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For a continuous random variable x, P(6 < x < 8) is represented by the area under the probability function over the interval from 6 to 8. True False...

Question

For a continuous random variable x, P(6 < x < 8) is represented by the area under the probability function over the interval from 6 to 8. True False

For a continuous random variable x, P(6 < x < 8) is represented by the area under the probability function over the interval from 6 to 8. True False



Answers

For a continuous random variable x, P(6 < x < 8) is represented by the area under the probability function over the interval from 6 to 8. True False

So if the P value in a statistical test is greater than the level of significance for the test, We actually failed to reject anil hypothesis, meaning if my alpha value is 0.05, and if my p value Comes out to be let's say 0.06, my p value will be greater than alpha, and hence I will fail to reject final hypothesis. Why is this? What exactly is fee value? P value is the probability that I am observing this by chance, right? P value means the value is basically the chance of getting something that you already have or something rarer than that. Okay, so I will fail to reject minor hypothesis, fail to reject my nail hypothesis. H not? Oh!

Number seven. The statement is false because the same thing I mean, it's no export is the center off the confidence interval and does not influence the width off and the confidence interval. So the confidence interval is not necessarily. Schwartz is the same bill, meaning it's more, yeah.

In problem 37. We want to determine if the following statement is true or false. If B of X equals X multiplied by, it was about minus x squared for all X greater than zero, and B of X equals zero four X smaller than equals zero. Then B of X is a probability density function. To see if this statement is true or false. We should first get the integration from minus infinity to infinity for B of X the X and see if it's equals one or not. If it equals one, then it's a probability density function. If not, then it's not the probability density function, then it equals we know that B of X equals zero for X smaller than zero, then it directly equals from zero to infinity. For the integration of this part X multiplied by it is a lot of mines, X squared dx. And to get this integration, we can notice that the differentiation of the power here can be represented here. The differentiation of the bar is minus two X. Then let's multiply by minus two and divide by minus two. Then it's minus two. Ex labour I e to the minus X squared dx. From zero to infinity. And divide by minus Stewart's minus one, divided by eight. Then we have the differentiation of the power not employed by E. Then we can integrate E to give, then it equals minus half. Got to blow it by E. It's about minus x squared. We integrate from from zero to infinity equals minus off. Multiplied. Boy, when we integrate using infinity then we take the limit and be tends to infinity for it was about uh minus X. We substitute by X equals B. Then it's minus b squared minus. We substitute by the lower limit is substituted by X equals zero, gives it was about zero, which is one. The evaluation of this limit gives us zero, then it's minus half. Are employed by minus one, then equals half. As long as this integration is not equals one, then it's not probability dynasty function, and we can make a conclusion for the statement to be false. It's false because the integration is not equal to one, it equals half.

No. So you have to grow up. So we have a function on a negative function. So here we can see that there is a graph of a function f in this area boundary from April X. So this. See this area that this will become the value off area a a up X. You can contact your that if the area X in the area under the graph off in an indicative patina function of the interval a X, then a x A off X will be a continuous function. So it is true that a prime X which equals toe function of mix it's not true.


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