ight erd Oblects _ baam end @ tre arached oquilbnum, wnalis tha mass 0i coletl String Beam 35.0 cm 100 cm Objects 220 K9 00 ko 0.108 [...
5 answers
(4pt) For continuously increasing whole life insurance on (r) , Ycu are given:The force of mortality is constant. 6 = 0.018 (iii) 2A, 0.2.Calculate (T)
(4pt) For continuously increasing whole life insurance on (r) , Ycu are given: The force of mortality is constant. 6 = 0.018 (iii) 2A, 0.2. Calculate (T)...

-- 0.025384--